McGraw-Hill/Irwin

Option Valuation

Chapter 21

Copyright © 2005 by The McGraw-Hill Companies, Inc. All rights reserved.

Option Values

Intrinsic value - profit that could be made if the option was immediately exercised. (Alternatively, the value of the option, if today was its maturity date)

Call: Max(stock price - exercise price,0)

Put: max(exercise price - stock price,0)

Time value - the difference between the option price and the intrinsic value.

21-2

Option value

Time Value of Options: Call

Value of Call

Time value

X

Intrinsic Value

Stock Price

21-3

Factors Influencing Option Values: Calls

Factor

Stock price

Exercise price

Volatility of stock price

Time to expiration

Interest rate

Dividend Rate

Effect on value increases decreases increases increases increases decreases

21-4

Restrictions on Option Value: Call

Value cannot be negative

Value cannot exceed the stock value

Value of the call must be greater than the value of levered equity

C > S

0

- ( X + D ) / ( 1 + R f

) T

C > S

0

- PV ( X ) - PV ( D )

21-5

Call Value

Allowable Range for Call

PV (X) + PV (D)

Lower Bound

= S

0

- PV (X) - PV (D)

S

0

21-6

Arbitrage

Arbitrage :

No possibility of a loss

A potential for a gain

No cash outlay

In finance, arbitrage is not allowed to persist.

“Absence of Arbitrage” = “No Free Lunch”

The “Absence of Arbitrage” rule is often used in finance to figure out prices of derivative securities.

Think about what would happen if arbitrage were allowed to persist. (Easy money for everybody)

21-7

The Upper Bound for a Call Option Price

Call option price must be less than the stock price .

Otherwise, arbitrage will be possible.

How?

Suppose you see a call option selling for $65, and the underlying stock is selling for $60.

The arbitrage: sell the call, and buy the stock.

Worst case? The option is exercised and you pocket $5.

Best case? The stock sells for less than $65 at option expiration, and you keep all of the $65.

There was zero cash outlay today, there was no possibility of loss, and there was a potential for gain.

21-8

The Upper Bound for a Put Option Price

Put option price must be less than the strike price. Otherwise, arbitrage will be possible.

How? Suppose there is a put option with a strike price of $50 and this put is selling for $60.

The Arbitrage : Sell the put, and invest the $60 in the bank. (Note you have zero cash outlay).

Worse case? Stock price goes to zero.

You must pay $50 for the stock (because you were the put writer).

But, you have $60 from the sale of the put (plus interest).

Best case? Stock price is at least $50 at expiration.

The put expires with zero value (and you are off the hook).

You keep the entire $60, plus interest.

21-9

The Lower Bound on Option Prices

Option prices must be at least zero.

By definition, an option can simply be discarded.

To derive a meaningful lower bound, we need to introduce a new term: intrinsic value .

The intrinsic value of an option is the payoff that an option holder receives if the underlying stock price does not change from its current value.

21-10

Option Intrinsic Values

Call option intrinsic value = max [ S – X ,0 ]

In words: The call option intrinsic value is the maximum of zero or the stock price minus the strike price.

Put option intrinsic value = max [X-S, 0 ]

In words: The put option intrinsic value is the maximum of zero or the strike price minus the stock price.

21-11

Option “Moneyness”

“In the Money” options have a positive intrinsic value.

For calls, the strike price is less than the stock price.

For puts, the strike price is greater than the stock price.

“Out of the Money” options have a zero intrinsic value.

For calls, the strike price is greater than the stock price.

For puts, the strike price is less than the stock price.

“At the Money” options is a term used for options when the stock price and the strike price are about the same.

21-12

Intrinsic Values and Arbitrage, Calls

Call options with American-style exercise must sell for at least their intrinsic value.

(Otherwise, there is arbitrage )

Suppose: S = $60; C = $5; X = $50.

Instant Arbitrage. How?

Buy the call for $5.

Immediately exercise the call, and buy the stock for

$50.

In the next instant, sell the stock at the market price of $60.

You made a profit with zero cash outlay.

21-13

Intrinsic Values and Arbitrage, Puts

Put options with American-style exercise must sell for at least their intrinsic value.

(Otherwise, there is arbitrage )

Suppose: S = $40; P = $5; K = $50.

Instant Arbitrage. How?

Buy the put for $5.

Buy the stock for $40.

Immediately exercise the put, and sell the stock for $50.

You made a profit with zero cash outlay.

21-14

Lower Bounds for Options (con’t)

As we have seen, to prevent arbitrage, option prices cannot be less than the option intrinsic value.

Otherwise, arbitrage will be possible.

Note that immediate exercise was needed.

Therefore, options needed to have American-style exercise.

Using equations: If S is the current stock price, and X is the strike price:

Call option price

 max [S-X,0 ]

Put option price

 max [X-S,0 ]

21-15

Pricing Bounds Summary

Calls:

Upper Bound: Stock Price, S

Lower Bound: Intrinsic Value : max [ S –X, 0]

Puts:

Upper Bound: Exercise Price, X

Lower Bound: Intrinsic Value max [X-S,0]

21-16

How would you price an option?

Step 1. Project the distribution of ending stock price (based on the stock price volatility)

Step 2. Compute the payoff for that distribution

Step 3. Using the correct risk adjusted discount rate, discount the expected payoffs

Nice idea – but although Step 1 and 2 are “easy” to do, what is the RADR for an option? Option problem took more than 75 years to solve

21-17

Binomial Option Pricing

Call options pay off when the stock prices rises above the eXercise price. Thus, to price options, we need a model that has variable stock prices

The simplest way to represent an uncertain stock price is to say it can either go up or down a given amount

21-18

Binomial Option Pricing Example

Today

Expiration

200

Today Expiration

75

100

C

50

0

Stock Price

Call Option Value

X = 125

21-19

Hedge ratio approach

If the stock goes up in value, so will the call option (as seen in the previous slide).

If you go long in the stock, and short in the call, its easy to set up a risk free future, by carefully choosing the fraction of stock to hold long for each option you write.

Buy d stock for every option you write, so that the payoff in the up state equals the payoff in the down state

21-20

Create Equal Expiration Cash Flows

Upstate: d

Su – Cu = d

200 – 75

Downstate: d

Sd – Cd = d

50 – 0

Set equal, and solve for d

(called a d hedge, or hedge ratio)

200 d – 75 = 50 d which gives: d

= 0.5

By inspection we can see that the hedge ratio is: d 

C

S u u

C

S d d

21-21

Create Equal Expiration Cash Flows

CF in up = .5*200 – 75 = 25 = CF down

What’s the PV of receiving $25 for sure? = 25/(1+r f

) for r f

= 8% = 23.15

So, the value of 0.5 stocks, minus the value of one Call option is $23.15 today

0.5(100) – C = 23.15

Solve to C, and you have = 26.85

21-22

Binomial Option Pricing: Alternate Portfolio

Alternative Portfolio

Buy 1 share of stock at $100

Borrow enough money to get a zero payout in down state

(Owe $50 at expiration, i.e. borrow $46.30 (8% Rate)

Net outlay $53.70

Payoff

Value of Stock 50 200

Repay loan - 50 -50

Net Payoff 0 150

53.70

Expiration

150

0

Payoff Structure is exactly 2 times the Call

21-23

53.70

Binomial Option Pricing

150

C

0

2C = $53.70

C = $26.85

75

0

21-24

Implied Probability

If the stock has a beta = 1.5, and the expected return on the market is 15%

(risk free as noted is 8%), then what is the probability the stock will go up to the higher value?

CAPM –

Hpr = {[ p

Su + (1p

)Sd] – So}/So

Solve for p

21-25

RADR for the Call

What is the discount rate implied on the call (ie RADR)

What is the Beta of the Call?

21-26

Price of the put

Use Put-Call parity to price the put

21-27

RADR for the Put

What is the RADR for the put?

What is the Beta for the put?

21-28

Option value if volatility is smaller

The size of the up or down movement must be set according to the volatility of the stock.

Lets say the upstate would yield a price of 160 and the downstate a price of

62.5. What happens to the value of the put and the call (with this lower volatility)? What happens to the RADR and the implied beta of the call and put

21-29

What if we change the eXercise Price?

If the strike price is $100, what happens to the value of the call and the put, using the revised pricing values?

21-30

What if the risk free interest rate decreases

For the previous example, what happens when we use a 2% risk free rate, rather than an 8% rate?

21-31

Generalizing the Two-State Approach

Assume that we can break the year into two sixmonth segments.

In each six-month segment the stock could increase by 10% or decrease by 5%.

Assume the stock is initially selling at 100.

Possible outcomes:

Increase by 10% twice

Decrease by 5% twice

Increase once and decrease once (2 paths).

21-32

Generalizing the Two-State Approach

Note: The size of the up and down jump is determined by the volatility of the stock price and the length of the period

121

110

104.50

100

95

90.25

21-33

Delta hedging

Assume that the eXercise price is $100

How many stock should you own at the outset? How many stock after the first period

How do I do that? Habit 2 – begin with the end in mind (solve like a dynamic program)

First solve for Su position, then for Sd position, then work back to origination

21-34

Compute hedge ratio and option values

At Su, d

= (21 – 4.5)/(121-104.5)=1

Risk free portfolio = 121-21 = 100

PV of ptf = 100/(1.04) = 96.1538

1*110 – Cu = 96.1538, so Cu = 13.8462

Hedge ratio for down state is 0.3103

Cd = 0.316

What do you notice about hedge ratios in relationship to the stock price versus exercise price?

21-35

Wind back to the beginning

Hedge ratio at beginning:

(13.85 – 2.60)/(110-95) = .75

Risk free ptf =

Present value ptf =

Value of call =

If I program a computer to buy or sell stock to keep my hedge in place (pursuing a

“delta hedging” strategy), when do I buy, and when do I sell?

21-36

21-37

Expanding to Consider Three Intervals

Assume that we can break the year into three intervals.

For each interval the stock could increase by 5% or decrease by 3%.

Assume the stock is initially selling at

100.

21-38

Expanding to Consider Three Intervals

S

S +

S -

S + +

S + -

S - -

S + + +

S + + -

S + - -

S - - -

21-39

Possible Outcomes with Three Intervals

Event

3 up

Probability

1/8

2 up 1 down 3/8

1 up 2 down 3/8

3 down 1/8

Stock Price

100 (1.05) 3

100 (1.05) 2 (.97)

100 (1.05) (.97) 2

100 (.97) 3

=115.76

=106.94

= 98.79

= 91.27

21-40

Black-Scholes Option Valuation

C o

= S o

N(d

1

) - Xe -rT N(d

2

) d d

1

2

= [ln(S o

/X) + (r +

2 /2)T] / (

T 1/2 )

= d

1

+ (

T 1/2 ) where

C o

= Current call option value.

S o

= Current stock price

N(d) = probability that a random draw from a normal dist. will be less than d.

21-41

Black-Scholes Option Valuation

X = Exercise price e = 2.71828, the base of the natural log r = Risk-free interest rate (annualizes continuously compounded with the same maturity as the option)

T = time to maturity of the option in years ln = Natural log function

 

Standard deviation of annualized cont. compounded rate of return on the stock

21-42

Call Option Example

S o

= 100 X = 95 r = .10

T = .25 (quarter)

= .50

d

1

= [ln(100/95) + (.10+(

5 2 /2))] / (

5 .25

1/2 ) d

2

= .43

= .43 + ((

5



.25

1/2 )

= .18

21-43

Probabilities from Normal Dist

N (.43) = .6664

Table 17.2

d

.42

N(d)

.6628

.43

.44

.6664 Interpolation

.6700

21-44

Probabilities from Normal Dist.

N (.18) = .5714

Table 17.2

d

.16

N(d)

.5636

.18

.20

.5714

.5793

21-45

Call Option Value

C o

= S o

N(d

1

) - Xe -rT N(d

2

)

C o

= 100 X .6664 - 95 e - .10 X .25

X .5714

C o

= 13.70

Implied Volatility

Using Black-Scholes and the actual price of the option, solve for volatility.

Is the implied volatility consistent with the stock?

21-46

Put Value Using Black-Scholes

P = Xe -rT [1-N(d

2

)] - S

0

[1-N(d

1

)]

Using the sample call data

S = 100 r = .10 X = 95 g = .5 T = .25

95e -10x.25

(1-.5714)-100(1-.6664) = 6.35

21-47

Put Option Valuation: Using Put-Call Parity

P = C + PV (X) - S o

= C + Xe -rT - S o

Using the example data

C = 13.70

X = 95 S = 100 r = .10

T = .25

P = 13.70 + 95 e -.10 X .25

- 100

P = 6.35

21-48

Black-Scholes Model with Dividends

The call option formula applies to stocks that do not pay dividends.

One approach is to replace the stock price with a dividend adjusted stock price.

Replace S

0 with S

0

- PV (Dividends)

21-49

Using the Black-Scholes Formula

Hedging: Hedge ratio or delta

The number of stocks required to hedge against the price risk of holding one option.

Call = N (d

1

)

Put = N (d

1

) - 1

Option Elasticity

Percentage change in the option’s value given a 1% change in the value of the underlying stock.

21-50

Portfolio Insurance

Buying Puts - results in downside protection with unlimited upside potential.

Limitations

Tracking errors if indexes are used for the puts.

Maturity of puts may be too short.

Hedge ratios or deltas change as stock values change.

21-51

Hedging On Mispriced Options

Option value is positively related to volatility:

If an investor believes that the volatility that is implied in an option’s price is too low, a profitable trade is possible.

Profit must be hedged against a decline in the value of the stock.

Performance depends on option price relative to the implied volatility.

21-52

Hedging and Delta

The appropriate hedge will depend on the delta.

Recall the delta is the change in the value of the option relative to the change in the value of the stock.

Delta =

Change in the value of the option

Change of the value of the stock

21-53

Mispriced Option: Text Example

Implied volatility = 33%

Investor believes volatility should = 35%

Option maturity

Put price P

= 60 days

= $4.495

Exercise price and stock price = $90

Risk-free rate r = 4%

Delta = -.453

21-54

Hedged Put Portfolio

Cost to establish the hedged position

1000 put options at $4.495 / option

453 shares at $90 / share

Total outlay

$ 4,495

45,265

40,770

21-55

Profit Position on Hedged Put Portfolio

Value of put option: implied vol. = 35%

Stock Price 89 90 91

Put Price $5.254

Profit (loss) for each put .759

$4.785

.290

$4.347

(.148)

Value of and profit on hedged portfolio

Stock Price

Value of 1,000 puts

89

$ 5,254

90 91

$ 4,785 $ 4,347

Value of 453 shares

Total

Profit

40,317 40,770 41,223

45,571 45,555 5,570

306 290 305

21-56