STOICHIOMETRY REVIEW ANSWERS • 1. The calculation of quantities in chemical equations is called • Stoichiometry • 2. The first step in most stoichiometry problems is to convert given quantities to • Moles • 3. When two substances react to form products, the reactant which is used up is called the • Limiting Reagent • 4. The amount of product that forms when a reaction is carried out in the laboratory is the • Actual Yield • 5. The maximum amount of products that could be formed from given amounts of reactants is the • Theoretical Yield • 6. When an equation is used to calculate the amount of product that will form during a reaction, then the value obtained is called the • Theoretical Yield • 7. 2Al(s) + 3Pb(NO3)2(aq) 2Al(NO3)3(aq) + 3Pb(s) • A.) 2 moles Al + 3 molecules Pb(NO3)2 2 molecules Al(NO3)3 + 3 moles Pb • F • • B.) 2 grams Al + 3 grams Pb(NO3)2 2 grams Al(NO3)3 + 3 grams Pb F • • C.) 2 moles Al + 3 moles Pb(NO3)2 2 moles Al(NO3)3 + 3 moles Pb T • 8. In every chemical reaction ___________ stay the same. • The Mass • 9. In the reaction 2CO + O2 2CO2, what is the ratio of moles of oxygen used to moles of CO2 produced? • 1:2 • 10. For C5H12 + 8O2 5CO2 + 6H2O • ______ moles of reactants chemically change into ______ moles of product. • 9 moles of reactant to 11 moles of product 11. How many moles of oxygen are required to react completely with 14.8 mol Al when given 4Al + 3O2 2Al2O3? 14.8 ----------mol Al x 3 mol O2 ----------------4 mol --------Al = 11.1 mol O2 12. Given the balanced equation 16HCl + 2KMnO4 2KCl + 2MnCl2 + 5Cl2 + 8H2O if 2.0 mol of KMnO4 reacts, how many moles of H2O are produced? 8.0 mol H2O 13. Based on… 16HCl + 2KMnO4 2KCl + 2MnCl2 + 5Cl2 + 8H2O …how many grams of KCl are produced when 3.0 mol of KmnO4 reacts? ------------3.0 mol KMnO4 2 mol --------KCl 74.5 g KCl x ---------------- X --------------------2 mol ------------KMnO4 1 mol --------KCl = 220 g KCl 14. If CuO + H2 Cu + H2O, how many moles of H2O are produced when 240 grams of CuO react? 1 mol --------CuO 1 mol H2O --------240 g CuO x ---------------- X --------------------80 g--------CuO 1 mol --------CuO = 3.0 mol H2O 15. In the reaction Zn + H2SO4 ZnSO4 + H2 how many grams of H2SO4 are required to produce 2.3 gram of H2? 1 mol H2 ----------2.3 g------H2 x ----------------- 2 g------H2 1 mol H2SO4 ---------------- 98 g H2SO4 x ------------------- x ----------------------------1 mol H2 1 mol H2SO4 ----------------- 113 g H2SO4 = 16. LiOH + HBr LiBr + H2O If you start with 15.0 grams of lithium hydroxide, how many grams of lithium bromide will be produced? 54.4 g LiBr 17. How many molecules of oxygen are required to react completely with 2.96 X 1023 molecules Al when given 4Al + 3O2 2Al2O3? 3 molecules O2 ---------------------2.96 x 1023 molecules Al x ----------------- 4 ---------------------molecules Al 2.22 x 23 10 = molecules O2 18. How many molecules of oxygen are produced by the decomposition of 6.54 g of potassium chlorate (KClO3)? 2KClO3 2KCl + 3O2 -----------1 mol KClO3 --------3 mol O2 6.02 x 1023 molecules O2 6.54 g-----------KClO3 x --------------- x --------------- x -----------------122.5 g-----------KClO3 4.82 x 22 10 -----------2 mol KClO3 --------1 mol O2 molecules O2 = • 19. LiOH + KCl LiCl + KOH • A) I began this reaction with 20 grams of lithium hydroxide. What is my theoretical yield of lithium chloride? Convert 20 grams of LiOH Grams of LiCl 35 g LiCl • B) I actually produced 6 grams of lithium chloride. What is my percent yield? Actual _________ Theoretical X 100 = 17% • 20.C3H8 + 5 O2 3 CO2 + 4 H2O • A) If I start with 5 grams of C3H8, what is my theoretical yield of water? Convert 5 grams C3H8 Grams of H2O 8.2 g H2O • B) I made 6.1 g of water. What was my percent yield? Actual _________ Theoretical X 100 = 74% 21. Be + 2 HCl BeCl2 + H2 My theoretical yield of beryllium chloride was 10.7 grams. If my actual yield was 4.5 grams, what was my percent yield? Actual ___ Theoretical X 100 = 42% 22. CaSO4 + NaI CaI2 + Na2SO4 If 34.7 g of calcium sulfate and 58.3 g of sodium iodide are placed in a reaction vessel, what will be the limiting reagent? NaI Note: Refer to Limiting Reagent Notes to see how to work it out.