GENERAL CHEMISTRY 2 TABLE OF CONTENTS Science Pocket Lesson 1 Kinetic Molecular Theory of Liquids and Solids 1 Science Pocket Lesson 2 Properties of Liquids 6 Science Pocket Lesson 3 Structure and Properties of Water 10 Science Pocket Lesson 4 Types and Properties of Solids 13 Science Pocket Lesson 5 The Temperature Curve and the Phase Changes of Water and 𝐂𝐎𝟐 17 Science Pocket Lesson 6 Concentration of Solutions 22 Science Pocket Lesson 7 Stoichiometric Calculations for Reactions in Solutions 27 Science Pocket Lesson 8 Boiling Point Elevation and Freezing Point Depression 31 Science Pocket Lesson 9 Thermodynamics vs. Thermochemistry 35 Science Pocket Lesson 10 Science Pocket Lesson 11 Colligative Properties of Solutions Rates of Reaction 39 43 Science Pocket Lesson 12 Molecular Collisions and the Orders of Reaction 47 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 GENERAL CHEMISTRY 2 KINETIC MOLECULAR THEORY OF LIQUIDS AND SOLIDS INSTANT TASK Put all the items in the correct box according to their state of matter. From the lists in Activity 1, fill up the table below and mark the relationship to you of each. Characteristic Relatives Grand Parent Aunt / Uncle Cousin Mother or Father Sibling 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 1 DIRECT TALK Kinetic Molecular Theory of Liquids and Solids The the properties properties of of gases gases by by assuming assuming that that gas gas particles particles act act The kinetic kinetic molecular molecular theory theory explains explains the independently very weak weak attractive attractive forces forces between between them, them, the the particles particles are are free free totomove moveabout about independently of of each each other. other. Due Due to to the the very at at random random and and fill fill their their containers. containers. Gases Gases are are compressible compressible and and they they diffuse diffuse through through one one another another easily. easily. The particles of a liquid are close together because of strong attractive forces between them. Like gas particles, liquid particles also collide with each other and with the walls of their containers. However, since the particles are close together, they can move only at short distances. This type of movement allows liquids to flow and take the shape of their container without filling it completely as gases do. This also explains why liquids compress only very slightly, have higher densities than gases, and diffuse more slowly than gases. In solids, the attractive forces between the particles are stronger than those in liquids and gases. These result to an ordered arrangement of particles in which the particles are not free to move around. The movement of the particles is limited to vibrations while they remain in their fixed positions. Thus a solid has a fixed volume and shape. Solids compress even less than liquids and hardly diffuse. The three phases of matter. Notice that the spacing between atoms or molecules increases as we move from a description of the solid phase to the gaseous one. Intermolecular Forces nnkh Intermolecular forces (IMF) or (secondary forces) are the forces which intimidate the reaction between particles between molecules, including forces of attraction or repulsion which act between atoms and other types of neighboring particles, e.g. atoms or ions. Intermolecular forces are weak relative to intramolecular forces – the forces which hold a molecule together. They are ion-dipole, dipole-dipole, dipole-induced dipole, and London dispersion forces. Another more specific intermolecular forces that affects only certain kinds of molecules is the hydrogen bond. Intermolecular Forces 2 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 Ion - Dipole Forces An ion-dipole forces results when an ion and the partial charge on the end of a polar molecule attract each other. Polar molecules are dipoles, that is, they have a positive and a negative end. Positive ions are all attracted to the negative end of a dipole, while negative ions are attracted to the positive end. Ion-dipole forces are particularly important in solutions of ionic substances such as NaCl in polar liquids such as water. Dipole - Dipole Forces Neutral polar molecules experience dipole-dipole forces. Polar molecules attract each other when the positive end of one molecule is near the negative end of another. A dipole-dipole force is generally weaker than an ion-dipole force. The strength of a given dipole-dipole interaction depends on the sizes of the dipole moments involved. Comparison of Molecular Weights, Dipole Moments, and Boiling Points Comparison of Molecular Weights, Dipole Moments, and Boiling Points The more polar the substance, the stronger its dipole-dipole interactions. The higher the dipole moment, the stronger the intermolecular forces that must be overcome for a substance to boil, and the higher the boiling point. London - Dispersion Forces It is rather easy to understand intermolecular forces among charged and polar particles, but it is not so among atoms or nonpolar molecules. Nonpolar molecules such as Cl2 and CH4 exhibit attractive forces. These nonpolar substances can be condensed to liquid and even solid if cooled enough to low temperature. The origin of this attraction was explained in 1930 by Fritz London (1900-1954), a German-American physicist. On the average, the electrons in a nonpolar molecule or atom are distributed uniformly around the nucleus. However, at certain instances, the electrons may be on one side of the nucleus. The molecule becomes temporary dipole or momentary dipole or instantaneous dipole. An instantaneous dipole exerts an influence on nearby particles. It causes the distortion of the electron clouds of neighboring molecules. As a result, the neighboring molecules also become dipoles. They are called induced dipoles because they are caused by the formation of the first dipole. This kind of attraction is called instantaneous dipole-induced dipole attraction or London forces. They are short-lived attractions because electrons keep on moving which causes the dipole to vanish as quickly as they are formed. The ease with which a dipole can be induced is called polarizability. Polarizability increases with increased molecular mass. In large molecules, the electrons are less firmly held and therefore easier to be polarized. As polarization and London forces increase, the boiling and melting points of covalent substances generally increase with increasing molecular mass. . SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 3 The ease with which a dipole can be induced is called polarizability. Polarizability increases with increased molecular mass. In large molecules, the electrons are less firmly held and therefore easier to be polarized. As polarization and London forces increase, the boiling and melting points of covalent substances generally increase with increasing molecular mass. Molar Mass, Melting Points, and Boiling Points of Halogen Hydrogen Bond A hydrogen bond is an attractive interaction between a hydrogen atom bonded to an electronegative O, N, or F atom and an unshared electron pair of another nearby electronegative atom. For example, hydrogen bonds occur in water, ammonia, and hydrofluoric acid. Hydrogen bond is a special type of dipole-dipole interaction. Bonds between hydrogen and nitrogen, oxygen, or fluorine are highly polar with partial positive charge on the hydrogen and a partial negative charge on the electronegative atom. In addition, the hydrogen atom has no inner core electrons and almost a bare proton. Thus, this small electron-deficient hydrogen can approach an electronegative atom very closely and interact strongly with it. One of the consequences of hydrogen bond in hydrogen compounds is the increase of boiling point with increasing molecular weight due to increased dispersion forces. O, N, and F atoms have significant hydrogen bonding ability because of their electronegative values and small atomic sizes. Chlorine has the same electronegative value as nitrogen but its size is larger, so it has less hydrogen bonding ability. The type of attraction used in life processes that can easily be formed and broken and reformed especially in water, DNA, and proteins is the hydrogen bond. 4 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 FLASH CHECK Identify the dominant intermolecular forces for the following Identify the dominant intermolecular forces of the following substances. higher boiling point in each substances. Select the substance theboiling Select the substance with thewith higher point in each pair. pair. A. Ne and Ar A. Ne and Ar __________________________________________________________ ____________________________________________________________________ ____________________________________________________________________ B. CH3OH and CH3CH2OH B. CH33OH and CH33CH22OH _________________________________________________________ ____________________________________________________________________ C. HF and CH F 3 3F C. HF and CH3__________________________________________________________ ____________________________________________________________________ ____________________________________________________________________ D. BaCl2 and PCl3 D. BaCl22 and PCl 33 __________________________________________________________ _____________________________________________________________________ QUICK CONNECT You only have to think about water to appreciate how different the three states of matter are. Flying, swimming, and ice skating are all done in contact with water in its various states. We swim in liquid water and skate on water in its solid form (ice). Airplanes fly in an atmosphere containing water in the gaseous state (water vapor). To allow these various activities, the arrangements of the water molecules must be significantly different in their gas, liquid, and solid forms. REFERENCES • Breaking through chemistry pp. 313 - 323 • World of chemistry pp. 516 - 522 • https://www.liveworksheets.com/os987191op • https://cscsdashaicechem.weebly.com/chapter4---chemical-bonding.html • http://brainfuse.com/curriculumupload/12240578 98133.html • https://chem.libretexts.org/Courses/University_of _Arkansas_Little_Rock/Chem_1403%3A_Gener al_Chemistry_2/Text/11%3A_Intermolecular_For ces_and_Liquids/11.03%3A__DipoleDipole_Forces • https://irpcdn.multiscreensite.com/89a70595/files/uploade d/Liga%C3%A7%C3%B5es%20intermoleculares _.pdf • https://legacy.chemgym.net/environmental_chem istry/topic_3c/page_4.html SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 5 GENERAL PROPERTIES OF LIQUIDS CHEMISTRY 2 INSTANT TASK NOTE: There are 10 terms you need to find. Encircle the term that are related to the properties of liquids I L O I M Q O U L I A D R S E E O O U U S S R R C C N S I I 6 N E N N O F I S S N N E E T T E E C C A A F F R R U U U S S T T B T O V I I L S I C N O G S P I O T I Y N N T T X R N S E E P E E E Y Y U U E E T T F F R R G G S S N O B B O F O I R R O R M M E E R R S S A A G G B B C C E E W I L L D A I Y M O M M Q Q H H E H A Y T I H H G G M M R R I T R R B C T F O F B O O R H C T E V S I D S O C O O G S D I A T Z Y E A E L E H L M M H H T A J J I S L L N N A A P P S Z I I S T Z R E N R E U U T T A T R R E A S P M M E E T T F I Q Q Z E I U C E O C C C O O M M P R O O U U C N D D S S S R B B C N R T U O Q U Y Y M M T T N N G G H H X X O U F F E O V V Z S O X L U I L Q E U V I F D F S E G G S S T T S J C P C C X I P I A S C A K K N N I I J J N N I I H H D D S S R A Q Q B O A M SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 R H U R E E R C U N S A S T E S R B P U R S O V P R A N V P R R S S D T E N C I R O E P A G S N L I I L F I U O Y B D D DIRECT TALK VISCOSITY Viscosity can be measured using a viscometer. It measures the time it takes for a known volume of a liquid to flow through the small neck. Some liquids such as water or alcohol flow easily. They are fluid. Others such as molasses or motor oil take longer time to flow (they are viscous). Viscosity is related to the movement of the molecules in the liquid, and thus to the intermolecular forces present. Nonpolar molecules like benzene (C6H6), pentane (C5H12), and carbon tetrachloride (CCl4) experience only weak intermolecular forces (dispersion forces) and low viscosities. More polar molecules like glycerol (C3H5C (OH)3) and aqueous sugar solution (syrup) have high viscosities because of H-bonding among many -OH groups and dispersion forces at many points along the chain. The viscosity of a liquid decreases with increasing temperature because at higher temperatures, the average kinetic energy of the molecules that overcomes the attractive forces between molecules is greater. SURFACE TENSION TAKE NOTE To increase the surface area, molecules move to the surface by breaking some attractions in the interior, which requires energy. The energy required to increase the surface area of a liquid is called surface tension. Surface tension, like viscosity, is higher in liquids that have higher intermolecular forces. Both properties are also temperature dependent because at higher temperatures, molecules have more kinetic energy to counteract the attractive forces holding them. Surfactants (surface-active agents) such as detergents, soaps, and biological fat emulsifiers decrease the surface tension of water and destroy the H-bonds. CAPILLARITY When you go for simple blood tests, a sample may be obtained by pricking your finger with a needle. A narrow tube called capillary tube is placed on the skin opening and the blood rises up through the tube. This phenomenon is called capillarity or capillary action. This results from a competition between the intermolecular forces within the liquid molecules (cohesive forces) and those between the liquid molecules and the walls of the tube (adhesive forces). When a capillary tube is placed in water, the surface or meniscus takes a U-shape (concave) because the adhesive forces are greater than cohesive forces. In mercury, the meniscus is curved downward (convex) because the cohesive forces (metallic bonding are stronger than adhesive forces. Capillarity is also observed in the transport of water from the roots to the other parts of plants. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 7 VAPOR PRESSURE The vapor pressure of a liquid depends on the magnitude of the intermolecular forces present and on temperature. Liquids like acetone and alcohol have high vapor pressure and are considered volatile because their intermolecular forces are weak; whereas molasses and honey have low vapor pressures and are said to be nonvolatile. The volatility of a liquid at a given temperature is determined by its intermolecular forces of attraction. BOILING POINT The temperature at which boiling point occurs at a pressure of 1 atm is called the normal boiling point of the liquid. This property changes as pressure changes. If the atmospheric pressure is below 1 atm, especially at high altitudes like in Baguio City, liquids boil at lower than normal temperatures. At an altitude of 1600 m, atmospheric pressure is about 640 torr and water boils at 95 0C. This is because particles in the liquid need less kinetic energy to escape. Cooking under these conditions takes longer than at sea level. The effect of high altitudes and lower boiling temperature can be counteracted by using a pressure cooker. In a pressure cooker, water boils at higher temperature and higher pressure. The increased heat content of the boiling water allows the food to absorb heat from the water faster than at 100 0C. A rise of about to 10 0C inside a pressure cooker cooks food twice as fast as in 100 0C. MOLAR HEAT OF VAPORIZATION Vaporization is a change of state from liquid to gas. In order for a liquid to change into a gas, energy must be added to the liquid. This is an endothermic process and the total kinetic energy of the substance increases. Energy added is in the form of heat. The amount of heat needed to vaporize a given amount of liquid at its boiling point is called heat of vaporization. 8 TAKE NOTE Refrigerators operate by using refrigerant (Freon or ammonia) which evaporates in the coils inside the refrigerator. Evaporation is an endothermic process that absorbs heat inside the refrigerator. The compressor recondenses the gas back to liquid releasing heat through the coils outside of the refrigerator. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 FLASH CHECK 4 Identify the why dominant forces for the following Explain eachintermolecular of the following occurs: substances. Select the substance with the higher boiling point in each pair. 1. A freely falling drop of water is spherical in shape. A. Ne and Ar __________________________________________________________________________________ __________________________________________________________________________________ ____________________________________________________________________ ____________________________________________________________________ __________________________________________________________________________________ B. CHarm 33OH and CH33CH22OH 2. Your feels cool when alcohol evaporates from your skin. ____________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ C. HF and CH33F __________________________________________________________________________________ ____________________________________________________________________ ____________________________________________________________________ 3. On a warm day, water droplets form outside the bottle of carbonated beverage. D. BaCl22 and PCl33 __________________________________________________________________________________ __________________________________________________________________________________ _____________________________________________________________________ __________________________________________________________________________________ QUICK CONNECT The hair on a gecko's foot are so tiny that it can form intermolecular forces of attraction with most surfaces and thus making the gecko adhere even on glass without the use of liquids or surface tension. REFERENCES • Breaking through chemistry pp. 323 - 328 • World of chemistry pp. 516 - 522 • Pin by Nitza I Marin on DYK? | Did you know, Surface tension, Fun facts (pinterest.ph) • Learn Boiling vs Evaporation in 3 minutes. (toppr.com) • Surfact Active Agents, Surfactants (ncsu.edu) • Chapter 13 Solids and Liquids. - ppt video online download (slideplayer.com) • a steel needle floating on water to illustrate surface tension Stock Photo - Alamy SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 9 GENERAL STRUCTURE AND PROPERTIES OF CHEMISTRY 2 WATER INSTANT TASK S WATER SOLID LIQUID GAS SHAPE FREEZING POINT BOILING POINT Complete the diagram about the concept of water by writting the correct terms from the box. I N T E R M O L E C U L A R R 1. A clear, odorless O N B P O M liquid B that H Q I C U S has no R taste. O M O O E M Q O M U C Y Q K E D O I I Y E H H H T O M U N R E L S L U R3. TheEtemperature T T A M T I I U C 2. The temperature 8. A hard substance 9. A free flowing I E Sat which A a Vliquid J R Jsubstance. S R atAwhichN a liquid that P has N three D turns into a solid. boils. R E N T A T I I dimensions. E O G S N S E E T G4. AnFobjectGform H S L S U H G I E A O E Por figure. R B G C N M C 10. X A Ssubstance H R S such as air that is U C O G C M O A E D not O solidTor liquid. D P L 5. A ___ has and keeps 6. A ___ borrows the S shape. A I S E shape Rof itsScontainer. P T S F S S R I its own R F N N W I I S F S E C R O F C R T7. A ___Bhas noLfixedR T I Q B V C Q P U shape. N U X O D B Y S Z C Z X B A Y I S N O I T A Z I R Note: O Answers P A mayVbe D repeated 10 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 DIRECT TALK Water makes up a large proportion of the entire biosphere and of these, 95 % is saltwater and the remaining 5 % is freshwater. Water is locked up in ice and glaciers, deep and shallow underground lakes, soil, atmosphere, and in the rivers. The human body consist of 50-75% water. Water serves important purposes for life on earth. Water's unique properties result from the strong intermolecular forces of attraction characterized by the hydrogen bond. The following are the properties of water. 1. High boiling point The high boiling point of water is a consequence of its strong intermolecular forces of attraction caused by the formation of the H-bond. It also, explains why water is liquid at room temperature. 3. High density in its liquid form Water is the only substance that contracts when cooled. For most substances, their solid form is denser than their liquid form. This is because the Hbond is more extensive in its solid state (ice) than in its liquid state. Ice has an open structure because the hydrogen bonds could not get inside the hexagonal ring structure. 2. High specific heat Specific heat refers to the amount of heat needed to change the temperature of 1 gram of a substance by 1 0C. For water, its specific heat is 1cal/g 0C. It means that water can absorb and release large quantities of heat without change in temperature. This is the reason why body temperature remains 370C even when there's a change in the surrounding. This also explains why oceans and lakes exert an influence on the climate. If there were no longer bodies of water that surround the earth, the earth would experience great temperature variations. 4. High surface tension The hydrogen bond formation among water molecules causes water to have high surface tension, as described earlier. This high surface tension causes water to move from the roots of a tree to the top of very tall trees and explains why water moves into the fibers of a towel. This phenomenon is called capillarity. 5. High heat of vaporization Large amount of heat is needed to vaporize a given amount of water. This causes a significant drop in temperature during evaporation. This explains why perspiration lowers the body temperature. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 11 FLASH CHECK Identify the dominant intermolecular forces for the following EXPLAIN BRIEFLY substances. Select the substance with the higher boiling point in each pair. A. Ar If Ne iceand were denser than liquid water, how would this affect the ____________________________________________________________________ environment we live in? ____________________________________________________________________ __________________________________________________________________________________ B. CH33OH and CH33CH22OH __________________________________________________________________________________ ____________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ C. HF and CH33F __________________________________________________________________________________ __________________________________________________________________________________ ____________________________________________________________________ ____________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ D. BaCl22 and PCl33 __________________________________________________________________________________ _____________________________________________________________________ QUICK CONNECT 12 REFERENCES • General Chemistry 2 pp. 12 - 14 • https://www.pinterest.com.au/pin/657244139356 993388/ SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 GENERAL CHEMISTRY 2 TYPES AND PROPERTIES OF SOLIDS INSTANT TASK Complete the diagram about the classifications of solids by arranging the terms from the box. Metallic Crystalline Molecular Hydrogen bond Ionic Polar Amorphous Non-polar Covalent SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 13 DIRECT TALK The Nature of Solids Solids whose particles are arranged in regular geometric patterns are called crystalline solids. The representative particles exist in a high ordered and repetitive pattern. This orderly arrangement produces a beautiful regularly shaped crystal. NaCl and sugar are crystalline in form and so is snow. Many precious stones used in jewelry are crystals. Crystalline Solids Crystalline solids are those whose atoms, ions, or molecules are ordered in well-defined arrangements. They usually have flat surfaces or faces and sharp angles. These solids have regular shapes. Ice, sugar, salt, and gems are examples of crystalline solids. Amorphous Solids Amorphous solids (from the Greek word for "without form") are solids whose particles do not have orderly structures; therefore, they have poorly defined shapes. Some examples of amorphous solids are glass, rubber, and some plastics. TAKE NOTE Crystalline solids have particles that are arranged in a definite geometric pattern. Amorphous solids have particles that are not located in any particular position. 14 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 TYPES OF CRYSTALS The physical properties of solids depend on the kind of particles that make up the solid. They are also dependent on the strength of the attractive forces between the particles. Solids are classified based on the kind or nature of the particles that make them up. For the melting and boiling points, it is important to note that the energy required is that needed to break the intermolecular forces of attraction and not the intramolecular. A. IONIC SOLIDS The particles of ionic solids are positive and negative ions. Since oppositely charged particles are present, the forces between the ions are electrostatic in nature. The crystal arrangement in ionic solids maximizes attractions and simultaneously minimizes repulsion making the compound possess a high degree of stability. These solids are hard, they are brittle, have high melting points, and have poor electrical and thermal conductivity. B. COVALENT SOLIDS This type of solids are made up of atoms and are joined by covalent bonds. Some solids form covalent bonds resulting in the formation of molecules. In some solids, however, molecules are not formed. Rather, a covalent network is formed extending throughout the solid crystal. They are very hard, have very high melting points, and often have poor thermal and electrical conductivity. C. MOLECULAR SOLIDS The particles in molecular solids can be either atoms or molecules held together by intermolecular forces like dispersion forces, dipole-dipole forces, and hydrogen bonds. Solids with dispersion forces that are also large are solids at room temperature. This is true for solids that are highly polar. This type of solids are soft, have low to moderately high melting points, and have poor electrical and thermal conductivity. They are poor conductors of heat and electricity because there are no free moving electrons and no charge particles. D. METALLIC SOLIDS These are joined by metallic bonds. Metallic bonds are characterized by the presence of mobile electrons around the positive metal ion. The force that binds the atoms together is the force attraction between the mobile valence electrons and the fixed positive metal ion. The strength of the force depends on the metal and, depending on the nature of the metal, they can be soft to hard, and melting points range from low to high. These solids are good electrical conductors (because of the mobile electrons), good thermal conductors, and are malleable and ductile. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 15 FLASH CHECK 4 Identify the dominant intermolecular forces for the following EXPLAIN BRIEFLY substances. Select the substance with the higher boiling point in each pair. Suppose you are a molecule of water in the solid state (ice) at -10 0C. Write a short A. description Ne and Ar of your movement as the temperature around you is gradually and continuously increased to 110 0C. ____________________________________________________________________ ____________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ B. CH33OH and CH33CH22OH __________________________________________________________________________________ ____________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ C. HF and CH33F __________________________________________________________________________________ __________________________________________________________________________________ ____________________________________________________________________ ____________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ D. BaCl22 and PCl33 __________________________________________________________________________________ _____________________________________________________________________ __________________________________________________________________________________ QUICK CONNECT Quartz glass forms from silica (SiO2) heated above 1600 0C. It then evolves to form amorphous solids like window glass (with CaCO3 and Na2CO3), colored glass (with metal ions), and barosilicate glass in pyrex (B2O3). 16 REFERENCES • Breaking through chemistry pp. 330 - 332 • General Chemistry 2 pp. 14 - 17 • E School (apsacwestridge.edu.pk) • Classification of solids (brainkart.com) • Crystalline Solids | Crystalline solid, Solid, Intermolecular force (pinterest.ph) SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 GENERAL CHEMISTRY 2 The Temperature Curve and The Phase Changes of Water and CO2 INSTANT TASK The diagram below shows the cooling curve for a gas. Draw the diagram and write/draw the correct word/figure in each number. A B C SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 17 Heating and Cooling Curves Explained What happens when you let a glass of ice sit out on the counter for several minutes? It melts, of course! The increase in temperature causes the water to change from solid to liquid. What happens when you pour that cup of water into a pot on the stove and let it cook for several minutes? It boils! Once again, the increase in temperature causes the water to change phases, this time from a liquid state to a gaseous state. In the science world, we use heating and cooling curves to model such physical changes. A heating or cooling curve is a simple line graph that shows the phase changes a given substance undergoes with increasing or decreasing temperature. T E M P E R A T U R E HEAT ADDED Fig. 1.1 Heating and Cooling Curve of Water. Temperature is measured on the vertical y-axis and the amount of heat added over time is measured on the horizontal x-axis. Changes of state occur during plateaus because the temperature is constant. The change of state behavior of all substances can be represented with a heating and cooling curve of this type. The melting, boiling, freezing, and condensing points of the substance can be determined by the horizontal lines or plateaus on the curve. Phase changes happen when you reach certain special points. Sometimes a liquid wants to become a solid. Scientists use something called a freezing point or melting point to measure the temperature at which a liquid turn into a solid. Melting - or Fusion, is a physical process that results in the phase transition of a substance from a solid to a liquid. This occurs when the internal energy of the solid increases, Freezing – The opposite of Melting. The process through which a substance changes from a liquid to a solid. 18 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 Boiling - is the process by which a liquid turn into a vapor when it is heated to its boiling point. Condensation - is the process of a substance that is in its gaseous state converting into a liquid state. This change is brought about by a change in pressure and temperature of the substance. Sublimation - refers to the phase transition in which matter changes state from a solid immediately into a gas, without passing through an intermediate liquid phase. Deposition - refers to the phase transition in which matter changes state from a gas immediately into a solid, without passing through an intermediate liquid phase. PHASE DIAGRAMS OF WATER AND CARBON DIOXIDE We can use the phase diagram of water to identify the physical state of a sample of water under specified conditions of pressure and temperature. For example, a pressure of 50 kPa and a temperature of −10 °C correspond to the region of the diagram labeled “ice.” Under these conditions, water exists only as a solid (ice). A pressure of 50 kPa and a temperature of 50 °C correspond to the “water” region—here, water exists only as a liquid. At 25 kPa and 200 °C, water exists only in the “gas” or in gaseous state. Note that on the H2O phase diagram, the pressure and temperature axes not drawn to a constant scale in order to permit the illustration of several important features as are not described here. The curve BC in the figure above is the plot of vapor pressure versus temperature. This “liquid-vapor” curve separates the liquid and gaseous regions of the phase diagram and provides the boiling point for water at any pressure. The solid-vapor curve, labeled AB in the graph above indicates the temperatures and pressures at which ice and water vapor are in equilibrium. These temperature-pressure data pairs correspond to the sublimation, or deposition, points for water. The solidliquid curve labeled BD shows the temperatures and pressures at which ice and liquid water are in equilibrium, representing the melting/freezing points for water. Example: Determining the State of Water Using the phase diagram for water given in the graph, determine the state of water at the following temperatures and pressures: (a) 50 °C and 40 kPa (b) 80 °C and 5 kPa (c) −10 °C and 0.3 kPa Solution: Using the phase diagram for water, we can determine that the state of water at each temperature and pressure given are as follows: (a) liquid; (b) gas; (c) solid. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 19 You already know about solids melting and becoming liquids. Some of you may have also seen a solid become a gas. It's a process called sublimation. The easiest example of sublimation might be dry ice. Dry ice is solid carbon dioxide (CO2). Amazingly, when you leave dry ice out in a room, it just turns into a gas. Have you ever heard of liquid carbon dioxide? It can be made, but not in normal situations. Coal is another example of a compound that will not melt at normal atmospheric pressures. It will sublimate at very high temperatures. Can you go from a gas to a solid? Sure. Deposition occurs when a gas without going through the liquid state of matter. Those of you who live near not have seen it, but closer to the poles we see frost on winter mornings. crystals on plants build up when water vapor from the air becomes a solid plants. becomes a solid the equator may Those little frost on the leaves of Consider the phase diagram for carbon dioxide shown in the figure as another example. The solid-liquid curve exhibits a positive slope, indicating that the melting point for CO2 increases with pressure as it does for most substances (water being a notable exception as described previously). Notice that the triple point is well above 1 atm (101.325 kPa), indicating that carbon dioxide cannot exist as a liquid under ambient pressure conditions. Instead, cooling gaseous carbon dioxide at 1 atm results in its deposition into the solid state. Likewise, solid carbon dioxide does not melt at 1 atm pressure but instead sublimes to yield gaseous CO2. Finally, notice that the critical point for carbon dioxide is observed at a relatively modest temperature and pressure in comparison to water. Example: Determining the State of Carbon Dioxide Using the phase diagram for carbon dioxide shown in the graph, determine the state of CO2 at the following temperatures and pressures: (a) −30 °C and 2000 kPa (b) −90 °C and 1000 kPa (c) −60 °C and 100 kPa Solution: Using the phase diagram for carbon dioxide provided, we can determine that the state of CO2 at each temperature and pressure given are as follows: (a) liquid; (b) solid; (c) gas. 20 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 Instructions: Answer the following questions. Write your answer in a separate sheet of paper. Using the phase diagram for water, determine the state of water at the following temperatures and pressures: (a) −10 °C and 50 kPa (b) 25 °C and 90 kPa (c) 50 °C and 0.3 kPa Using the phase diagram for carbon dioxide, determine the state of water at the following temperatures and pressures: (d) 20 °C and 1500 kPa Answer to START-UP (e) 0 °C and 100 kPa (f) 20 °C and 2 atm The steamboats got their power from steam – liquid water converted to a gas at high temperatures. The steam would push the pistons of the engine, causing the paddle wheels to turn and propel the boat. References: QUICK CONNECT Gases under Pressure If you have a propane (C3H8) barbecue, you have probably seen those cylinders filled with fuel. In the cylinder, the propane molecules are in a liquid state at a high pressure. When the molecules are released from the cylinder, they immediately become a gas and you can cook your food. Pressure differences make the phase change. • • • • • http://www.chem4kids.com/ https://study.com/academy/le sson https://www.ck12.org/ https://opentextbc.ca/ SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 21 GENERAL CHEMISTRY 2 Concentration of Solutions INSTANT TASK MATH SKILL BUILDER 101 Percent = Part Whole x 100% Solve the following problems. Write your solutions in a separate sheet of paper. 1.) There are 200 apples. 30 apples are considered bad and will be not for sale. How many percent of apples are bad? 2.) What percentage of 80 is 20? 3.) A skateboard is on sale that has a 25% discount of its price. The skateboard’s original price is Php 750.00. Find the new price. 22 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 The key difference between solvent and solute is that the solute is the one to be dissolved while, the solvent is responsible for dissolving it. Fig. 1: The solution on the left is more concentrated than the solution on the right because there is a greater ratio of solute (red balls) to solvent (blue balls) particles. The solution particles are closer together. The solution on the right is more dilute (less concentrated). Concentration is the measure of how much of a given substance is mixed with another substance. Solutions are said to be either dilute or concentrated. When we say that vinegar is 5% acetic acid in water, we are giving the concentration. If we said the mixture was 10% acetic acid, this would be more concentrated than the vinegar solution. A concentrated solution is one in which there is a large amount of solute in a given amount of solvent. A dilute solution is one in which there is a small amount of solute in a given amount of solvent. A dilute solution is a concentrated solution that has been, in essence, watered down. Think of the frozen juice containers you buy in the grocery store. To make juice, you have to mix the frozen juice concentrate from inside these containers with three or four times the container size full of water. Therefore, you are diluting the concentrated juice. In terms of solute and solvent, the concentrated solution has a lot of solute versus the dilute solution that would have a smaller amount of solute. Therefore: Concentration of a solution is the mass or volume of the solute present in a given amount of solvent or solution. The Ways of Expressing Concentration of a Solution Another way of expressing concentration is to give the number of moles of solute per unit volume of solution. Of all the quantitative measures of concentration, molarity is the one used most frequently by chemists. Molarity is defined as the number of moles of solute per liter of solution. The symbol for molarity is M or moles/liter. It is important to remember that “mol” in this expression refers to moles of solute and that “L” refers to liters of solution. number of moles of solute Molarity = number of liters of solution Example: What is the molar concentration of a solution of 22.4 g of HCl dissolved in 1.56 L? STEP 1 Find the molar mass of HCl. Hydrochloric Acid = HCl = 1 H atom + 1 C atom Atomic Mass of H = 1 x 1.008 g/mol = 1.008 g Atomic Mass of Cl = 1 x 35.453 g/mol = 35.453 g (add) Molar Mass of HCl = 36.453 g STEP 2 Convert the mass of solute to moles using the molar mass of HCl. 22.4 g HCl x 1 mol HCl 36.5 g HCl = 0.614 mol HCl STEP 3 Now, we can use the definition of molarity to determine a concentration. 0.614 mol HCl 1.56 L solution = 0.394 M HCl M = *Remember! If the quantity of the solute is given in mass units, you must convert mass units to mole units before using the definition of molarity to calculate concentration. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 23 There are several ways of expressing the concentration of a solution using a percentage. The mass/mass percent (% m/m) is defined as the mass of a solute divided by the mass of a solution times 100: % m/m = mass of solute mass of solution *Remember! If you can measure the masses of the solute and the solution, determining the mass/mass percent is easy. Each mass must be expressed in the same units to determine the proper concentration. X 100% Where: mass of solution = mass of solute + mass of solvent Example: Suppose that a solution was prepared by dissolving 25.0g of sugar into 100.0g of water. Determine the concentration. STEP 1 Find the mass of the solution. mass of solution = 25.0 g sugar + 100.0 g water = 125.0 g STEP 2 Calculate the percent by mass. Percent by Mass = 25.0 g sugar 125.0 g solution X 100% = 20% sugar Related concentration units are parts per million (ppm). Example: If there is 0.551 mg of As in 348 g of solution, what is the As concentration in ppm? STEP 1 Convert 0.551 mg to grams. STEP 2 Determine the concentration. 0.551 mg x 0.000551 g 348 g 1 gram 1000 mg = 0.000551 g x 1,000,000 = 1.58 ppm The percent solutions can be in the form volume/volume percentage. In each case, the concentration in percentage is calculated as the fraction of the volume of the solute related to the total volume of the solution. Volume Percent = volume of solute x 100% volume of solution Example: Determine the volume/volume percent solution made by combining 25 mL of ethanol with enough water to produce 200 mL of the solution. STEP 1 Substitute the values in the given formula. Volume Percent = 25 mL 200 mL x 100% = 12.5% Molality is also known as molal concentration. It is a measure of solute concentration in a solution. The solution is composed of two components; solute and solvent. Molality is defined as the “total moles of a solute contained in a kilogram of a solvent.” 24 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 m= Number of moles of solute Mass of solvent in kilograms Difference between Molality and Molarity Example: Calculate the molality of a solution where 5.0 grams of toluene (C7H8) is dissolved in 225 grams of Benzene (C6H6). Calculate the moles of given solute. STEP 1 Find the molar mass of Toluene. STEP 2 Find the moles of Toluene. STEP 3 Calculate the kilogram of solvent. STEP 4 Calculate the molality. C7H8 = (7 x 12 g/mol) + (8 x 1.008 g/mol) = 92 g/mol Moles of Toluene = Mass in grams Molar mass = 5.0 g 92 g/mol = 0.054 mole 225 g of Benzene / 1000 = 0.225 kilograms m= Number of moles of Toluene Mass of Benzene in kgs = 0.054 moles 0.225 kg = 0.24 m Mole fraction is a unit of concentration, defined to be equal to the number of moles of a component divided by the total number of moles of a solution. Because it is a ratio, mole fraction is a unitless expression. The mole fraction of all components of a solution, when added together, will equal 1. Example: In a solution of 1 mol benzene, 2 mol carbon tetrachloride, and 7 mol acetone, the mole fraction of the acetone is ______. STEP 1 Find the total number of moles in the solution Total number of Moles in Solution = 1 mole (benzene) + 2 moles (carbon tetrachloride) + 7 moles (acetone) Total number of Moles in Solution = 10 moles STEP 2 Apply the Mole Fraction formula of a substance (shown below) Mole Fraction of Acetone = Moles of Acetone / Total Moles Solution Mole Fraction of Acetone = 7/10 Mole Fraction of Acetone = 0.7 Similarly, the mole fraction of benzene would be 1/10 or 0.1 and the mole fraction of carbon tetrachloride would be 2/10 or 0.2. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 25 Instructions: Perform the different ways of calculating the concentrations of solutions. Write your answer in a separate sheet of paper. a. Calculate the molarity of 0.000889 g of glycine, C2H5NO2, in 1.05 mL of solution. 1. b. A saline solution with a mass of 355 g has 36.5 g of NaCl dissolved in it. What is the mass/mass percent concentration of the solution? c. If there is 0.6 g of Pb present in 277 g of solution, what is the Pb concentration in parts per million? f. A solution is prepared by dissolving 90 mL of hydrogen peroxide in enough water to make 3000 mL of solution. Identify the concentration of the hydrogen peroxide solution through volume/volume percentage. e. Calculate the molarity of 25.0 grams of KBr dissolved in 750.0 mL pure water. (K = 40 g/mol; Br = 80 g/mol) d. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of ethanol. (The molecular weight of ethanol = 46.07 g/mol; water = 18 g/mol) Answer to START-UP By looking at percentages, it is easier to tell if one recipe is drier, sweeter, saltier, etc. than another recipe. It also makes predicting what the final product will look like easier. Baker’s % can be used to quickly and easily convert between batch sizes as well. QUICK CONNECT Anyone who has made instant coffee or lemonade knows that too much powder gives a strongly flavored, highly concentrated drink, whereas too little results in a dilute solution that may be hard to distinguish from water. In chemistry, the concentration of a solution is the quantity of a solute that is contained in a particular quantity of solvent or solution. Knowing the concentration of solutes is important in controlling the stoichiometry of reactants for solution reactions. 26 References: • • • • https://chem.libretexts.org/ https://byjus.com/ https://www.thoughtco.com/ https://byjus.com/ SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 GENERAL CHEMISTRY 2 Stoichiometric Calculations for Reactions in Solutions INSTANT TASK Let us bake cookies! If we will make 10 cookies, the exact number of ingredients are as follows: 200 grams of flour + 2 eggs + 200 grams of butter + 1 cup of sugar = 10 cookies But it turns out that the ingredients are incomplete because you only have one (1) egg. A new equation is made, where everything is cut in half to achieve a result: ___grams of flour + 1 egg + ___grams of butter + ___cup of sugar = ___cookies 1. Fill in the blanks the right amount of ingredients and the cookies to be made with just one egg. 2. Airbags inside a car contains sodium azide. Write the coefficients so that the chemical equation below will be balanced. ___NaN3 → __Na + __N2 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 27 Introduction to Stoichiometry A balanced chemical equation is analogous to a recipe for chocolate chip cookies. It shows what reactants (the ingredients) combine to form what products (the cookies). It also shows the numerical relationships between the reactants and products (such as how many cups of flour are required to make a single batch of cookies). These numerical relationships are known as reaction stoichiometry, a term derived from the Ancient Greek words stoicheion ("element") and metron ("measure"). In this lesson, we'll look at how we can use the stoichiometric relationships contained in balanced chemical equations to determine amounts of substances consumed and produced in chemical reactions. Balanced Equations and Mole Ratios A common type of stoichiometric relationship is the mole ratio, which relates the amounts in moles of any two substances in a chemical reaction. We can write a mole ratio for a pair of substances by looking at the coefficients in front of each species in the balanced chemical equation. For example, consider the equation for the reaction between iron(III) oxide (Fe2O3) and aluminum metal (Al): The coefficients in the equation tell us that 1 mole of Fe2O3 reacts with 2 moles of Al, forming 2 moles of Fe and 1 mole of Al2O3. We can write the relationship between the Fe2O3 and the Al as the following mole ratio: Using this ratio, we could calculate how many moles of Al are needed to fully react with a certain amount of Fe2O3, or vice versa. To illustrate, let's walk through an example where we use a mole ratio to convert between amounts of reactants. Using mole ratios to calculate mass of a reactant Consider the following unbalanced equation: O 3 reactant side product side Question: How many grams of NaOH are required to fully consume 3.10 grams of H 2SO4? start text, F, e, end text, start subscript, 2, end subscript, start text, O, end text, start first:orwe need to balance the equation! In this case, we have 1 Na atom and subscript, 3,First endthings subscript, vice versa. 3 H atoms on the reactant side, and 2 Na atoms and 2 H atoms on the product side. We can balance the equation by placing a 2 in front of NaOH (so there are 2 Na atoms on each side) and another 2 in front of H2O (so that there are 6 O atoms and 4 H atoms on each side.) Doing so gives the following balanced equation: Now that we have the balanced equation, let's get to problem solving. To review, we want to find the mass of NaOH that is needed to completely react 3.10 grams of H2SO4. We can tackle this stoichiometry problem using the following steps: (See next page) 28 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 Step 1: Convert known reactant mass to moles In order to relate the amounts H2SO4 and NaOH using a mole ratio, we first need to know the quantity of H2SO4 in moles. We can convert the 3.10 grams of H2SO4 to moles using the molar mass of H2SO4. H2SO4= 2 H atoms + 1 S atom + 4 O atoms Atomic Mass of H = 2 x 1.008 g/mol = 2.016 g/mol Atomic Mass of S = 1 x 32 g/mol = 32 g/mol Atomic Mass of O = 4 x 16 g/mol = 64 g/mol (add) Molar Mass of H2SO4 = 98.02 g/mol Proceed to conversion of 3.10 grams of H2SO4 to moles: Step 2: Use the mole ratio to find moles of other reactant Now that we have the quantity of H2SO4 in moles, let's convert from moles of H2SO4 to moles of NaOH using the appropriate mole ratio. According to coefficients in the balanced chemical equation, 2 moles of NaOH are required for every 1 mole of H2SO4, so the mole ratio is: Multiplying the number of moles of H2SO4 by this factor gives us the number of moles of NaOH needed: Notice how we wrote the mole ratio so that the moles of H2SO4 cancel out, resulting in moles of NaOH as the final units. Step 3: Convert moles of other reactant to mass We were asked for the mass of NaOH in grams, so our last step is to convert the 6.32 x 10-2 moles of NaOH to grams. We can do so using the molar mass of NaOH: Molar Mass of NaOH = (1 x 23 g/mol) + (1 x 16 g/mol) + (1 x 1.008 g/mol) = 40 g/ mol So, 2.53 grams of NaOH are required to fully consume 3.10 grams of H2SO4 in this reaction. Shortcut! We could have combined all three steps into a single calculation, as shown in the following expression: SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 29 Instructions: Solve the problem stated below. Write your solution in a separate sheet of paper. Propane (C3H8) burns in this reaction: Question: If 200 g of propane is burned, how many grams of H2O is produced? Answer to START-UP With stoichiometry, you can know how much nitrogen gas must be produced in a matter of seconds for the bag to inflate by impact and can save the life of the driver or passengers. References: QUICK CONNECT Stoichiometry is at the heart of the production of many things you use in your daily life. Soap, tires, fertilizer, gasoline, deodorant, and chocolate bars are just a few commodities you use that are chemically engineered, or produced through chemical reactions. Chemically engineered commodities all rely on stoichiometry for their production. 30 1. 2. 3. 4. http://www.chem4kids.com/ https://study.com/academy/le sson https://www.ck12.org/ https://opentextbc.ca/ SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 GENERAL BOILING POINT ELEVATION AND CHEMISTRY 2 FREEZING POINT DEPRESSION INSTANT TASK Unscramble the letters to form the term that describes the given phrase. Write the letters on the blanks provided. 1. L O N G B I I T I P N O __ __ __ __ __ __ __ __ __ __ __ __ ➢ The ________________ of a substance is the temperature at which the vapor pressure of a liquid equals the pressure surrounding the liquid and the liquid changes into a vapor. 2. R I N G Z E E F O T N I P __ __ __ __ __ __ __ __ __ __ __ __ __ ➢ The ________________ is lower than the melting point in the case of mixtures and for certain organic compounds such as fats. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 31 DIRECT TALK BOILING POINT ELEVATION The boiling point is the temperature at which the vapor pressure of a liquid is equal to the atmospheric pressure. If a liquid has a high vapor pressure it means that the molecules evaporate faster, and it takes a shorter time to equalize the vapor pressure of the liquid and the atmospheric pressure. Therefore, the boiling point of the liquid is low. The boiling point of water is 100 0C. Sea water, however, does not boil at this temperature but at a higher temperature. In the same manner, the burn caused by boiling point of syrup is higher than that of pure water. This is because the interaction of the solute-solvent in a solution is greater than the interaction of solvent-solvent in pure solvent or solute-solute in a pure solute. Since the vapor pressure is lower in solutions, it takes a longer time to equalize the vapor pressure of the liquid and the atmospheric pressure. Thus, it takes a higher temperature to attain the boiling point of a solution. The boiling point of a solution, therefore; is greater than the boiling point of a pure solvent. The boiling point elevation of a solution, ΔTb, is directly proportional to the number of solute particles. For dilute solutions, ΔTb is proportional to molality, that is, ΔTb = Kb x m Where K is the molal boiling point elevation constant of the solvent and m is the molal concentration of the solution. The K of water is 0.52 0C/m, so 1 m aqueous solution of a nonvolatile solute like sucrose will boil at 0.52 0C higher than pure water. The boiling point elevation is proportional to the number of solute particles in the solution. When 1 mole of NaCl dissolves in water, 2 moles of solute are formed 1 mole of Na and 1 mole Cl. Therefore, a 1 m solution of NaCl in water causes a boiling point elevation twice as large as a 1 m solution of sucrose. Example Molal Boiling Point Constant Calculate the boiling point of a solution containing 3.5 g sugar (molar mass = 342 g) dissolved in 150 g of water. The mass of solute (3.5 g) is given which is dissolved in 150 g of solvent, water. STEP 1: Solve for the molality of the solution, the unit of which is mole solute/kilogram solvent. Using the dimensional analysis, the first factor converts mass to mole, then divide with the mass of solvent, and the last factor converts the mass in grams to kilogram. 𝐌𝐨𝐥𝐚𝐥𝐢𝐭𝐲 (𝑚) = 𝚫𝐓𝐛 = 𝐊𝐛 𝐱 𝐦 0.513 °C x 0.068 m = 𝟎. 𝟎𝟑𝟓 °𝑪 1m mole solute kg solvent 1 mole 1 1 000 g 𝐌𝐨𝐥𝐚𝐥𝐢𝐭𝐲 (𝑚) = 3.5 g sugar x x x 342 g 150 g water 1 kg 𝐌𝐨𝐥𝐚𝐥𝐢𝐭𝐲 (𝑚) = STEP 2: Solve for boiling point elevation 3500 mole = 𝟎. 𝟎𝟔𝟖 𝐦𝐨𝐥𝐞/𝐤𝐠 51300 kg STEP 3: Solve for boiling point of the solution Boiling point of solution = boiling point of solvent + ΔTb 62.8 0C = 61.2 0C + ΔTb ΔTb = 62.8 − 61.2 = 𝟏. 𝟔 °𝑪 32 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 FREEZING POINT DEPRESSION The freezing point of a substance is the temperature at which the solid and liquid phases coexist and their vapor pressures are the same. If a nonvolatile solute is added to a solvent, the freezing point of the solvent is lowered and the reduction in the freezing point depends on the number of moles of solute present. Again, the effect of electrolytes as solutes is greater than nonelectrolytes because electrolytes ionize in solution and as such contain a greater number of particles. The greater the number of solute particles, the greater the effect on the reduction of the freezing point. If one mole of nonelectrolyte solute is dissolved in one kilogram of water, the freezing point of water is reduced by 1.86 °C. If two moles of nonelectrolyte solute dissolved in one kg of water, then the freezing point is reduced by 3.72 °C. In other words, the freezing point depression constant for water (Kf) is 1.86 °C/1 molal solution and Kf varies depending on the solvent. The identity of the solute does not have any effect on the freezing point just like in the vapour pressure and boiling point. The freezing point depression then is equal to ΔTf = Kf x m ΔTf = freezing point of pure solvent - freezing point of a solution Freezing point solution = freezing point solvent - ΔTf Solvent Molal Freezing Point Depression Constant Kf (0C/m) Freezing Point 0C Acetic acid (CH3COOH) Benzene (C6H6) Naphthalene (C6H8) Chloroform (CHCl3) Water (H2O) Example 3.90 5.12 7.00 4.68 1.86 16.6 5.51 80.2 -63.5 1.86 What is the freezing point depression when 155 g of Iodine (I2) crystals is added to 1200 g of benzene? Kf benzene = 5.12 0C/m FP benzene = 5.51 0C STEP 1: Solve for the molality of benzene 1 mole I2 1 1000 g benzene x x 254 g 1200 g benzene 1 kg benzene 𝟎. 𝟓𝟎𝟗 𝐦𝐨𝐥𝐞 = 𝐤𝐠 STEP 2: Solve for freezing point depression 155 g I2 x 𝚫𝐓𝐟 = 𝐊𝐟 𝐱 𝐦 = 5.12 °C x 0.509 m = 𝟎𝟐. 𝟔𝟏 °𝐂 1m SCIENCE OVERLOAD An application of freezing point depression is the addition of rock salt to ice on wintry roads to melt the ice and snow. NaCl when dissolved in water lowers the freezing point of water several degrees. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 33 FLASH CHECK 4 PROBLEM PROBLEMSOLVING SOLVING 1. What is the molality of a solution dissolved in chloroform that boils at 62.8 0C? Boiling point of chloroform is 61.2 62.2 0C? Kb chloroform 3.63 0c/m 2. A solution prepared from 0.3 boiling point of 0.392 0C higher solute? g of an unknown nonvolatile solute and 30 g CCl 4 has a than that pure CCl4. What is the molecular weight of the QUICK CONNECT The greatest application of boiling point elevation is in the preparation of candies. Sugar and flavours are added to water and boil for a long time to make the solution concentrated. As the solution becomes more concentrated, the vapor pressure is reduced and the boiling point is increased. A candy thermometer determines if the candy is ready for the next procedure. Syrup is prepared in the same manner. A dilute sugar solution is boiled for a long time to make it very concentrated. The temperature is monitored to determine when the desired concentration of the syrup has been attained. 34 REFERENCES • Breaking through chemistry p. 336 - 370 • General Chemistry 2 pp. 50 - 52 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 GENERAL CHEMISTRY 2 THERMODYNAMICS vs. THERMOCHEMISTRY Coffee in a bottle or Coffee in a thermos jug INSTANT TASK Decipher the Mystery Word! Using the Morse Code, decode the unknown word below. ___ / . . . . / . / .___. / ___ ___ / ___ ___ ___ / ___ . ___ . / . . . . / . / ___ ___ / . . / . . . / ___ / . ___ . / ___ . ___ ___ Mystery Word: _________________________________________________ SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 35 DIRECT TALK First Law of Thermodynamics THERMODYNAMICS Is the study of processes which involve heat transfer and the performance of work. The term thermodynamics is derived from the Greek word "themes" which means heat and "dynamo" which means power. Thermodynamics deals with the study of energy and its transformation. This field of study will help in understanding the relationship between heat and work in all living and nonliving things. A living cell, for instance, evolves heat, does not work, and utilizes energy obtained from burning of food. Burning of gasoline inside an internal combustion engine provides the push that propel the vehicle, aside from giving out heat. A moving machine that does work also generates heat. Thermodynamics will provide guidelines that will enable us to understand the energies and directions of reactions. TAKE NOTE Enthalpy of Chemical Reactions The term enthalpy, from the Greek word, enthalpein, meaning "to warm" refers to the energy transferred under constant pressure. It is represented by the symbol, H. It is often referred to, as heat content. Like E (internal energy), enthalpy, H, is also a state function, and therefore, not path dependent. Enthalpy cannot be measured, but, it is possible to measure the change in enthalpy or heat content, ΔH. Internal energy (E) is the sum of the kinetic and potential energy found in the system. It is the total energy found on the system being studied. However, this is not quantifiable. But internal energy also changes as the system changes. THERMOCHEMISTRY Is the study of this heat exchange and work on chemical reactions. The law of conservation of energy states that the total energy of universe is constant. Energy univ = constant Hess's Law For any chemical reaction at standard conditions, the standard enthalpy change is the sum of the standard molar enthalpies of formation of the products (each multiplied by its coefficient in the balanced chemical equation) minus the corresponding sum for the reactants. 36 According to Germain Hess, a Russian chemist, the enthalpy change is the same whether a reaction takes place in one step or a series of steps. For a chemical reaction that takes place using different pathways, overall enthalpy change is the same regardless of the route, so long as initial and final conditions are the same. Hess's Law states that the enthalpy change of an overall reaction is the sum of the enthalpy change of its individual steps. Since enthalpy is a state function where the final and initial states are the only important states, the individual equations and their known enthalpy can be manipulated to determine the enthalpy of the reaction. A thermochemical equation can be expressed as the sum of two or more equations, overall equation = equation 1 + equation 2 + ………..and, ΔH0 for the overall equation is the sum of the ΔH0 for the individual equations: ΔH0 = ΔH1 + ΔH2 + ….. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 Example: 1.) S (s) + O2 (g) → SO2 (g) ΔH0 = -296.8 kJ 2.) 2SO (s) + O2 (g) → 2SO3 (g) ΔH0 = -798.4 kJ 3.) S (s) + 3/2O2 (g) →SO3 (g) ΔH0 = ? STEP 1 Identify the net equation whose ΔH0 is unknown. Make sure that the reaction is balanced. S (s) + 3/2O2 (g) → SO3 (g) ΔH0 = ? STEP 2 Manipulate equations where ΔH0 is known so that the correct moles of reactants and products are on correct sides. Remember that reversing the direction of the reaction will give a ΔH0 of the same magnitude but with different sign. Multiplying or dividing the reaction by a factor should be done to both the ΔH0 value and the reaction. S (s) + O2 (g) → SO2 (g) ΔH0 = -296.8 kJ 2SO (s) + O2 (g) → 2SO3 (g) ΔH0 = -798.4 kJ STEP 3 Add these individual reactions to get the net reaction. The value of the unknown ΔH0 is the sum of the individual manipulated ΔH0. S (s) + O2 (g) → SO2 (g) ΔH0 = -296.8 kJ SO2(s) + 1/2O2 (g) → SO3 (g) ΔH0 = -399.2 kJ S(s) + 3/2O2 (g) → SO3 (g) ΔH0 = -696.0 kJ STRATEGY In applying Hess's Law, equations can be arranged so that the desired reactants and products will appear in the overall reaction. If the equation is reversed, the sign of ΔH0 must be reversed. If the equations are multiplied by a factor to obtain the desired coefficients, the ΔH0 values should also be multiplied by the same number. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 37 FLASH CHECK 4 PROBLEM SOLVING 1.) Calculate the standard enthalpy of formation, ΔH0 for methane gas, CH4, produced from graphite and hydrogen gas according to the following reaction: C (graphite) + 2H2 (g) → CH4 (g) Analysis: Since this reaction that forms methane gas does not take place as written, ΔH0 of methane is determined indirectly by using the following set of reaction whose ΔH0 values have been accurately determined and applying Hess's Law. A. Write equation (1) as is. 1.) C (graphite) + O2 (g) → CO2 (g) ΔH0 = -393.5 kJ 2.) H2 (g) + 1/2O2 (g) → H2O (l) ΔH0 = -285.8 kJ 3.) CH4 (g) + 2O2 (g) → CO2 (g) + 2HO2 (l) ΔH0 = -890.4 kJ B. Multiply reaction (2) by two including the value of ΔH0. C. Rewrite reaction (3) in the reverse direction and change the sign of ΔH0 from - to +. D. Add the equations algebraically. Substances that appear on opposite sides of the equation may be cancelled. QUICK CONNECT Hess's Law can be applied to sever every day factors, such as the engine in your car which turns the heat of combustion of the fuel, through several steps, into the energy which is translated to the movement of the car. This can be applied industrially as the engineers creating the cars can use it to determine if new fuels would heat the engine more or less and how they would affect the ability of movement and speed of the car. 38 REFERENCES • Breaking through chemistry pp. 410 - 420 • World of chemistry pp. 72 - 83 • Applications - Thermodynamics- Enthalpy/Hess's Law (google.com) • Coffee Cup Vector PNG & Download Transparent Coffee Cup Vector PNG Images for Free - NicePNG SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 GENERAL CHEMISTRY 2 Colligative Properties of Solutions INSTANT TASK Study the disorganized letters. Try to organize or rearrange the letters to form the exact word based on the supported description. A property of a solution that is dependent on the ratio between the total number of solute particles (in the solution) to the total number of solvent particles. RGASU LGVEICOALTI TYPPOERR A sweet crystalline substance obtained from various plants, consisting essentially of sucrose, and used as a sweetener in food and drink. A colorless crystalline compound occurring naturally in seawater and halite; common salt. VRULASINE NLEVSTO MUSDOI RDLEOCIH A substance that dissolves most chemicals. Water is referred as this because it dissolves more substances than any other solvent. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 39 A colligative property is a property of a solution that is dependent on the ratio between the total number of solute particles (in the solution) to the total number of solvent particles. Colligative properties are not dependent on the chemical nature of the solution’s components. We can observe the colligative properties of solutions by going through the following examples. If we add a pinch of salt to a glass full of water, its freezing temperature is lowered considerably than the normal temperature. Similarly, if we add alcohol to water, the solution’s freezing point goes down below the normal temperature that is observed for either pure water or alcohol. Different Types of Colligative Properties of Solution Recall that the vapor pressure of a liquid is determined by how easily its molecules are able to escape the surface of the liquid and enter the gaseous phase. This vapor pressure is temperature dependent: the higher the temperature, the higher the vapor pressure. When a liquid evaporates easily, it will have a relatively large number of its molecules in the gas phase and thus will have a high vapor pressure. Liquids that do not evaporate easily have a lower vapor pressure. The figure below shows the surface of a pure solvent compared to a solution. Vapor Pressure Lowering Red ones are the nonvolatile solutes REMEMBER! Vapor pressure of a solvent is bigger than vapor pressure of a solution. In the picture on the left (pure solvent), the surface is entirely occupied by liquid molecules, some of which will evaporate and form a vapor pressure. On the right (solution), a nonvolatile solute has been dissolved into the solvent. Nonvolatile means that the solute itself has little tendency to evaporate. Because some of the surface is now occupied by solute particles, there is less room for solvent molecules. This results in less solvent being able to evaporate. The vapor pressure of a solvent is lowered by the addition of a non-volatile solute to form a solution. By definition, a non-volatile substance does not evaporate. The boiling point of a solvent will increase when a solute is dissolved in it. This is referred to as boiling point elevation. The elevation of the boiling point is directly dependent on the amount of solute present in the solution, but it is not based on the identity of the solute, so it is considered a colligative property. We know that on the addition of a non-volatile liquid to a pure solvent, the vapor pressure of a solution decrease. Therefore, to make vapor pressure equal to atmospheric pressure, we have to increase the temperature of the solution. The most common example of this phenomenon is that the boiling point of water is increased by adding salt to the water. Basically, it is the temperature change (rising) of the boiling point of solvent caused by adding a solute. Boiling Point Elevation Freezing Point Depression When a substance is dissolved in water or some other solvent, the freezing point is lowered. This observation can be explained based on the lowering of the vapor pressure of a solution. When we add a solute to the solvent, some of the molecules 40 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 take up spaces at the surface of the liquid. As we know, to vaporize, solvent molecules must be present at the surface of the solution. Adding about 68.5 grams of salt to 1 liter of water lowers its freezing point by 1.86 degrees Celsius (3.4 degrees Fahrenheit). When salt is added to an icy road, it dissolves into water above the ice and keeps it from freezing even though the temperature of the road is lower than 0 degrees Celsius -- the freezing point of water. Osmotic pressure can be thought of as the pressure that would be required to stop water from diffusing through a barrier by osmosis. In other words, it refers to how hard the water would “push” to get through the barrier called semipermeable membrane, in order to diffuse to the other side. A semipermeable membrane is a layer that only certain molecules can pass through. Semipermeable membranes can be both biological and artificial. When we sit in the bathtub or submerge our fingers in water for a while, they got wrinkly. And that is too because of osmosis. The skin of our fingers absorb water and get expanded or bloated; leading to the pruned or wrinkled fingers. You must have heard about the killing of slugs or snails by putting salt on it. The liquid inside them comes out and try to dilute the salt concentration and maintain the mucus layer, and hence, they end up shedding water. Too much salt and slugs or snails will dry up and die! Osmotic pressure is determined by solute concentration – water will “try harder” to diffuse into an area with a high concentration of a solute, such as a salt, than into an area with a low concentration. Osmotic Pressure Electrolytes are chemical compounds that can break down into ions when dissolved in water. These ions can conduct electricity through this aqueous solution. There are two types of electrolytes: strong electrolytes and weak electrolytes. Strong electrolytes readily produce ions when they are soluble. For example, strontium hydroxide, Sr(OH)2 is partially dissolved in water. But it is a strong electrolyte since the amount that is dissolved is completely ionized. Moreover, salts such as NaCl, MgCl2 are also strong electrolytes since they are ionic compounds with a high degree of ionic characteristics. Nonelectrolytes are chemical compounds whose aqueous solutions cannot conduct electricity through the solution. These compounds do not exist in ionic form. Most nonelectrolytes are covalent compounds. When dissolved in water, these compounds do not form ions at all. Sugars, fat, and alcohols are examples of nonelectrolytes. Different Types of Colligative Properties of Solution SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 41 1. Identify whether the following statements are TRUE or FALSE. _________________ 1. Salt water solution will boil faster than just water alone. _________________ 2. The higher the temperature, the higher the vapor pressure. _________________ 3. A glass of water will evaporate faster than a glass of soda. _________________ 4. A dissolved sugar in H2O can conduct electricity but will evaporate slowly. _________________ 5. The effect of electrolytes on colligative properties is very low compared to nonelectrolytes. 2. Observe from your surroundings. Pick one from the different types of colligative properties and cite one example that best exhibits it. Explain. Example: When we soak resins in water they swell up. This happens due to osmotic pressure. Water travels from high concentration to low concentration and keeps moving by osmosis until the equilibrium is reached, that is when the concentration of both solutions is the same. Answer to START-UP We tend to drink lots of water after consuming salty foods because salt is a solute and after consuming lots of salt, our cells become concentrated with salt, which triggers the process of thirst. So, our cells absorb water and we feel thirsty, and hence, we start drinking water. References: QUICK CONNECT Salt water helps you relieved from sore throat get In case you have a sore throat, cells and tissues surrounding the throat are swollen because of the excess of water. The salt water which we use for gargles has a lower concentration of water than the cells of the throat. So, water molecules move from the swollen cells of the throat to the salt water; reducing pain and swelling. 42 1. 2. 3. 4. http://www.chem4kids.com/ https://study.com/academy/le sson https://www.ck12.org/ https://opentextbc.ca/ SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 GENERAL CHEMISTRY 2 Rates of Reaction INSTANT TASK LET’S DO THE NAKED EGG EXPERIMENT! Prepare these materials for this fun and interesting activity. You will need: ✓ Raw egg ✓ Vinegar ✓ A glass container with a tight lid Questions: (You must finish the experiment first to answer the following questions.) 1. Looking at the physical appearance of the egg, explain how does it look like after soaking for 24 hours. 2. What have you noticed in the vinegar at the container? 3. Touching the egg after 24 hours of soaking, explain how does it feel. 4. Remove the raw egg from the vinegar and allow it to sit out on the table for one (1) day. What have you observed to the egg? Instructions: 1. Place an egg inside a large glass container, such as a beaker or jar. If you want to make more than one naked egg, make sure the eggs do not touch inside the container. 2. Pour enough vinegar into the jar to cover the egg completely. The egg might float to the top, but the vinegar should still cover most of the egg. 3. Set your jar aside and wait 12 to 24 hours for the eggshell to dissolve. 4. Pour out the vinegar carefully and catch the naked egg in your hand. You may also use a wooden spoon to remove the egg, but this method might cause it to break. If a small amount of white eggshell still remains on the egg, you can lightly wipe it off with your fingers. If the shell has not dissolved enough, place the egg in a fresh jar of vinegar for another 12 to 24 hours. Write your answers in a separate sheet of paper! SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 43 The rate of reaction or reaction rate is the speed at which reactants are converted into products. When we talk about chemical reactions, it is a given fact that rate at which they occur varies by a great deal. Some chemical reactions are nearly instantaneous, while others usually take some time to reach the final equilibrium. Example: Wood combustion has a high reaction rate since the process is fast and rusting of iron has a low reaction rate as the process is slow. Five Factors That Can Affect The Rates of a Chemical Reaction For a chemical reaction to occur, there must be a collision between the reactants at the correct place on the molecule, the reactive site. If the collision doesn’t transfer enough energy, no reaction will occur. The various factors that can affect the rate of a chemical reaction are listed below: Nature of the Reactants. The rate of reaction highly depends on the type and nature of the reaction. As mentioned earlier, few reactions are naturally faster than others while some reactions are very slow. The physical state of reactants, number of reactants, complexity of reaction and other factors highly influence the reaction rate as well. The rate of reaction is generally slower in liquids when compared to gases and slower in solids when compared to liquids. Size of the reactant also matters a lot. The smaller the size of reactant, the faster the reaction. The Temperature. According to collision theory, a chemical reaction that takes place at a higher temperature generates more energy than a reaction at a lower temperature. This is because colliding particles will have the required activation energy at high temperature and more successful collisions will take place. The Concentration of Reactants. Increasing the concentration of the reactants (or pressure, if gases are involved) normally increases the reaction rate due to the increased number of collisions. Less Concentrated More Concentrated Physical State of Reactants. Gases and liquids tend to react faster than solids because of the increase in surface area of the gases and liquids versus the solid. If the size of a particle is small, the surface area will be more and this increases the speed of heterogeneous chemical reactions. Catalysts. A catalyst can be defined as a substance that increases or decreases the rate of the reaction without actually participating in the reaction. The definition itself describes its effect on chemical reactions. With a helping hand from a catalyst, molecules that might take years to interact can now do so in seconds. All reactants need to overcome certain energy, better known as activation energy in order to form products. 44 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 and how it affects the chemical reaction How do catalysts work? Particles stick the surface of the catalyst (called adsorption) and then move around, so they are more likely to collide and react. A good example is the way the platinum catalyst in a car’s catalytic converter works to change toxic carbon monoxide into less-toxic carbon dioxide (see pictures in left). Another process of catalyst affecting chemical reactions is called reaction intermediate, wherein a catalyst first combines with a chemical to make a new compound. This new compound is unstable, so it breaks down, releasing another new compound and leaving the catalyst in its original form. Many enzymes (special biological catalysts) work in this way. One example of a catalyst that involves an intermediate compound can be found high in the Earth’s atmosphere. Up there, the chemical ozone (with molecules containing three oxygen atoms) helps protect the Earth from harmful UV radiation. But also up there is chlorine, which gets into the atmosphere from chemicals (chlorofluorocarbons, CFCs) used in some refrigerators, air conditioners and aerosol cans. Chlorine is a catalyst, which steals an oxygen atom from ozone (O 3) leaving stable oxygen (O2). At the same time, it forms an unstable intermediate chlorine-oxygen compound, which breaks down to release its oxygen. This leaves the chlorine free to repeat the process. One chlorine atom can destroy about a million ozone molecules every second. This can have a drastic effect on the atmosphere’s ability to protect us from UV radiation. onto Types of Catalysts Homogeneous Catalyst Heterogeneous Catalyst Biological Catalyst Homogeneous catalysis of chemical reactions is a process where the reactants involved in the reaction and the catalyst are in the same phase. For example, if the reactants are gases, then the catalyst is also a gas. Heterogeneous catalysts are in a different phase than the reactants. For example, the reactants may be solid, but the catalyst is a liquid. Natural proteins (enzymes) or nucleic acids (RNA or ribozymes and DNAs) used to catalyze specific chemical reactions outside the living cells are called biocatalysts. Example: Yeast, Bacteria, fungi, etc. Activation Energy Activation energy and catalyst are closely related because the function of the catalyst is to lower down the activation energy so that more particle has enough energy to react. Activation energy is defined as the minimum amount of extra energy required by a reacting molecule to get converted into product. It can also be described as the minimum amount of energy needed to activate or energize molecules or atoms so that they can undergo a chemical reaction or transformation. Examples of Chemical reactions that require Activation energy: ✓ ✓ The combustion reaction requires activation energy. Carbon and oxygen combine to form carbon dioxide and transformed the energy. Lighting a match which creates friction and turns to heat. The heat thus liberated then produce enough activation energy that allows the chemical on the match to react and ignite the flame. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 45 Answer the following questions below. Write your answer in a separate sheet of paper. 1. Enumerate the five factors that affects the rate of chemical reaction. 2. 1. a. b. c. d. e. 2. Why does a chemical reaction that takes place at a higher temperature generates more energy? 3. Explain how do catalysts work in a chemical reaction. Give examples. 4. What is the relation of activation energy and catalyst? Answer to START-UP The rusting process of an iron is pretty much fast, not to mention if it’s in rough climate, but we don’t want the process to occur, or at least we want to delay the process, so we paint it, or cover it with a substance that slows down the process. References: QUICK CONNECT 1. 2. In wildlife, a wood could decompose in over 300 years if it exposed to open air, but we want the process faster to get heat out of it, so we light the wood by adding extra energy to fasten the process. 46 3. 4. http://www.chem4kids.com / https://study.com/academy /lesson https://www.ck12.org/ https://opentextbc.ca/ SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 GENERAL CHEMISTRY 2 Molecular Collisions and the Orders of Reaction INSTANT TASK SHARING EXPERIENCES. Have you experienced colliding into something or someone unexpectedly? Have you seen two things collided with an ear-splitting crash? A thing dropped from a high place and crushed as it landed? Tell us your experience through writing an essay! Relate your experience with the idea of molecular collisions. ____________________________________________________ ____________________________________________________ ____________________________________________________ ____________________________________________________ ____________________________________________________ ____________________________________________________ ____________________________________________________ ____________________________________________________ ____________________________________________________ ________ ____________________________________________________________________ ____________________________________________________________________ ____________________________________________________________________ ____________________________________________________________________ SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 47 What is Collision Theory? When cars moving at a high speed collide with one another, the result can be a particularly dramatic change. A high energy collision can convert a functional car into a pile of scrap metal and spare parts. On the other hand, a slower, low energy collision might just cause a scratch or a minor dent. Not all collisions are purely destructive. You are probably familiar with the phrase, “You can’t make an omelet without breaking some eggs.” Similarly, you can’t cause a chemical reaction without breaking some bonds. Most chemical reactions occur only when reactants collide with one another. However, not every collision leads to a chemical change. In order for a reaction to occur, the reactants must collide in a certain relative orientation with enough energy to break one or more chemical bonds. Based on this simple model, we can predict which factors will speed up or slow down a chemical reaction. Do you ever wonder how reactions actually happen? What are the conditions necessary for a reaction to happen? Is it certain that a reaction will take place even after the conditions are fulfilled? The answer to all these questions is Collision Theory. The collision theory states that a chemical reaction can only occur between particles when they collide (hit each other). The collision between reactant particles is necessary but not sufficient for a reaction to take place. The collisions also have to be effective. It is important to understand the exact nature of an effective collision since this determines whether particles react with each other and form new products. The more molecules are present, the more collisions will happen. Molecules must collide before they can react. To effectively initiate a reaction, collisions must be sufficiently energetic (kinetic energy) to bring about this bond disruption. The molecules must collide with energies greater than or equal to the activation energy of the reaction. If this does not happen the reaction will not take place. The molecules need the energy to break their existing bonds and form new bonds. This is the kinetic energy that the molecules possess. If this energy is not equal to or greater than the activation energy, the reaction will not proceed. As the temperature rises, molecules move faster and collide more vigorously, greatly increasing the likelihood of bond cleavages and rearrangements. Most reactions involving neutral molecules cannot take place at all until they have acquired the activation energy needed to stretch, bend, or otherwise distort one or more bonds. 48 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 Orders of Reaction Explained The order of the reaction is a relationship between the rate of a chemical reaction and the concentration of the species. But remember! Orders of reaction are always found by doing experiments. You can't deduce anything about the order of a reaction just by looking at the equation for the reaction. This topic will introduce you the basic concept of the orders of the reaction. First, let us discuss the relationship of the reaction orders to the Rate Law. For any general reaction occurring at a fixed temperature: The term k is the rate constant, which is specific for a given reaction at a given temperature. The exponents m and n are reaction orders and are determined by experiment. The value of m and n are not necessarily related in any way to the coefficients a and b. A reaction has an individual order ““with respect to” or “in” each reactant. For the simple reaction A → products: ✓ If the rate doubles when [A] doubles, the rate depends on [A]1 and the reaction is first order with respect to A. ✓ If the rate quadruples when [A] doubles, the rate depends on [A]2 and the reaction is second order with respect to A. ✓ If the rate does not change when [A] doubles, the rate does not depend on [A], and the reaction order is zero order with respect to [A]. Individual and Overall Reaction Orders Example: Determining Reaction Orders from Rate Laws For the reaction: 2NO + 2H2 → N2 + 2H2O The rate law is: k [NO]2[H2] Answer: The reaction order is second order with respect to NO, first order with respect to H2 and third order overall (addition of all exponents). Note that the reaction order is first order with respect to H2 even though the coefficient for H2 in the balanced equation is 2. This is because as stated from above, that the value of m and n are not necessarily related in any way to the coefficients a and b. SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 49 Answer the following questions. Write your answer in a separate sheet of paper. 1. In your own words, explain the collision theory. 2. Differentiate the orders of reaction. 3. Determine the reaction orders from the given rates: a.) b.) Answer to START-UP Molecules with greater kinetic energy diffuse faster; in other words, the rate of diffusion increases as kinetic energy increases. For example, the food coloring will spread out faster in the warmer water because of greater kinetic energy. QUICK References: CONNECT The game of pool provides an example of a collision in which one object, the cue ball, is moving, while the other—known as the object ball—is stationary. Due to the hardness of pool balls, and their tendency not to stick to one another, this is also an example of an almost perfectly elastic collision—one in which kinetic energy is conserved. 50 1. 2. 3. 4. http://www.chem4kids.com/ https://study.com/academy/le sson https://www.ck12.org/ https://opentextbc.ca/ Read more: http://www.scienceclarified.com/e veryday/Real-Life-Chemistry-Vol-3Physics-Vol-1/Momentum-Real-lifeapplications.html#ixzz6ng39JSBT SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 The Temperature Curve and The Phase Changes of Water and CO2 INSTANT TASK 1. 2. 3. 4. 5. 6. 7. 8. Gas C Liquid B Solid A Gas - Liquid Liquid – Solid FLASH CHECK a. b. c. d. e. f. Solid Liquid Gas Liquid Gas Gas START - UP - THEIR SIMILARITIES ARE NOT BASED ON THE COMPOSITION OR STRUCTURE OF THE CONTAINER. THEIR SIMILARITIES ARE BASED ON THEIR SURROUNDINGS IN THE FORM OF HEAT AND ON THEIR ABILITY TO DO WORK ON THE SURROUNDINGS. INSTANT TASK 1. 2. 3. 4. 5. 6. 7. 8. 9. CRYSTALLINE AMORPHOUS MOLECULAR IONIC METALLIC COVALENT POLAR NON-POLAR HYDROGEN BONDED FLASH CHECK - ANSWERS MAY VARY SCIENCE POCKET LESSON 5 SCIENCE POCKET LESSON 4 INSTANT TASK *SOLID 1. ICE 2. BOOK 3. WOOD 4. BLOCK 5. *LIQUID 1. MILK 2. WATER 3. JUICE 4. COFFEE 5. PAINT *GAS 1. BALLOON 2. CLOUD 3. TORNADO 4. AIR 5. BOILING 1. INTERMOLECULAR 2. SURFACE TENSION 3. BOILING POINT 4. VISCOSITY 5. LIQUIDS 6. VAPORIZATION 7. MOLAR 8. FORCES 9. HEAT 10. VAPOR - ANSWERS MAY VARY - SURFACE TENSION - ICE IS ACTUALLY ABOUT 9% LESS DENSE START-UP START - UP THAN WATER. SINCE THE WATER IS HEAVIER, IT DISPLACES THE LIGHTER ICE, CAUSING THE ICE TO FLOAT TO THE TOP. INSTANT TASK 1. WATER 2. FREEZING POINT 3. BOILING POINT 4. SHAPE 5. SOLID 6. LIQUID 7. GAS 8. SOLID 9. LIQUID 10. GAS START-UP INSTANT TASK FLASH CHECK 1. 2. 3. FLASH CHECK FLASH CHECK ANSWERS MAY VARY 1. LONDON DISPERSION FORCES (Ar) 2. DIPOLE-DIPOLE, H-BOND (CH3CH2OH) 3. DIPOLE-DIPOLE, H-BOND (HF) 4. DIPOLE-DIPOLE (BaCl2) - ANSWERS MAY VARY SCIENCE POCKET LESSON 2 SCIENCE POCKET LESSON 1 SCIENCE POCKET LESSON 3 ANSWER KEY SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 - ANSWERS MAY VARY INSTANT TASK START-UP Colligative Properties of Solutions 1. 2. 3. 4. Colligative Property Sugar Sodium Chloride Universal Solvent 1. TRUE 2. TRUE 3. TRUE 4. FALSE 5. FALSE (Answers may vary.) 5 grams of flour, 100 grams of butter, ½ cup of sugar, 5 cookies 2NaN3 → 2Na + 3N2 START-UP INSTANT TASK INSTANT TASK - C (graphite) + 2H2 (g) → CH4 (g) ΔH0 = -74.7 kJ FLASH CHECK 1. 0.441 m 2. 128 g/mol Concentrations of Solutions INSTANT TASK INSTANT TASK 1. 2. - ANSWERS MAY VARY 1. BOILING POINT 2. FREEZING POINT -THERMOCHEMISTRY FLASH CHECK FLASH CHECK A. B. SCIENCE POCKET LESSON 10 Stoichiometric Calculations for Reactions in Solutions SCIENCE POCKET LESSON 9 1. 2. 3. 15% apples are bad. 25% Php 562.50 FLASH CHECK a. FLASH CHECK 1. SCIENCE POCKET LESSON 8 a. 200g C3H8 = 4.54 mol C3H8 b. (ratio of H2O to C3H8= 4:1); for every 4.54 mol C3H8 there are 18.18 mol H2O c. 18.18 mol H2O is equal to 327.27 g H2O. (2 x 12) + (5 x 1.008) + (1 x 14) + (2 x 16) = 75.04 g/mol → molar mass [0.000889 g C2H5NO2 x (1 mol C2H5NO2 / 75.04 g C2H5NO2) = 1.18 x 10-5 mol HCl Convert 1.05mL to L = 0.00105 L M = 1.18 x 10-5 mol HCl / 0.00105 L = 0.0112 M C2H5NO2 (0.6 g Pb / 277 g solution)(1000000) = 2166 ppm (90mL / 3000mL)(100%) = 3% 25 g KBr x (1 mol KBr / 120 g KBr) x (1 / 0.75 L) = 0.278 M (25 g / 46.07 g/mol) = 0.543 moles ethanol (25 g / 18 g/mol) = 1.389 moles water Total number of moles in the solution = 0.543 + 1.389 = 1.932 moles Mole fraction of ethanol = (0.543 / 1.932) = 0.281 Mole fraction of water = (1.389 / 1.932) = 0.718 c. d. e. f. (36.5 g / 355 g)(100%) = 10.3% b. SCIENCE POCKET LESSON 6 SCIENCE POCKET LESSON 7 SAN PEDRO RELOCATION CENTER NATIONAL HIGH SCHOOL – SCIENCE DEPARTMENT © 2020 INSTANT TASK INSTANT TASK Rates of Reaction Molecular Collisions and the Orders of Reactio 1. (Answers may vary.) (Answers may vary.) FLASH CHECK FLASH CHECK 1. 2. 3. (Answers may vary.) (Answers may vary.) a. The exponent of [NO] is 2 and the exponent of [O2] is 1, so the reaction order is second order with respect to NO, first order with respect to O2, and third order overall. b. The reaction is first order in H2O2, first order in I-, and second order overall. The reactant H+ does not appear in the rate law, so the reaction is zero order with respect to H+. 1. Five factors: a. Nature of the Reactants b. Temperature c. Concentration of Reactants d. Physical State of Reactants Catalysts e. 2 – 4. (Answers may vary based on student’s interpretation.) SCIENCE POCKET LESSON 11 SCIENCE POCKET LESSON 12 ANSWER KEY