Course roadmap ME451: Control Systems Modeling Analysis Laplace transform Lecture 15 Time response of 2nd-order systems Transfer function Models for systems • electrical • mechanical • electromechanical Block diagrams Linearization Dr. Jongeun Choi Department of Mechanical Engineering Michigan State University Design Time response • Transient • Steady state Design specs Root locus Frequency response • Bode plot Frequency domain PID & LeadLead-lag Stability • RouthRouth-Hurwitz • Nyquist Design examples (Matlab simulations &) laboratories 1 Performance measures (review) Transient response 2 Second-order systems A standard form of the second-order system (Today’ (Today’s lecture) Peak value Peak time Percent overshoot Delay time Rise time Next, we will connect these measures with ss-domain. Settling time Amplifier Steady state response Steady state error DC motor position control example Motor ClosedClosed-loop TF (Done) 3 4 Step response for 2nd-order system Input a unit step function to a 2nd-order system. What is the output? u(t) u(t) Step response for 2nd-order system for various damping ratio Undamped 2 y(t) y(t) Underdamped 1 0 0 Critically damped Overdamped DC gain 1.5 1 0.5 0 0 5 10 15 5 Step response for 2nd-order system Underdamped case 6 Peak value/time: Underdamped case Math expression of y(t) for underdamped case 1 .6 1 .4 1 .2 1 0 .8 0 .6 0 .4 0 .2 0 0 5 10 15 Damped natural frequency 7 8 Properties of 2nd-order system Some remarks Percent overshoot depends on ζ, but NOT ωn. From 2nd-order transfer function, analytic expressions of delay & rise time are hard to obtain. Time constant is 1/(ζωn), indicating convergence speed. For ζ>1, we cannot define peak time, peak value, percent overshoot. (5%) (2%) 9 P.O. vs. damping ratio 10 Pole locations of G Poles (0<ζ<1) Damping ratio Next, we clarify the influence of pole location on step response. 11 12 Influence of real part of poles Influence of imag. part of poles Oscillation frequency ωd increases. Settling time ts decreases. ts 13 Influence of angle of poles 14 An example Over/under-shoot decreases. Require 5% settling time ts < tsm (given): Im Re 15 16 An example (cont’d) An example (cont’d) Require PO < POm (given): Combination of two requirements & Im Im Re Re 17 18 Exercises (Use a calculator if necessary.) Summary Transient response of 2nd-order system is characterized by Read the related topics from the textbook. 1. For the system below with ζ=0.6, ωn=5 (rad/sec), obtain Damping ratio ζ & undamped natural frequency ωn Pole locations Delay time and rise time are not so easy to characterize, and thus not covered in this course. For transient responses of high order systems, we need computer simulations. Next, Root locus 19 • • Percent overshoot ? 5% settling time ? 20 Exercises 2. For the system below, design K1 and K2 s.t. Percent overshoot is at most 20%? Peak time is at most 1 sec.? With designed K1 and K2, what is 5% settling time? 21