REACTIONS OF ALKYL HALIDES Alkyl halides (R-X) undergo two types of reactions : substitution reactions and elimination reactions. In a substitution reaction, the X group in R-X is replaced by a different group, e.g. R-XR-OH +XӨ In an elimination reaction, the elements of H-X are eliminated from R-X; the product is very often an alkene. H CH3 CH2 C Br CH3 base CH2 CH3 C + HBr CH3 1 ALKYL HALIDES – Substitution reactions H H HC C H H Br + OH HH H C C OH + Br HH This is a nucleophilic substitution or nucleophilic displacement reaction on which OH displaces Br. The C-Br bond is polar, and the carbon (⊕) is susceptible to attack by an anion or any other nucleophile. ӨOH is the nucleophile (species which “loves nuclei” or has an affinity for positive charges). BrӨ is the leaving group 2 ALKYL HALIDES – Substitution reactions CH3-CH2—Br + ӨOH CH3-CH2—OH + BrӨ The general reaction is: R-X + NuӨ R-Nu + XӨ These are ionic reactions. There are two possible ionic mechanisms for nucleophilic substitution, SN1 and SN2. S – substitution; N – nucleophilic; 1 – unimolecular (the rate determining, r.d.s., step entails one molecule); 2 – bimolecular (the rate determining step entails two species). 3 ALKYL HALIDES The unimolecular (SN1) reaction R X (a) R + X In the first step, R-X dissociates, forming a carbocation, R⊕, and the leaving group XӨ. This is a slow, rate determining step (r.d.s.) and entails only one species, R-X. (b) R⊕+ NuӨ R-Nu In the second step the carbocation and the nucleophile combine. This occurs rapidly. The overall reaction is R-X + NuӨ R-Nu + XӨ The rate of the reaction = k[R-X] 4 ALKYL HALIDES: The bimolecular (SN2) reaction (a) NuӨ + R-X ⇋ ӨNu---R---XӨ The nucleophile and the alkyl halide combine to form a pentacoordinate transition state. This is the slow rate determining step (r.d.s); it entails two species, R-X and NuӨ . The dotted lines indicate partially formed or partially broken covalent bonds. (b) ӨNu---R---XӨ Nu-R + XӨ The pentacoordinate transition state dissociates to form the product, Nu-R, and the halide ion (the leaving group). The rate of the reaction = k[R-X][NuӨ] The rate is dependent of the concentration of two species; higher concentrations increase the frequency of molecular collisions. 5 ALKYL HALIDES The unimolecular (SN1) reaction R X (a) R + X In the first step, R-X dissociates, forming a carbocation, R⊕, and the leaving group XӨ. This is a slow, rate determining step (r.d.s.) and entails only one species, R-X. (b) R⊕+ NuӨ R-Nu In the second step the carbocation and the nucleophile combine. This occurs rapidly. The overall reaction is R-X + NuӨ R-Nu + XӨ The rate of the reaction = k[R-X] 6 ALKYL HALIDES: SN1 reactions in more detail (a) 2-bromo-2-methylpropane, a 3o alkyl halide dissociates, in a slow r.d.s. to a 3o carbocation and BrӨ. Br CH3 CH3 C CH3 C CH3 CH3 + Br CH3 The positively charged carbon in a carbocation is sp2 hybridized and carbocations have trigonal geometry. This is a very important point. (b) A nucleophile, ӨOH, adds to the carbocation to give the product, 2-methylpropanol. This is a fast process. OH CH3 C CH3 CH3 OH CH3 C CH3 CH3 7 The Stereochemistry of SN1 Reactions A 3o alkyl halide with three different alkyl groups X attached to the head carbon is chiral. R1 There are two enantiomers of such a compound, e.g. 3-bromo-3-methylhexane. (1) Br (2) CH3CH2CH2 C C* R3 R2 (1) Br (4) CH3 CH2CH3 (3) (S)-enantiomer (3) CH3CH2 C (4) CH3 (2) CH2CH2CH3 (R)-enantiomer 8 The Stereochemistry of SN1 Reactions Br CH3CH2CH2 C CH3CH2CH2 C CH3 CH3 + Br CH2CH3 CH2CH3 CH3 Pr (S)-enantiomer C Et CH3 Et C Pr 9 The Stereochemistry of SN1 Reactions The initially formed carbocation is planar. Br CH3CH2CH2 C CH3CH2CH2 C CH3 CH3 + Br CH2CH3 CH2CH3 (S)-enantiomer In the second step, the nucleophile will add from either face of the carbocation. OH OH Pr C Et CH3 Et + OH CH3CH2CH2 C CH3 CH2CH3 (S)-enantiomer C Pr CH3 + OH CH3CH2 C CH3 CH2CH2CH3 (R)-enantiomer Both enantiomers of the product are formed in equal amounts. The same result is obtained starting with the R enantiomer of the alkyl halide, because exactly the same carbocation is formed. 10 Other Aspects of SN1 Reactions X (a) R1 C R3 2 R 1 R slow R3 C + R2 carbocation X R1 (b) Nu R3 C R2 fast Nu R1 C R3 R2 The most important feature of SN1 reactions is the carbocation intermediate. A. Alkyl halides which form stable carbocations will undergo SN1 reactions. 3o alkyl halides form 3o carbocations (stable) and will undergo SN1 reactions. 11 Other Aspects of SN1 Reactions X (a) R1 C R3 2 R 1 R slow R3 C + R2 carbocation X R1 (b) Nu R3 C R2 fast Nu R1 C R3 R2 Alkyl halides which form stable carbocations will undergo SN1 reactions. 2o alkyl halides form 2o carbocations (fairly stable) and undergo SN1reactions. 1o carbocations are unstable, 1o alkyl halides will not undergo SN1 reactions. Substitution reactions of 1o alkyl halides proceed via the SN2 mechanism. 12 Other Aspects of SN1 Reactions B. The RATE of SN1 reactions increases with increasing stability of the carbocation. OH Br 1. CH3 C CH3 slow CH3 C CH3 OH CH3 fast CH3 C CH3 CH3 CH3 3o carbocation + Br OH Br 2. CH3 C CH3 H slow CH3 C OH CH3 fast H CH3 C CH3 H 2o carbocation + Br The carbocation formed in reaction 1 is more stable than that formed in reaction 2, reaction 1 is faster than reaction 2. 13 Other Aspects of SN1 Reactions C. Polar solvents STABILIZE carbocations, and accelerate SN1 reactions. The first step of an SN1 reaction is R X R + X If R⊕ is stabilized via interactions with the solvent, the equilibrium is pulled to the RIGHT, and the overall process is accelerated. The DIELECTRIC CONSTANT (, “epsilon”) is an index of solvent polarity. H2O ( 79) is a polar, protic solvent. CH3CH2OH (ethanol, 25) is also protic, but much less polar than H2O. 14 Other Aspects of SN1 Reactions C. Polar solvents STABILIZE carbocations, and accelerate SN1 reactions. R X R + X H2O ( 79) interacts with R⊕ and XӨ as shown here. The rate of an SN1 reaction of (CH3)3C-Br in pure H2O ( 79) is approximately 12,000 times the rate in pure CH3CH2OH (ethanol, 25). 15 Other Aspects of SN1 Reactions When some 2o alkyl halides undergo the SN1 reaction, products of rearrangement are observed. D. Br CH3 CH3 slow, r.d.s. CH3 C CH3 C H CH3 C CH3 C CH3 H CH3 + Br 2o carbocation CH3 CH3 C CH3 CH3 CH3 CH CH3 + CH3OH 2o carbocation CH3 (CH3 shift) H C H + CH3OH CH3 3o carbocation -H CH3 C CH3 C H OCH3 CH3 CH CH3 yield 4% OCH3 CH3 CH3 C CH3 C H CH3 3o carbocation 3-methoxy-2,2-dimethyl... CH3 C CH3 C -H CH3 CH3 rearrangement 2o carbocation CH3 CH3 C CH3 C CH3 2-methoxy-2,3-dimethyl... yield 41% 16 ALKYL HALIDES: The bimolecular (SN2) reaction (a) NuӨ + R-X ⇋ ӨNu---R---XӨ The nucleophile and the alkyl halide combine to form a pentacoordinate transition state. This is the slow rate determining step (r.d.s); it entails two species, R-X and NuӨ . The dotted lines indicate partially formed or partially broken covalent bonds. (b) ӨNu---R---XӨ Nu-R + XӨ The pentacoordinate transition state dissociates to form the product, Nu-R, and the halide ion (the leaving group). The rate of the reaction = k[R-X][NuӨ] The rate is dependent of the concentration of two species; higher concentrations increase the frequency of molecular collisions. 17 The Stereochemistry of SN2 Reactions (a) NuӨ + R-X ⇋ ӨNu---R---XӨ (slow, r.d.s) (b) ӨNu---R---XӨ Nu-R + XӨ (fast) Let us consider a chiral substrate undergoing an SN2 reaction. (2) CH3 (4) H C Br (1) D (3) (S)-1-bromo-1deuterioethane 18 The Stereochemistry of SN2 Reactions CH3 H HO C + Br slow, r.d.s H HO CH3 C Br (nucleophile) D (S)-1-bromo-1deuterioethane H HO CH3 C D Br D fast (2) (4) CH 3 H HO (1) C D (3) (R)-1-deuterioethanol 19 The Stereochemistry of SN2 Reactions NuӨ + R-X ⇋ ӨNu---R---XӨ (slow, r.d.s) ӨNu---R---XӨ Nu-R + XӨ (fast) (a) (b) CH3 H HO + C Br slow, r.d.s H HO CH3 C Br (nucleophile) D (S)-1-bromo-1-deuterioethane D The pentacoordinate transition state formed at the end of the first, slow, rate-determining step is a trigonal bipyramid: a three-sided plane perpendicular to the screen; the OH and Br groups form apices on either side of the pentacoordinate carbon, in the plane of the screen. 20 The Stereochemistry of SN2 Reactions The nucleophile attacks the substrate from the side opposite to the leaving group. The stereochemistry of the product is INVERTED, relative to that of the starting material. D H HO C + D Br slow, r.d.s H HO C Br (nucleophile) CH3 (R)-1-bromo-1-deuterioethane D H fast Br HO C H3C H3C (3) D (4) H HO (1) C CH (2) 3 (S)-1-deuterioethanol 21 The Stereochemistry of SN2 Reactions For chiral substrates, reactions proceeding via the SN2 mechanism result in inversion of configuration. This is a consequence of the “back side” attack by the nucleophile. CH3 H HO C + Br slow, r.d.s H HO CH3 C Br (nucleophile) D (S)-1-bromo-1deuterioethane H HO CH3 C D Br D fast (2) (4) CH 3 H HO (1) C D (3) (R)-1-deuterioethanol 22 Other Aspects of SN2 Reactions SUBSTRATE The SN2 reaction involves a transition state with pentacoordinate carbon, so sterically hindered alkyl halides do not react via this mechanism. The RATE of the SN2 reaction for the following substrates therefore follow the trend: CH3 Br > CH3CH2 Br >> CH3 CH3 CH Br Tertiary alkyl halides do not undergo the SN2 reaction. 23 Other Aspects of SN2 Reactions NUCLEOPHILE The SN2 reaction is bimolecular, and more effective nucleophiles will react faster. Order of nucleophilicity: ӨCN > ӨOR > ӨOH. Therefore, CH3Br + ӨCN CH3CN + Br Ө is a faster reaction than CH3Br + ӨOR CH3OR + Br Ө , and this in turn is faster than CH3Br + ӨOH CH3OH+ Br Ө . 24 Other Aspects of SN2 Reactions POSSIBILITY OF REARRANGEMENT When an alkyl halide undergoes substitution via the SN2 mechanism, the product has the same carbon skeleton as the starting material. No rearrangement takes place. 25 Other Aspects of SN2 Reactions SOLVENT The rate of SN2 reactions (involving negatively charged nucleophiles) increases when the reactions are carried out in polar APROTIC solvents. Dimethyl sulfoxide (DMSO, 37) is an example of a polar aprotic solvent. CH3 S O CH3 26 Other Aspects of SN2 Reactions SOLVENT: Dimethyl sulfoxide (DMSO, 37) is an CH3 example of a polar aprotic solvent. S O CH3 If, for example, the nucleophile is ӨCN, and the source is KCN (potassium cyanide) DMSO will solvate the K⊕ ion, thus making ӨCN readily available for reaction. 27