3.91
2 XI3 + 3 Cl2  2 XCl3 + 3 I2
(0.5000g)
ANALOGY: If you had
$126.90 which I take, then
I give you back $35.45,
you have lost 72.07% of
your money, or have 27%!
(0.2360)
1)The compound lost 0.2640g of mass as Cl swaps out the iodine. This
mass represents the differential between the atomic molar mass if iodine
and Cl.
2) The ratio of atomic masses is 35.445/126.90 = 0.2793, indicating that Cl
is 27.93% as massive as I.
3) The mass difference 0.2640g represents mass lost as iodine swapped
out, this equals 0.7207 (72.07% the mass of the original I in XI3).
4) The total mass of iodine in XI3 is
0.7207 =
1
0.2640 g
mass
= 0.3663 g I in XI3
1)The compound lost 0.2640g of mass as Cl swaps out the iodine. This
mass represents the differential between the atomic molar mass of iodine
and Cl.
2) The ratio of atomic masses is 35.445/126.90 = 0.2793, indicating that Cl
is 27.93% as massive as I.
3) The mass difference 0.2640g represents mass lost as iodine swapped
out, this equals 0.7207 (72.07% the mass of the original I in XI3).
4) The total mass of iodine in XI3 is
0.7207 =
1
0.2640 g
mass
= 0.3663 g I in XI3
5) The sample was 0.5000g – 0.3663 g = 0.1337g of X
6) 0.3663 g I / 126.99 g/mol = 0.002887 mol of I in XI3 therefore x is
.000961mol X
7) 0.1337 g X/ .000961 mol X = 139.0 g/mol, La.