Chemistry 1201 Section 4
Professor Russo
Spring 1999
Exam #9
Type of exam: In class. You can use your cheat sheet and a calculator. In most cases,
vital constants and conversion factors are supplied. If you cannot see the periodic table
from where you are seated, ask one of the proctors to provide you a periodic table.
Covers: Chapter 2 & 3. Problems are modifications of the take-home exams or other
assigned problems.
Duration: 30 minutes.
Value: 50 points. Each question is 10 points. Remember….you are trying to earn 700
points on all in-class and take-home exams. After this, we will have had 850 total
possible points.
Instructions: Mark your answers on a LARGE scantron using a #2 pencil. Be sure to
write and bubble in your name and student ID number! Fill out the scantron just
before turning it in. You should mark the right answers directly on this exam until you
are sure you have the answer you wish to select.
Correct Answers: Will show immediately after exam. So stick around if you finish
early!
________________________________________________________________________
Question #1. (Similar to BLB 2.43) The proper name for the anion ClO4- is:
a) Chlorate
b) Perchlorate
c) Chlorite
d) Hypochlorite
Question #2. (Similar to BLB 3.4) After you balance it, using no fractions, the
stoichiometric coefficient in front of O2 for the reaction below is:
_______C7H14 + _______O2  _______CO2 + _______H2O
a)
b)
c)
d)
e)
7
15
21
24
28
Chem 1201 Sec. 4
Exam 9
Page 1
Question #3. (BLB 3.70 & TakeHome Exam 8) How many grams of carbon dioxide
can form when a mixture of 3.43 g ethylene (C2H4) and 1.73 g of oxygen is ignited,
assuming complete combustion to form carbon dioxide and water? You should use
"round numbers" for atomic weights --e.g., use 12 for C, not 12.01.
a) 0.054 g
b) 1.59 g
c) 10.8 g
d) 2.38 g
e) 0.52 g
Question #4. (BLB 3.70 & TakeHome Exam 8) In the previous problem, how much
water will be produced?
a) 0.649 g
b) 0.218 g
c) 4.42 g
d) 2.21 g
e) 0.974 g
Chem 1201 Sec. 4
Exam 9
Page 2
Question #5. (BLB 3.47) Determine the molecular formula for ethylene glycol (the
stuff used in antifreeze) which is 38.7 %C, 9.7 % H and 51.6 % O by mass. It has a
molar mass of about 62.1 g/mol.
a) CH3O
b) C3H10O3
c) C2H6O2
d) C4H8O
Chem 1201 Sec. 4
Exam 9
Page 3