Chapter 7 Review, pages 358–363 Knowledge 1. d 2. a 3. d 4. a 5. d 6. b 7. a 8. c 9. b 10. b 11. a 12. c 13. c 14. c 15. c 16. b 17. True 18. False. During the formation of a polypeptide, mRNA is transcribed from the DNA, exits the nucleus, and is translated on a ribosome to tRNA molecules, which carry the amino acids to form the polypeptide. 19. False. RNA polymerase does not require a primer when making a complementary strand. 20. False. rRNA binds with proteins to form ribosomes. 21. False. Eukaryotes use spliceosomes to remove introns during post-transcriptional modification. 22. False. The process of alternative splicing results in different combinations of introns being removed to synthesize multiple proteins from the one gene. 23. True 24. True 25. False. The formation of proteins is slower in eukaryotes than in prokaryotes because polysomes cannot form in the nucleus, with no coupling of transcription and translation. 26. True 27. False. The trp repressor is activated by high concentrations of tryptophan. 28. False. When lactose is absent, the lac repressor is active and binds to the operator. 29. True 30. False. Silent mutations insert, delete, or change base(s) and have no effect on the protein. 31. False. Pseudogenes are mutated vestigial genes that have lost their evolutionary adaptive value. 32. True 33. (a) iv (b) iii (c) i (d) vi (e) v (f) ii Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-2 34. (a) iii (b) iv (c) vi (d) ii (e) i (f) v 35. The amino acid sequence that corresponds to the DNA template strand 5'-GTTGATTTTCGC-3' is valine, aspartic acid, phenylalanine, and arginine. 36. Answers may vary. Students’ answers should include three of the following sequences: GGTCATATT; GGTCATATC; GGTCATATA; GGTCACATT; GGTCACATC; GGTCACATA; GGCCATATC; GGCCATATA; GGCCACATT; GGCCACATC; GGCCACATA; GGACATATC; GGACATATA; GGACACATT; GGACACATC; GGACACATA; GGGCATATC; GGGCATATA; GGGCACATT; GGGCACATC; GGGCACATA. 37. Alternative spicing refers to the process in which multiple mRNAs are produced from the parent pre-mRNA. In humans this accounts for the larger number of proteins produced from a smaller number of genes. 38. snRNPs combine with pre-mRNA and proteins to form spliceosomes that excise introns from pre-mRNA to form mRNA molecules. 39. The purpose of aminoacylation is to charge the tRNA with its amino acid. 40. There are several advantages that prokaryotes have over eukaryotes in protein synthesis, including that transcription and translation can occur in the same location; no 5′ cap must be added; prokaryotes have a higher rate of protein synthesis; and polysomes can transcribe almost simultaneously with transcription. 41. The effects of the poly(A) tail include increased translation time. 42. It is important for cells to regulate genes because transcription and translation of genes are metabolically expensive. In many cases, other than housekeeping genes, protein synthesis only needs to occur for short periods of time or under specific conditions. Gene regulation prevents the over- or under-transcription and translation of genes when they are not required. 43. The mRNA codons UAA, UGA, and UAG are stop codons that signal the end of a polypeptide chain and cause the ribosome to terminate translation. 44. The types of mutagens are: chemical (for example, ethidium bromide), radiation (for example, exposure to x-rays), and viral (for example, viruses cause some cancers). 45. Scientists believe these sequences help protect the DNA from damage and the shortfalls of DNA replication. 46. The genomic structures found in viruses are single-stranded DNA, single-stranded RNA, double-stranded DNA, and double-stranded RNA. Understanding 47. You can conclude that this is RNA because it contains uracil. The nucleic acid is a singlestranded molecule because the bases do not have equal concentrations and the ratios of A:U and C:G are not equivalent as you would find in a double-stranded molecule. 48. Garrod’s work with alkaptonuria helped him understand that there is a specific relationship between genes and metabolism. He found that alkaptonuria was an “inborn error of metabolism.” Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-3 49. 50. The amino acid sequence Arg-Leu-Ser is a good example of the wobble hypothesis because each of the amino acids is coded for by six different codons. Mathematically, a total of 216 (6 × 6 × 6) different sequences of nucleotides could code for this short sequence. Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-4 51. 52. The longer 70 kbp gene belongs to the eukaryotic organism. It is longer because it contains introns, unique to eukaryotic organisms, which are not found in the 20 kbp prokaryotic version of the gene. Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-5 53. A code could be sent by associating groups of RNA nucleotides with letters and symbols. The message could be inserted into a host genome and lay dormant, controlled using a specific nutrient “key” that would induce mRNA synthesis, which could be sequenced and analyzed. 54. Alternative splicing is a mechanism that enables eukaryotes to synthesize more than one protein per gene by modifying the splicing of exons. This is an important feature that increases protein variation by enabling more than one protein to be synthesized for each gene. 55. The A site is the location where the tRNA enters the ribosome with an amino acid. The P site is the site in the middle of the ribosome where amino acid from the A site is joined to the amino acid chain. The E site is the location where the tRNA is released after it has released its amino acid to the growing peptide chain. 56. Peptide elongation cannot occur while erythromycin blocks ribosomal translocation. Any peptide that was being synthesized prior to the administration of the drug would be locked into the ribosome since the A site could not advance and eject the de-acylated tRNA. 57. Table 1 C G A A T T A C C DNA template strand G C T T A A T G G DNA other strand G C U U A A U G G mRNA C G A A U U A C C tRNA Alanine Stop Trp amino codon acids Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-6 58. 59. It is believed that the post-translational modification by the addition of ubiquitin helps cells mark proteins that require degradation. Ubiquitin is seen as a marker to aid the cellular machinery in the degradation of proteins. 60. Answers may vary. Sample answer: Most mutation are not harmful; many are silent mutations. Additionally, the wobble hypothesis allows for some variation in the genetic code, which allows for some base-pair substitutions in the DNA that will not correspond to a change in the amino acid. Many mutations that do have effects allow organisms to adapt to their environment. Most traits could be defined as mutations. 61. Non-coding sequences are no longer referred to as referred to as “junk” DNA because of the role they play in epigenetic regulation. Non-coding sequences play different roles in epigenetics by modifying gene expression in different ways. Telomeres protect the important coding regions. Transposable elements have the ability to recruit silencing machinery, single genes, and large chromosomal regions. Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-7 62. Answers may vary. Sample answer: 63. Retro virus replication process: Retro virus injects RNA into cell. Reverse transcriptase copies viral RNA making complementary DNA. Reverse transcriptase synthesizes second DNA complement to first strand. Integrase incorporates new DNA into host cell. Host now transcribes viral RNA and translates it into viral proteins. Analysis and Application 64. (a) Students should use the formula yn ≥ number of amino acids, where n = number of nucleotides per codon, y = total number number of nucleotides, in this case,6n ≥ 180. One solution is to simply substitute 1, 2, 3... for n. There must be a minimum of 3 nucleotides per codon and 63 = 216 combinations. (b) Students should use the formula yn ≥ number of amino acids, where n = number of nucleotides per codon, y = total number number of nucleotides, in this case,6n ≥ 356. A simple substitution shows at least 4 nucleotides per codon are required. 65. During RNA transcription, mRNA does not bind to template DNA. mRNA is produced at many initiation points along a template strand, serves to produce a template RNA and is short term. During DNA replication, DNA polymerase synthesizes DNA, a primer is required to initiate synthesis, and DNA replication continues until it runs out of DNA on a strand. DNA replication follows helicase as it unwinds the double helix. 66. Table 2 Number of Number of Number of exons introns possible genes 5 1 5 5 2 20 5 3 60 5 4 120 Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-8 67. The sample that unwinds at 60 °C more likely contains the promoter, as it unwinds at a lower temperature. This is because the promoter region contains the TATA box and has a larger concentration of adenine and thiamine. Adenine and thiamine share only two hydrogen bonds versus the three in guanine and cytosine. The smaller number of hydrogen bonds requires less energy to break and break at lower temperatures. 68. During treatment A the fluorescent label would be present throughout the cell in the cytosol as free uracil and incorporated into the various RNA structures, for example, mRNA, tRNA, and rRNA. During treatment B the fluorescent label would only be localized in RNA structures still active in the cell, for example, mRNA, rRNA, and tRNA, and will not be freely distributed in the cytosol or the nucleus. 69. When tetracycline associates with the ribosome and prevents the aminoacyl-tRNA from binding to the ribosome, no proteins can be produced. This prevents the cell from performing most metabolic processes, thus the infecting organism dies. 70. Answers may vary. Sample answer: Since there are 20 amino acids, there should be at least 20 tRNA. The wobble hypothesis suggests that more tRNA are available, allowing the third base to change (wobble) while allowing the codon to still code for a particular amino acid. 71. (a) The three stop codons tRNA sequences do not code for any amino acid. (b) Answers may vary. Sample answer: To determine their function you could perform an experiment that places the stop codon immediately after the start codon or in the middle of a gene. Your expected result would be methionine only or a shorter protein than usual for that gene. 72. Answers may vary. Sample answer: Gene regulation in eukaryotes is performed by several different mechanisms during transcription, post-transcription, translation, and post-translation, including the control of transcription and the rate of transcription, promoters, alternative exon and intron splicing, and post-translation regulation of protein functionality. Prokaryotes use only the operon system in which certain proteins can turn off the transcription of a gene or a group of genes. 73. This is a silent mutation; it does not affect expression of the gene. The substitution of cytosine with thymine yields the same amino acid threonine before and after the mutation. 74. The inversion mutation would result in the following sequence: 5′-GGT AAT CGG ACA-3′. The original polypeptide would be Cys-Pro-Iso-Thr while the new sequence would be Pro-Leu-Ala-Cys. Depending on the protein, this could have a range of effects from none to serious. 75. Answers may vary. Sample answer: In drug manufacturing the next important pharmaceutical step is gene therapy. The guidelines that the Government of Canada adopts should allow companies to patent therapeutic genes and vectors that will be used in treatment of numerous genetic related disorders. Evaluation 76. (a) This statement refers to the wobble hypothesis, or redundancy, in which the third codon can vary and still produce the desired amino acid. (b) The total number of sense codons is 61. The ratio of sense codons that have synonyms to sense codons that do not is 59:2. (c) Degeneracy protects a cell from mutations by allowing for a change in one of the nitrogenous bases in a codon, without changing the amino acid that is built from that codon. Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-9 (d) Answers will vary but should focus on testing a non-variant line versus a normal population. For example: How would a viral infection affect a population of genetic clones versus a wild type population? 77. Cyclohexamide only blocks eukaryotic protein synthesis; the mitochondria still manufacture their own proteins. Therefore this protein is being produced by the mitochondria, not the DNA in the nucleus. 78. (a) The insulin is not being synthesized because the human insulin gene has been inserted into a prokaryote. The protein is too long as the prokaryote will include both introns and exons that are normally excised after the formation of pre-mRNA in a eukaryote prior to the formation of mRNA. (b) In order for the process to work, the gene must have the introns removed so that the gene only contains exons prior to insertion into the E. coli. 79. Gene regulation, either through environmental or internal mechanisms, plays an important part in transcription and translation, which ultimately determines not only which genes are read but also the duration and frequency. In this way your body’s internal environment and your external environment can cause genes to be turned on and off. Since you are made of proteins this makes you a product of your environment. 80. The promoter region, shown as the rectangle, occurs on the 3' side of the start of translation. The mRNA is synthesised in a 5' to 3' direction and the transcription is stopped at the terminator region on the 5' side of the start of translation on the DNA. 81. Since Actinomycin D is claimed to be a transcription inhibitor, you would sample the concentration of mRNA:proteins before and after the administration of the drug. If the claim were true, you would expect to see the mRNA concentration decrease, as they are not transcribed. Initially there may be an increase in protein concentration but only as a result of mRNA synthesized prior to the administration of the medication. 82. (a) Sequence B is from a eukaryote because it is longer and contains introns that the prokaryotic gene does not contain. (b) Sequence A has 3 promoter regions and sequence B has 2 promoter regions, identified by the TATA box. Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-10 (c) There are 3 copies of the gene in sequence A, and 2 copies of the gene in sequence B. Example: Sequence A: 5'GCAGGCCATATAAAATAGCGCCATACTAGATACGGGCCATATTATTGCATATCCGCCG ATTACAGGATTTAATTTGGGAATTCCCCGATTAACGCGATCGATCGGGCCATATCGAT ATGCATCGTAATCCGGTAGATTCACAGGTAG-3'; Sequence B: 5'GCATACCCAAATTAATAACGGCGGTAGGCGACTCATTCTGATATACGCATCGGCATTT ACCTACGGCCGGCCGGCCGGCCGGCCTAGATTTACCGCATTTACCGGCCGCATCGGA TCGGGATTAGCATAATTAAAATGCATCGGCGTAGTAGGCAATCGGCGCAGCCGAGC CACCTCCCGGAGAATCATCTCATCATCATCATCATCATCATCATCATCATCATACGG ATAGATCCATTACCATGCGATTTAAAGGCCATTCATGGGCCCCCGATTTATCCATTT AGGCCGGATTCCATGGATTCATTTCCATTTTTCGGCATCATCATCATCATCATCATCA TCATCA TCATCATCATCATCATCAT-3'. 83. (a) Individual A has a frame shift mutation because of a T deletion. (b) Individual B has a silent mutation, as the substitution of A for G did not affect the amino acid sequence. (c) Individual C has had a frameshift mutation caused by the removal of the ATA codon and the addition of extra nucleotides GCTA. 84. Answers may vary. Answers should include some of the following information: In support of continued sale: adults have the freedom to choose and information about the risks is easily available. It also brings in tax dollars. By selling these products legally you reduce the price and increase access, eliminating a great deal of crime. Alcohol has been shown to have health benefits in reducing the effects of stress and lowering blood pressure. Refuting of continued sale: the health effects cause lost productivity and take resources out of the health care system. The sale of these products results in a great deal of criminal activity and lost police time for their enforcement. Reflect on Your Learning 85. Answers may vary. Sample answer: Though genes do code for enzymes, a better statement would have been genes code for proteins and enzymes are a type of proteins. Although the statement is true, it is not accurate, since not all proteins are enzymes. 86. Answers may vary. Sample answer: This information makes me realize that science is about the question, and sometimes an experiment can point you in the direction of an answer but not directly produce an answer. In both these situations their experiments were designed to show the existence of an answer, but not necessarily solve the puzzle. 87. Answers may vary. Answers should show insight into the students’ knowledge and understanding of genetics. Students should give examples of concepts that they used to understand different mechanisms of genetic maintenance. They should reflect on how this knowledge alters their perspective of life in general. 88. Answers may vary. Answers should focus on the knowledge that each cell type has specific machinery that can be interfered with. This machinery is cell specific and medicines are designed to only interfere with these specific pathways. 89. Answers may vary. Answers should focus on viral structure, reproductive methods, and genetic makeup. Humans have learned a great deal about our cellular machinery as a result of working on the genetically simple virus genome. Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-11 Research 90. (a) The “RNA world” hypothesis is supported by the fact that RNA can act as both a gene and an enzyme. There have been in vitro studies that have shown self-contained spontaneously replicating systems composed entirely of RNA. The absence of this quality in DNA and proteins suggests RNA existed first. (b) Sequences of RNA can form polymers that can process complex tertiary structures that allow them to act as an enzyme and catalyze the formation of RNA polymers. (c) This hypothesis suggests that life on earth was started with simple RNA interactions and then associated into proteins to form virus-type molecules and then more complex membrane bound organisms. 91. (a) Answers may vary. Answers should show that eukaryotic ribosomes are larger than prokaryotic ribosomes and use different proteins in their structures. Sample answer: Table 3 Prokaryotic ribosomes Eukaryotic ribosomes 50S 30S 60S 40S Subunits 23S (2900) 16S (1540) 28S (4800) 18S (1900) rRNA 5.8S (160) species (and 5S (120) 5S (120) number of bases) L1, L2, L3 S1, S2, S3 L1, L2, L3 S1, S2, S3 Proteins (total: 31) (total: 21) (total: 50) (total): 33) bind with rRNA (b) Erythromycin disrupts bacterial ribosomes by binding to the 23S rRNA molecule of the bacterial ribosome blocking the exit of the growing peptide chain. 92. Answers may vary. Projects should include information about the ability of bacteria to become resistant to antibiotics. Students should relate the use of antibiotics to the resistant bacteria. Viruses cannot be stopped with typical antibiotics. However, some antiviral drugs exist and act to inhibit certain viral proteins or to mask viral genetic material. 93. Answers may vary. Answers should include information about how vaccines work and difficulties faced with HIV. Most vaccines stimulate immunologic memory without blocking the actual infection. Most successful vaccines induce potent antibody production. Viruses are hard to develop because the HIV virus has a high rate of mutation and a population that is polymorphic. 94. (a) Answers may vary. Sample answer: Genetically engineered bacteria might displace naturally occurring bacteria, altering the present ecosystem. (b) Answers may vary. Answers should include information about the safety of transgenic food and the potential movement of genetic information from the modified species into the natural population. (c) Answers may vary. Sample answer: Legislation should require labeling indicating how a food is genetically modified. Some students could take this further and suggest that legislation about the farmers and processes with which the food is grown should be more secure and monitored. Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-12 95. (a) The epigenome is the expression of genes based on their environment. (b) MVPs are used to examine gene activity, tissue type, and health and are used as a measure of epigenetics. (c) Scientists use MVPs because they alter the structure of the DNA and this causes changes to the expression of proteins. Scientists can then examine the alterations in structure to infer evolutionary patterns. (d) Answers may vary. Pamphlets should discuss how the degree of methylation is thought to be a measure of the healthiness of a genome. In general, cells that are highly methylated tend to be at a higher risk of forming cancers or having embedded viral DNA components. 96. Answers may vary. Answers should mention that UV radiation can cause mutations in genetic material, which can result in aging and diseases like cancer. Students should include an explanation of UV radiation and why tanning beds cause similar damage to that caused by the Sun. Copyright © 2012 Nelson Education Ltd. Chapter 7: Genes and Protein Synthesis 7-13