SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-21 The General Second-Order System • Two important quantities that describes the response of second order systems: o Natural frequency, ωn : The frequency of oscillation of the system without damping. o Damping ratio, ζ : Parameter that describes the damped oscillations of the 2nd order response. Bigger, means more ‘damped’ response, i.e. less oscillations. ζ = = Exponential decay frequency Natural frequency (rad/second ) 1 Natural period (seconds) 2π Exponential time sonstant • Define general 2nd order response in terms of ωn and ζ as: • Hence the pole is given as: ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-22 • Four time responses based on ζ : ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI Example: Given the 4-23 transfer function ωn 2 G(s) = 2 , find ζ and ωn . 2 s + 2ζω n s + ωn Example: Find the value of ζ , and sketch the kind of response expected. ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-24 Underdamped Second-Order Systems • A common model for physical problems. • A detailed description of the underdamped response is necessary for both analysis and design. ωn 2 C ( s) = s ( s 2 + 2ζω n s + ωn 2 ) = K 2 s + K3 K1 + 2 , ζ <1 2 s s + 2ζω n s + ωn 1 = − s ( s + ζω n ) + ζ 1−ζ 2 ω 1 − ζ n 2 ( s + ζω n ) 2 + ωn 2 1 − ζ 2 • Taking the inverse Laplace transform, c(t ) = 1 − e ⎛ −ζω n t ⎜ ⎜ ⎝ 2 cos ωn 1 − ζ t + ζ 1−ζ 2 sin ωn ⎞ 1−ζ t ⎟ ⎟ ⎠ 2 ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-25 • plot of c(t) • Less ζ implies more oscillation. ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI Second order specifications underdamped 4-26 response • Peak time, Tp: The time required to reach the first, or maximum, peak. ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-27 • Percent overshoot, %OS: The amount that the response overshoots the final value at the peak time, expressed as a percentage of the steady-state value. • We can also find the inverse of the equation allowing us to find ζ given %OS. • Relationship between ζ and %OS can be used: ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-28 • Rise time, Tr: The time required for the response to go from 0.1 to 0.9 of the final value. • Relationship between Trωn and ζ can be used. • Settling time, TS: The time required for the response to reach and stays within ± 2% of the steady-state value/final value. ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-29 Example: Given a transfer function, G ( s ) = Tp, %OS, TS, and Tr. 100 2 s + 15s + 100 , find ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-30 Relation between Tp, %OS, TS, and Tr to the system poles. • Consider the pole plot for an underdamped secondorder system: • Notice that the distance from the origin to the pole equals ωn. • cos θ = − ζω n ωn =ζ . • Before we already defined: Tp = π ωn 1 − ζ 2 , TS = 4 ζω n ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-31 • ωd = ωn 1 − ζ 2 is the imaginary part of the pole, called the damped frequency of oscillation. • TP is inversely proportional to the imaginary part of the pole. ⇒ Horizontal lines are lines of constant peak time. • TS is inversely proportional to the magnitude of the real part of the pole. ⇒ Vertical lines are lines of constant settling time. • Radial lines are lines of constant ζ . ⇒ Radial lines are lines of constant %OS. ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-32 • Step responses of second order underdamped systems as pole moves: (a) with constant real part, (b) with constant imaginary part, (c) with constant damping ratio. ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-33 Example: Given the pole plot shown, find ζ , ω n , Tp, %OS, and TS. ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-34 Example: For the system shown, find J and D to yield 20% overshoot and a settling time of 2 seconds for a step input of torque T(t). ZHI SEE 2113 KAWALAN: PEMODELAN DAN SIMULASI 4-35 Example: For the unit step response shown, find the transfer function of the system. ZHI