THE EINSTEIN–YANG–MILLS EQUATIONS IN GAUGE SPACES OF ORDER k ∗ IRENA ČOMIĆ † Faculty of Technical Sciences, University of Novi Sad, Trg D. Obradovića 6, 21000 Novi Sad, SERBIA E-mail: comirena@uns.ns.ac.yu In the (k + 1)n dimensional space P , where the transformation group is given by 0 0 0 0 0 0 y 0a = y 0a (y 0a ), y 1a = y 1a (y 0a , y 1a ), . . . , y ka = y ka (y 0a , y 1a , . . . , y ka ) the adapted basis in tangent and its dual space is constructed. The Einstein-YangMills equations which give the extreme value of integral of action Z √ I(φ) = gL(φ, ∂0a φ, ∂1a φ, . . . , ∂ka φ)dω Ω (L is Lagrangian, g is the determinant of the metric tensor) are determined. They are similar to those obtained from Gh. Munteanu in [22]. 1. Natural and adapted bases Let P be a (k + 1)n dimensional C ∞ manifold in which some point p in local chart (U, ϕ) has coordinates (y 0a , y 1a , y 2a , . . . , y ka ) = (y Aa ) A, B, C, D, E, . . . = 0, 1, 2, . . . , k, a, b, c, d, e, . . . = 1, 2, . . . , n. (1.1) If in another chart (U 0 , ϕ0 ) the same point p has coordinates 0 0 0 0 (y 0i , y 1i , y 2i , . . . , y ki ), then the allowable coordinate transformations are ∗ MSC 2000: 53B40, 53C60, 53C80, 81T13, 53C07. Keywords: gauge transformations of order k, Einstein–Yang–Mills equations. † This research was partly supported by Science Fund of Serbia, grant number 1262. 119 120 given by 0 0 0 0 0 0 0 0 y 0a = y 0a (y 0a ), y 1a = y 1a (y 0a , y 1a ), (1.2) y 2a = y 2a (y 0a , y 1a , y 2a ), . . . , y ka = y ka (y 0a , y 1a , y 2a , . . . , y ka ). Definition 1.1 The transformations of type (1.2) are called gauge transformations of order k. The natural basis of T ∗ (P ) is B̄ ∗ = {dy 0a , dy 1a , . . . , dy ka }. (1.3) Under the transformations of type (1.2) the elements of B̄ ∗ are transforming in the following way: 0 0 0 0 ka0 ka0 dy 0a = (∂0b y 0a )dy 0b , 0 dy 1a = (∂0b y 1a )dy 0b + (∂1b y 1a )dy 1b , . . . , dy = (∂0b y )dy 0b + (∂1b y ka0 )dy 1b (1.4) + · · · + (∂kb y ka0 kb )dy , where ∂Ab = ∂ , ∂y Ab A = 0, 1, . . . , k. If we introduce the notations: 0a0 dy 1a0 dy Aa0 [dy ] = . , .. dy ka dy 0b dy 1b [dy Bb ] = . , . . 0 (1.5) dy kb 0 ∂0b y 0a 0 ··· 1a0 1a0 ∂ y ∂ y ··· 0b 1b 0 Aa [JBb ] = . .. 0 0 0 0 ∂0b y ka ∂1b y ka · · · ∂kb y ka , (1.6) 0 then (1.4) can be written in the form 0 0 Aa [dy Aa ] = [JBb ][dy Bb ]. (1.7) The elements of the Jacobian matrix are matrices of type n × n. If 0 Aa rank[JBb ] = n(k + 1), (1.8) 121 then exists inverse transformation of (1.2), which is the same type. The identity transformation is the special case of (1.2) and where the composition is defined, the product of two transformations is also of type (1.2). Theorem 1.1 The transformations of type (1.2) form a pseudo-group. The natural basis of T (P ) is B̄ = {∂0a , ∂1a , . . . , ∂ka }. (1.9) The elements of B̄ under transformations of type (1.2) are transforming as follows: 0 0 0 ∂0a = (∂0a y 0b )∂0b0 + (∂0a y 1b )∂1b0 + . . . + (∂0a y kb )∂kb0 , 0 0 (∂1a y 1b )∂1b0 + · · · + (∂1a y kb )∂kb0 , . . . , ∂1a = (1.10) 0 (∂ka y kb )∂kb0 . ∂ka = If we use the notations [∂Aa ] = [∂0a ∂1a . . . ∂ka ], [∂Bb0 ] = [∂0b0 ∂1b0 . . . ∂kb0 ], (1.11) then (1.10) can be written in the form: 0 Bb [∂Aa ] = [∂Bb0 ][JAa ]. (1.12) Remark 1.1 The transformations of type (1.2) are more general as those in Osck M . The allowable transformations in Osck M are the special cases of (1.2). The relations 0 0 0 ∂y 0a ∂y 1a ∂y ka = = · · · = , ∂y 0a ∂y 1a ∂y ka 0 ∂y (A+B)a = ∂y Ba (1.13) µ ¶ 0 A + B ∂y Aa , B ∂y 0a which are valid in Osck M ([6], [7]) in P are not valid in general case. We shall construct the adapted basis B ∗ = {δy 0a , δy 1a , δy 2a , . . . , δy ka } (1.14) of T ∗ (P ) in the following way: δy 0a = dy 0a , 1a δy 1a = dy 1a + M0b dy 0b , 2a 2a dy 0b , . . . , dy 1b + M0b δy 2a = dy 2a + M1b ka ka dy 0b . δy ka = dy ka + M(k−1)b dy (k−1)b + · · · + M0b (1.15) 122 If we introduce the notations a 0a δb 0 0 δy 1a a M δ 0 b 0b δy 1a M 2a M 2a δ a Aa Aa 1b b [MBb ] = 0b [δy ] = . , . .. . . δy ka ka ka ka M0b M1b M2b ··· 0 ··· 0 ··· 0 , (1.16) · · · δba then (1.15) can be written in the form: Aa ][dy Bb ]. [δy Aa ] = [MBb (1.17) Aa MBb in such a way, that the elements of We shall determine the functions ∗ B = {δy 0a , δy 1a , . . . , δy ka } are transforming in the following way: 0 δy Aa0 = Aa0 BAa δy Aa , Aa0 BAa ∂y Aa = , A = 0, 1, . . . , k, ∂y Aa (1.18) no summation over A. Remark 1.2 The transformation (1.18) is more general, then the corresponding formula 0 0 0 δy Aa = Baa δy Aa , 0 Baa = 0 ∂xa ∂y 0a = a ∂x ∂y 0a in T ∗ (Osck M ), because in T ∗ (P ) (1.13) is not necessarily satisfied. We have: Theorem 1.2 The elements of the adapted basis B ∗ of T ∗ (P ) determined Aa by (1.17) satisfy the transformation law (1.18) if the functions MBb are transforming in the following way: 0 0 0 Aa Aa Aa Bb [BAa ][MCc ] = [MBb 0 ][JCc ], (no summation over A) where 0 ∂0a y 0a 0 ··· 1a0 0 ∂ y ··· 1a Aa0 [BAa ]= .. . 0 0 0 · · · ∂ka y ka 0 (1.19) , (1.20) 0 or in the explicite form (A+B)a0 (A+B)a B(A+B)a MAc (A+B)a0 = MAb0 0 (A+B)a0 ∂Ac y Ab + M(A+1)b0 ∂Ac y (A+1)b (A+B)a0 0 0 (1.21) 0 + · · · + M(A+B−1)b0 ∂Ac y (A+B−1)b + ∂Ac y (A+B)a . 123 Proof. Using (1.7), (1.17) and (1.18) we can write: 0 0 0 0 0 Aa Bb Aa Bb Cc [δy Aa ] = [MBb ] = [MBb ], 0 ][dy 0 ][JCc ][dy 0 0 0 Aa Aa Aa [δy Aa ] = [BAa ][δy Aa ] = [BAa ][MCc ][dy Cc ], no summation over A. From the above two equations it follows (1.19). From (1.2) and (1.19) it follows, that (A+B)a MAc (A+B)a = MAc (y 0a , y 1a , y 2a , . . . , y (A+B)a ), for 0 ≤ A ≤ A + B ≤ k. We shall construct the adapted basis B = {δ0a , δ1a , . . . , δka } (1.22) of T (P ) in the following way kb 2b 1b ∂kb , ∂2b − · · · − N0a ∂1b − N0a δ0a = ∂0a − N0a δ1a = kb 2b ∂kb , . . . , ∂2b − · · · − N1a − N1a ∂1a δka = (1.23) ∂ka . If we introduce the notations [δAa ] = [δ0a δ1a . . . δka ], [δAa0 ] = [δ0a0 δ1a0 . . . δka0 ], δab 0 ··· 0 1b −N0a δab · · · 0 −N 2b −N 2b · · · 0 Bb 1a 0a [NAa ] = . .. (1.24) (1.25) kb kb −N1a · · · δab −N0a then (1.23) can be written in the form: Bb [δAa ] = [∂Bb ][NAa ]. (1.26) Bb We shall determine the transformation law of functions NAa under conditions that the elements of B are transforming in the following way: 0 Aa δAa = BAa δAa0 A = 0, 1, 2, . . . , k, (1.27) no summation over A. (1.27) in the matrix form can be written as follows 0 Aa [δAa ] = [δAa0 ][BAa ]. (1.28) 124 We have Theorem 1.3 The elements of the adapted basis B of T (P ) satisfy the Bb are transforming in the transformation law (1.27) if the functions NAa following way: 0 0 0 Cc Aa Cc Bb [NAa 0 ][BAa ] = [JBb ][NAa ], (1.29) or in the explicite form (A+B)a0 (A+B)c0 B(A+B)a NAa0 (A+B)b = NAa 0 ∂(A+B)b y (A+B)c + (A+B−1)b NAa (B+1)b NAa 0 ∂(A+B−1)b y (A+B)c + · · · + 0 (1.30) 0 ∂(B+1)b y (A+B)c − ∂Aa y (A+B)c . Proof. From (1.12) and (1.23) and (1.28) it follows 0 Bb Cc Bb [δAa ] = [∂Bb ][NAa ] = [∂Cc0 ][JBb ][NAa ], 0 0 0 Aa Aa Cc [δAa ] = [δAa0 ][BAa ] = [∂Cc0 ][NAa 0 ][BAa ]. From the above two equations it follows (1.29). From (1.29) and (1.30) we have (A+B)b NAa (A+B)b = NAa (y 0a , y 1a , y 2a , . . . , y (A+B)a ) (1.31) for 0 ≤ A ≤ A + B ≤ k. Theorem 1.4 The necessary and sufficient condition that the adapted basis B ∗ is dual to the adapted basis B, when B̄ ∗ is dual to B̄, i.e. B b [δy Bb ][δAa ] = δA δa I (1.32) Bb Aa B b [MAa ][NCc ] = δC δc I. (1.33) is the following equation: The explicit form of (1.33) is: (A+B)b NAa (A+B)b = MAa (A+B)b (A+B)b (A+1)c − M(A+1)c NAa (A+2)c M(A+2)c NAa − (A+B)b (A+B−1)c − · · · − M(A+B−1)c NAa 125 Proof. The substitution of (1.17) and (1.26) into (1.32) gives Bb Dd [δy Bb ][δCc ] = [MAa ][dy Aa ][∂Dd ][NCc ]= Bb A a Dd Bb Aa B b [MAa ]δD δd I[NCc ] = [MAa ][NCc ] = δC δc I. Aa Bb ] are inverse matrices. ] and [NCc (1.33) means, that the matrices [MAa Theorem 1.5 The elements of natural basis B̄ are connected with the elements of the adapted basis B in the following way: Bb [∂Aa ] = [δBb ][MAa ]. (1.34) The explicit form of (1.34) is kb 2b 1b δkb , δ2b + . . . + M0a δ1b + M0a ∂0a = δ0a + M0a ∂1a = δ1a kb 2b δkb , . . . , δ2b + · · · + M1a + M1a ∂ka = δka . Aa Proof. The multiplication of (1.26) with the matrix [MCc ] and (1.33) results Aa Bb Aa B b [δAa ][MCc ] = [∂Bb ][NAa ][MCc ] = [∂Bb ]δC δc I = [∂Cc ]. The above equation is equivalent to (1.34). Theorem 1.6 The elements of the natural basis B̄ ∗ are connected with the elements of the adapted basis B ∗ in the following way Aa [dy Aa ] = [NBb ][δy Bb ]. The explicit form of (1.35) is dy 0a = δy 0a 1a dy 1a = δy 1a − N0b δy 0b 2a 2a dy 2a = δy 2a − N1b δy 1b − N0b δy 0b , . . . , ka ka dy ka = δy ka − N(k−1)b δy (k−1)b − · · · − N0b δy 0b . Cc Proof. The multiplication of (1.17) with [NAa ] and (1.33) results Cc Cc Aa C c [NAa ][δy Aa ] = [NAa ][MBb ][dy Bb ] = δB δb I[dy Bb ] = [dy Cc ]. The above equation is equivalent to (1.35). (1.35) 126 Definition 1.2 Some tensor T in the space T (P ) ⊗ T ∗ (P ) is a d-tensor if it can be expressed in the form T = T AaBb δAa ⊗ δy Bb (1.36) and the components of T under (1.2) are transforming as follows 0 0 Aa Bb T AaBb0 = T AaBb BAa BBb 0, (1.37) no summation over A and B. This transformation is good defined, because 0 0 0 Aa Bb Bb T = T AaBb0 δAa0 ⊗ δy Bb = T AaBb BAa BBb 0 δAa0 ⊗ δy 0 = T AaBb δAa ⊗ δy Bb . In the above equation (1.18) and (1.27) was used. 2. The Einstein-Yang-Mills equations in gauge spaces of order k The metric tensor in P is a symmetric, positive definite tensor of type (0, 2). In the natural basis B̄ ∗ of T ∗ (P ), G has the form G = ḡAaBb dy Aa ⊗dy Bb = [dy Aa ]T [ḡAaBb ]⊗[dy Bb ], (T − transposed ). (2.1) From (1.35) we have Bb Aa T [dy Bb ] = [NCc ][δy Cc ], [dy Aa ]T = [δy Dd ]T [NDd ] , so (2.1) can be written in the form G = [δy Dd ]T [gDdCc ] ⊗ [δy Cc ] = gDdCc δy Dd ⊗ δy Cc (2.2) Aa T Bb [gDdCc ] = [NDd ] [ḡAaBb ][NCc ]. (2.3) where Let us denote by T0∗ , T1∗ , T2∗ , . . . , Tk∗ the subspaces of T ∗ (P ) generated by {δy 0a }, {δy 1a }, {δy 2a }, . . . , {δy ka } respectively. If they are mutually orthogonal to each other with respect to the metric tensor G, then all blocks in matrix [gDdCc ] for which D 6= C are equal to zero. Theorem 2.1 The subspaces T0∗ , T1∗ , T2∗ , . . . , Tk∗ of T ∗ (P ) are mutually orthogonal to each other with respect to G, if and only if G = g0a0b δy 0a ⊗ δy 0b + g1a1b δy 1a ⊗ δy 1b + · · · + gkakb δy ka ⊗ δy kb . (2.4) 127 Let L(y 0a , y 1a , . . . , y ka ) be a Lagrangian defined on the compact set Ω ⊂ Rn(k+1) . As it is a scalar field we have 0 0 0 L(y 0a , y 1a , . . . , y ka ) = L(y 0a , y 1a , . . . , y ka ). (2.5) We shall suppose that the adapted basis B = {δ0a , δ1a , . . . , δy ka } are chosen in such a way, that T0∗ , T1∗ , . . . , Tk∗ are mutually orthogonal to G, i.e. when (2.4) is satisfied. We have g = det|gAaBb | = det|g0a0b |det|g1a1b | . . . det|gkakb |. (2.6) and 0 0 Aa Ab gAaAb = gAa0 Ab0 BAa BAb , A = 0, 1, . . . , k. (2.7) From (1.6) it follows that the Jacobian matrix 0 0 Aa [JBb ]= 0 0 D(y 0a , y 1a , . . . y ka ) D(y 0b , y 1b , . . . , y kb ) 0 (2.8) 0 0 0a 1a ka is a triangle matrix which has blocks B0b , B1b , . . . , Bkb on the main diagonal, so 0 0 0 0a 1a ka |J| = |B0a ||B1a | . . . |Bka |. (2.9) From (2.6) and (2.7) it follows 0 0 0 Aa Ab Aa 2 |gAaAb | = |gAa0 Ab0 ||BAa ||BAb | = |gAa0 Ab0 ||BAa | , A = 0, 1, 2, . . . , k. (2.10) The substitution of (2.7), (2.9) and (2.10) into (2.6) gives g = det|gAaBb | = det|gAa0 Bb0 ||J|2 = g 0 |J|2 . (2.11) Let us define the Lagrangian density by √ L(y 0a , y 1a , . . . , y ka ) = L(y 0a , y 1a , . . . , y ka ) g. (2.12) The substitution of (2.5) and (2.11) into (2.12) results 0 0 0 p L(y 0a , y 1a , . . . , y ka ) = L(y 0a , y 1a , . . . , y ka ) g 0 |J| = L(y 0a0 ,y 1a0 ,...,y ka0 (2.13) )|J|. The elementary volume element dω in Ω under coordinate transformation (1.2) is transforming in known way: 0 0 0 dω(y 0a , y 1a , . . . , y ka ) = |J|dω(y 0a , y 1a , . . . , y ka ). (2.14) 128 Proposition 2.1 The integral of action Z I = L(y 0a , y 1a , . . . , y ka )dω (2.15) Ω does not depend on coordinate system if and only if L(y 0a , y 1a , . . . , y ka ) satisfies the relation 0 0 0 L(y 0a , y 1a , . . . , y ka ) = |J|L(y 0a , y 1a , . . . , y ka ). (2.16) Proof. I is invariant if L(y 0a , y 1a , . . . , y ka )dω(y 0a , y 1a , . . . , y ka ) = L(y 0a0 ,y 1a0 ,...,y ka0 )dω(y (2.17) 0a0 ,y 1a0 ,...,y ka0 ). The substitution of (2.14) into (2.17) results (2.16). The proof in the opposite direction is obvious. From (2.12) and (2.13) we obtain that one example for L, which gives coordinate invariant action is √ L(y 0a , y 1a , . . . , y ka ) = gL(y 0a , y 1a , . . . , y ka ). Proposition 2.2 For arbitrary C 2 function L(y 0a , y 1a , . . . , y ka ) the following relation is valid: dL = (δ0a L)δy 0a + (δ1a L)δy 1a + · · · + (δka L)δy ka . (2.18) Proof. As L = L(y 0a , y 1a , . . . , y ka ) we have dL = (∂0a L)dy 0a + (∂1a L)dy 1a + · · · + (∂ka L)dy ka . (2.19) The substitution of (1.34) into (2.19) gives: 1b 2b kb dL = (δ0a + M0a δ1b + M0a δ2b + · · · + M0a δkb )Ldy 0a + = + (2.20) 2b M1a δ2b 0a kb (δ1a + + · · · + M1a δkb )Ldy 1a + · · · + δka Ldy ka 1a (δ0a L)dy + (δ1a L)(dy 1a + M0b dy 0b ) + · · · ka ka (δka L)(dy ka + · · · + M1b dy 1b + M0b dy 0b ). From (1.17) and (2.20) it follows (2.18). We shall suppose that the Lagrangian L(y 0a , y 1a , . . . , y ka ), is the function of φα (y 0a , y 1a , . . . , y ka ), ∂0a φα (y 0a , y 1a , . . . , y ka ), ∂1a φα (y 0a , y 1a , . . . , y ka ), . . . , ∂ka φα (y 0a , y 1a , . . . , y ka ), where α = 1, 2, . . . , p. 129 For the simplification we shall consider only one function φ = φ(y 0a , y 1a , . . . , y ka ) and use the abbreviations ∂Aa φ = ∂φ(y 0a , y 1a , . . . , ∂y ka ) , A = 0, 1, . . . , k. ∂y Aa Now we have L(y 0a , y 1a , . . . , y ka ) = L(φ, ∂0a φ, ∂1a φ, . . . , ∂ka φ) √ = gL(φ, ∂0a φ, ∂1a φ, . . . , ∂ka φ) and the integral of action has the form: Z I(φ) = L(φ, ∂0a φ, ∂1a φ, . . . , ∂ka φ)dω. (2.21) (2.22) Ω We are looking for such function φ, for which I(φ) has maximal or minimal value, i.e. for which δI(φ) = 0. For the simplicity we shall suppose that Ω is the (k + 1)n dimensional rectangle, such that 0a Z 1a Zb dω = Ω ka Zb dy 0a a0a Zb dy ka , (2.23) dy An , A = 0, 1, 2, . . . , k. (2.24) dy 1a a1a ··· aka where Aa A1 Zb dy Aa = aAa A2 Zb An Zb dy A1 aA1 b Z dy A2 · · · aA2 aAn The variation of φ on the boundary of Ω is equal to zero, i.e. δφ(b0a , y 1a , . . . , y ka ) = δφ(a0a , y 1a , . . . , y ka ) = 0, . . . , 0a δφ(y , . . . , y (k−1)a ka 0a , b ) = δφ(y , . . . , y (k−1)a (2.25) ka , a ) = 0, for a = 1, 2, . . . , n, where for instance δφ(y 0a , . . . , bA2 , . . . , y ka ) = δφ(y 01 , . . . , y 0n , . . . , y A1 bA2 , y A3 , . . . , y An , . . . , y k1 , . . . , y kn ), A = 0, 1, 2, . . . , k. (2.26) 130 From the variation principle we have Z δI(φ) = δL(y 0a , y 1a , . . . , y ka )dω Ω Z · = Ω (2.27) ¸ ∂L ∂L ∂L δφ + δ(∂0a φ) + · · · + δ(∂ka φ) dω. ∂φ ∂(∂0a φ) ∂(∂ka φ) From (2.21) it can be seen, that L is a function of independent variables φ, ∂0a φ, . . . , ∂ka φ. To express this fact in (2.28) we shall write dL ∂L dL ∂L = ,··· , = . ∂(∂0a φ) d(∂0a φ) ∂(∂ka φ) d(∂ka φ) (2.28) From (2.18) it follows L(φ, ∂0a φ, ∂1a φ, . . . , ∂ka φ) = L(φ, δ0a φ, δ1a φ, . . . , δka φ), (2.29) where (see (1.23) 1a 2a ka δ0b φ = ∂0b φ − N0b ∂1a φ − N0b ∂2a φ − · · · − N0b ∂ka φ, 2a ka δ1b φ = ∂1b φ − N1b ∂2a φ − · · · − N1b ∂ka φ, . . . , δka φ = ∂ka φ. (2.30) We have A0 = dL ∂L ∂(δ0b φ) ∂L = = d(∂0a φ) ∂(δ0b φ) ∂(∂0a φ) ∂(δ0a φ) A1 = dL ∂L ∂(δ0b φ) ∂L ∂(δ1b φ) = + d(∂1a φ) ∂(δ0b φ) ∂(∂1a φ) ∂(δ1b φ) ∂(∂1a φ) = (2.31) ∂L ∂L 1a − N0b , ∂(δ1a φ) ∂(δ0b φ) A2 = dL ∂L ∂L ∂L 2a 2a = − N1b − N0b , d(∂2a φ) ∂(δ2a φ) ∂(δ1b φ) ∂(δ0b φ) A3 = dL ∂L ∂L ∂L ∂L 3a 3a 3a = − N2b − N1b − N0b , d(∂3a φ) ∂(δ3a φ) ∂(δ2b φ) ∂(δ1b φ) ∂(δ0b φ) .................................................................................................... Ak = dL ∂L ∂L ∂L ka ka = − N(k−1)b − · · · − N1b d(∂ka φ) ∂(δka φ) ∂(δ(k−1)b ) ∂(δ1b φ) ∂L ka − N0b . ∂(δ0b φ) 131 We shall suppose, that δ(∂0a φ) = (∂0a δφ), δ(∂1a φ) = ∂1a (δφ), . . . , δ(∂ka φ) = ∂ka (δφ). (2.32) From (2.28) and (2.31) we get δL = dL dL ∂L δφ + δ(∂0a φ) + δ(∂1a φ) + · · · + dφ d(∂0a φ) ∂(∂1a φ) + ∂L δ(∂ka φ) = ∂(∂ka φ) (2.33) = ∂L δφ + A0 δ(∂0a φ) + A1 δ(∂1a φ) + · · · + Ak δ(∂ka φ) ∂φ = ∂L δφ + A0 ∂0a (δφ) + A1 ∂1a (δφ) + · · · + Ak ∂ka (δφ) ∂φ = ∂L δφ + ∂0a (A0 δφ) + ∂1a (A1 δφ) + · · · + ∂ka (Ak δφ) ∂φ − (∂0a A0 )δφ − (∂1a A1 )δφ − · · · − (∂ka Ak )δφ. Using (2.24) and (2.25) we have 1a Z 2a Zb dy 1a ∂0a (A0 δφ)dω = Ω a1a 1a Zb dy ka aka ∂0a (A0 δφ)dy 0a a0a ka Zb dy a1a dy 2a · · · 2a Zb 0a Zb a2a 1a = ka Zb Zb dy 2a ··· a2a ¯b0a dy ka (A0 δφ)¯a0a = 0. In the similar way we obtain Z Z ∂1a (A1 δφ)dω = 0, . . . , ∂ka (Ak δφ)dω = 0. Ω (2.34) aka (2.35) Ω From (2.33)–(2.35) we obtain ¶ Z Z µ ∂L δI(φ) = (δL)dω = − ∂0a A0 − ∂1a A1 − · · · − ∂ka Ak δφdω. ∂φ Ω Ω (2.36) 132 The extreme value of integral of action is obtained when δL = 0. If we in (2.36) substitute A0 , A1 , . . . , Ak from (2.31) we get δL = ∂L ∂L 1b kb − (∂0a − N0a ∂1b − · · · − N0a ∂kb ) ∂φ ∂(δ0a φ) 2b kb −(∂1a − N1a ∂2b − · · · − N1a ∂kb ) −(∂ka ) (2.37) ∂L − ··· − ∂(δ1a φ) ∂L + B0 + B1 + B2 + · · · + B(k−1) , ∂(δka ) where B0 = ∂L 1a 2a ka [∂1a N0b + ∂2a N0b + · · · + ∂ka N0b ] ∂(δ0b φ) B1 = ∂L 2a 3a ka [∂2a N1b + ∂3a N1b + · · · + ∂ka N1b ] ∂(δ1b φ) B2 = ∂L 3a ka [∂3a N2b + · · · + ∂ka N2b ] ∂(δ2b φ) B(k−1) = ∂L ka ∂ka N(k−1)b . ∂(δ(k−1)b φ) Using (1.23) we have Theorem 2.2 The extreme value of integral of action is obtained, when δL = 0, i.e. δL = ∂L ∂L ∂L ∂L − δ0a − δ1a − · · · − δka ∂φ ∂(δ0a φ) ∂(δ1a φ) ∂(δka φ) (2.38) + B0 + B1 + B2 + · · · + B(k−1) = 0, In Osck M we have (A+B)a NAb (A+B)a = NAb (y 0a , y 1a , . . . , y Ba ) ⇒ B1 = 0, B2 = 0, . . . , Bk−1 = 0. (2.39) (2.40) Proposition 2.3 In Osck M the integral of action has extreme value if δL = ∂L ∂L ∂L ∂L − δ0a − δ1a − · · · − δka + B0 = 0. (2.41) ∂φ ∂(δ0a φ) ∂(δ1a φ) ∂(δka φ) 133 √ √ As from (2.19) we have L = gL and g is not the function of φ, ∂0a φ, ∂1a φ, . . . , ∂ka φ, so from (2.38) we obtain Theorem 2.3 The Einstein-Yang-Mills equation for the gauge transformation of order k given by (1.2) expressed as function of the Lagrangian L and the metric function g is given by ·µ ¶ ∂ ∂ ∂ ∂ √ δL = g − δ0a − δ1a − · · · − δka L ∂φ ∂(δ0a φ) ∂(δ1a φ) ∂(δka φ) + ∂L 1a 2a ka [∂1a N0b + ∂2a N0b + · · · + ∂ka N0b ] ∂(δ0b φ) + ∂L 2a 3a ka [∂2a N1b + ∂3a N1b + · · · + ∂ka N1b ] ∂(δ1b φ) + ∂L 3a ka [∂3a N2b + · · · + ∂ka N2b ] + ··· + ∂(δ2b φ) ∂L + ∂(δ(k−1)b φ) · − (2.42) ¸ ka ∂ka N(k−1)b ¸ ∂L ∂L ∂L √ g = 0. δ0a + δ1a + · · · + δka ∂(δ0a φ) ∂(δ1a φ) ∂(δka φ) Proposition 2.4 In Osck M the integral of action has extreme value if ·µ ¶ ∂L ∂L ∂L ∂L √ δL = g − δ0a − δ1a − · · · − δka ∂φ ∂(δ0a φ) ∂(δ1a φ) ∂(δka φ) ¸ ∂L 1a 2a ka + [∂1a N0b + ∂2a N0b + · · · + ∂ka N0b ] ∂(δ0b φ) · − (2.43) ¸ ∂L ∂L ∂L √ δ0a + δ1a + · · · + δka g = 0. ∂(δ0a φ) ∂(δ1a φ) ∂(δka φ) Proof. 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