Leading order contribution to lateral Casimir force between corrugated dielectric slabs. Prachi Parashar Oklahoma Center for High Energy Physics and Homer L. Dodge Department of Physics and Astronomy, University of Oklahoma, Norman, OK 73019, USA Collaborators: Inés Cavero-Peláez, Kimball. A. Milton, and K. V. Shajesh Date: July 8-9, 2010 Event: Quantum Vacuum Meeting Venue: Texas A & M University, College Station, Texas. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 1 / 26 Outline 1 Lateral Casimir force 2 Motivation Scalar case: Review of Noncontact Gears I and II 3 Formalism Electromagnetic case: Statement of the problem 4 Leading order contribution Evaluation of the reduced Green’s dyadic General result for the leading order term 5 Limits Conductor limit Thin plate limit 6 Conclusions and things to do Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 2 / 26 Lateral Casimir force Consider potential Vi (z, y ) = λi δ(z − ai − hi (y )), i = 1, 2, a = a2 − a1 > 0, where, the functions hi (y ) describe the corrugations on the plate. Casimir energy for a configuration when one of the plate is laterally shifted by an amount y0 , h1 h1 (y + y0 ), h2 (y ), can be written in the form a h2 y0 ∆E (a, hi , y0 ) = E − E (0) d= 2π k0 (a) = E1 (a, h1 ) + E2 (a, h2 ) + E12 (a, hi , y0 ), where E12 isolates the interaction energy due to the lateral shift. Lateral Casimir force is defined as the negative change in energy due to the lateral shift: ∂E12 ∂ ∆E = − . FLat (a, hi , y0 ) = − ∂y0 ∂y0 Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 3 / 26 Motivation 1997-2010: Starting with first theoretical study by Golestanian et. al. in 1997, various theoretical and experimental analysis of lateral Casimir force has been done till now. One remarkable theoretical calculation for lateral Casimir force between dielectric gratings was done exactly by Lambrecht and Marachevsky, which shows 0.1% accuracy between theory and experiment. In noncontact Gears I and II (PRD 78, 065018, 065019) we presented next-to-leading order contibution to the lateral Casimir force in planar geometry and leading order contribution in cylinderical geometry due to scalar field interacting with semi-transparent delta potential. h1 a a h2 y0 d= a1 θ0 2π k0 a2 Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 4 / 26 Leading order perturbation-Dirichlet and Weak Leading order contribution to the lateral Casimir force in Dirichlet limit and weak limit for sinusoidal corrugations are (2) h1 h2 (1,1) (k0 a), A a a D (0) h1 h2 (2) A (k0 a). = k0 a sin(k0 y0 ) FCas,W a a W (0) FLat,D = 2k0 a sin(k0 y0 ) |FCas,D | (2) FLat,W (1,1) AD (k0 a) e−k0 a e2 (k0 a) 1.0 1.0 0.8 0.8 0.6 0.6 0.4 0.4 0.2 0.2 2 4 6 Prachi Parashar (University of Oklahoma) 8 10 k0 a Non-contact gears III:EM Case 2 4 6 8 QV: July 9, 2010 10 k0 a 5 / 26 Next-to-leading order perturbation - Dirichlet Next-to-Leading order contribution to the lateral Casimir force in the Dirichlet limit for sinusoidal corrugations is (0) h1 h2 15 (4) FLat,D = 2 k0 a sin(k0 y0 ) FCas,D a a 4 2 h1 h22 h1 h2 (2,2) (3,1) × + 2 AD (k0 a) − 2 cos(k0 y0 ) A (k0 a) . a2 a a a D (3,1) AD (2,2) (k0 a) AD (k0 a) 1.0 1.0 0.8 0.8 0.6 0.6 0.4 0.4 0.2 0.2 2 4 Prachi Parashar (University of Oklahoma) 6 8 10 k0 a Non-contact gears III:EM Case 2 4 6 8 QV: July 9, 2010 10 k0 a 6 / 26 Next-to-leading order perturbation - Weak The next correction to the lateral Casimir force for the the weak coupling case is (0) h1 h2 3 (4) FLat,W = k0 a sin(k0 y0 ) FCas,W a a 2 2 h1 h2 (4) h22 h1 (4) + 2 AW (k0 a) − 2 cos(k0 y0 ) A (2k0 a) , × a2 a a a W where (n) AW (t0 ) = e −t0 n X en (t0 ) t0m = . m! e t0 m=0 e−k0 a e4 (k0 a) e−2k0 a e4 (2k0 a) 1.0 1.0 0.8 0.8 0.6 0.6 0.4 0.4 0.2 0.2 2 4 Prachi Parashar (University of Oklahoma) 6 8 10 k0 a Non-contact gears III:EM Case 2 4 6 8 10 k0 a QV: July 9, 2010 7 / 26 Analysis Weak coupling limit - Non-perturbative results Z (k0 a)3 1 ∞ dt sin(t + k0 y0 ) [∞,∞] FW =− Re 3 , sin(k0 y0 ) π −∞ t [(t + ik0 a)2 + {k0 r (t)}2 ] 2 for 2h < a. [∞,∞] FW [∞,4] FW [∞,∞] 1.4 k0 y0 = FW π 4 −1 2 4 6 10 k0 a 8 1.2 k0 h = 0.3 −0.01 1.0 0.8 −0.02 0.6 −0.03 0.4 k0 y0 = π 4 k0 h = 0.1, 0.3, 0.5 0.2 −0.04 0.5 1.0 1.5 2.0 k0 a We observe that the perturbative results, when the next-to-leading order is included, compares with the exact result remarkably well for k0 h ≪ 1 and 2h < a. Similar results should hold for the Dirichlet limit also. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 8 / 26 Electromagnetic case: Statement of the problem We consider two dielectric slabs Vi (z, y ; ω) = ω 2 (ǫi (ω) − 1) [θ(z − ai − hi (y )) − θ(z − bi − hi (y ))] , where i = 1, 2 y0 ε1 ε2 d1 d2 d= 2π k0 a h1 h2 where, the thickness of the individual slabs is di = bi − ai , such that a = a2 − b1 > 0 represents the distance between the slabs. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 9 / 26 Lateral Casimir force The vacuum energy arising from the fluctuation of the electromagnetic field in presence of the potential is given by Z dω i Tr ln Γ Γ−1 E =− 0 , 2 2π where Γ is the Green’s dyadic which obeys −∇ × ∇ × + ω 2 1 + V1 (x) + V2 (x) Γ(x, x′ ; ω) = −ω 2 1 δ(x − x′ ), and Γ0 is the Green’s dyadic for the free space. As shown earlier Casimir energy for a configuration when one of the slab is laterally shifted by an amount y0 is ∆E (a, hi , y0 ) = E − E (0) (a) = E1 (a, h1 ) + E2 (a, h2 ) + E12 (a, hi , y0 ). Lateral Casimir force is defined as the negative change in energy due to the lateral shift ∂ ∂E12 FLat (a, hi , y0 ) = − ∆E = − . ∂y0 ∂y0 Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 10 / 26 Formalism(contd.) Interaction energy E12 is given by Z dω i Tr ln 1 − Γ1 ∆V 1 Γ2 ∆V 2 . E12 = 2 2π where Γi is the Green’s dyadic when one slab has corrugations. h i−1 Γ(0) , Γi = 1 − Γ(0) ∆V i (0) where ∆V i = V i − V i (0) V i given by is the deviation from the background potential (0) V i (z; ω) = (ǫi (ω) − 1) [θ(z − ai ) − θ(z − bi )] . Γ(0) is the Green’s dyadic for no corrugation configuration. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 11 / 26 Leading order contribution - perturbative expansion Formally expanding the log and keeping terms to second order in corrugation amplitude (which requires expanding potential for small corrugation amplitude) we get Z 1 dζ (1) (1) (2) Tr ln Γ(0) ∆V 1 Γ(0) ∆V 2 , E12 = − 2 2π where (1) ∆ V i (z, y ; iζ) = −hi (y ) (ǫi (iζ) − 1) [δ(z − ai ) − δ(z − bi )] , is the first term in expansion of potential for small corrugation amplitude. Γ(0) is translationally invariant in x and y direction. So we can Fourier transform x and y directions Z ∞ Z (2) E12 dky ∞ dky′ h̃1 (ky − ky′ ) h̃2 (ky′ − ky ) L(2) (ky , ky′ ), = Lx −∞ 2π −∞ 2π where Lx is the length in x direction and h̃i (ky ) are the Fourier transforms of the corrugation amplitude functions hi (y ). Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 12 / 26 Leading order contribution(cont.) Kernel L(2) (ky , ky′ ) is given by L (2) (ky , ky′ ) 1 =− 2 Z dζ 2π Z dkx (2) I (kx , ζ, ky , ky′ ), 2π where, I (2) (kx , ζ, ky , ky′ ) = (ǫ1 (iζ) − 1) (ǫ2 (iζ) − 1) × h (0) (0) Γ̃ij (a2 , a1 ; kx , ky , ω) Γ̃ji (a1 , a2 ; kx , ky′ , ω) (0) (0) (0) (0) −Γ̃ij (b2 , a1 ; kx , ky , ω) Γ̃ji (a1 , b2 ; kx , ky′ , ω) −Γ̃ij (a2 , b1 ; kx , ky , ω) Γ̃ji (b1 , a2 ; kx , ky′ , ω) i (0) (0) +Γ̃ij (b2 , b1 ; kx , ky , ω) Γ̃ji (b1 , b2 ; kx , ky′ , ω) , So the quantity we need to evaluate is the Green’s dyadic for the background potential, which is the slabs without corrugation. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 13 / 26 Evaluation of the reduced Green’s dyadic The Green’s dyadic Γ(0) obeys h i (0) (0) −∇ × ∇ × + ω 2 1 + ω 2 V1 (x) + ω 2 V2 (x) Γ(0) (x, x′ ; ω) = −ω 2 1 δ(x − x′ ). For planar geometry the problem reduces to solving for two scalar Green’s function g E (z, z ′ ) and g H (z, z ′ ) which satisfies ∂2 − 2 + k 2 + ζ 2 ǫ(z) g E (z, z ′ ) = δ(z − z ′ ), ∂z k2 ∂ 1 ∂ 2 + +ζ g H (z, z ′ ) = δ(z − z ′ ), − ∂z ǫ(z) ∂z ǫ(z) where ǫ(z) = 1 + V (z) and k = kx since we can choose ky = 0. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 14 / 26 Evaluation of the reduced Green’s dyadic(cont.) The reduced Green’s dyadic in terms of g E (z, z ′ ) and g H (z, z ′ ) is Γ(0) (z, z ′ ; k, 0, ζ) = 2 6 6 6 6 6 4 1 ∂ 1 ∂ ǫ(z ′ ) ∂z ′ ǫ(z) ∂z g H (z, z ′ ) −ζ 2 g E (z, z ′ ) 0 ∂ ik ǫ(z) ǫ(z ′ ) ∂z 0 g H (z, z ′ ) 0 3 g H (z, z ′ ) 7 7 7 0 7. 7 5 H ′ k2 g (z, z ) ǫ(z) ǫ(z ′ ) ik ∂ ǫ(z) ǫ(z ′ ) ∂z where we have dropped the delta functions, which do not contribute. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 15 / 26 Evaluation of the reduced Green’s dyadic(cont.) Denoting Γ matrix components as Γij , we can write the general form as kx2 Γ k 2 11 + ky2 Γ k 2 22 (0) ′ k k k k Γ (z, z ; kx , ky , ζ) = kx 2 y Γ11 − kx 2 y Γ22 kx k Γ31 Prachi Parashar (University of Oklahoma) kx ky Γ k 2 11 Non-contact gears III:EM Case ky2 Γ k 2 11 − + kx ky Γ kx Γ k 2 22 k 13 kx2 k2 ky k Γ31 Γ22 ky Γ 13 k Γ33 QV: July 9, 2010 16 / 26 Green’s function regions 5 Q 6 R 3 N O P B Y 4 M 2 X 9 L A U V W 1 S 7 T 8 z ′ = b2 z ′ = a2 z ′ = b1 Prachi Parashar (University of Oklahoma) z = b2 z = a2 z = b1 z = a1 z = z′ z ′ = a1 Non-contact gears III:EM Case QV: July 9, 2010 17 / 26 General result for the leading order term Using solutions to the electric and the magnetic Green’s function we can evaluate I (2) (kx , ζ, k1y , k2y ) as " − 1 1 1 1 k 2 k ′2 2κ 2κ′ 1 1 M(−α1 , −α1′ )M(−α2 , −α2′ )(kx2 ∆ ∆′ + ky ky′ )2 ζ 4 + ∆1 ∆¯1′ M(−α1 , ᾱ1′ )M(−α2 , ᾱ2′ )kx2 (ky − ky′ )2 ζ 2 κ′ 2 + ∆1¯ ∆1′ M(ᾱ1 , −α1′ )M(ᾱ2 , −α2′ )kx2 (ky − ky′ )2 ζ 2 κ2 o n 2 + ∆¯1 ∆¯1′ M(ᾱ1 , ᾱ1′ )(kx2 + ky ky′ )κκ′ + M(−ᾱ1 , −ᾱ1′ )k 2 k ′ ε11 # n o 2 × M(ᾱ2 , ᾱ2′ )(kx2 + ky ky′ )κκ′ + M(−ᾱ2 , −ᾱ2′ )k 2 k ′ ε12 , where ˆ ∆ = (1 − α12 e −2κ1 d1 )(1 − α22 e −2κ2 d2 ) e κa ˜ −α1 α2 (1 − e −2κ1 d1 )(1 − e −2κ2 d2 ) e −κa , ˆ ′ 2 M(αi , αi′ ) = (εi − 1) (1 − αi2 ) e −κi di (1 − αi′ ) e −κi di ˜ ′ −(1 + αi )(1 − αi e −2κi di )(1 + αi′ )(1 − αi′ e −2κi di ) , Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 18 / 26 General result for the leading order term(cont.) κ2i = k 2 + ζ 2 εi κ̄i = κi /εi αi = (κi − κ)/(κi + κ) Quantities with primes are obtained by replacing ky → ky′ everywhere. Quatities with bar are defined in similar way with κ replaced with κi → κi = Prachi Parashar (University of Oklahoma) κi ǫi Non-contact gears III:EM Case QV: July 9, 2010 19 / 26 Conductor limit In the conductor limit ǫ → ∞ # " 2 + κ′ 2 − (k − k ′ )2 }2 ′ {κ κ κ y y (2) . Iε→∞ (κ, κ′ , ky − ky′ ) = − 1+ sinh κa sinh κ′ a 4 κ2 κ′ 2 For the case of sinusoidal corrugations described by h1 (y ) = h1 sin[k0 (y + y0 )] h2 (y ) = h2 sin[k0 y ] the lateral force is evaluated to be (0) h1 h2 (1,1) (2) Fε→∞ = 2k0 a sin(k0 y0 ) FCas A (k0 a), a a ε→∞ Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 20 / 26 Conductor limit cont. A(1,1) ε→∞ (t0 ) s2 15 = 4 π s̄ 2 Z ∞ dt −∞ + t2 Z 2 s+ where = and the Dirichlet scalar case. ∞ 0 2 − t 2 )2 s s+ 1 (s 2 + s+ 0 s̄ds̄ + , 2 sinh s sinh s+ 2 8 s 2 s+ = s̄ 2 + (t + t0 )2 . The first term corresponds to (1,1) Aε→∞ (k0 a) 1.0 0.8 0.6 0.4 0.2 2 (1,1) 4 6 8 10 k0 a Figure: Plot of Aε→∞ (k0 a) versus k0 a. The dotted curve represents 2 times the Dirichlet Prachi Parashar case. (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 21 / 26 Conductor limit cont. We can evaluate one of the integrals to get " Z sin(2t0 u/π) sinh2 u 7 15 ∞ 2 (1,1) du − sinh u Aε→∞ (t0 ) = 4 0 (2t0 u/π) cosh6 u 2 # 1 2t0 2 sinh2 u 1 2t0 4 sinh2 u − , + 2 π cosh4 u 16 π cosh2 u (2) which reproduces the result in Emig et. al. apart from an overall factor of 2. The double integral representation is more useful for numerical evaluation because of the oscillatory nature of the function sin x/x the above expression. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 22 / 26 Thin plate limit It is under construction....... It is interesting to analyze di → 0 limit. If we set ω 2 (ǫi − 1) = ωp2i λi = ωp2i di = fixed as di → 0, then we can write our potential as Vi = λi δ(z − ai − hi (y )). This should model 2D sheets. However, if a ∼ 10−7 m and ωp ∼ 1015 Hz, then for conductor case ωp2i da ≫ 1 ⇒ d ≫ 10−7 m, which is not exactly a single atom thin layer. This limit can work for weak case. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 23 / 26 Conclusion and things to do 1 We have obtained result for leading order contribution to the lateral Casimir force for corrugated dielectric slabs and obtained conductor limit for the same. 2 Obtain thin plate limit and get exact results in weak case. 3 Calculate next-to-leading order contribution and compare results with experiment as well as various numerical/analytical exact results (Mohideen, Reynaud, Emig, Marachevsky). Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 24 / 26 1 Thanks to Jef Wagner, Elom Albalo and Nima Pourtolami for useful comments and discussion. 2 Thank you all for listening. Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 25 / 26 References I. Cavero-Pelaez, K. A. Milton, P. Parashar and K. V. Shajesh, Phys. Rev. D 78, 065018 (2008) [arXiv:0805.2776 [hep-th]]. I. Cavero-Pelaez, K. A. Milton, P. Parashar and K. V. Shajesh, Phys. Rev. D 78, 065019 (2008) [arXiv:0805.2777 [hep-th]]. T. Emig, A. Hanke, R. Golestanian and M. Kardar, Phys. Rev. A 67, 022114 (2003). K. A. Milton, P. Parashar and J. Wagner, Phys. Rev. Lett. 101, 160402 (2008) [arXiv:0806.2880 [hep-th]]. K. A. Milton, P. Parashar and J. Wagner, arXiv:0811.0128 [math-ph]. J. S. Schwinger, L. L. . DeRaad and K. A. Milton, Annals Phys. 115, 1 (1979). Prachi Parashar (University of Oklahoma) Non-contact gears III:EM Case QV: July 9, 2010 26 / 26