EXISTENCE OF POSITIVE PERIODIC SOLUTIONS FOR DELAYED PREDATOR-PREY PATCH SYSTEMS WITH STOCKING HUI FANG AND ZHICHENG WANG Received 28 July 2005; Revised 11 December 2005; Accepted 25 January 2006 A sufficient condition is derived for the existence of positive periodic solutions for a delayed predator-prey patch system with stocking. Some known results are improved. Copyright © 2006 Hindawi Publishing Corporation. All rights reserved. 1. Introduction Predator-prey systems have been studied extensively. See, for instance, [1, 6, 8–10] and the references cited therein. Most of the previous papers focused on the predator-prey systems without stocking. Brauer and Soudack [2, 3] studied some predator-prey systems under constant rate stocking. To our knowledge, few papers have been published on the existence of positive periodic solutions for delayed predator-prey patch systems with periodic stocking. In this paper, we investigate the following predator-prey system with stocking: x1 (t) = x1 (t) a1 (t) − b1 (t)x1 (t) − c(t)y(t) + D1 (t) x2 t − τ1 (t) − x1 (t) + S1 (t), x2 (t) = x2 (t) a2 (t) − b2 (t)x2 (t) + D2 (t) x1 t − τ2 (t) − x2 (t) + S2 (t), y (t) = y(t) − d(t) + p(t)x1 (t) − q(t)y(t) − β(t) 0 −τ k(s)y(t + s)ds + S3 (t), (1.1) with the initial conditions x1 (s) = ϕ1 (s) ≥ 0, s ∈ [−σ,0], ϕ1 (0) > 0, x2 (s) = ϕ2 (s) ≥ 0, s ∈ [−σ,0], ϕ2 (0) > 0, y(s) = ψ(s) ≥ 0, (1.2) s ∈ [−σ,0], ψ(0) > 0, where x1 and y are the population densities of prey species x and predator species y in patch 1, and x2 is the density of species x in patch 2. Predator species y is confined to Hindawi Publishing Corporation International Journal of Mathematics and Mathematical Sciences Volume 2006, Article ID 63182, Pages 1–14 DOI 10.1155/IJMMS/2006/63182 2 Periodic solutions for predator-prey patch systems patch 1, while the prey species x can diffuse between two patches. Di (t) (i = 1,2) are diffusion coefficients of species x. Si (t) (i = 1,2,3) denote the stocking rates. ϕ1 (s), ϕ2 (s), and ψ(s) are continuous on [−σ,0], σ = max{τ,supt∈R τ1 (t),supt∈R τ2 (t)}. The delay τ1 (τ2 ) represents the time that species x migrates from patch 2 to patch 1 (patch 1 to patch 2). When Si (t) ≡ 0 (i = 1,2,3), τi ≡ 0 (i = 1,2), system (1.1) was considered by Zhang and Wang [15], Song and Chen [11], and Chen et al. [5]. The purpose of this paper is to derive a set of easily verifiable conditions for the existence of positive periodic solutions of system (1.1). The method in this paper is different from those of [4, 12–14]. 2. Existence of positive periodic solutions To show the existence of solutions to the considered problems, we will use an abstract theorem developed [7]. We first state this abstract theorem. For a fixed σ ≥ 0, let C := C([−σ,0]; Rn ). If x ∈ C([γ − σ,γ + δ]; Rn ) for some δ > 0 and γ ∈ R, then xt ∈ C for t ∈ [γ,γ + δ] is defined by xt (θ) = x(t + θ) for θ ∈ [−σ,0]. The is, φc = maxθ∈[−σ,0] φ(θ) for φ ∈ C, supremum norm in C is denoted by · c , that n where · denotes the norm in R , and u = ni=1 |ui | for u = (u1 ,...,un ) ∈ Rn . We consider the following functional differential equation: dx(t) = f t,xt , dt (2.1) where f : R × C → Rn is completely continuous, and there exists T > 0 such that for every (t,ϕ) ∈ R × C, we have f (t + T,ϕ) = f (t,ϕ). The following lemma is a simple consequence of [7, Theorem 4.7.1]. Lemma 2.1. Suppose that there exists a constant M > 0 such that (i) for any λ ∈ (0,1) and any T-periodic solution x of the system dx(t) = λ f t,xt , dt (2.2) x(t) < M for t ∈ R; T (ii) g(u) := (1/T) 0 f (s, u)ds = 0 for u ∈ ∂BM (Rn ), where BM (Rn ) = {u ∈ Rn : u < M }, and u denotes the constant mapping from [−σ,0] to Rn with the value u ∈ Rn ; (iii) Brouwer degree deg(g,BM (Rn )) = 0. Then there exists at least one T-periodic solution of the system dx(t) = f t,xt dt (2.3) that satisfies supt∈R x(t) < M. In the following, we set ḡ = 1 T T 0 g(t)dt, g l = min g(t) , t ∈[0,T] where g is a continuous T-periodic function. g u = max g(t) , t ∈[0,T] (2.4) H. Fang and Z. Wang 3 In system (1.1), we always assume the following. (H1 ) ai (t), bi (t), Di (t) (i = 1,2), c(t), d(t), p(t), q(t), and β(t) are positive continuous T-periodic functions. Si (t) (i = 1,2,3), τi (t) (i = 1,2) are nonnegative continuous T-periodic functions. τi (t) < 1 (i = 1,2), t ∈ R. (H2 ) k(s) ≥ 0 on [−τ,0] (0 ≤ τ < +∞); and k(s) is a piecewise continuous and normal0 ized function such that −τ k(s)ds = 1. Set K= q̄ + β̄ , p̄ a M − D1 M0 + S1 l K = 1 0 , b1 M0 ∗ M0 = max l m0 = min u 0 = M u a2 + a22 + 4b2 S2 , 2b2 0 exp − 2T D̄1 + b̄1 M0 + c̄M m 0 = min a M +S l Ki = i 0 i , bi M0 a1 + a21 + 4b1 S1 2b1 a1 /c − S3 /q b1u /cl + (p/q)u ∗ pM0 + p2 M02 + 4qS3 2q i = 1,2, u , a2 + a22 + 4b2 S2 , 2b2 l , u , ¯ p̄ K2∗ − d/ ¯ p̄ K ∗ − d/ ¯ p̄ K1∗ − d/ 0 + β̄M 0 . u , u exp − 2T d¯ + q̄M , K K + c/b1 K + c/b1 (2.5) Theorem 2.2. In addition to (H1 ), (H2 ), assume further that system (1.1) satisfies one of the following assumptions: ¯ p̄ (i = 1,2); (H3 ) (a1 /c)l > (S3 /q)u , Ki∗ > d/ ¯ p̄. (H4 ) (a1 /c)l > (S3 /q)u , K ∗ > d/ Then system (1.1) has at least one positive T-periodic solution, say (x1∗ (t),x2∗ (t), y ∗ (t))T such that m0 ≤ xi∗ (t) ≤ M0 (i = 1,2), 0 , m 0 ≤ y ∗ (t) ≤ M t ≥ 0. (2.6) Proof. Consider the following system: u1 (t) = a1 (t) − D1 (t) − b1 (t)eu1 (t) − c(t)eu3 (t) + D1 (t)eu2 (t−τ1 (t))−u1 (t) + u2 (t) = a2 (t) − D2 (t) − b2 (t)eu2 (t) + D2 (t)eu1 (t−τ2 (t))−u2 (t) + u3 (t) = −d(t) + p(t)eu1 (t) − q(t)eu3 (t) − β(t) 0 −τ S1 (t) , eu1 (t) S2 (t) , eu2 (t) k(s)eu3 (t+s) ds + S3 (t) , eu3 (t) (2.7) 4 Periodic solutions for predator-prey patch systems where ai (t), bi (t), Di (t) (i = 1,2), Si (t) (i = 1,2,3), c(t), d(t), p(t), q(t), and β(t) are the same as those in assumption (H1 ), and τ, τi (i = 1,2) and k(s) are the same as those in assumption (H2 ). We first show that system (2.7) has one T-periodic solution. Let C := C([−σ,0]; R3 ). We define the following map: f : R × C −→ R3 , f (t,ϕ) = f1 (t,ϕ), f2 (t,ϕ), f3 (t,ϕ) , ϕ = ϕ1 ,ϕ2 ,ϕ3 ∈ C, f1 (t,ϕ) = a1 (t) − D1 (t) − b1 (t)eϕ1 (0) − c(t)eϕ3 (0) + D1 (t)eϕ2 (−τ1 (t))−ϕ1 (0) + f2 (t,ϕ) = a2 (t) − D2 (t) − b2 (t)eϕ2 (0) + D2 (t)eϕ1 (−τ2 (t))−ϕ2 (0) + f3 (t,ϕ) = −d(t) + p(t)eϕ1 (0) − q(t)eϕ3 (0) − β(t) 0 −τ S1 (t) , eϕ1 (0) (2.8) S2 (t) , eϕ2 (0) k(s)eϕ3 (s) ds + S3 (t) . eϕ3 (0) Clearly, f : R × C → R3 is completely continuous. Now, the system (2.7) becomes du(t) = f t,ut . dt (2.9) Corresponding to du(t) = λ f t,ut , dt λ ∈ (0,1), (2.10) we have u1 (t) = λ a1 (t) − D1 (t) − b1 (t)eu1 (t) − c(t)eu3 (t) + D1 (t)eu2 (t−τ1 (t))−u1 (t) + u2 (t) = λ a2 (t) − D2 (t) − b2 (t)eu2 (t) + D2 (t)eu1 (t−τ2 (t))−u2 (t) + u3 (t) = λ − d(t) + p(t)eu1 (t) − q(t)eu3 (t) − β(t) 0 −τ S1 (t) , eu1 (t) S2 (t) , eu2 (t) k(s)eu3 (t+s) ds + S3 (t) . eu3 (t) (2.11) Suppose that (u1 (t),u2 (t),u3 (t))T is a T-periodic solution of system (2.11) for some λ ∈ (0,1). Choose tiM ,tim ∈ [0,T], i = 1,2,3, such that ui tiM = max ui (t), t ∈[0,T] ui tim = min ui (t), t ∈[0,T] i = 1,2,3. (2.12) Then, it is clear that ui tiM = 0, ui tim = 0, i = 1,2,3. (2.13) H. Fang and Z. Wang 5 From this and system (2.11), we obtain that a1 t1M − D1 t1M − b1 t1M u1 (t1M ) e −c t1M e u3 (t1M ) M +D1 t1M e u2 (t1M −τ1 (t1M ))−u1 (t1M ) M M M a2 t2M − D2 t2M − b2 t2M eu2 (t2 ) + D2 t2M eu1 (t2 −τ2 (t2 ))−u2 (t2 ) + M M −d t3M + p t3M eu1 (t3 ) − q t3M eu3 (t3 ) − β t3M m 0 −τ m S2 t2M = 0, M eu2 (t2 ) M k(s)eu3 (t3 +s) ds + m m m a1 t1m − D1 t1m − b1 t1m eu1 (t1 ) − c t1m eu3 (t1 ) +D1 t1m eu2 (t1 −τ1 (t1 ))−u1 (t1 ) + m m m (2.16) m S1 t1 m = 0, eu1 (t1 ) (2.17) S2 t2m = 0. m eu2 (t2 ) m a2 t2m − D2 t2m − b2 t2m eu2 (t2 ) + D2 t2m eu1 (t2 −τ2 (t2 ))−u2 (t2 ) + (2.15) S3 t3M = 0, M eu3 (t3 ) S1 t M + u (t1M ) = 0, e1 1 (2.14) (2.18) Next we make the following claims. Claim 1. For ui (tiM ) (i = 1,2), one of the following cases holds: u2 t2M ≤ u1 t1M ≤ M1∗ ≤ M1 , u1 t1M < u2 t2M (2.19) ∗ ≤ M2 ≤ M1 , (2.20) where M1 := max{M1∗ ,M2∗ }, M ∗j := ln((a j + a2j + 4b j S j )/2b j )u , j = 1,2. There are two cases to consider. Case 1. Assume that u1 (t1M ) ≥ u2 (t2M ); then u1 (t1M ) ≥ u2 (t1M − τ1 (t1M )). From this and (2.14), we have b1 t1M e u1 (t1M ) ≤ a1 t1M S1 t M + u (t1M ) . e1 1 (2.21) That is, M M b1 t1M e2u1 (t1 ) − a1 t1M eu1 (t1 ) − S1 t1M ≤ 0. (2.22) Therefore, e u1 (t1M ) a1 t1M + a21 t1M + 4b1 t1M S1 t1M a1 + a21 + 4b1 S1 M ≤ ≤ 2b1 2b1 t1 u . (2.23) Hence, M u2 t2 M ≤ u1 t1 a1 + a21 + 4b1 S1 ≤ ln 2b1 u . (2.24) 6 Periodic solutions for predator-prey patch systems Case 2. Assume that u1 (t1M ) < u2 (t2M ); then u1 (t2M − τ2 (t2M )) < u2 (t2M ). From this and (2.15), we have b2 t2M e u2 (t2M ) ≤ a2 t2M S2 t M + u (t2M ) . e2 2 (2.25) By a similar argument to Case 1, we have M u1 t1 M < u2 t2 a2 + a22 + 4b2 S2 ≤ ln 2b2 u . (2.26) It follows from (2.24) and (2.26) that Claim 1 holds. Claim 2. M u3 t3 pM0 + p2 M02 + 4qS3 ≤ ln 2q u := M2 , (2.27) where M0 = eM1 . By (2.16), we have M M q t3M eu3 (t3 ) ≤ p t3M eu1 (t3 ) + S3 t3M S3 t M M ≤ p t3M eu1 (t1 ) + u (t3M ) . M u (t ) e3 3 e3 3 (2.28) That is, M M M q t3M e2u3 (t3 ) − p t3M eu1 (t1 ) eu3 (t3 ) − S3 t3M ≤ 0. Therefore, e u3 (t3M ) M M (2.29) p t3M eu1 (t1 ) + p2 t3M e2u1 (t1 ) + 4q t3M S3 t3M ≤ , 2q t3M (2.30) which implies that Claim 2 holds. Claim 3. For ui (tim )(i = 1,2), one of the following cases holds: 0 ≤ u1 t1m ≤ u2 t2m , m1 ≤ m∗1 − 2T D̄1 + b̄1 M0 + c̄M m1 ≤ m∗2 ≤ u2 t2m < u1 t1m , (2.31) where 0 ,m∗ m1 := min m∗1 − 2T D̄1 + b̄1 M0 + c̄M 2 , l u a1 /c − S3 /q , m∗1 := ln b1u /cl + (p/q)u a2 + a22 + 4b2 S2 m2 := ln 2b2 ∗ There are two cases to consider. (2.32) l . H. Fang and Z. Wang 7 Case 1. Assume that u1 (t1m ) ≤ u2 (t2m ); then u1 (t1m ) ≤ u2 (t1m − τ1 (t1m )). From this and (2.17), we have m m M M a1 t1m ≤ b1 t1m eu1 (t1 ) + c t1m eu3 (t1 ) ≤ b1 t1m eu1 (t1 ) + c t1m eu3 (t3 ) . (2.33) From (2.30), by using the inequality (a + b)1/2 < a1/2 + b1/2 , a > 0, b > 0, (2.34) we have e u3 (t3M ) M p t3M eu1 (t1 ) + q t3M S3 t3M < . q t3M (2.35) From this and (2.33), we have a1 t1m b1 t1m ≤ c tm p tM + 1 M 3 q t3 e u1 (t1M ) +c t1m M S3 t3 , q t3M (2.36) which implies a1 c l u p b1u ≤ + l c q e u1 (t1M ) + S u 3 q . (2.37) That is, M u1 t1 l a1 /c − S3 /q ≥ ln b1u /cl + (p/q)u u := m∗1 . (2.38) From the first equation of system (2.11), we obtain that T 0 T a1 (t)dt + = T 0 D1 (t)e T u (t) dt < 1 0 T D1 (t)dt + 0 T 0 u2 (t −τ1 (t))−u1 (t) 0 0 T + 0 D1 (t)e T D1 (t)dt + dt + b1 (t)eu1 (t) dt + T a1 (t)dt + T 0 T 0 0 S1 (t) dt eu1 (t) c(t)eu3 (t) dt, u2 (t −τ1 (t))−u1 (t) b1 (t)eu1 (t) dt + T dt + T 0 0 (2.39) S1 (t) dt eu1 (t) c(t)eu3 (t) dt. 8 Periodic solutions for predator-prey patch systems It follows that T 0 u (t) dt < 2 T T 1 ≤2 D1 (t)dt + 0 T 0 0 b1 (t)eu1 (t) dt + D1 (t)dt + eM1 T 0 T c(t)eu3 (t) dt 0 b1 (t)dt + eM2 T c(t)dt 0 (2.40) 0 . = 2T D̄1 + b̄1 M0 + c̄M From (2.38) and (2.40), we have u1 t1m ≥ u1 t1M − T 0 u (t) dt ≥ m∗ − 2T D̄1 + b̄1 M0 + c̄M 0 . 1 1 (2.41) Case 2. Assume that u1 (t1m ) > u2 (t2m ); then u1 (t2m − τ2 (t2m )) > u2 (t2m ). From this and (2.18), we have m b2 t2m eu2 (t2 ) ≥ a2 t2m + S2 (t2m ) m , eu2 (t2 ) (2.42) which implies e u2 (t2m ) a2 t2m + a22 t2m + 4b2 t2m S2 t2m ≥ . 2b2 t2m (2.43) That is, a2 + a22 + 4b2 S2 u2 (t2m ) ≥ ln 2b2 l := m∗2 . (2.44) It follows from (2.41) and (2.44) that Claim 3 holds. Claim 4. 0 + β̄M 0 := m2 , u3 t3m ≥ min m∗3 ,m∗4 ,m∗5 − 2T d¯ + q̄M (2.45) where m∗3 = ln ¯ p̄ K1∗ − d/ u , K + c/b1 m∗4 = ln ¯ p̄ K2∗ − d/ , K m∗5 = ln ¯ p̄ K ∗ − d/ u . K + c/b1 (2.46) From the third equation of (2.11), we obtain T 0 p(t)eu1 (t) dt + T 0 T 0 S3 (t) dt = eu3 (t) u (t) dt < 3 T 0 T 0 T d(t)dt + 0 p(t)eu1 (t) dt + T + 0 q(t)eu3 (t) dt + T 0 S3 (t) dt + eu3 (t) q(t)eu3 (t) dt + T 0 T 0 −τ k(s)eu3 (t+s) dsdt, T 0 0 β(t) 0 β(t) −τ d(t)dt k(s)eu3 (t+s) dsdt. (2.47) H. Fang and Z. Wang 9 It follows that T 0 u (t) dt < 2 T T 3 ≤2 d(t)dt + 0 T 0 0 T q(t)eu3 (t) dt + d(t)dt + eM2 T 0 0 β(t) 0 q(t)dt + eM2 −τ k(s)eu3 (t+s) dsdt T 0 (2.48) β(t)dt 0 + β̄M 0 , = 2T d¯ + q̄M M q̄ + β̄ eu3 (t3 ) ≥ p̄eu1 t1m ¯ − d. (2.49) There are two cases to consider. Case 1. Assume that the assumption (H3 ) holds. If u1 (t1m ) ≤ u2 (t2m ), by (2.17), we have e u1 (t1m ) m M S1 t m a1 t1m − c t1m eu3 (t1 ) m ≥ + m 1u1 (tm ) b1 t1 b1 t1 e 1 (2.50) S1 t m a1 t1m − c t1m eu3 (t3 ) m ≥ + m 1 M1 . b1 t1 b1 t1 e Substituting this into (2.49) gives [q̄ + β̄]e u3 (t3M ) M p̄S1 t m p̄a1 t1m p̄c t1m eu3 (t3 ) ¯ m − m ≥ + m 1 M1 − d, b1 t1 b1 t1 b1 t1 e (2.51) which implies q̄ β̄ c t1m S1 t m a1 t m M d¯ + + m eu3 (t3 ) ≥ 1m + m 1 M1 − . p̄ p̄ b1 t1 p̄ b1 t1 b1 t1 e (2.52) Therefore, c K+ b1 u M d¯ eu3 (t3 ) ≥ K1∗ − . p̄ (2.53) ¯ p̄ K1∗ − d/ u := m∗ 3. K + c/b1 (2.54) That is, u3 t3M ≥ ln It follows from (2.48) and (2.54)that u3 t3m ≥ u3 t3M − T 0 u (t) dt ≥ m∗ − 2T d¯ + q̄M 0 + β̄M 0 . 3 3 (2.55) If u1 (t1m ) > u2 (t2m ), by (2.42), (2.49), and (2.19), we have [q̄ + β̄]e u3 (t3M ) ≥ p̄e u2 (t2m ) p̄ a2 t2m + S2 t2m e−M1 ¯ − d¯ ≥ − d, b2 t2m (2.56) 10 Periodic solutions for predator-prey patch systems which implies q̄ β̄ u3 (t3M ) a2 t2m + S2 t2m e−M1 d¯ m + − . e ≥ p̄ p̄ p̄ b2 t2 (2.57) Therefore, Keu3 t3M ≥ K2∗ − d¯ . p̄ (2.58) That is, ¯ p̄ K2∗ − d/ := m∗4 . K u3 t3M ≥ ln (2.59) From (2.48) and (2.59), we have u3 t3m ≥ u3 t3M − T u (t) dt ≥ m∗ − 2T d¯ + q̄M 0 + β̄M 0 . 3 0 4 (2.60) Case 2. Assume that the assumption (H4 ) holds. From (2.17), we have b1 t1m e u1 (t1m ) m ≥ a1 t1m m − D1 t1m −c t1m e u3 (t1m ) S1 t m + u1 (t1m ) e 1 (2.61) a1 t1m − D1 t1m − c t1m eu3 (t3 ) + S1 t1m e−M1 ≥ . b1 t1m (2.62) m ≥ a1 t1 − D1 t1 − c t1 e u3 t3M S1 t m + M11 . e Therefore, e u1 (t1m ) M Substituting this into (2.49) gives [q̄ + β̄]e p̄ a1 t1m − D1 t1m ≥ b1 t1m M p̄c t1m eu3 t3 − b1 t1m p̄S1 t m ¯ + m 1 M1 − d, b1 t1 e (2.63) q̄ β̄ c t1m a1 t1m − D1 t1m + S1 t1m e−M1 d¯ M m + + m eu3 (t3 ) ≥ − . p̄ p̄ b1 t1 p̄ b1 t1 (2.64) u3 (t3M ) which implies Therefore, c K+ b1 u M d¯ eu3 (t3 ) ≥ K ∗ − . p̄ (2.65) ¯ p̄ K ∗ − d/ u := m∗ 5. K + c/b1 (2.66) That is, u3 t3M ≥ ln H. Fang and Z. Wang 11 It follows from(2.48) and (2.66)that u3 t3m ≥ u3 t3M − T u (t) dt ≥ m∗ − 2T d¯ + q̄M 0 + β̄M 0 . 3 0 5 (2.67) It follows from (2.55), (2.60), and (2.67) that Claim 4 holds. Clearly, one of the following inequalities holds: (i) M1∗ > m∗2 , (ii) M1∗ ≤ m∗2 . Since m∗1 < M1∗ and m∗2 ≤ M2∗ , (ii) implies M2∗ > m∗1 . Thus, according to Claims 1–3, one of the following four cases must hold: 0 ) ≤ u1 (t1m ) ≤ u2 (t2m ), u2 (t2M ) ≤ u1 (t1M ) ≤ M1∗ ≤ M1 ; (P1 ) m1 ≤ m∗1 − 2T(D̄1 + b̄1 M0 + c̄M m m ∗ (P2 ) m1 ≤ m2 ≤ u2 (t2 ) < u1 (t1 ), u2 (t2M ) ≤ u1 (t1M ) ≤ M1∗ ≤ M1 ; 0 ) ≤ u1 (t1m ) ≤ u2 (t2m ), u1 (t1M ) < u2 (t2M ) ≤ M2∗ ≤ (P3 ) m1 ≤ m∗1 − 2T(D̄1 + b̄1 M0 + c̄M M1 ; (P4 ) m1 ≤ m∗2 ≤ u2 (t2m ) < u1 (t1m ), u1 (t1M ) < u2 (t2M ) ≤ M2∗ ≤ M1 . From this and Claims 3 and 4, we have max ui (t) ≤ max M1 , M2 , m1 , m2 := M ∗ , t ∈[0,T] i = 1,2,3. (2.68) Obviously, M ∗ is independent of λ. Set Bi∗ := āi + 2 āi i = 1,2. + 4b̄i S̄i , (2.69) Take sufficiently large M such that M > 3max M ∗ , m∗1 , m∗2 , m∗3 , m∗4 , m∗5 , M > v1∗ + |v2∗ + v3∗ , (2.70) where v1∗ = ln B1∗ , 2b̄1 v2∗ = ln B2∗ , 2b̄2 2 p̄B1∗ + [ p̄B1∗ ]2 + 16 b̄1 v3∗ = ln 4b̄1 q̄ + β̄ (2.71) q̄ + β̄ S̄3 . Clearly, the condition (i) in Lemma 2.1 is satisfied by system (2.7). Define H(u1 ,u2 ,u3 ,μ) : R3 × [0,1] → R3 by ⎛ ⎜ ⎜ ⎜ H u1 ,u2 ,u3 ,μ = ⎜ ⎜ ⎜ ⎝ ⎞ S̄1 ⎛ ⎞ ⎟ eu1 ⎟ D̄1 eu2 −u1 − c̄eu3 − D̄1 ⎟ ⎟ S̄ ⎟ + μ⎜ ⎝ D̄2 eu1 −u2 − D̄2 ⎠ . ā2 − b̄2 eu2 + u22 ⎟ ⎟ e ¯ −d S̄ ⎠ p̄eu1 − [q̄ + β̄]eu3 + u33 e ā1 − b̄1 eu1 + (2.72) 12 Periodic solutions for predator-prey patch systems We show that H u1 ,u2 ,u3 ,μ = 0 for any u = u1 ,u2 ,u3 ∈ ∂BM R3 , μ ∈ [0,1]. (2.73) Indeed, assume to the contrary, that H u∗1 ,u∗2 ,u∗3 ,μ∗ = 0 for some u∗ = u∗1 ,u∗2 ,u∗3 ∈ ∂BM R3 , μ∗ ∈ [0,1]. (2.74) Then, there exist ti ∈ [0,T], i = 1,2, such that ∗ ∗ ∗ S1 t1 a1 t1 − b1 t1 e + u∗ + μ∗ D1 t1 eu2 −u1 − μ∗ c t1 eu3 − μ∗ D1 t1 = 0, e1 ∗ S2 t2 ∗ ∗ a2 t2 − b2 t2 eu2 + u∗ + μ∗ D2 t2 eu1 −u2 − μ∗ D2 t2 = 0, e2 ∗ S̄3 ∗ −μ∗ d¯ + p̄eu1 − q̄ + β̄ eu3 + u∗ = 0. e3 u∗ 1 (2.75) By using the arguments of (2.19), (2.20), (2.27), (2.38), (2.44), (2.54), (2.59), (2.66), one can prove that ∗ u ≤ max M1 , M2 , m∗ , m∗ , m∗ , m∗ , m∗ |, i 1 2 3 4 5 i = 1,2,3, (2.76) which implies that u∗ = |u∗1 | + |u∗2 | + |u∗3 | ≤ 3max{M ∗ , |m∗1 |, |m∗2 |, |m∗3 |, |m∗4 |, ∗ 3 |m∗ 5 |} < M. This contradicts the fact that u ∈ ∂BM (R ). Therefore, H(u1 ,u2 ,u3 ,μ) is a homotopy. Since ⎛ ⎞ S̄1 u u u −u ⎜ā1 − D̄1 − b̄1 e 1 − c̄e 3 + D̄1 e 2 1 + u1 ⎟ e ⎟ ⎜ ⎜ ⎟ S̄2 ⎟ = H u1 ,u2 ,u3 ,1 , u u −u g(u) = ⎜ ⎜ ā2 − D̄2 − b̄2 e 2 + D̄2 e 1 2 + u2 ⎟ ⎜ ⎟ e ⎝ ⎠ S̄3 u u ¯ 1 3 −d + p̄e − [q̄ + β̄]e + u 3 e (2.77) g(u) = 0 for any (u1 ,u2 ,u3 ) ∈ ∂BM (R3 ). Thus, the condition (ii) in Lemma 2.1 is satisfied. Next we show that condition (iii) also holds. It is easy to see that H(u1 ,u2 ,u3 ,0) = 0 has a unique solution v∗ = (v1∗ ,v2∗ ,v3∗ ), where v1∗ ,v2∗ ,v3∗ are the same as those in (2.71). Clearly, v∗ = |v1∗ | + |v2∗ | + |v3∗ | < M, that is, v∗ ∈ BM (R3 ). According to the invariance of homotopy, we obtain deg g,BM R3 = deg H(·,1),BM R3 = deg H(·,0),BM R3 = −1. (2.78) Therefore, all of the conditions required in Lemma 2.1 hold. According to Lemma 2.1, system (2.7) has one T-periodic solution (u∗1 (t),u∗2 (t),u∗3 (t))T . It is easy to see that (x1∗ (t), x2∗ (t), y ∗ (t))T = (exp[(u∗1 (t)],exp[u∗2 (t)],exp[u∗3 (t)])T is a positive T-periodic solution of system (1.1). By the arguments similar to Claims 1–4, one can show m1 ≤ u∗i (t) ≤ M1 (i = 1,2), m2 ≤ u∗3 (t) ≤ M2 , t ≥ 0, (2.79) H. Fang and Z. Wang 13 which implies m0 ≤ xi∗ (t) ≤ M0 (i = 1,2), 0 , m 0 ≤ y ∗ (t) ≤ M t ≥ 0. (2.80) The proof is complete. Consider the special case of system (1.1) that Si (t) ≡ 0, i = 1,2,3. 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Hui Fang: Faculty of Information Science and Engineering, Ningbo Institute of Technology, Zhejiang University, Ningbo, Zhejiang 315100, China E-mail address: huifang@public.km.yn.cn Zhicheng Wang: Department of Applied Mathematics, Hunan University, Changsha 410082, China E-mail address: zcwang2004@163.com