Ohmic contacts • Common techniques to make ohmic contacts – – – • Ohmic contacts should be – – – – • Choose metal so that its work function Fmetal is close to that of semiconductors Fsemi (thermal ionic) Insert thin layer of narrow bandgap material between metal and semiconductor Increase the doping level near the semiconductor surface as high as possible (tunneling assisted) Low contact resistance (< 10-6 Ωcm2) Thermally stable (does not degrade at elevated temperature or react with oxygen), which requires no phase change or no phase change leading to high resistance Smooth morphology Compatibility with the whole device process Both semiconductors and metal sources should be CLEAN! Michaelson, IBM J. of R&D, 1978 Slide # 1 Common Techniques for Ohmic contacts (i) Ohmic contact by band alignment Evac φM Evac EF χ EF φM < χ+Ec-EF = φS For n-type semiconductor. Reverse for p-type φB = φS - φM n doped φB = band bending (ii) Ohmic contact by high doping • Usually for compound semiconductors the ohmic contact by band alignment is hard to realize due to surface states and Fermi pinning. For p-type, the problem is caused by unavailability of metals with large enough work function • High n-type doping required for ohmic contacts to n-type semiconductors, which can also be realized by interfacial layer reaction chemistry n-doped n+ doped Electrons from conduction band can move very easily to the metal and vice versa by tunneling Slide # 2 Ohmic on n-GaN • Possible metals: Ag, Nb, Ti, Al, In, Ta, Cr – – • • Ag: poor adhesion Nb: extremely easy to oxidize thus difficult to process – Ti: formation of TiN (intermetallic) and high N vacancies in GaN -> good! But easy to oxidize… need a stable cap like Au – Al: formation of AlN (not intermetallic) and high N vacancies in GaN -> ok! Also easy to oxidize… Au cap is necessary – In: most popularly used for quick contacts – Ta: studied by Qiao et al. 5.7e10-7 Ωcm2 on AlGaN/GaN (2001); but others could not reproduce the results – Others: also studied but not as good as the one below As deposited or alloy: generally alloyed unless doping near the surface is very high! Popular schemes: Ti/Al/Ni/Au – – – – Ti/Al bilayer: formation of N vacancies, TiN, Al3Ti (thermally very stable ☺); but ratio of Ti/Al has to be carefully controlled (~1/2.5) Add high conductive and protective layer of Au, but Au diffuses easily Add Ni as diffusion barrier (decent, other metals were tried, Pd and Pt were worse) State-of-art: 0.1-0.2 Ωcm2 (~ 10-8 Ωcm2 ) Lim et al, APL 78, 3797(2001) Liu et al, Solid State Electronics, 42, 677(1998) Slide # 3 Schottky contacts • Schottky contacts are formed when Evac Evac φs χ φM Doping in the EF semiconductor is not very high i.e. > ~5x1018 cm-3 The metal work function is greater than the n- type φM > χ+Ec-EF = φS semiconductor work For n-type semiconductor and function reverse for p-type The metal work function is lower than p-type Schottky contact Electrons from φBn = semiconductor work conduction band φM -χ function or in the metal faces barrier to Very high density of free movement, surface states “pinning” the n doped Fermi level at the surface and tunneling is w.r.t. the conduction band also not easy (Example: GaAs) Slide # 4 Conduction mechanisms in schottky contacts • Thermionic emission Electrons emit over the barrier Low probability of direct tunneling Valid for low doping (ND < ~ 1017 cm-3) • Thermionic-field emission Electrons use thermal energy to tunnel trough the thin barrier in the upper end of the conduction band Valid for intermediate doping (~ 1017 cm-3 < ND < ~ 1018 cm-3) • Field emission Direct tunneling, as depletion region is very narrow Valid for heavy doping (ND > ~ 1018 cm-3); almost ohmic • Leakage current High probability of defect-assisted tunneling and simple conduction Occurs in poor material/interface quality; dislocations Slide # 5 Thermionic emission current: Schottky diode I-V characteristics Typical I-V characteristics Forward bias Reverse bias Schottky diode I-V equation: J = J0 (e qV / kT – 1), where J0 is the saturation current density given by qφ J o = A*T 2 exp − Bn T = temperature, A* = effective Richardson’s constant kT 6 Slide # Schottky on n-GaN • • Experimentally shown very weak surface pinning Surface cleanness has been heavily investigated, however – – • Thermal stability is IMPORTANT – – – • • External cleaning is generally sufficient to achieve decent Schottky Leakage is largely due to dislocations Ni does not react with GaN below ~ 600 C Pd reacts with GaN at ~ 400-500 C W and Rd ~ 600 C The higher the schottky barrier, the lower the leakage current Using polarization in nitrides i.e. GaN/AlGaN/GaN structure, the schottky barrier can be made larger Liu et al, Solid State Electronics, 42, 677(1998) Slide # 7 Electrical properties of dislocations in MBE-grown n-GaN (Ed Yu --- UCSD) • Pure screw dislocations can be highly conductive in MBE-grown n-GaN: topography: 1µm current: 1µm [E. J. Miller, D. M. Schaadt, E. T. Yu, C. Poblenz, C. Elsass, J. Speck, J. Appl. Phys. 91, 9821 (2002).] • Edge and mixed dislocations typically contain negative charge in dislocation core: high current leakage in Schottky contacts Screw: conducting, uncharged Edge: nonconducting , –e charge Mixed: nonconducting, –e charge scattering, local carrier depletion [B.S. Simpkins, E.T. Yu, P. Waltereit, J.S. Speck, J. Appl. Phys. 94, 1448 (2003).] Slide # 8 Mitigation of dislocation-induced leakage currents in MBE n-GaN (Ed Yu, UCSD) AFM AFM 2µm 2µm current current AFM 1µm current ~10µA 1µm with electrochemical process • NaOH solution • V = 30V • pH = 13.1 • I ~ 1-10mA • T = 30°C • t = 1000s ~100pA φb = 0.80±0.02V n = 1.74±0.01 φb = 0.86±0.02V n = 1.13±0.02 AFM unmodified area = 1.23×10-4cm2 1µm [E. J. Miller, D. M. Schaadt, E. T. Yu, P. Waltereit, C. Poblenz, and J. S. Speck, Appl. Phys. Lett. 82, 1293 (2003).] Slide # 9 Ohmic to p-GaN • Similar techniques like ohmic to n-GaN have been tried, but: – • P-GaN/Ni/Au annealed in air (N2/O2) proved to be one of the best: – • rC~ 10-6 Ωcm2 Why? – – • rC~ 10-3 Ωcm2 After annealing, new phases form: NiO, NiGa-O with Au particles, GaN NiO is p-semiconductor with high Ni vacancies Continuing challenges: – – – Transparency to visible and UV Ohmic to p-AlGaN Tunneling junction contacts Ho et al. JAP 85, 4491 (1999) Slide # 10 Another Contact Metal for p-GaN • The absence of a metal with a sufficiently high work function. The band gap of GaN is 3.4 eV, and the electron affinity is 4.1 eV, but metal work functions are typically ~ 5 eV • The relatively low hole concentrations in p-GaN due to the deep ionization level of the Mg acceptor ~170 meV • The tendency for the preferential loss of nitrogen from the GaN surface during processing, which may produce surface conversion to n-type conductivity. TEM image • Palladium gallide creates Ga vacancies that reduce contact resistances • Temperature and time of anneal also important Slide # 11 Schottky to p-GaN • • Schottky (Ni) on as grown GaN:Mg (MOCVD) --- quasi-ohmic (higher Mg near the surface?) Schottky (Ni) on etched GaN:Mg --- rectifying (tunneling and defect-assisted tunneling still significant thus it is difficult to extract barrier height and Richardson constant from I-V) Slide # 12 Schottky contact characterization • Current-Voltage (IV) measurements * 2 J0 = A T e − qφ Bn kT . VF vs. J intercept gives J0 and φ Bn kT A*T 2 ln = q J 0 • Capacitance-Voltage (CV) measurements 1 qε s N D 2ε s ⇒ 2 ∝ (φBn − V ) (φBn − V ) ⇒ C = W= C 2(φ Bn − V ) qN D – So the intercept of 1/C2 vs. V gives the barrier height • Photoelectric measurements (by photon incident on the schottky contact; this is very accurate) – Photocurrent R is related to the barrier height as R ~ hv − qφBn So the intercept gives the barrier height Slide # 13 Evaporation systems Contact Metallization (Ti, Al, Ni, Au etc) Metal Electron-Beam Evaporation System Sample Target Metal Source with e-beam Rapid Thermal Annealing System from 20 oC to 1000 oC in seconds Slide # 14 Ohmic contacts: n-type or undoped nitride • Standard recipe for ohmic contact: – Ti/Al/Ti/Au or Ti/Al/Ni/Au deposition. Ti/Al thickness ratio is important – Annealing at 800 – 900 ºC for about 1 min for alloying. Alloying temperature and alloying time are important factors controlling contact resistance. Ti/Al/Ni/Au Since TiN and AlN are formed by reaction between the nitride layers and Ti or Al, Nvacancies are created, which can dope the contact region and create ohmic contact Slide # 15 Specific contact resistivity and sheet resistance For any semiconductor device there are two main resistances: • Contact resistance • Semiconductor resistance d Z t Product of contact resistance Rc and area A is called specific contact resistivity ρc: ρc = 1 ∂J ∂V V =0 (Ω . cm2) (Can also be expressed in terms of Ω . mm) Semiconductor layer resistivity ρ: 1 ρ= enµ (Ω . cm) Sometimes semiconductor resistance is expressed in terms of sheet resistance ρsh 1 ρ = ρ sh = t (e n µ ) t (Ω/ ) The total semiconductor resistance is then given by d 1 ρd (Ω) Rs = ∫ ρ dx = A0 Zt Slide # 16 Ohmic contact characterization: Transmission line method (TLM) I(x) L I(x+∆x) ρsh∆x/Z V(x) ρc/(Z∆x) V(x +∆x) ∆I dI V ( x) Z =− dx ρc Iρ Iρ dV = − s = − sh dx Zt Z d 2 I I ( x) ρc ⇒ 2 = 2 , where LT = ρ sh dx LT The solution for I(x) is given as: is called the transfer length. I ( x ) = Ae x / LT + Be − x / LT Now putting the boundary condition I(x = L) = 0, and finding the solution for V(x), we can find the contact resistance as the ratio of the input voltage and input current as: RC = V (x = 0 ) I ( x = 0) Slide # 17 Transmission line method (TLM) II L coth The contact resistance Rc is then given by: RC = ZLT LT ρ For L >>LT , we have, RC = C Ohmics ZLT ρC Z When the following conditions are further d satisfied, d << Z and t << LT (to avoid t current spreading in the sides or into the film), ρsh = ρ /t ρ sh d Then, RTot = 2 Rc + Rs = 2 Rc + Z Putting Rtot = 0, and using the relation ρ c = Rc LT Z , we have, d ( RT = 0) = − 2 LT . So, the transfer length can be found from the intercept of the total resistance on the x-axis. Note that the contact resistivity is not given by the product of the contact resistance and the total contact area, but by the product of contact resistance, width Z, and transfer length LT. Slide # 18 L Measurement technique 100 Typical measurement set up B1205 UV LED n-TLM Current, mA 50 4um 6um 8um 10um 12um 14um 16um 0 -50 -100 -2 -1 0 1 2 Voltage, V 40 Slope = ρsh/Z 30 What is wrong in this measurement? Resistance, Ohm Plot of total resistance vs. distance B1205 UV LED n-TLM 20 Y =14.51607+1.13839 X Rc=7.258Ω LT=6.373um 10 ρc=6.93*10-5Ω-cm2 Rsh=170.7Ω/sq 0 0 5 10 15 gap, um Slide # 19 20