• Follow the powerpoint as an example of how to calculate the mass of the
barium phosphate product ( in filter paper)with your data, we will use only the
Barium Chloride as the known or starting point. The amount of the barium
phosphate product should be compared to your experimental lab mass to get
the percent error.
• The calculation should be neat and well explained, submit a picture by
Wednesday midnight
• The formula of the barium chloride is BaCl2 2 H20, a hydrate, and its molar mass
is 244.
• After you have calculated your yield of barium phosphate from the 1.2 grams of
barium chloride, you should do the calculation using sodium phosphate
( 1.7.grams) as the known.
• Study the other slides as examples with other reactions.
REACTION STOICHIOMETRY(II) FACTOR LABEL LOGIC
2 Na2PO4(s) + 3 BaCl2 (s) 6 NaCl(aq) + 2 Ba3PO4(s)
1) CALCULATE THE YIELD OF BARIUM PHOSPHATE IN
GRAMS IF 1.2 GRAMS OF BARIUM CHLORIDE IS CONSUMED
IN THE ABOVE BALANCED REACTION.
KNOWN
1.2 g BaCl2
DATA
1 mol BaCl2
2 mol
Ba3PO4
600 g
Ba3PO4
244 gBaCl2
3 mol BaCl2
1 mol
Ba3 PO4
( ) ( )( )
(1) CONVERT KNOWN TO
MOLES FROM GRAMS,
GRAMS CANCEL. MOLAR
MASS OF BaCl2 IS 244
G/MOL. GIVES MOLES OF
KNOWN
MOLES =
MASS
MOLAR MASS
(2) MOLE RATIO: RATIO
MOLES OF OBJECTIVE
TO MOLES OF KNOWN.,
USE COEFFICIENTS OF
BALANCED REACTION.
THIS STEP GIVES MOLES
OF OBJECTIVE.
=
OBJECTIVE
Ba3PO4
(3) CONVERT MOLES OF
OBJECTIVE TO GRAMS.
THIS STEP GIVES GRAMS
OF OBJECTIVE, WHICH
THE QUESTION CALLED
FOR
REACTION STOICHIOMETRY(II) FACTOR LABEL LOGIC
2 H2(g) + O2 (g) 2 H20(g)
1) CALCULATE THE YIELD OF OXYGEN IN GRAMS IF 4.0
GRAMS OF WATER IS CONSUMED IN THE ABOVE BALANCED
REACTION.
KNOWN
4.O g H2O
( ) ( )( )
1 mol H2O
2 mol H2O
36 g O2
18 gH2O
1 mol O2
1 mol H2O
CONVERT KNOWN TO
MOLES FROM GRAMS,
GRAMS CANCEL.
MOLAR MASS OF O2 IS
18 G/MOL. GIVES
MOLES OF KNOWN.
MOLES =
MASS
MOLAR MASS
MOLE RATIO: RATIO
MOLES OF OBJECTIVE
TO MOLES OF KNOWN.,
USE COEFFICIENTS OF
BALANCED REACTION.
THIS STEP GIVES MOLES
OF OBJECTIVE.
=
OBJECTIVE
16 g H2O
CONVERT MOLES OF
OBJECTIVE TO GRAMS.
THIS STEP GIVES GRAMS
OF OBJECTIVE, WHICH
THE QUESTION CALLED
FOR
REACTION STOICHIOMETRY FACTOR LABEL LOGIC
2 CH3OH + 3 O2 (g)  2 CO2 (g) + 4 H2O
2) CALCULATE THE TOTAL MASS OF PRODUCTS FORMED
FROM 1 MOLE OF METHANOL.
KNOWN
1 MOLE CH3OH
KNOWN
1 MOLE CH3OH
( )( ) =
2 mol CO2
44. g CO2
2 MOLE CH2OH
1 mol CO2
( )( )
4 mol H2O
18. g H2O
2 MOLE CH2OH
1 mol H2O
OBJECTIVE
44 g CO2
=
OBJECTIVE
36 g LH2O
THE SUM OF BOTH
PRODUCTS IS 80. g