Surface Area and Volume

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SURFACE AREA and VOLUME
Solid Figures Introduction
CYLINDERS
PRISMS
PYRAMIDS
SPHERES
CONES
APPENDIX
SURFACE AREA and VOLUME
SOLID FIGURES
In a previous unit we discussed POLYGONS.
POLYGONS are 2-dimensional objects.
That means they have length and width, but no depth.
Like they are cut out of paper.
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SURFACE AREA and VOLUME
SOLID FIGURES
In this unit, we will learn about SOLIDS.
A SOLID is a 3-dimensional (3D) object.
That means it has length, width AND depth.
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SURFACE AREA and VOLUME
SOLID FIGURES
When the SOLID is made up of POLYGONS, it is called a
POLYHEDRON
Each POLYHEDRON is made up of
Surfaces (called faces)
Segments (called edges)
Corners (called vertices)
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SOLID FIGURES
There are many types of solids,
we are going to study the 5 basic types:
PRISM
CYLINDER
PYRAMID
CONE
SPHERE
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SURFACE AREA and VOLUME
SOLID FIGURES
PRISMS: To create a prism, draw any polygon you like.
Next, draw another polygon, just like the first one
Connect the corresponding vertices
BASE
BASE
BASE
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SURFACE AREA and VOLUME
SOLID FIGURES
PRISMS:
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SURFACE AREA and VOLUME
SOLID FIGURES
PYRAMIDS: Pyramids have one base
Instead of connecting to an identical base…
They connect to a point.
BASE
BASE
BASE
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SOLID FIGURES
Pyramids:
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SOLID FIGURES
When we name prisms and pyramids, we describe the base
to tell what kind of prism or pyramid it is.
BASE
PRISM
PYRAMID
Triangle
Triangular Prism
Triangular Pyramid
Rectangle
Rectangular Prism
Rectangular Pyramid
Pentagon
Pentagonal Prism
Pentagonal Pyramid
Hexagon
Hexagonal Prism
Hexagonal Pyramid
Heptagon
Heptangonal Prism
Heptangonal Pyramid
Octagon
Octagonal Prism
Octagonal Pyramid
Decagon
Decagonal Prism
Decagonal Pyramid
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SOLID FIGURES
CYLINDERS: A cylinder is like a prism…
But the bases are circles
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SOLID FIGURES
Cylinders:
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SURFACE AREA and VOLUME
SOLID FIGURES
CONES: A cone is a circular pyramid.
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SURFACE AREA and VOLUME
SOLID FIGURES
Cones:
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SURFACE AREA and VOLUME
SOLID FIGURES
SPHERES: A sphere is a unique shape...
It has no base or sides or edges or vertices.
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SURFACE AREA and VOLUME
SOLID FIGURES
SPHERES:
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SURFACE AREA and VOLUME
SOLID FIGURES
Identify each of the following shapes as a
PRISM, PYRAMID, CYLINDER, CONE or SPHERE
#1
#2
#3
SPHERE
#5
CYLINDER
#4
PRISM
#6
PYRAMID
#7
CYLINDER
#8
PRISM
CONE
PYRAMID
#9
#10
SPHERE
CONE & SPHERE
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SOLID FIGURES
So what are we going to do with these shapes?
We are going to calculate
SURFACE AREA and VOLUME
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SURFACE AREA and VOLUME
SOLID FIGURES
SUFARCE AREA:
Is literally the area of all the surfaces of a solid.
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SURFACE AREA and VOLUME
SOLID FIGURES
SUFARCE AREA:
Is literally the area of all the surfaces of a solid.
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SURFACE AREA and VOLUME
SOLID FIGURES
SUFARCE AREA:
Is literally the area of all the surfaces of a solid.
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SURFACE AREA and VOLUME
SOLID FIGURES
SUFARCE AREA:
Is literally the area of all the surfaces of a solid.
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SOLID FIGURES
VOLUME:
Is the measure of how much “space” an object occupies.
It is often thought of as how much water an object can hold.
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SOLID FIGURES
VOLUME:
Or how many cubic units it would take to fill an object
This is why
volume is
measured in
CUBIC UNITS
Like:
Cubic feet:
ft3
Cubic centimeters
cm3
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PRISMS
A prism is a solid with 2 congruent BASES connected by
LATERAL FACES
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Late
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SURFACE AREA and VOLUME
PRISMS
To find the surface area of a PRISM, you can do it 2 ways:
Method 1:
Find the area of each shape that makes up the
Solid, and add them together
10
6
2
The front
2 x 10 = 20
The back
2 x 10 = 20
The left
6 x 10 = 60
The right
6 x 10 = 60
The top
2x6
= 12
The bottom
2x6
= 12
= 184
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PRISMS
To find the surface area of a PRISM, you can do it 2 ways:
Method 2:
Use the formula for SURFACE AREA:
•Identify the BASEs
(in a rectangular prism any pair of opposite sides can be bases)
•Find the Area and Perimeter of the base
Surface Area
•
( S . A.)  2 B  ph
10
6
SA  2 12  16 10
 24 160
 184
2
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PRISMS
Find the surface area of this regular decagonal prism:
SA  2 B  ph
Find the perimeter of the base
SA  2  270  60  4
6+6+6+6+6+6+6+6+6+6 =60
Area of
the bases
Lateral
Area
 540  240
 780m
2
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PRISMS
Finding Volume is easier!
Find the VOLUME of this regular decagonal prism:
Volume : B  h
Volume  270 4
 1080m
3
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PRISMS
RIGHT PRISMS
A right prism is a prism
where the lateral faces are
all perpendicular to the
bases.
vs
OBLIQUE PRISMS
An oblique prism is a prism
where the lateral faces are
NOT perpendicular to the
bases.
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PRISMS
SUMMARY:
Things you need to know about a prism:
A prism has 2 bases
All the lateral faces are rectangles
Surface Area = 2B + ph
B is the area of the base
p is the perimeter of the base
h is the height of the prism
p x h gives the lateral area
Volume = B x h
B is the area of the base
h is the height of the prism
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PRISMS
Find the…
…Surface Area
3cm
4cm
2cm
…Lateral Area
…Volume
3cm
4cm
5cm
First we have to find
that missing side
Use the Pythagorean
theorem
A: 6cm2
P: 12cm
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PRISMS
Find the…
…Surface Area
…Lateral Area
 2 B  ph
 2  6 12  2
 12  24
 36cm 2
3cm
4cm
5cm
2cm
 24cm 2
…Volume
 Bh
 6 2
 12cm 3
A: 6cm2
P: 12cm
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PRISMS
Find the surface area
and volume.
SA  2 B  ph
SA  2 136  52  5
SA  272  260
 532 ft 2
V  Bh
10
6
24
8
112
14
Area: 136ft2
Perimeter: 52ft
V  136  5
 680 ft 3
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PRISMS
Find the volume.
9 14  8
1008
 1008  880
 1888u 2
1110  8
880
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PRISMS
Archimedes problem.
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SURFACE AREA and VOLUME
CYLINDERS
Since CYLINDERS are like prisms with circular
bases,
We need to remember a few basic rules
for circles.
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CYLINDERS
Find the Circumference and area of the circle:
Circumference  2 r
 2 6
 12
 37.68 in
6in
Area   r 2
 6
2
 36
 113.04 in 2
The red segment is the DIAMETER
We need the RADIUS
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CYLINDERS
A CYLINDER is like a prism with circular bases
The surface area of a cylinder can be
found with this formula
r
SA  2B  ch
Area of
the bases
Lateral
Area
h
Most people find this formula easier:
SA  2 r  2 rh
2
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CYLINDERS
Find the SURFACE AREA of this cylinder:
SA  2 r  2 rh
2
 2 32  2 3 10
3 ft
 18  60
10 ft
 78
2
 244.92 ft
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CYLINDERS
The VOLUME of a Cylinder:
The VOLUME of a cylinder can be
found with this formula
r
V  Bh
h
The expanded version of the formula:
V r h
2
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SURFACE AREA and VOLUME
CYLINDERS
Find the VOLUME of this cylinder:
V r h
2
  3  10
  9  10
 90
2
3 ft
10 ft
 282.6ft
3
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SURFACE AREA and VOLUME
CYLINDERS
SUMMARY
What you need to know about a cylinder:
•A cylinder is a prism with circular bases
r
•The lateral area is a rectangle
•Surface Area:
•Volume:
SA  2 r  2 rh
2
h
V   r 2h
•Lateral Area:
LA  2 rh
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SURFACE AREA and VOLUME
CYLINDERS
Find the Lateral Area, Surface Area and Volume:
LA  2 rh
 2 11  9
 198
 621.72mm2 9mm
SA  2 r  2 rh
 2 112  2 11 9
 242  198
 440  1381.6mm2
2
11mm
V   r 2h
2
  11  9
 3419.46mm3
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SURFACE AREA and VOLUME
CYLINDERS
Find the surface area and volume of this shape
31ft
8ft
If it was a complete cylinder:
SA  2 r  2 rh
 2 82  2 8  31
2
 1959.36 ft
31ft
2
But we only want half of it
 979.68 ft 2
What did we forget?
 979.68  496
2
 1475.68 ft
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SURFACE AREA and VOLUME
CYLINDERS
Find the surface area and volume of this shape
31ft
8ft
If it was a complete cylinder:
V r h
2
  8  31
 6,229.76ft 3
2
But we only want half of it
 3,114.88ft
3
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SURFACE AREA and VOLUME
PYRAMIDS
A PYRAMID is a shape with a single base, where all the vertices
of the base are connected to a single point (apex)
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SURFACE AREA and VOLUME
PYRAMIDS
Just like with prisms, we will need to find:
height
•Base Perimeter
•Base Area
•Height of the pyramid
However, with pyramids, we will
also need to find a different
measurement…
…SLANT HEIGHT
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SURFACE AREA and VOLUME
PYRAMIDS
Slant height is the distance
someone would travel walking up
the OUTSIDE of a pyramid.
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SURFACE AREA and VOLUME
PYRAMIDS
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PYRAMIDS
Finding the SURFACE AREA of a PYRAMID
1
SA  B  Pl
2
Rectangular Pyramid
25m
22m
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22m
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SURFACE AREA and VOLUME
PYRAMIDS
Finding the SURFACE AREA of a PYRAMID
1
SA  B  Pl
2
Rectangular Pyramid
1
 484  88  25
2
 484  1100
25m
Lateral
Area
 1584m
2
22m
22m
Base Area: 484m2
Base Perimeter: 88m
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PYRAMIDS
Finding the VOLUME of a PYRAMID
Rectangular Pyramid
11ft
8ft
10ft
80ft2
Base Area:
Base Perimeter: 36ft
1
V  Bh
3
1
V  80 11
3
 293.3ft 3
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PYRAMIDS
SUMMARY:
Things you need to know about a pyramid:
A pyramid has only 1 base
All the lateral faces are triangles
Surface Area = SA  B 
1
Pl
2
B is the area of the base
p is the perimeter of the base
l is the slant height of the pyramid
½ x p x l is the lateral area
V
h
l
1
Bh
3
Volume =
B is the area of the base
h is the height of the prism
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PYRAMIDS
Hey, I need to know the slant height.
15
Hey, I need to know the height.
12 2  h 2  20 2
2
144  h  400
h 2  256
h  16
82  152  L2
2
289  L
17  L
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SURFACE AREA and VOLUME
PYRAMIDS
Find the Lateral Area, Surface area and Volume:
1
SA  B  Pl
2
B:
P:
400
80
Lateral
Area
1
LA  Pl
2
1
  80  26  1040u 2
2
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SURFACE AREA and VOLUME
PYRAMIDS
Find the Lateral Area, Surface area and Volume:
1
SA  B  Pl
2
1
SA  400  80 26
2
B:
P:
400
80
SA  1440u 2
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PYRAMIDS
Find the Lateral Area, Surface area and Volume:
1
V  Bh
3
h
B:
P:
400
80
1
V  400 h
3
102  h 2  262
100  h 2  676
h  576
2
1
V  400 24
3
V  3200u
3
h  24
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SURFACE AREA and VOLUME
PYRAMIDS
Find the Volume:
48  44
1
12 11
3
92u 2
44
4 6 2
48
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CONES
A CONE is basically a pyramid with a circular base
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CONES
R: radius
H: height
L: slant height
L
H
Lateral
Area
SA  B   r l
or
SA   r   r l
2
R
1 2
V  r h
3
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CONES
SA   r   r l
 25    5 13
 25  65
2
 90
 282.6in
2
1
V   r2h
3
1
   52 12
3
 100
Find the slant height with
the Pythagorean Theorem
13
12in
Find the surface area and
volume for the cone shown:
5in
 314in
3
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CONES
Find the surface area and volume:
SA   r   r l
  92    9 15
 678.24u 2
2
1 2
V  r h
3
1
   9 2 12
3
 3052.08u
2
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CONES
Find the Lateral Area:
Lateral
Area
SA  B   r l
  3 5
5
47.1u 2
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CONES
Find the Volume:
Cylinder:
V  2 r h
 2 10 2 18
2
TOTAL:
 12,560m3
 11304m3
Cone:
1 2
V  r h
3
1
  10 2 12
3
 1256m3
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SPHERES
A sphere is just a ball.
R
It has 1 important
measurement, that is used to
find all its other properties
The RADIUS R
Official definition of a SPHERE:
The collection of all points in space that are the
same distance (radius) from a point (center).
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SPHERES
SA  4    r 2  4   12 2
 576
12m
 1808.64m 2
4
4
3
V     r    123
3
3
 2304
 7,234.56m
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SPHERES
Find the surface area:
S  4 r
2
 4 (8)
8 in.
2
 4  64  804in.
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SPHERES
Find the volume:
4 3
V  r
3
2 ft.
4
  (2)3
3
4
  (8)
3
32
 
3
32
 (3.14)
3
 34 ft.
3
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SURFACE AREA and VOLUME
SPHERES
Find the volume and surface area of the hemisphere:
SA  4    r 2
 4   10
 400
Half the sphere
+
the circle
2
 200  100
 300
 942in 2
10in
A   r2
  102
 100
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SURFACE AREA and VOLUME
SPHERES
Find the volume and surface area of the hemisphere:
SA  4    r
4
V    r 3
3
2
10in
4
   103
3
 4186.7in
3
We only want half
 942in 2
 2093.3in
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3
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SURFACE AREA and VOLUME
SPHERES
Find the volume:
1 2
V

r h
Cone:
3
1
  52 12
3
 314mm3
4
4
3 1
3 1
Ice cream: V      r        5  
 2
3
 2 3
 261.67 mm3
TOTAL:  314  261.67
 575.67
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APPENDIX
OPENERS
REVIEWS
ASSIGNMENTS
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OPENERS
A
B
C
D
E
F
G
H
I
J
K
L
M
N
O
P
Q
R
S
T
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A
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B
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C
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E
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F
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M
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O
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R
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S
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OPENERS
T
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REVIEWs
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REVIEWs
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