Chem. 31 – 3/16 Lecture Announcements I • More on Additional Problem + Quiz – When stoichiometry is the same, Ksp gives solubility (e.g. Ksp(AgCl) = 1.8 x 10-10 and Ksp(AgI) = 8.3 x 10-17) – When stoichiometry is different, one must look at reaction (e.g. Ag2CrO4 – Ksp = 1.2 x 10-12 vs. BaCrO4 Ksp = 2.1 x 10-10) – For Sparingly Soluble Salts, any further reactions of solubility products lead to greater solubility – Ca in quiz was tricky because the stoichiometry stayed 1:1 CaSO4 (s) ↔ Ca2+ + SO42- ↔ CaSO4 (aq) • Water Hardness Lab Report – Turn in completed report form – Due Wednesday Announcements II • Today’s Lecture – Chapter 7 “Advanced Equilibrium Theory” – – – – Replacement Equations: Activity and Activity Coefficients Consideration of Activity in Solving Equilibrium Problems The Real Equation for pH The Systematic Method • Examples of failures • 6 steps to method • More on Mass Balance Factors Influencing g • Ionic Strength: as m increase, g decreases • Charge of Ion: a larger decrease in g occurs for more highly charged ions • Size of Ion: Note: very small ions like Li+ actually have large hydrated spheres ion Gamma Plots 1.20 Activity coefficient 1.00 0.80 Li+ 0.60 Ba2+ Li+ PO430.40 0.20 0.00 0.00 0.02 0.04 0.06 0.08 0.10 0.12 Ionic Strength (M) Hydrated sphere Rb+ Ionic Strength Effects on Equilibria Qualitative Effects • An increase in ionic strength shifts equilibria to the side with more ions or more highly charged ions • Example Problems: (predict the shift as m increases) – NH3(aq) + H2O(l) ↔ NH4+ + OH– Cu2+ + 4OH- ↔ Cu(OH)42– 2HSO3- ↔ S2O32- + H2O(l) – HSO4- ↔ SO42- + H+ Ionic Strength Effects Effects on Equilibrium - Quantitative • Calculate expected [Mg2+] in equilibrium with solid MgCO3 for cases both with and without NaCl. – Go to Board Ionic Strength Effects Real Equation for pH • pH = -logAH+ = -log(gH+[H+]) • Example Problem: Determine the pH of a solution containing 0.0050 M HCl and 0.020 M CaCl2. • Note: H2O H+ + OH- also affected by ionic strength Second Part to Chapter 7 The Systematic Method • Question: Why can’t we apply the ICE (initial, change, equilibrium) method to any type of equilibrium problem? • Answer: That method is best designed for cases where there is only one relevant equilibrium reaction. • Examples of failures: – Solubility of MgCO3 – pH of 5.0 x 10-8 M HCl solution (Show failure of Chem. 1B method) – Note: both problems can be solved using ICE method, but problem set up is more complicated The Systematic Method Solubility of MgCO3 – Why did it fail? • • • • • • MgCO3 Mg2+ + CO32x x Equil. (in ICE) 1/2 So x = (Ksp) = 1.87 x 10-4 M (neglecting ionic strength effects) Problem is both ions can react further: enhancements: (% over rxn 1 only) CO32- + H2O HCO3- + OH90% And HCO3- + H2O H2CO3 + OH0% Also, Mg2+ + OH- MgOH+ 9% And Mg2+ + CO32- MgCO3 (aq) 16% Finally, we also have H2O H+ + OH- re-establishing equilibrium Each additional reaction results in greater dissolution To properly solve problem we must consider 6 reactions not just 1 Measured “[CO32-]” from titration = [CO32-] + 0.5[OH-] + 0.5[HCO3-] + [MgCO3] + 0.5[MgOH+] • The “further” reactions makes [Mg2+] ≠ [CO32-], so ICE method fails (or needs modification by ICE tables for other reactions) • Actual solubility is greater than ICE method finds [Mg2+]total = solubility ~ 3.3 x 10-4 M (from systematic approach) Predicted HCl needed = 3.3 mL (close to that measured) These calculations didn’t include activity which would lead to a ~10% increase in solubility (~3.6 mL HCl needed). In 0.1 M NaCl, I get 6.1 mL HCl needed The Systematic Method The Six Steps 1. 2. 3. 4. 5. Write out all relevant reactions Write a “Charge Balance Equation” Write “Mass Balance Equations” Write out all equilibrium equations Check that the number of equations (in 2 to 4 above) = (or maybe >) the number of unknowns (undefined concentrations) 6. Solve for the desired unknown(s) by reducing the equations to one equation with one unknown. Then solve for remaining unknowns Note: the emphasis of teaching the systematic method is steps 1 to 5. Step 6 will be reserved for “easy” problems with 2 to max 3 unknowns The Systematic Method pH of 5.0 x 10-8 M HCl • Demonstrate Method on Board The Systematic Method Conceptual Approach to Mass Balance Equations • With every source of related species, there should be one mass balance equation (or one set for ionic compounds) • Example: – Solubility of AgCl in water with 0.010 M 1,10-phenathroline (Ph) – Reactions: 1) AgCl(s) Ag+ + Cl2) Ag+ + 2Ph Ag(Ph)2+ – Mass Balance equations: • if only rxn 1) [Cl-] = [Ag+] • w/ rxn 2) [Cl-] = [Ag+] + [Ag(Ph)2+] 1,10-phenathroline N N Ag+ Ph Ph Ph Ph Ag+ + Ag Cl + Cl- Ag Cl- Ag+ Cl- 2nd Mass Balance Equation: AgCl(s) +] + [Ph]oNotes: = 0.010 M = [Ph] = [Ph] + 2[Ag(Ph) with rxn 1) Total only, 2 Ag s = 2 Cl s; 2with rxn 2) also, 3 Cls = 22 Phs Ags++one 1 Ag(Ph) Initially 4 Phs, then complex 2 containing 2 Phs (so total # of Phs remains constant) The Systematic Method 2nd Example • An aqueous mixture of CdCl2 and NaSCN is made – Initial concentrations are [CdCl2] = 0.0080 M and [NaSCN] = 0.0040 M – Cd2+ reacts with SCN- to form CdSCN+ K = 95 – HSCN is a strong acid – Ignore any other reactions (e.g. formation of CdOH+) – Ignore activity considerations – Determine the concentrations of all species