Genetics: Part II Predicting Offspring 2 Key Male 1st generation Affected male Female Affected female Mating 1st generation Ww ww Ww ww 2nd generation Ww ww 3rd generation WW or Ww Widow’s peak ff ff (a) Is a widow’s peak a dominant or recessive trait? Ff Ff Ff ff ff FF or Ff 3rd generation ww No widow’s peak ff Ff 2nd generation FF or Ff Ww ww ww Ww Ff Offspring Attached earlobe Free earlobe b) Is an attached earlobe a dominant or recessive trait? Pedigree Symbols Pedigree #1 Pedigree #1 Pedigree #1 Pedigree #1 • Characteristics of a dominant pedigree: 1) Every affected individual has at least one affected parent 2) Affected individuals who mate with unaffected individuals have a 50% chance of transmitting the trait to each child; and 3) Two affected individuals may have unaffected children. Pedigree #2 Pedigree #2 Pedigree #2 Pedigree #2 • Characteristics of recessive pedigrees: 1) An individual who is affected may have parents who are not affected 2) All the children of two affected individuals are affected 3) In pedigrees involving rare traits, the unaffected parents of an affected individual may be related to each other. Pedigree #3 Pedigree #3 Pedigree #3 Pedigree #3 • Characteristics of sex-linked pedigrees 1) All females from the affected male have the trait, but not all males from affected females (dominant) 2) All males from the affected female have the trait, but not all females from affected males (recessive) Probability 17 Rule of Addition • Rule of addition: Chance that an event can occur 2 or more different ways. – Sum of separate probabilities – Ex.1/4 Pp +1/4 Pp 1/2 Pp 18 Rule of Multiplication • The multiplication rule states that the probability that two or more independent events will occur together is the product of their individual probabilities • Chance that 2 or more independent events will occur together – Ex. Probability that 2 coins tossed at the same time will land heads up – Probability of H x H HH –½ x ½ = ¼ Rule of Multiplication Cross: GgSs x GgSS • What is the probability of producing green, smooth seeds in this cross? • Solution • Green = 3/4 Smooth = 4/4 • 3/4 X 4/4 = 12/16 = 3/4 probability of producing green smooth seed From your formula chart: If A and B are mutually exclusive, then P (A or B) = P (A) + P (B) If A and B are independent, then P (A and B) = P(A) X P(B) Ex. Probability of a couple having three girls? Ex. Probability of a couple having three boys? Ex. Probability of having three boys or three girls? 21 For example: In a heterozygous cross YyRr Probability of YYRR 1/4 (probability of YY) 1/4 (RR) 1/16 Probability of YyRR 1/2 (Yy) 1/4 (RR) 1/8 Cross PpYyRr x PPyyrr ppyyRr ppYyrr Ppyyrr PPyyrr ppyyrr 1/ 1/ (yy) 1/ (Rr) (probability of pp) 1/16 4 2 2 1/16 ? ? 1/16 Chance of at least two recessive traits 6/16 or 3/8 Cross PpYyRr x Ppyyrr (Answer) ppyyRr ppYyrr Ppyyrr PPyyrr ppyyrr 1/ (yy) 1/ (Rr) (probability of pp) 4 2 2 1/ 1/ 1/ 4 2 2 1/ 1/ 1/ 2 2 2 1/ 1/ 1/ 4 2 2 1/ 1/ 1/ 4 2 2 1/ Chance of at least two recessive traits 1/16 1/16 2/16 1/16 1/16 6/16 or 3/8 Practice • Now that you have reviewed some basic genetics concepts solidify your skill by completing the set of practice problems available at http://anthro.palomar.edu/practice/mendqui2.htm 25