Precalculus Module 2, Topic B, Lesson 12: Teacher

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Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS
Lesson 12: Matrix Multiplication Is Distributive and
Associative
Student Outcomes

Students discover and verify that matrix multiplication is distributive.

Students discover and verify that matrix multiplication is associative.
Lesson Notes
In this lesson, students use specific matrix transformations on points to show that matrix multiplication is distributive
and associative. They then revisit some of the properties of matrices to prove that these properties hold for all matrices
under multiplication.
Classwork
Opening Exercise (10 minutes)
Students review transformations represented by matrices studied in previous lessons in preparation for their work in
Lesson 13. Students write the matrix that represents the given transformation. Each transformation should be written
on the board, and as the class agrees on the correct matrix that represents that transformation, a student should write
the matrix under the transformation heading. Students can do this on paper at their desks, or this can be completed as a
Rapid White Board Exchange. This could also be done in pairs or groups, and each group could present one
transformation and explain it. The exercise can be modified to a matching activity if students are struggling.
Opening Exercise
Write the πŸ‘ × πŸ‘ matrix that would represent the transformation listed.
a.
No change when multiplying (the multiplicative identity matrix)
𝟏 𝟎 𝟎
[𝟎 𝟏 𝟎]
𝟎 𝟎 𝟏
MP.2
b.
No change when adding (the additive identity matrix)
𝟎 𝟎 𝟎
[𝟎 𝟎 𝟎]
𝟎 𝟎 𝟎
c.
A rotation about the 𝒙-axis of 𝜽 degrees
𝟏
𝟎
𝟎
[𝟎 𝐜𝐨𝐬(𝜽) −𝐬𝐒𝐧(𝜽)]
𝟎 𝐬𝐒𝐧(𝜽) 𝐜𝐨𝐬(𝜽)
Lesson 12:
Matrix Multiplication Is Distributive and Associative
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This file derived from PreCal-M2-TE-1.3.0-08.2015
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Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS
d.
A rotation about the π’š-axis of 𝜽 degrees
[
e.
𝐜𝐨𝐬(𝜽) 𝟎 𝐬𝐒𝐧(𝜽)
𝟎
𝟏
𝟎 ]
−𝐬𝐒𝐧(𝜽) 𝟎 𝐜𝐨𝐬(𝜽)
A rotation about the 𝒛-axis of 𝜽 degrees
𝐜𝐨𝐬(𝜽) −𝐬𝐒𝐧(𝜽) 𝟎
[ 𝐬𝐒𝐧(𝜽)
𝐜𝐨𝐬(𝜽 𝟎]
𝟎
𝟎
𝟏
f.
A reflection over the π’™π’š-plane
Scaffolding:
𝟏 𝟎 𝟎
[𝟎 𝟏 𝟎 ]
𝟎 𝟎 −𝟏
Students could create a graphic
organizer listing the matrix in
one column and the
transformation represented in
the next column.
MP.2
g.
A reflection over the π’šπ’›-plane
−𝟏 𝟎 𝟎
[ 𝟎 𝟏 𝟎]
𝟎 𝟎 𝟏
h.
A reflection over the 𝒙𝒛-plane
𝟏 𝟎 𝟎
[𝟎 −𝟏 𝟎]
𝟎 𝟎 𝟏
i.
A reflection over π’š = 𝒙 in the π’™π’š-plane
𝟎 𝟏 𝟎
[𝟏 𝟎 𝟎]
𝟎 𝟎 𝟏
Scaffolding:
Example (15 minutes)
This example should be completed by students in pairs for parts (a) through (g). Part (h)
should be completed as a teacher-led discussion after debriefing together the results of
parts (a) through (g). Students look at transformations in two-dimensional space on a
point. They predict the transformation, write a matrix that would represent that
transformation, and apply the transformation to the point. Through a series of steps, they
see that matrix multiplication is distributive and associative, revisit properties of matrices,
and prove that these properties hold for all matrices under matrix multiplication.

What are the dimensions of a matrix that represents two-dimensional space?
οƒΊ

2×2
Using your geometric intuition, can you tell me how the point (1, 1) would
transform if it was rotated 90° clockwise? What are the new coordinates?
οƒΊ
The π‘₯-coordinate would stay the same, and the 𝑦-coordinate would
change signs. (1, −1)
Lesson 12:
Matrix Multiplication Is Distributive and Associative
This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from PreCal-M2-TE-1.3.0-08.2015
 Students with spatial
issues may not be able to
see the transformations in
three dimensions.
Consider using a graphing
program to help them
visualize the
transformations or
demonstrating each one
visually in some other way.
 For advanced learners,
have students work in
groups to complete this
example with no leading
questions. They should
write up a summary and
present their findings
during the class discussion.
187
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NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 12
M2
PRECALCULUS AND ADVANCED TOPICS

What would happen to the point (1, 1) if it was rotated 180° counterclockwise? What are the new
coordinates?
οƒΊ






If matrix 𝐴 represents a rotation of 90° clockwise, write matrix 𝐴. Show your steps.
cos(−90°) − sin(−90°)
0 1
οƒΊ 𝐴=[
]=[
]
sin(−90°) cos(−90°)
−1 0
If matrix 𝐡 represents a reflection about the π‘₯-axis, write matrix 𝐡.
1 0
οƒΊ 𝐡=[
]
0 −1
If matrix 𝐢 represents a rotation of 180° about the 𝑦-axis, write matrix 𝐢. Show your steps.
cos(180°) −sin(180°)
−1 0
οƒΊ 𝐢=[
]=[
]
sin(180°) cos(180°)
0 −1
1
𝑋 = [ ]; confirm your answers above by performing the transformations 𝐡𝑋 and 𝐢𝑋. Were your instincts
1
correct? If not, analyze your mistakes.
1
−1
οƒΊ 𝐡𝑋 = [ ]; 𝐢𝑋 = [ ]; answers will vary.
−1
−1
What is 𝐡𝑋 + 𝐢𝑋? What did you notice about the results of part (e) and part (g)?
0
οƒΊ 𝐡𝑋 + 𝐢𝑋 = [ ]. The results are the same matrix.
−2
Write out the mathematical statement.
οƒΊ


𝐡𝑋 + 𝐢𝑋
We also know that applying a matrix 𝐡 and then matrix 𝐴 is the same as applying the matrix product 𝐴𝐡. So,
𝐴(𝐡𝑋) = ? And 𝐴(𝐢𝑋) = ?
οƒΊ
(𝐴𝐡)𝑋
οƒΊ
(𝐴𝐢)𝑋
Let’s use what we have just stated to explain why 𝐴(𝐡 + 𝐢) and 𝐴𝐡 + 𝐴𝐢 have the same geometric effect on a
point or points for any matrices 𝐴, 𝐡, and 𝐢.
οƒΊ

We have proven for this set of matrices that 𝐴(𝐡𝑋 + 𝐢𝑋) = (𝐴𝐡)𝑋 + (𝐴𝐢)𝑋, but we need
𝐴(𝐡𝑋 + 𝐢𝑋) = 𝐴(𝐡𝑋) + 𝐴(𝐢𝑋). That means (𝐴𝐡)𝑋 + (𝐴𝐢)𝑋 = 𝐴(𝐡𝑋) + 𝐴(𝐢𝑋), which means the
associative property must hold.
The sum of two matrices is the sum of corresponding elements. What would be the value of (𝐡 + 𝐢)𝑋?
οƒΊ

𝐴(𝐡𝑋 + 𝐢𝑋) = 𝐴(𝐡𝑋) + 𝐴(𝐢𝑋)
What property would be necessary in order for us to prove matrix multiplication is distributive given what we
have already proven?
οƒΊ

𝐴(𝐡𝑋 + 𝐢𝑋) = (𝐴𝐡)𝑋 + (𝐴𝐢)𝑋
Do you think matrix multiplication is distributive? If so, what would 𝐴(𝐡𝑋 + 𝐢𝑋) be equivalent to?
οƒΊ

The π‘₯- and 𝑦-coordinates would change signs. (−1, −1)
Applying the product of 𝐴 and (𝐡 + 𝐢) has the same effect as applying 𝐴𝐡 and then 𝐴𝐢 and then
adding them together.
How do we know that (𝐴(𝐡 + 𝐢))𝑋 = 𝐴((𝐡 + 𝐢)𝑋)?
οƒΊ
Applying the product of 𝐴 and (𝐡 + 𝐢) has the same effect as applying (𝐡 + 𝐢) and then 𝐴.
Lesson 12:
Matrix Multiplication Is Distributive and Associative
This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from PreCal-M2-TE-1.3.0-08.2015
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This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS

Now, 𝐴((𝐡 + 𝐢)𝑋) = 𝐴(𝐡𝑋 + 𝐢𝑋). Why?
οƒΊ

The sum of two matrices acts by summing the images.
We also know that 𝐴(𝐡𝑋 + 𝐢𝑋) = 𝐴(𝐡𝑋) + 𝐴(𝐢𝑋). Why?
οƒΊ


Each matrix represents a linear transformation.
Continuing, 𝐴(𝐡𝑋) + 𝐴(𝐢𝑋) = (𝐴𝐡)𝑋 + (𝐴𝐢)𝑋. Explain.
οƒΊ
Applying 𝐡 and then 𝐴 is the same as applying 𝐴𝐡.
οƒΊ
Applying 𝐢 and then 𝐴 is the same as applying 𝐴𝐢.
And finally, why does (𝐴𝐡)𝑋 + (𝐴𝐢)𝑋 = (𝐴𝐡 + 𝐴𝐢)𝑋?
οƒΊ

The sum of two matrices acts by summing the images.
Therefore, what must be true?
οƒΊ
𝐴(𝐡 + 𝐢) = 𝐴𝐡 + 𝐴𝐢

We have just shown that matrix multiplication is distributive and associative.

Take a few minutes, and discuss what we have just proven with your neighbor. Write a summary.
Example
In three-dimensional space, let 𝑨 represent a rotation of πŸ—πŸŽ° about the 𝒙-axis, 𝑩 represent a reflection about the
𝟏
π’šπ’›-plane, and π‘ͺ represent a rotation of πŸπŸ–πŸŽ° about the 𝒛-axis. Let 𝑿 = [𝟏].
𝟏
a.
As best you can, sketch a three-dimensional set of axes and the location of the point 𝑿.
b.
Using only your geometric intuition, what are the coordinates of 𝑩𝑿? π‘ͺ𝑿? Explain your thinking.
−𝟏
−𝟏
𝑩𝑿 = [ 𝟏 ]; π‘ͺ𝑿 = [−𝟏]; answers will vary but could include that when rotating about the 𝒙-axis πŸ—πŸŽ°, only
𝟏
𝟏
the 𝒙-coordinate would change signs; however, when rotating about the 𝒛-axis πŸπŸ–πŸŽ°, the 𝒙- and
π’š-coordinates would change signs.
c.
Write down matrices 𝑩 and π‘ͺ, and verify or disprove your answers to part (b).
−𝟏 𝟎 𝟎
−𝟏 𝟎 𝟎
−𝟏
−𝟏
𝑩 = [ 𝟎 𝟏 𝟎]; π‘ͺ = [ 𝟎 −𝟏 𝟎]; 𝑩𝑿 = [ 𝟏 ]; π‘ͺ𝑿 = [−𝟏]
𝟎 𝟎 𝟏
𝟎
𝟎 𝟏
𝟏
𝟏
Lesson 12:
Matrix Multiplication Is Distributive and Associative
This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from PreCal-M2-TE-1.3.0-08.2015
189
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS
d.
What is the sum of 𝑩𝑿 + π‘ͺ𝑿?
−𝟐
𝑩𝑿 + π‘ͺ𝑿 = [ 𝟎 ]
𝟐
e.
Write down matrix 𝑨, and compute 𝑨(𝑩𝑿 + π‘ͺ𝑿).
𝟏 𝟎 𝟎
𝑨 = [𝟎 𝟎 −𝟏]
𝟎 𝟏 𝟎
𝟏 𝟎 𝟎 −𝟐
−𝟐
𝑨(𝑩𝑿 + π‘ͺ𝑿) = [𝟎 𝟎 −𝟏] [ 𝟎 ] = [−𝟐]
𝟎 𝟏 𝟎
𝟎
𝟐
f.
Compute 𝑨𝑩 and 𝑨π‘ͺ.
𝟏 𝟎 𝟎 −𝟏 𝟎 𝟎
−𝟏 𝟎 𝟎
𝑨𝑩 = [𝟎 𝟎 −𝟏] [ 𝟎 𝟏 𝟎] = [ 𝟎 𝟎 −𝟏]
𝟎 𝟏 𝟎
𝟎 𝟎 𝟏
𝟎 𝟏 𝟎
𝟏 𝟎 𝟎 −𝟏 𝟎 𝟎
−𝟏 𝟎
𝟎
𝑨π‘ͺ = [𝟎 𝟎 −𝟏] [ 𝟎 −𝟏 𝟎] = [ 𝟎
𝟎 −𝟏]
𝟎 𝟏 𝟎
𝟎
𝟎 𝟏
𝟎 −𝟏 𝟎
g.
Compute (𝑨𝑩)𝑿, (𝑨π‘ͺ)𝑿, and their sum. Compare your result to your answer to part (e). What do you
notice?
−𝟏 𝟎 𝟎 𝟏
−𝟏
(𝑨𝑩)𝑿 = [ 𝟎 𝟎 −𝟏] [𝟏] = [−𝟏]
𝟎 𝟏 𝟎 𝟏
𝟏
−𝟏 𝟎
𝟎 𝟏
−𝟏
(𝑨π‘ͺ)𝑿 = [ 𝟎
𝟎 −𝟏] [𝟏] = [−𝟏]
𝟎 −𝟏 𝟎 𝟏
−𝟏
−𝟏 −𝟏
−𝟐
(𝑨𝑩)𝑿 + (𝑨π‘ͺ)𝑿 = [−𝟏] [−𝟏] = [−𝟐]
𝟎
𝟏 −𝟏
𝑨(𝑩𝑿 + π‘ͺ𝑿) = (𝑨𝑩)𝑿 + (𝑨π‘ͺ)𝑿
h.
In general, must 𝑨(𝑩 + π‘ͺ) and 𝑨𝑩 + 𝑨π‘ͺ have the same geometric effect on a point, no matter what matrices
𝑨, 𝑩, and π‘ͺ are? Explain.
Yes. See full explanation in questions above.
Exercises 1–2 (10 minutes)
Allow students to complete the exercises in pairs, each doing the work individually and then comparing answers. Some
groups may need more help or one-on-one instructions. Exercise 1, part (b) and Exercise 2, part (a) are fully discussed as
a class and are the focus of the Lesson Summary. Have early finishers write the results of Exercise 1, part (c) and
Exercise 2, parts (a)–(b) on large paper and prepare an explanation to present to the class as part of the
Lesson Summary.
Lesson 12:
Matrix Multiplication Is Distributive and Associative
This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from PreCal-M2-TE-1.3.0-08.2015
190
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS
Exercises
1.
𝒆
𝒙 𝒛
𝒂 𝒄
Let 𝑨 = [π’š π’˜], 𝑩 = [
], and π‘ͺ = [𝒇
𝒃 𝒅
a.
π’ˆ
𝒉].
Write down the products 𝑨𝑩, 𝑨π‘ͺ, and 𝑨(𝑩 + π‘ͺ).
𝒆𝒙 + 𝒇𝒛 π’ˆπ’™ + 𝒉𝒛
𝒂𝒙 + 𝒃𝒛 𝒄𝒙 + 𝒅𝒛
𝑨𝑩 = [
] ; 𝑨π‘ͺ = [
];
π’‚π’š + π’ƒπ’˜ π’„π’š + π’…π’˜
π’†π’š + π’‡π’˜ π’ˆπ’š + π’‰π’˜
(𝒂 + 𝒆)𝒙 + (𝒃 + 𝒇)𝒛 (𝒄 + π’ˆ)𝒙 + (𝒅 + 𝒉)𝒛
𝑨(𝑩 + π‘ͺ) = [
]
(𝒂 + 𝒆)π’š + (𝒃 + 𝒇)π’˜ (𝒄 + π’ˆ)π’š + (𝒅 + 𝒉)π’˜
b.
Verify that 𝑨(𝑩 + π‘ͺ) = 𝑨𝑩 + 𝑨π‘ͺ.
(𝒂 + 𝒆)𝒙 + (𝒃 + 𝒇)𝒛 (𝒄 + π’ˆ)𝒙 + (𝒅 + 𝒉)𝒛
𝑨(𝑩 + π‘ͺ) = [
]
(𝒂 + 𝒆)π’š + (𝒃 + 𝒇)π’˜ (𝒄 + π’ˆ)π’š + (𝒅 + 𝒉)π’˜
=[
𝑨𝑩 + 𝑨π‘ͺ = [
𝒂𝒙 + 𝒆𝒙 + 𝒃𝒛 + 𝒇𝒛
𝒄𝒙 + π’ˆπ’™ + 𝒅𝒛 + 𝒉𝒛
]
π’‚π’š + π’†π’š + π’ƒπ’˜ + π’‡π’˜ π’„π’š + π’ˆπ’š + π’…π’˜ + π’‰π’˜
𝒆𝒙 + 𝒇𝒛 π’ˆπ’™ + 𝒉𝒛
𝒂𝒙 + 𝒃𝒛 𝒄𝒙 + 𝒅𝒛
]+[
]
π’‚π’š + π’ƒπ’˜ π’„π’š + π’…π’˜
π’†π’š + π’‡π’˜ π’ˆπ’š + π’‰π’˜
𝒂𝒙 + 𝒃𝒛 + 𝒆𝒙 + 𝒇𝒛
𝒄𝒙 + 𝒅𝒛 + π’ˆπ’™ + 𝒉𝒛
=[
]
π’‚π’š + π’ƒπ’˜ + π’†π’š + π’‡π’˜ π’„π’š + π’…π’˜ + π’ˆπ’š + π’‰π’˜
Therefore, 𝑨(𝑩 + π‘ͺ) = 𝑨𝑩 + 𝑨π‘ͺ.
2.
Suppose 𝑨, 𝑩, and π‘ͺ are πŸ‘ × πŸ‘ matrices and 𝑿 is a point in three-dimensional space.
a.
Explain why the point (𝑨(𝑩π‘ͺ))𝑿 must be the same point as ((𝑨𝑩)π‘ͺ)𝑿.
(𝑨(𝑩π‘ͺ))𝑿 = (𝑨)(𝑩)(π‘ͺ)𝑿. Applying 𝑩π‘ͺ and then 𝑨 is the same as applying π‘ͺ, then 𝑩, and then 𝑨.
(𝑨)(𝑩)(π‘ͺ)𝑿 = ((𝑨𝑩)π‘ͺ)𝑿. Applying π‘ͺ, then 𝑩, and then 𝑨 is the same as applying π‘ͺ and then 𝑨𝑩.
b.
Explain why matrix multiplication must be associative.
Matrix multiplication is associative because performing the transformation 𝑩 and then 𝑨 on a point 𝑿 is the
same as applying the product of 𝑨𝑩 to point 𝑿.
c.
Verify using the matrices from Exercise 1 that 𝑨(𝑩π‘ͺ) = (𝑨𝑩)π‘ͺ.
𝑩π‘ͺ = [
𝒂𝒆 + 𝒄𝒇 π’‚π’ˆ + 𝒄𝒉
𝒂 𝒄 𝒆 π’ˆ
][
]=[
]
𝒃 𝒅 𝒇 𝒉
𝒃𝒆 + 𝒅𝒇 π’ƒπ’ˆ + 𝒅𝒉
𝒙 𝒛 𝒂𝒆 + 𝒄𝒇 π’‚π’ˆ + 𝒄𝒉
𝒙(𝒂𝒆 + 𝒄𝒇) + 𝒛(𝒃𝒆 + 𝒅𝒇) 𝒙(π’‚π’ˆ + 𝒄𝒉) + 𝒛(π’ƒπ’ˆ + 𝒅𝒉)
𝑨(𝑩π‘ͺ) = [π’š π’˜] [
]=[
]
𝒃𝒆 + 𝒅𝒇 π’ƒπ’ˆ + 𝒅𝒉
π’š(𝒂𝒆 + 𝒄𝒇) + π’˜(𝒃𝒆 + 𝒅𝒇) π’š(π’‚π’ˆ + 𝒄𝒉) + π’˜(π’ƒπ’ˆ + 𝒅𝒉)
𝒙 𝒛 𝒂 𝒄
𝒂𝒙 + 𝒃𝒛 𝒄𝒙 + 𝒅𝒛
𝑨𝑩 = [π’š π’˜] [
]=[
]
𝒃 𝒅
π’‚π’š + π’ƒπ’˜ π’„π’š + π’…π’˜
𝒂𝒙 + 𝒃𝒛 𝒄𝒙 + 𝒅𝒛 𝒆
(𝑨𝑩)π‘ͺ = [
][
π’‚π’š + π’ƒπ’˜ π’„π’š + π’…π’˜ 𝒇
π’ˆ
(𝒂𝒙 + 𝒃𝒛)𝒆 + (𝒄𝒙 + 𝒅𝒛)𝒇
(𝒂𝒙 + 𝒃𝒛)π’ˆ + (𝒄𝒙 + 𝒅𝒛)𝒉
𝒉] = [(π’‚π’š + π’ƒπ’˜)𝒆 + (π’„π’š + π’…π’˜)𝒇 (π’‚π’š + π’ƒπ’˜)π’ˆ + (π’„π’š + π’…π’˜)𝒉]
𝒂𝒆𝒙 + 𝒄𝒇𝒙 + 𝒃𝒆𝒛 + 𝒅𝒇𝒛
π’‚π’ˆπ’™ + 𝒄𝒉𝒙 + π’ƒπ’ˆπ’› + 𝒅𝒉𝒛
𝑨(𝑩π‘ͺ) = [
] = (𝑨𝑩)π‘ͺ
π’‚π’†π’š + π’…π’‡π’š + π’ƒπ’†π’˜ + π’…π’‡π’˜ π’‚π’ˆπ’š + π’„π’‰π’š + π’ƒπ’ˆπ’˜ + π’…π’‰π’˜
Lesson 12:
Matrix Multiplication Is Distributive and Associative
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Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS
Closing (5 minutes)
As a class, discuss the results of Exercises 1 and 2, focusing on the properties of matrix multiplication (distributive and
associative) that were discovered/confirmed in this lesson and these exercises. Alternately, revisit the properties used in
the example and the exercises of matrix multiplication.

What matrix multiplication property did you prove in Exercise 1? Explain how you proved it in part (c).
οƒΊ

In Exercise 2, parts (a) and (b), explain why you knew that matrix multiplication was associative.
οƒΊ

The distributive property. See exercises to ensure students understand properties.
Review the steps from the exercises to ensure students understand the properties.
Some properties of matrices:
οƒΊ
Each matrix represents a linear transformation, so 𝐴(𝐡𝑋 + 𝐢𝑋) = 𝐴(𝐡𝑋) + 𝐴(𝐢𝑋).
οƒΊ
The sum of two matrices acts by summing the image points, (𝐡 + 𝐢)𝑋 = 𝐡𝑋 + 𝐢𝑋.
οƒΊ
Applying matrix 𝐡 and then 𝐴 is the same as applying the matrix product 𝐴𝐡, meaning
𝐴(𝐡𝑋) = (𝐴𝐡)𝑋.
Exit Ticket (5 minutes)
Lesson 12:
Matrix Multiplication Is Distributive and Associative
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Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS
Name
Date
Lesson 12: Matrix Multiplication Is Distributive and Associative
Exit Ticket
In three-dimensional space, matrix 𝐴 represents a 180° rotation about the 𝑦-axis, matrix 𝐡 represents a reflection about
the π‘₯𝑧-plane, and matrix 𝐢 represents a reflection about the π‘₯𝑦-plane. Answer the following:
a.
Write matrices 𝐴, 𝐡, and 𝐢.
b.
2
If 𝑋 = [2], compute 𝐴(𝐡𝑋 + 𝐢𝑋).
2
c.
What matrix operations are equivalent to 𝐴(𝐡𝑋 + 𝐢𝑋)? What property is shown?
d.
Would (𝐴(𝐡𝐢))𝑋 = ((𝐴𝐡)𝐢)𝑋? Why?
Lesson 12:
Matrix Multiplication Is Distributive and Associative
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Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS
Exit Ticket Sample Solutions
In three-dimensional space, matrix 𝑨 represents a πŸπŸ–πŸŽ° rotation about the π’š-axis, matrix 𝑩 represents a reflection about
the 𝒙𝒛-plane, and matrix π‘ͺ represents a reflection about the π’™π’š-plane. Answer the following:
a.
Write matrices 𝑨, 𝑩, and π‘ͺ.
−𝟏 𝟎 𝟎
𝟏 𝟎
𝟎
𝟏 𝟎 𝟎
𝑨 = [ 𝟎 𝟏 𝟎 ] ; 𝑩 = [𝟎 −𝟏 𝟎 ] ; π‘ͺ = [𝟎 𝟏 𝟎 ]
𝟎 𝟎 −𝟏
𝟎 𝟎 −𝟏
𝟎 𝟎 −𝟏
b.
𝟐
If 𝑿 = [𝟐], compute 𝑨(𝑩𝑿 + π‘ͺ𝑿).
𝟐
𝟏 𝟎
𝟎 𝟐
𝟐
𝟏
𝑩𝑿 = [𝟎 −𝟏 𝟎 ] [𝟐] = [−𝟐]; π‘ͺ𝑿 = [𝟎
𝟎 𝟎 −𝟏 𝟐
𝟎
−𝟐
𝟎 𝟎 𝟐
𝟐
𝟏 𝟎 ] [𝟐] = [ 𝟐 ]
𝟎 −𝟏 𝟐
−𝟐
πŸ’
−𝟏 𝟎 𝟎
πŸ’
−πŸ’
𝑩𝑿 + π‘ͺ𝑿 = [ 𝟎 ]; 𝑨(𝑩𝑿 + π‘ͺ𝑿) = [ 𝟎 𝟏 𝟎 ] [ 𝟎 ] = [ 𝟎 ]
−πŸ’
𝟎 𝟎 −𝟏 −πŸ’
πŸ’
c.
What matrix operations are equivalent to 𝑨(𝑩𝑿 + π‘ͺ𝑿)? What property is shown?
𝑨(𝑩𝑿 + π‘ͺ𝑿) = (𝑨𝑩)𝑿 + (𝑨π‘ͺ)𝑿; matrix multiplication is distributive.
d.
Would (𝑨(𝑩π‘ͺ))𝑿 = ((𝑨𝑩)π‘ͺ)𝑿? Why?
Yes; matrix multiplication is associative.
Problem Set Sample Solutions
1.
Let matrix 𝑨 = (
a.
πŸ” −πŸ”
)
−πŸ’ −πŸ’
𝑨π‘ͺ
(
c.
𝟐
). Calculate the following:
−πŸ“
𝑨𝑩
(
b.
πŸ‘ −𝟐
πŸ’ πŸ’
πŸ–
), matrix 𝑩 = (
), and matrix π‘ͺ = (
−𝟏 𝟎
πŸ‘ πŸ—
πŸ•
𝟏𝟎 πŸπŸ”
)
−πŸ– −𝟐
𝑨(𝑩 + π‘ͺ)
𝑩+π‘ͺ =(
𝟏𝟐 πŸ”
πŸπŸ” 𝟏𝟎
πŸπŸ” 𝟏𝟎
); 𝑨(𝑩 + π‘ͺ) = (
); 𝑨𝑩 + 𝑨π‘ͺ = (
)
𝟏𝟎 πŸ’
−𝟏𝟐 −πŸ”
−𝟏𝟐 −πŸ”
We have that 𝑨(𝑩 + π‘ͺ) = 𝑨𝑩 + 𝑨π‘ͺ.
d.
𝑨𝑩 + 𝑨π‘ͺ
(
πŸπŸ” 𝟏𝟎
)
−𝟏𝟐 −πŸ”
Lesson 12:
Matrix Multiplication Is Distributive and Associative
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NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 12
M2
PRECALCULUS AND ADVANCED TOPICS
e.
(𝑨 + 𝑩)π‘ͺ
(𝑨 + 𝑩)π‘ͺ = 𝑨π‘ͺ + 𝑩π‘ͺ, so 𝑩π‘ͺ has not been calculated yet. We get
πŸ”πŸŽ −𝟏𝟐
𝑩π‘ͺ = (
).
πŸ–πŸ• −πŸ‘πŸ—
So,
πŸ’
(𝑨 + 𝑩)π‘ͺ = (πŸ•πŸŽ
).
πŸ•πŸ— −πŸ’πŸ
f.
𝑨(𝑩π‘ͺ)
πŸ”πŸŽ
πŸ–πŸ•
πŸ”
=(
−πŸ”πŸŽ
𝑨(𝑩π‘ͺ) = 𝑨 (
2.
−𝟏𝟐
)
−πŸ‘πŸ—
πŸ’πŸ
)
𝟏𝟐
𝟏
−πŸ‘
Apply each of the transformations you found in Problem 1 to the points 𝒙 = ( ), π’š = ( ), and 𝒙 + π’š.
𝟏
𝟐
𝟎
(𝑨𝑩)𝒙 = ( )
a.
−πŸ–
(𝑨𝑩)π’š = (−πŸ‘πŸŽ)
πŸ’
(𝑨𝑩)(𝒙 + π’š) = (−πŸ‘πŸŽ)
−πŸ’
b.
(𝑨π‘ͺ)𝒙 = ( πŸπŸ” )
−𝟏𝟎
(𝑨π‘ͺ)π’š = ( 𝟐 )
𝟐𝟎
(𝑨π‘ͺ)(𝒙 + π’š) = (πŸπŸ–)
𝟏𝟎
πŸπŸ”
)
−πŸπŸ–
−πŸπŸ–
)
(𝑨(𝑩 + π‘ͺ))π’š = (
πŸπŸ’
−𝟐
(𝑨(𝑩 + π‘ͺ))(𝒙 + π’š) = ( )
πŸ”
c.
(𝑨(𝑩 + π‘ͺ))𝒙 = (
d.
Same as part (c)
(𝑨𝑩 + 𝑨π‘ͺ)𝒙 = ( πŸπŸ” )
−πŸπŸ–
(𝑨𝑩 + 𝑨π‘ͺ)π’š = (−πŸπŸ–)
πŸπŸ’
(𝑨𝑩 + 𝑨π‘ͺ)(𝒙 + π’š) = (−𝟐)
πŸ”
πŸ•πŸ’
)
πŸ‘πŸ–
−𝟐𝟎𝟐
)
((𝑨 + 𝑩)π‘ͺ)π’š = (
−πŸ‘πŸπŸ—
−πŸπŸπŸ–
)
((𝑨 + 𝑩)π‘ͺ)(𝒙 + π’š) = (
−πŸπŸ–πŸ
e.
((𝑨 + 𝑩)π‘ͺ)𝒙 = (
f.
(𝑨(𝑩π‘ͺ))𝒙 = (
πŸ’πŸ–
)
−πŸ’πŸ–
πŸ”πŸ”
)
(𝑨(𝑩π‘ͺ))π’š = (
πŸπŸŽπŸ’
πŸπŸπŸ’
)
(𝑨(𝑩π‘ͺ))(𝒙 + π’š) = (
πŸπŸ“πŸ”
Lesson 12:
Matrix Multiplication Is Distributive and Associative
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This file derived from PreCal-M2-TE-1.3.0-08.2015
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Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS
3.
Let 𝑨, 𝑩, π‘ͺ, and 𝑫 be any four square matrices of the same dimensions. Use the distributive property to evaluate
the following:
a.
(𝑨 + 𝑩)(π‘ͺ + 𝑫)
(𝑨 + 𝑩)π‘ͺ + (𝑨 + 𝑩)𝑫 = 𝑨π‘ͺ + 𝑩π‘ͺ + 𝑨𝑫 + 𝑩𝑫
b.
(𝑨 + 𝑩)(𝑨 + 𝑩)
𝑨𝑨 + 𝑨𝑩 + 𝑩𝑨 + 𝑩𝑩
c.
What conditions need to be true for part (b) to equal 𝑨𝑨 + πŸπ‘¨π‘© + 𝑩𝑩?
𝑨𝑩 = 𝑩𝑨 needs to be true.
4.
Let 𝑨 be a 𝟐 × πŸ matrix and 𝑩, π‘ͺ be the scalar matrices 𝑩 = (
𝟐 𝟎
πŸ‘ 𝟎
), and π‘ͺ = (
). Answer the following
𝟎 𝟐
𝟎 πŸ‘
questions.
a.
Evaluate the following:
i.
𝑩π‘ͺ
πŸ” 𝟎
(
)
𝟎 πŸ”
ii.
π‘ͺ𝑩
πŸ” 𝟎
(
)
𝟎 πŸ”
iii.
𝑩+π‘ͺ
(
iv.
πŸ“ 𝟎
)
𝟎 πŸ“
𝑩−π‘ͺ
−𝟏 𝟎
(
)
𝟎 −𝟏
b.
Are your answers to part (a) what you expected? Why or why not?
Answers may vary. Students should expect that the matrices behave like real numbers since they represent
scalars.
c.
𝒙
Let 𝑨 = (
𝒛
Yes, 𝑨𝑩 = (
π’š
); does 𝑨𝑩 = 𝑩𝑨? Does 𝑨π‘ͺ = π‘ͺ𝑨?
π’˜
πŸπ’™ πŸπ’š
πŸ‘π’™ πŸ‘π’š
) = 𝑩𝑨, and 𝑨π‘ͺ = (
) = π‘ͺ𝑨.
πŸπ’› πŸπ’˜
πŸ‘π’› πŸ‘π’˜
Lesson 12:
Matrix Multiplication Is Distributive and Associative
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This file derived from PreCal-M2-TE-1.3.0-08.2015
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Lesson 12
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
PRECALCULUS AND ADVANCED TOPICS
d.
What is (𝑨 + 𝑩)(𝑨 + π‘ͺ)? Write the matrix 𝑨 with the letter and not in matrix form. How does this compare
to (𝒙 + 𝟐)(𝒙 + πŸ‘)?
(𝑨 + 𝑩)(𝑨 + π‘ͺ) = 𝑨𝑨 + 𝑩𝑨 + 𝑨π‘ͺ + 𝑩π‘ͺ
πŸ” 𝟎
= 𝑨𝑨 + πŸπ‘¨ + πŸ‘π‘¨ + (
)
𝟎 πŸ”
πŸ” 𝟎
= 𝑨𝑨 + πŸ“π‘¨ + (
)
𝟎 πŸ”
This is identical to (𝒙 + 𝟐)(𝒙 + πŸ‘), with 𝒙 = 𝑨.
e.
With 𝑩 and π‘ͺ given as above, is it possible to factor 𝑨𝑨 − 𝑨 − 𝑩π‘ͺ?
Yes. We need factors of −𝑩π‘ͺ that add to −𝟏. It looks like 𝑩 and −π‘ͺ work, so we get (𝑨 + 𝑩)(𝑨 − π‘ͺ).
5.
Define the sum of any two functions with the same domain to be the function 𝒇 + π’ˆ such that for each 𝒙 in the
domain of 𝒇 and π’ˆ, (𝒇 + π’ˆ)(𝒙) = 𝒇(𝒙) + π’ˆ(𝒙). Define the product of any two functions to be the function π’‡π’ˆ, such
that for each 𝒙 in the domain of 𝒇 and π’ˆ, (π’‡π’ˆ)(𝒙) = (𝒇(𝒙))(π’ˆ(𝒙)).
𝟏
𝟐
Let 𝒇, π’ˆ, and 𝒉 be real-valued functions defined by the equations 𝒇(𝒙) = πŸ‘π’™ + 𝟏, π’ˆ(𝒙) = − 𝒙 + 𝟐, and
𝟐
𝒉(𝒙) = 𝒙 − πŸ’.
a.
Does 𝒇(π’ˆ + 𝒉) = π’‡π’ˆ + 𝒇𝒉?
Yes. If we can show that (𝒇(π’ˆ + 𝒉))(𝒙) = (π’‡π’ˆ)(𝒙) + (𝒇𝒉)(𝒙), then we will have shown that the functions
are equal to each other.
(𝒇(π’ˆ + 𝒉))(𝒙) = (𝒇(𝒙))((π’ˆ + 𝒉)(𝒙))
𝟏
= (πŸ‘π’™ + 𝟏) (− 𝒙 + 𝟐 + π’™πŸ − πŸ’)
𝟐
𝟏
= (πŸ‘π’™ + 𝟏) ((− 𝒙 + 𝟐) + (π’™πŸ − πŸ’))
𝟐
𝟏
= (πŸ‘π’™ + 𝟏) (− 𝒙 + 𝟐) + (πŸ‘π’™ + 𝟏)(π’™πŸ − πŸ’)
𝟐
= (𝒇(𝒙))(π’ˆ(𝒙)) + (𝒇(𝒙))(𝒉(𝒙))
= (π’‡π’ˆ)(𝒙) + (𝒇𝒉)(𝒙)
b.
Show that this is true for any three functions with the same domains.
(𝒇(π’ˆ + 𝒉))(𝒙) = (𝒇(𝒙))((π’ˆ + 𝒉)(𝒙))
= (𝒇(𝒙))(π’ˆ(𝒙) + 𝒉(𝒙))
= (𝒇(𝒙))(π’ˆ(𝒙)) + (𝒇(𝒙))(𝒉(𝒙))
= (π’‡π’ˆ)(𝒙) + (𝒇𝒉)(𝒙)
c.
Does 𝒇 ∘ (π’ˆ + 𝒉) = 𝒇 ∘ π’ˆ + 𝒇 ∘ 𝒉 for the functions described above?
No
𝟏
(𝒇 ∘ (π’ˆ + 𝒉))(𝒙) = 𝒇 (− 𝒙 + 𝟐 + π’™πŸ − πŸ’)
𝟐
𝟏
= πŸ‘ ⋅ (− 𝒙 + 𝟐 + π’™πŸ − πŸ’) + 𝟏
𝟐
𝟏
= πŸ‘ ⋅ (− 𝒙 + 𝟐) + πŸ‘ ⋅ (π’™πŸ − πŸ’) + 𝟏
𝟐
The addition by 𝟏 prevented it from working. If 𝒇(𝒙) would have been a proportion, then the composition
would have worked.
Lesson 12:
Matrix Multiplication Is Distributive and Associative
This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from PreCal-M2-TE-1.3.0-08.2015
197
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Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
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