Name (Please Print) ______________________________________ Class Times (Circle yours): 9:30 – 10:20 1:30 – 2:20 2:30 – 3:20 STAT 350 Exam 2 Spring 2012 You may have ONLY one sheet of paper with notes handwritten in your own handwriting to take this test. *1 SHOW ALL YOUR NECESSARY WORK to receive credit. You MUST write the correct letter ON THE LINE for EACH multiple choice question. When you finish your exam, turn it in to your instructor, sign the roster, and show your Purdue I.D. You are expected to uphold the Honor Code of Purdue University. It is your responsibility to keep your work covered at all times, you must not exchange anything during the exam. *2 *1 and 2: A grade of 0 will be given, as a punishment to any violations. All multiple choice questions are worth 4 points each. Page Points Score 2 20 3 24 4 16 5 20 6 19 VERSION A Cheat-Sheet Total 1 100 _______ 1.The Arkansas State Police wish to estimate the average mph being traveled on the Interstate Highways, which cross the state. If the estimate is to be within 8 mpg of the true mean with 98% confidence and the estimated standard deviation is 24 mph, how large a sample size must be taken? A. 42 B. 49 C. 15 D. 14 E. 41 _______ 2. A random sample of 100 observations has 25 successes. A 90% confidence interval for p, the population proportion of success is A) B) C) D) E) .179 and .321 .246 and .254 .248 and .252 .423 and .567 None of the above answers are correct. _______ 3. Purdue and IUPUI students are asked if they stay up all night before exams. 32% of Purdue students admitted they have done so, and 29% of IUPUI student said they have done so. A 95% confidence interval for p1 – p 2 yields 0.03 ± 0.023. If we conducted a significance test of H0: p1 = p 2 vs. Hα: p 1 ≠ p 2 with α = 0.05, we should (1: Purdue, 2: IUPUI) A. Reject H0 B. Fail to Reject H0 C. Reject Ha D. Fail to reject Ha E. None of A to D. _______ 4. Which of the following is not typical ANOVA applications? A) Will three different levels of a chemical concentration have different effects on an electroplating process? B) Do four different brands of gasoline have different effects on automobile fuel efficiency? C) Is there any difference in crop yields when five different fertilizers are used? D) All of the above. E) None of the Above. _______ 5. In a single-factor ANOVA problem involving five populations, which of the following statements are true about the alternative hypothesis? A) All five population means are equal. B) All five population means are different. C) At least two of the population means are different. D) At least three of the population means are different. E) At most, two of the population means are equal. For question #6-#11 (4 pts each), in each of the two boxes, specify which type of problem it is and identify whether the distribution is a Z, t or F. For the type of story, it can be any of the following (specify by the letter): May be used more than once. A. 1-sample mean D. 1-sample Proportion B. 2-sample comparison of means E. 2-Sample Proportion(s) C. Matched pair Data F. One-Way ANOVA Type of Story Distribution ( Z, t, or F ) 6. Are there more percentage of vegans in New York than in California? Suppose if we compare samples of 100 people from each state? 7. Is there a difference in the average number of green M&Ms for plain, peanut and almond M&Ms? 8. A report from the M&M/Mars candy company claims that there is an average of 5 brown M&Ms in each fun pack. Does our sample of 20 fun packs agree with this? 9. Will a change in the production process will result in a reduced defective rate? Previous report claimed that 5% of items produced by a manufacturer during a certain period were defective. An engineer use a sample of 1000 items by the manufacturer to test this statement. 10. Do vegans in the population consume less than 2000 calories a day on average? We use a sample of 100 people to test this claim. 11. Each pack has both brown plain M&Ms and brown peanut M&Ms. 15 packs are randomly selected, for each Joey counts the numbers of both brown plain M&Ms and brown peanut M&Ms. He wants to know: On average, are there a larger number of brown plain M&Ms than brown peanut M&Ms in the fun packs? 12. Suppose that the two-sided large sample confidence interval for a population mean at the 95% confidence level based on a particular sample is (104.6, 109.4). Consider now using this sample to test, at a significance level of .05, the null hypothesis Ho : 110 against the two-sided alternative H a : 110 . Then the p-value must be _______ .05, so that H o ______ rejected. A. >, is B. >, isn’t C. <, is D. <, isn’t In fabric production, does unabraded condition lead to higher breaking load than the braded condition? Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both an unabraded condition and an abraded condition. Assume the fabrics are randomly selected. Answer questions 13-15. Fabric U B d= U-B _______ 13. 1 2 3 4 5 6 7 8 25.6 26.5 -0.9 48.8 52.5 -3.7 49.8 46.5 3.3 43.2 36.5 6.7 38.7 34.5 4.2 55.0 20.0 35.0 36.4 28.5 7.9 51.5 46.0 5.5 What is an appropriate alternative hypothesis for this situation? Suppose d = Unbraded – Braded. A. d 0 B. d 0 . C. d 0 D. Unbraded 0 . _______ 14. What is the most appropriate description about this experiment? A. B. C. D. E. One-Sample Mean test Two-Sample Mean test Matched-Pair Data’s Mean test One-Way ANOVA None of the above. Given d 7.25, sd 11.8628 , what is the conclusion to the test in question #13? _______ 15. A. There is not enough evidence to say that the unbraded condition leads to higher breaking load than the braded condition does. B. There is enough evidence to say that the unbraded condition leads to higher breaking load than the braded condition does. C. There is not enough evidence to claim that the breaking load for the two fabric conditions (brade and unbraded) are equal. D. There is sufficient evidence to claim that the breaking load for the two fabric conditions (brade and unbraded) are equal. 16. When exposed to 100 pCi/L of radon, the radon detector readings are normally distributed. A sample of 12 radon detectors of a certain type was selected (with each exposed to 100 pCi/L of radon) and had a sample average reading of 97.075 with a sample standard deviation of 6.1095. a) (4 pts) Based on above data, construct a 95% confidence interval for the population mean reading. b) (3 pts) Does this data suggest that the population mean reading under these conditions differs from 100? State the appropriate hypotheses. c) (3 pts) Calculate the test statistic. d) (3 pts) Find the p-value. e) (4 pts) Do you reject H0 or fail to reject H0? Assume =.05. Also, state the conclusion in layman's terms. f) (3 pts) Briefly interpret how you could answer part e) using your calculated confidence interval in part a), instead of the test and P-value in parts c) & d). 17. Are there equal numbers of the different colors of M&Ms in a package? Data was collected to study this question. Use the outputs below to answer the following questions: The MEANS Procedure Color N Mean Std Dev ƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒ Brown 275 74.748 30.8780 ƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒ Yellow 329 88.588 41.1042 ƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒ Red 327 79.135 32.4722 ƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒ Blue 405 116.338 50.6202 ƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒ Orange 564 144.889 56.3664 ƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒ Green 337 94.246 42.6666 Ƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒƒ Source Model Error Corrected Total DF ______ 2231 ______ Sum of Squares Analysis of Variance Mean Square 1667491.213 ___________ ___________ __________ 855.731 F Value _______ a) (2 pts)What is the factor(s) in this study? How many levels does the factor(s) have? b) (4 pts)What are the appropriate (both the null and alternative hypotheses) hypotheses for your test? c) (9 pts) Complete the above ANOVA table by filling the six missing values. Write them on the above lines. d) (4 pts) Regardless of the answer to part (b), What is the test statistic value (keep 3 decimal places)? Do you reject H0 or fail to reject it? Summarize you conclusion in Layman’s terms.