Experiment 9: Preparation of Methyl Salicyclate O O H2SO4 OH OCH3 + CH3OH OH OH + H2O Wintergreen (methyl salicylate) Gaultheria procumbens This tiny, North American plant of the heath family grows in pine forests and on humid ground with sphagnum. The Indians knew its effects, which is due to methyl salicylate. Like salicylic acid, it is analgesic and antipyretic. O OCH3 HO *bottle Experimental setup: total reflux Vacuum Distillation OCH3 O HO BP 222 °C at 100 kPa Vapor Pressure vs Temperature of Water 250 At what temperature will it boil at 10 kPa? Vapor Pressure (kPa) 200 150 P/kPa 100 50 0 0 20 40 60 80 100 120 140 Temperature, °C Rule of thumb: BP decreases by 10 °C each time the atm pressure decreases by ½. T/ C 100 22 50 210 25 200 12.5 190 6.3 180 3.1 170 1.6 160 0.8 150 0.4 140 How do I go about figuring out what my unknown is? 1. From your solubility measurements, you should be able to classify your unknowns according to the solubility classes discussed. 2. Look up some reference IR spectra in your manual that have the possible functional groups present in your unknown. 3. Look up some possible classification tests you can run to confirm their presence. 4. Complete and hand in your preliminary report if you haven’t done so. 5. Select a possible derivative based on the properties of the derivative. For example, choose a derivative that will allow you to distinguish between other possible compounds with melting points (±5 C) or boiling points (±10 C) within the value of your unknown Classification Tests Classification test should only be run to confirm your suspicions regarding the presence of a functional group suggested by your solubility tests or IR. Always run a blank and a known at the same time you run your unknown so that you know what a positive test looks like and that you performed the classification test properly. Derivatives A derivative should be chosen whose melting temperature will allow you to differentiate between possible compounds. If you have a carboxylic acid or an amine, a titration can be substituted for a derivative providing that the molecular weights of other possible compounds in your possibility list can be excluded on the basis of your titration results. What information can we deduce from this spectrum? 100 % Transmittance 80 60 40 20 1718 cm-1 0 4000 3500 neat liquid 3000 2500 2000 -1 Wavenumbers, cm 1500 1000 500 What information can we deduce from this spectrum? 100 % Transmittance 80 60 40 20 0 4000 3500 3000 2500 2000 -1 Wavenumber cm KBr disk 1500 1000 500 100 % Transmittance 80 60 carbon-carbon triple bond stretch 40 20 0 4000 3500 3000 2500 2000 -1 Wavenumbers, cm neat liquid 1500 1000 500 100 % Transmittance 90 80 70 60 50 40 sp2 C-H stretches overtones of the benzene ring 3 sp C-H stretches 30 20 4000 3500 3000 2500 2000 Wavenumbers, cm-1 The following is a liquid hydrocarbon 1500 1000 100 % Transmittance 80 60 40 20 Top: CHCl3 vs CHCl3 Bottom: 5% in CHCl3 0 4000 3500 3000 2500 2000 Wavenumbers, cm-1 The compound contains nitrogen 1500 1000 500 100 % Transmittance 80 60 40 20 0 4000 3500 3000 2500 2000 1500 -1 Wavenumbers, cm Compound contains C, H, O 1000 500