Physics 249 Homework 11 Due Dec 14th 1) Two charged pions at rest annihilate according to the interaction π + + π − → πΎ + πΎ. a) Why must the energies of the two gamma rays be equal? b) Find the energy of each gamma ray. c) Can two pions annihilate to one gamma ray? Explain your answer. a,b) In rest frame the four vectors are: for the initial state ππ− = (πΈπ , πβπ ) ππ+ = (πΈπ , −πβπ ) where πΈπ = (|πβπ |2 + ππ2 )1/2 for the final state: ππΎ1 = (πΈπΎ1 , πβπΎ1 ) ππΎ2 = (πΈπΎ2 , −πβπΎ1 ) 2 1/2 where πΈπΎ1 = (|πβπΎ1 | + ππΎ2 ) 2 1/2 = |πβπΎ1 | = πΈπΎ2 = (|−πβπΎ1 | + ππΎ2 ) = |πβπΎ1 | c) For the final state in this problem ππΎ = (2πΈπ , πβπ + (−πβπ )) = (2πΈπ , 0) then π£πΎ = 0 and ππΎ = ((2πΈπ )2 + 0)1/2 = 2πΈπ ≠ 0 both of which are unphysical properties for a real photon. Note they are fine for a virtual photon. 2) Antiproton can be made via the interaction π + π → π + π + π + πΜ . a) Derive the minimum kinetic energy for this interaction of one proton is at rest in this interaction. b) Why can’t we produce antiprotons via π + π → π + πΜ ? Give one reason. a) In the lab frame of the proton at rest. For the initial state ππ1 = (ππ , 0) ππ2 = (πΈπ2 , πβπ2 ) 1/2 πΈπ2 = (|πβπ2 |2 + ππ2 ) For the final state in the lab frame of the proton at rest. The minimum energy occurs when there is not extra momentum. i.e. the four particles are going in the direction of the original proton with no negative contributions. In fact should have the same momentum or there would be extra contributions to the energy in their rest own frame. 1/2 ππ = (πΈπ2 + ππ , πβπ2 ) = ((|πβπ2 |2 + ππ2 ) where 1/2 πΈπ2 + ππ = (|πβπ2 |2 + 16ππ2 ) 1/2 (|πβπ2 |2 + ππ2 ) + ππ , πβπ2 ) 1/2 + ππ = (|πβπ2 |2 + 16ππ2 ) 1/2 |πβπ2 |2 + ππ2 + 2ππ (|πβπ2|2 + ππ2 ) 1/2 2ππ (|πβπ2 |2 + ππ2 ) + ππ2 = |πβπ2 |2 + 16ππ2 = 14ππ2 1/2 (|πβπ2 |2 + ππ2 ) = 7ππ |πβπ2 |2 + ππ2 = 49ππ2 |πβπ2 | = (48)1/2 ππ then 1/2 1/2 πΈπ2 = (|πβπ2 |2 + ππ2 ) = (48ππ2 + ππ2 ) and for kinetic (non mass energy) = 7ππ πΎπΈπ2 = 7ππ − ππ = 6ππ = 5.6πΊππ b) Conservation or charge or conservation of baryon number 3) Text book 12-12 a) EM b) Weak c) EM d) Weak e) Strong f) Weak 4) Text book 12-17 a) Conservation of energy, though this can be allowed in a atom where the energy can come from the bound state energy of the nucleus. b) Conservation of energy. The pion is too massive. c) Conservation of momentum would be violated to give the photon non zero momentum and thus velocity in the center of mass frame. d) This is fine e) Conservation of leptons number f) Conservation of baryon number