Unit 3 Pressure in a Fluid System

advertisement

Pressure in

Fluid Systems

Unit 3 Pressure Pages 43-60

Fluid

Hydraulic

System

Pneumatic

System

Density

Specific gravity

Buoyant force

Hydrometer

Pressure

PSI

Atmospheric

Pressure

Absolute pressure

Gage pressure

Manometer

Pressure in a Fluid System

Unit 3 Review

Page 53

#1-15

Fluid

Gas or liquid that conforms to the shape of the container

“Anything that flows”

Hydraulic system

Fluid system that uses liquid as the fluid

Pneumatic system

Fluid system that uses air or gas as the fluid

Why does a hot air balloon float?

Why does motor oil rise to the top of water?

Density

Amount of matter in a given amount of substance

= Mass/Volume

Density

SI measured in:

 Kg/m 3 or gm/cm 3

English measured in:

 Lbm/ft 3 or lb/ft 3

Density

What is the density of gold if you have a 1.036cm

3 piece that had a mass of 20grams?

D=m/v

D=20g/1.036cm

3

D=19.3g/cm 3

Density

What is the density of gold if you have a 3.108cm

3 piece that had a mass of 60grams?

D=m/v

D=60g/3.108cm

3

D=19.3g/cm 3

Other Densities

Platinum

Diamond

Chromium

Tin (white)

Tin (gray)

21.45

3.5-3.53

7.15

7.265

5.769

Density

What is the mass in grams of mercury with a volume of 1cm 3 ?

D = m / v

13.6 g/cm 3 = m / 1cm 3

13.6 g = m

Density

What is the mass in kilograms of balsa wood with a volume of 1m 3 ?

1m

3

= __cm

3

1m

3

= 100cm x

100cm x 100cm

= 1,000,000 cm

3

D = m / v

.3g / cm 3 = m / 1m 3

.3g / cm 3 = m / 1,000,000cm 3

300,000 g = m

300 kg = m

Specific Gravity

Density of a substance divided by the density of water

Because specific gravity is density/density the units cancel out and is written as a whole number

Specific Gravity

Copper has a density of

8.9g/cm 3

What is its specific gravity?

Specific Gravity = density of substance density of water

S.G. = (8.9g/cm 3 ) / (1.0g/cm 3 )

S.G. = 8.9

Buoyant Force

The upward force on a substance from a fluid

Will lead sink or float in water?

Will it sink or float in mercury?

Hydrometer

Instrument that measures density or specific gravity of fluids

Can you sink or float in quick sand?

(mythbusters

)

Pressure

Force per unit area exerted by a fluid

Force on Airplane Windows

An airplane window has a surface area of

136 square inches.

Air pressure inside the cabin is 12.3 lb/in

2

The force pushing on the window

Pressure

What happens to the pressure as we move away from the earth?

 http://www.sciencedaily.com/videos/2006/1201home_runs_amp_holeinone.htm

Force on Airplane Windows

An airplane window has a surface area of

144 square inches.

Air pressure inside the cabin is 14.7 lb/in

2

Air pressure outside the window is 6.7 lb/in

2

The force pushing in the window

The force pushing out the window

Net force on window

Inward force on window

F = P x A

F = (6.7 lb/in 2 )(144in 2 )

F= 964.8lb

Outward force on window

F = P x A

F = (14.7lb/in 2 )(144in 2 )

F = 2116.8 lb

Net Force on window

Net Force = Force out – Force in

Net Force = 2116.8 lb – 964.8 lb

Net Force = 1152 lb

The window is being pushed outward with a net force of

1152 lb.

Net Force on window

If the plane rises to a higher altitude and the pressure outside the plane changes to 5.4 lb/in 2

How much stronger will the windows need to be in order to hold the pressure

Outward force on window

F = P x A

F = (14.7lb/in 2 )(144in 2 )

F = 2116.8 lb

Inward force on window

F = P x A

F = (5.4 lb/in 2 )(144in 2 )

F= 777.6lb

Net Force on window

Net Force = Force out – Force in

Net Force = 2116.8 lb – 777.6 lb

Net Force = 1339.2 lb

The window was originally pushing outward with a net force of 1152 lb.

Therefore it needs to hold 187.2 more pounds of pressure

(1339.2 – 1152)

Pressure

Pressure acts equally in all direction at any point in a fluid and therefore it is a scalar

Absolute vs. Gage Pressure

When we fill a tire to 30lb/in 2 is that the absolute or the gage pressure?

Atmospheric pressure =

14.7 lb/in 2

Absolute Pressure

Total pressure compared to a perfect vacuum

Gage Pressure

Pressure measured above atmospheric pressure

G.P = Total pressure – atmospheric pressure

Gage pressure is generally measured “with a gage”

Total Pressure

Pressure

Tire gage reads 38lb/in 2

What is the atmospheric pressure?

What is the gage pressure?

What is the total pressure?

Pressure

Tire gage reads 38lb/in 2

What is the atmospheric pressure?

What is the gage pressure?

What is the total pressure?

How does pressure change with depth?

Where is the pressure greater the shallow end or the deep end?

Why?

Pressure increases with depth

There is more water sitting on top of the deep end

There is more weight on top

Which means more force

Which means more pressure

Relationship between pressure and depth

Water Pressure Calculation

Given:

The height of the water in a storage tank is 100 ft above the valve. The weight density of water is 62.4 lb/ft 3

Find:

The pressure at the valve in lb/ft 2

Water Pressure Calculation

P = p w x h

P = (62.4 lb/ft 3 )(100ft)

P = 6240 lb/ft 2

Given: 1 ft 2 = 144 in 2

Now find:

Pressure in PSI

Water Pressure Calculation

P = pw x h

P = (62.4 lb/ft3)(100ft)

P = 6240 lb/ft 2

Given: 1 ft 2 = 144 in 2

 p = (6240 lb/ft 2 )(1ft2/144in 2 )

P = 43.3 lb/in 2 (psi)

Balanced pressure across the valve

Unbalanced pressure across the valve

Pressure on bottom does not depend on the size of the tank

Pressure acts like forces

Pressure is a prime mover

Measuring Pressures

Manometer – instrument used to measure fluid pressure

Hydraulic lift

Liquids are incompressible

Air compressor increases the pressure to the fluid

Large pushing force is exerted on the lifting piston

Hydraulic jack?

Large cylinder to a small cylinder

Same pressure = more force in the smaller cylinder

Small to large = allowable force but small increments?

An enclosed fluid under pressure exerts that pressure throughout its volume and against any surface containing it. That's called 'Pascal's Principle', and allows a hydraulic lift to generate large amounts of FORCE from the application of a small

FORCE.

Assume a small piston (one square inch area) applies a weight of 1 lbs. to a confined hydraulic fluid. That provides a pressure of 1 lbs. per square inch throughout the fluid. If another larger piston with an area of 10 square inches is in contact with the fluid, that piston will feel a force of 1 lbs/square inch x 10 square inches = 10 lbs.

So we can apply 1 lbs. to the small piston and get 10 lbs. of force to lift a heavy object with the large piston. Is this 'getting something for nothing'? Unfortunately, no. Just as a lever provides more force near the fulcrum in exchange for more distance further away, the hydraulic lift merely converts work (force x distance) at the smaller piston for the SAME work at the larger one. In the example, when the smaller piston moves a distance of 10 inches it displaces 10 cubic inch of fluid.

That 10 cubic inch displaced at the 10 square inch piston moves it only 1 inch, so a small force and larger distance has been exchanged for a large force through a smaller distance.

Download