Fluid
Hydraulic
System
Pneumatic
System
Density
Specific gravity
Buoyant force
Hydrometer
Pressure
PSI
Atmospheric
Pressure
Absolute pressure
Gage pressure
Manometer
Gas or liquid that conforms to the shape of the container
“Anything that flows”
Fluid system that uses liquid as the fluid
Fluid system that uses air or gas as the fluid
Why does a hot air balloon float?
Why does motor oil rise to the top of water?
Amount of matter in a given amount of substance
= Mass/Volume
SI measured in:
Kg/m 3 or gm/cm 3
English measured in:
Lbm/ft 3 or lb/ft 3
What is the density of gold if you have a 1.036cm
3 piece that had a mass of 20grams?
D=m/v
D=20g/1.036cm
3
D=19.3g/cm 3
What is the density of gold if you have a 3.108cm
3 piece that had a mass of 60grams?
D=m/v
D=60g/3.108cm
3
D=19.3g/cm 3
Platinum
Diamond
Chromium
Tin (white)
Tin (gray)
21.45
3.5-3.53
7.15
7.265
5.769
What is the mass in grams of mercury with a volume of 1cm 3 ?
D = m / v
13.6 g/cm 3 = m / 1cm 3
13.6 g = m
What is the mass in kilograms of balsa wood with a volume of 1m 3 ?
1m
3
= __cm
3
1m
3
= 100cm x
100cm x 100cm
= 1,000,000 cm
3
D = m / v
.3g / cm 3 = m / 1m 3
.3g / cm 3 = m / 1,000,000cm 3
300,000 g = m
300 kg = m
Density of a substance divided by the density of water
Because specific gravity is density/density the units cancel out and is written as a whole number
Copper has a density of
8.9g/cm 3
What is its specific gravity?
Specific Gravity = density of substance density of water
S.G. = (8.9g/cm 3 ) / (1.0g/cm 3 )
S.G. = 8.9
The upward force on a substance from a fluid
Will lead sink or float in water?
Will it sink or float in mercury?
Instrument that measures density or specific gravity of fluids
Can you sink or float in quick sand?
(mythbusters
)
Force per unit area exerted by a fluid
An airplane window has a surface area of
136 square inches.
Air pressure inside the cabin is 12.3 lb/in
2
The force pushing on the window
What happens to the pressure as we move away from the earth?
http://www.sciencedaily.com/videos/2006/1201home_runs_amp_holeinone.htm
An airplane window has a surface area of
144 square inches.
Air pressure inside the cabin is 14.7 lb/in
2
Air pressure outside the window is 6.7 lb/in
2
The force pushing in the window
The force pushing out the window
Net force on window
F = P x A
F = (6.7 lb/in 2 )(144in 2 )
F= 964.8lb
F = P x A
F = (14.7lb/in 2 )(144in 2 )
F = 2116.8 lb
Net Force = Force out – Force in
Net Force = 2116.8 lb – 964.8 lb
Net Force = 1152 lb
The window is being pushed outward with a net force of
1152 lb.
If the plane rises to a higher altitude and the pressure outside the plane changes to 5.4 lb/in 2
How much stronger will the windows need to be in order to hold the pressure
F = P x A
F = (14.7lb/in 2 )(144in 2 )
F = 2116.8 lb
F = P x A
F = (5.4 lb/in 2 )(144in 2 )
F= 777.6lb
Net Force = Force out – Force in
Net Force = 2116.8 lb – 777.6 lb
Net Force = 1339.2 lb
The window was originally pushing outward with a net force of 1152 lb.
Therefore it needs to hold 187.2 more pounds of pressure
(1339.2 – 1152)
Pressure acts equally in all direction at any point in a fluid and therefore it is a scalar
When we fill a tire to 30lb/in 2 is that the absolute or the gage pressure?
Atmospheric pressure =
14.7 lb/in 2
Total pressure compared to a perfect vacuum
Pressure measured above atmospheric pressure
G.P = Total pressure – atmospheric pressure
Gage pressure is generally measured “with a gage”
Tire gage reads 38lb/in 2
What is the atmospheric pressure?
What is the gage pressure?
What is the total pressure?
Tire gage reads 38lb/in 2
What is the atmospheric pressure?
What is the gage pressure?
What is the total pressure?
Where is the pressure greater the shallow end or the deep end?
Why?
There is more water sitting on top of the deep end
There is more weight on top
Which means more force
Which means more pressure
Relationship between pressure and depth
Water Pressure Calculation
Given:
The height of the water in a storage tank is 100 ft above the valve. The weight density of water is 62.4 lb/ft 3
Find:
The pressure at the valve in lb/ft 2
Water Pressure Calculation
P = p w x h
P = (62.4 lb/ft 3 )(100ft)
P = 6240 lb/ft 2
Given: 1 ft 2 = 144 in 2
Now find:
Pressure in PSI
Water Pressure Calculation
P = pw x h
P = (62.4 lb/ft3)(100ft)
P = 6240 lb/ft 2
Given: 1 ft 2 = 144 in 2
p = (6240 lb/ft 2 )(1ft2/144in 2 )
P = 43.3 lb/in 2 (psi)
Balanced pressure across the valve
Unbalanced pressure across the valve
Pressure on bottom does not depend on the size of the tank
Pressure acts like forces
Pressure is a prime mover
Measuring Pressures
Manometer – instrument used to measure fluid pressure
Hydraulic lift
Liquids are incompressible
Air compressor increases the pressure to the fluid
Large pushing force is exerted on the lifting piston
Hydraulic jack?
Large cylinder to a small cylinder
Same pressure = more force in the smaller cylinder
Small to large = allowable force but small increments?
An enclosed fluid under pressure exerts that pressure throughout its volume and against any surface containing it. That's called 'Pascal's Principle', and allows a hydraulic lift to generate large amounts of FORCE from the application of a small
FORCE.
Assume a small piston (one square inch area) applies a weight of 1 lbs. to a confined hydraulic fluid. That provides a pressure of 1 lbs. per square inch throughout the fluid. If another larger piston with an area of 10 square inches is in contact with the fluid, that piston will feel a force of 1 lbs/square inch x 10 square inches = 10 lbs.
So we can apply 1 lbs. to the small piston and get 10 lbs. of force to lift a heavy object with the large piston. Is this 'getting something for nothing'? Unfortunately, no. Just as a lever provides more force near the fulcrum in exchange for more distance further away, the hydraulic lift merely converts work (force x distance) at the smaller piston for the SAME work at the larger one. In the example, when the smaller piston moves a distance of 10 inches it displaces 10 cubic inch of fluid.
That 10 cubic inch displaced at the 10 square inch piston moves it only 1 inch, so a small force and larger distance has been exchanged for a large force through a smaller distance.