Aerodynamic Forces

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Aerodynamic Forces
Lift and Drag
Aerospace Engineering
© 2011 Project Lead The Way, Inc.
Lift Equation
Lift
Coefficient of Lift, Cl
– Determined experimentally
– Combines several factors
• Shape
• Angle of attack
2𝐿
𝐢𝑙 =
π΄πœŒπ‘£ 2
Alternate format
𝐿
𝐢𝑙 =
π‘žπ΄
Direction of Flight
𝐢𝑙 = πΆπ‘œπ‘’π‘“π‘“π‘–π‘π‘–π‘’π‘›π‘‘ π‘œπ‘“ 𝐿𝑖𝑓𝑑
𝐷 = π·π‘Ÿπ‘Žπ‘” 𝑁
𝐴 = π‘Šπ‘–π‘›π‘” π΄π‘Ÿπ‘’π‘Ž π‘š2
π‘˜π‘”
𝜌 = 𝐷𝑒𝑛𝑠𝑖𝑑𝑦
π‘š3
π‘š
𝑣 = π‘‰π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦
𝑠
π‘ž = π·π‘¦π‘›π‘Žπ‘šπ‘–π‘ π‘ƒπ‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘ƒπ‘Ž
Applying the Lift Equation
The Cessna 172 from Activity 1.2.2 step
#2 takes off successfully from Denver, CO
during an average day in May (22 OC) with
a standard pressure (101.3 kPa). Assume
that the take-off speed is 55 knots (102
kph). What is the minimum coefficient of
lift needed at the point where the aircraft
just lifts off the ground? The Cessna wing
area is 18.2 m2 and weight is 2,328 lb
(1,056 kg).
Applying the Lift Equation
Convert mass into weight
𝑀 = π‘šπ‘”
π‘š
𝑀 = (1,056 π‘˜π‘”) 9.81 2
𝑠
𝑀 = 10,359 𝑁
Convert velocity
π‘š
102 π‘˜π‘β„Ž 1000
π‘˜π‘š
𝑉=
π‘šπ‘–π‘›
𝑠
60
60
π‘šπ‘–π‘›
β„Žπ‘Ÿ
π‘š
𝑉 = 28.3
𝑠
Applying the Lift Equation
Calculate Air Density
𝜌=
0.2869
𝐽
π‘˜π‘” 𝐾
𝑝
𝐾
𝑇 + 273.1℃
℃
101.29 π‘˜π‘ƒπ‘Ž
𝜌=
0.2869
𝐽
π‘˜π‘” 𝐾
π‘˜π‘”
𝜌 = 1.196 3
π‘š
𝐾
22 ℃ + 273.1℃
℃
Applying the Lift Equation
Calculate coefficient of lift assuming that
lift equals weight
2𝐿
𝐢𝑙 =
π΄πœŒπ‘£ 2
𝐢𝑙 =
18.2 π‘š2
𝐢𝑙 = 1.19
2(10,359 𝑁)
π‘˜π‘”
π‘š
1.196 3 28.3
𝑠
π‘š
2
Boundary Layer
• Fluid molecules stick to object’s surface
• Creates boundary layer of slower moving
fluid
• Boundary layer is crucial to wing
performance
Boundary Layer and Lift
• Airflow over object is slower close to
object surface
• Air flow remains smooth until critical
airflow velocity
• Airflow close to object becomes turbulent
Reynolds Number, Re
• Representative value to compare different
fluid flow systems
• Object moving through fluid disturbs
molecules
• Motion generates aerodynamic forces
Airfoil1
Comparable
to
Airfoil2
when
Re1
=
Re2
Angle of Attack (AOA) Affects Lift
Lift increases with AOA up to stall angle
Airflow
Lift
Lift
Airflow
Direction of Flight
Lift
Stall
Direction
of Flight
Angle of Attack
Reynolds Number
• Ratio of inertial (resistant to change)
forces to viscous (sticky) forces
• Dimensionless number
πœ‡
v𝑙
𝜌v𝑙
ν=
𝑅𝑒 =
𝑅𝑒 =
or
𝜌
ν
πœ‡
𝑙 = πΏπ‘’π‘›π‘”π‘‘β„Ž π‘œπ‘“
𝑅𝑒 = π‘…π‘’π‘¦π‘›π‘œπ‘™π‘‘π‘  π‘π‘’π‘šπ‘π‘’π‘Ÿ
𝐹𝑙𝑒𝑖𝑑 π‘‡π‘Ÿπ‘Žπ‘£π‘’π‘™ π‘š
π‘˜π‘”
𝑁𝑠
𝜌 = 𝐹𝑙𝑒𝑖𝑑 𝐷𝑒𝑛𝑠𝑖𝑑𝑦
πœ‡ = 𝐹𝑙𝑒𝑖𝑑 π‘‰π‘–π‘ π‘π‘œπ‘ π‘–π‘‘π‘¦
π‘š3
π‘š2
π‘š
2
v = π‘‰π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦
π‘š
𝑠
ν = πΎπ‘–π‘›π‘’π‘šπ‘Žπ‘‘π‘–π‘ π‘‰π‘–π‘ π‘π‘œπ‘ π‘–π‘‘π‘¦
𝑠
Applying Reynolds Number
A P-3 Orion is cruising at 820 kph (509
mph) at an altitude of 4,023 m (13,198 ft).
Assume a fluid viscosity coefficient of
1.65x10-5 N(s)/m3. What is the average
Reynolds Number along a wing cross
section measuring 1.1 m (3.6 ft) from
leading edge to trailing edge?
Need components to calculate Re
𝜌v𝑙
𝑅𝑒 =
πœ‡
Applying Reynolds Number
Calculate Air Temperature
℃
𝑇 = 15.04℃ − 0.00649
β„Ž
π‘š
℃
𝑇 = 15.04℃ − 0.00649 (4,023 π‘š)
π‘š
𝑇 = −11.1℃
Calculate Air Pressure
𝑝 = 101.29π‘˜π‘ƒπ‘Ž
𝑝 = 61.5 π‘˜π‘ƒπ‘Ž
𝐾
−11.1℃ + 273.1℃
℃
288.08 𝐾
5.256
Applying Reynolds Number
Calculate Air Density
𝑝
𝜌=
0.2869
𝐽
π‘˜π‘” 𝐾
𝑇 + 273.1
61. 5 π‘˜π‘ƒπ‘Ž
𝜌=
0.2869
𝐽
π‘˜π‘” 𝐾
π‘˜π‘”
𝜌 = 0.818 3
π‘š
𝐾
−11.1 ℃ + 273.1
℃
Applying Reynolds Number
Convert Velocity
π‘š
820 π‘˜π‘β„Ž 1000
π‘˜π‘š
𝑉=
π‘šπ‘–π‘›
𝑠
60
60
π‘šπ‘–π‘›
β„Žπ‘Ÿ
π‘š
𝑉 = 227.8
𝑠
Applying Reynolds Number
Calculate Re
𝜌v𝑙
𝑅𝑒 =
πœ‡
π‘˜π‘”
π‘š
0.817 3 227.8
(1.1 π‘š)
𝑠
π‘š
𝑅𝑒 =
𝑁𝑠
−5
1.65 × 10
π‘š2
𝑅𝑒 = 12,408,000
Drag Equation
Drag
Coefficient of drag, Cd
– Determined experimentally
– Combines several factors
• Shape
• Angle of attack
2×𝐷
𝐢𝑑 =
𝐴 × πœŒ × π‘£2
Alternate format
𝐷
𝐢𝑑 =
π‘ž ×𝐴
Direction of Flight
𝐢𝑑 = πΆπ‘œπ‘’π‘“π‘“π‘–π‘π‘–π‘’π‘›π‘‘ π‘œπ‘“ π·π‘Ÿπ‘Žπ‘”
𝐷 = π·π‘Ÿπ‘Žπ‘” 𝑁
𝐴 = π‘Šπ‘–π‘›π‘” π΄π‘Ÿπ‘’π‘Ž π‘š2
π‘˜π‘”
𝜌 = 𝐷𝑒𝑛𝑠𝑖𝑑𝑦
π‘š3
π‘š
𝑣 = π‘‰π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦
𝑠
π‘ž = π·π‘¦π‘›π‘Žπ‘šπ‘–π‘ π‘ƒπ‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘ƒπ‘Ž
Coefficient of Drag (Cd)
Object shape affects Cd
Applying the Drag Equation
The same Cessna 172 from Activity 1.2.2
step #2 takes off under the same
conditions as described earlier in this
presentation. How much drag is produced
when the wing is configured such that the
coefficient of drag is 0.05?
Applying the Drag Equation
Calculate drag
2𝐷
𝐢𝑑 =
π΄πœŒπ‘£ 2
𝐢𝑑 π΄πœŒπ‘£ 2
𝐷=
2
0.05
18.2 π‘š2
𝐷=
𝐷 = 436 𝑁
π‘˜π‘”
1.196 3
π‘š
2
π‘š
28.3
𝑠
2
Downwash and Wingtip Vortices
• Pressure difference at wing tips
• Air to spill over wingtip perpendicular to
main airflow
• Air flows both upward and rearward,
forming a vortex
• Decreases lift
• Increases drag
Wingtip Vortices
• Air flows both upward and rearward, forming
a vortex
• Winglets are vertical airfoils that limit vortices
and improve fuel efficiency
Reference
National Aeronautics and Space Administration (2011). Aerodynamic
forces. Retrieved from http://www.grc.nasa.gov/WWW/K12/airplane/presar.html
National Aeronautics and Space Administration (2011). Reynolds
number. Retrieved from
http://www.grc.nasa.gov/WWW/BGH/reynolds.html
National Aeronautics and Space Administration (2011). Winglets.
Retrieved from
http://www.nasa.gov/centers/dryden/about/Organizations/Technolog
y/Facts/TF-2004-15-DFRC.html
Raymer, P. (2006). Aircraft design: A conceptual approach. Reston,
VA: American Institute of Aeronautics and Astronautics.
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