Lesson 6.7 Circumference and Arc Length Objectives/Assignment • Find the circumference of a circle and the length of a circular arc. • Use circumference and arc length to solve real-life problems. • Homework: – Lesson 6.7/1-11, 17, 19, 22 • Quiz Wednesday • Chapter 6 Test Friday Finding Circumference and Arc Length • The circumference of a circle is the distance around the circle. • For all circles, the ratio of the circumference to the diameter is the same: or pi. • The exact value of Pi = • The approximate value of Pi ≈ 3.14 Distance around the circle Z 120° Minor Arc 9 Major Arc C X Y Central Angle: XZ •Use 2 letters •Angle is less than or equal to 180 •Use 3 letters •Angle is greater than 180 XYZ Any angle whose vertex is the center of the circle m XZ = m<XCZ = 120o m XYZ = m<XCZ = 240o Circumference of a Circle • The circumference C of a circle is • C = d or C = 2r, where • d is the diameter of the circle and • r is the radius of the circle (2r = d) diameter d Comparing Circumferences • Tire Revolutions • Tires from two different automobiles are shown. • How many revolutions does each tire make while traveling 100 feet? Tire A Tire B Comparing Circumferences - Tire A • C = d • diameter = 14 + 2(5.1) d = 24.2 inches • circumference = (24.2) • C ≈ 75.99 inches. Comparing Circumferences - Tire B • • • • • C = d diameter = 15 + 2(5.25) d = 25.5 inches Circumference = (25.5) C ≈ 80.07 inches Comparing Circumferences Tire A vs. Tire B • Divide the distance traveled by the tire circumference to find the number of revolutions made. • First, convert 100 feet to 1200 inches. Revolutions = distance traveled circumference TIRE A: 100 ft. 75.99 in. 1200 in. = 75.99 in. 15.8 revolutions TIRE B: 100 ft. 80.07 in. 1200 in. = 80.07 in. 14.99 revolutions COMPARISON: Tire A required more revolutions to cover the same distance as Tire B. Arc Length • The length of part of the circumference. The length of the arc depends on what two things? 1) The measure of the arc. 2) The size of the circle (radius). An arc length measures distance while the measure of an arc is in degrees. An arc length is a portion of the circumference of a circle. Portions of a Circle: Determine the Arc measure based on the portion given. 180o 120o 90o 60o 90o 180o 120o 60o A. B. C. D. ¼ of a circle: ¼ ● 360 ½ of a circle: ½ ● 360 1/3 of circumference : 6π out of a total 36π on the circle: 90o 180o 1/3 ● 360 120o 1/6 ● 360 60o Arc Length Formula measure of the central angle or arc Arc Length = m˚ The circumference of the entire circle! 2πr 360˚ The fraction of the circle! . Arc Length • In a circle, the ratio of the length of a given arc to the circumference is equal to the ratio of the measure of the arc to 360°. Arc measure Arc length of AB = m AB • 2r 360° Arc length linear units (inches/feet/meters …) Arc measure degrees Finding Arc Lengths • Find the length of each arc. E a. 5 cm A b. 7 cm C 50° 50° c. 7 cm 100° B D F Finding Arc Lengths, con’t. • Find the length of each arc. a. a. Arc length of AB 5 cm # of ° = A 50° B • 2r 360° 4.36 centimeters 50° a. Arc length of AB Arc length of AB = 360° • 2(5) Finding Arc Lengths, con’t. • Find the length of each arc. b. b. Arc length of CD 7 cm C 50° b. Arc length of CD D # of ° = 360° 50° = • 2r • 2(7) 360° 6.11 centimeters Arc length of CD In parts (a) and (b), note that the arcs have the same measure but different lengths because the circumferences of the circles are not equal. Finding Arc Lengths, con’t. • Find the length of each arc. c. E 12.22 centimeters c. Arc length of EF 7 cm 100° c. Arc length of EF F Arc length of EF # of ° = 360° 100° = • 2r 360° • 2(7) Find the exact length of AB A 90o O 90o 6 300o 240o 240o B O B 300o 12 12 A A O 120o 108o B 120o O 2.4 A 108o O 10√2 A B B mAOB 90 mAOB 240 mAOB 300 mAOB 120 mAOB 108 radius 6 radius 12 radius 12 radius 2.4 radius 10 2 Fraction of circle: Fraction of circle: Fraction of circle: 108 3 360 10 Fraction of circle: 90 1 360 4 Fraction ● circumference ¼ ● 12π 3π units Fraction of circle: 240 2 360 3 Fraction ● circumference 2/3 ● 24π 16π units 300 5 360 6 5/6 ● 24π 20π units 120 1 360 3 1/3 ● 4.8π 1.6π units 3/10 ● 20√2π 6√2π units arclengthAB mAB d 360 60º 50º 50 arclength 2 5 360 arclength 1.38 arclength 4.36cm 60 3.82 d 360 1 3.82 d 6 22.92m d C Using Arc Lengths • Find the indicated measure. = Arc length of m XY XY b. m XY 360° 2r Substitute and Solve for m XY X 18 in. m XY 18 in. = Z 360° • 7.64 in. Y 2(7.64) 360° 18 = (15.28) m XY 135° m XY Finding Arc Length • • • • Race Track. The track shown has six lanes. Each lane is 1.25 meters wide. There is 180° arc at the end of each track. The radii for the arcs in the first two lanes are given. a. Find the distance around Lane 1. (use r1) b. Find the distance around Lane 2. (use r2) Finding Arc Length, con’t a. Find the distance around Lanes 1 and 2. The track is made up of two semicircles two straight sections with length s Finding Arc Length, con’t Lane 1 • Distance = 2s + 2r1 = 2(108.9) + 2(29.00) 400.0 meters Lane 2 • Distance = 2s + 2r2 = 2(108.9) + 2(30.25) 407.9 meters Finding Arc Length Find each arc length. Give answers in terms of and rounded to the nearest hundredth. FG Use formula for area of sector. Substitute 8 for r and 134 for m. 5.96 cm 18.71 cm Simplify. Finding Arc Length Find each arc length. Give answers in terms of and rounded to the nearest hundredth. an arc with measure 62 in a circle with radius 2 m Use formula for area of sector. Substitute 2 for r and 62 for m. 0.69 m 2.16 m Simplify. Check It Out! Find each arc length. Give your answer in terms of and rounded to the nearest hundredth. GH Use formula for area of sector. Substitute 6 for r and 40 for m. = m 4.19 m Simplify. Check It Out! Find each arc length. Give your answer in terms of and rounded to the nearest hundredth. an arc with measure 135° in a circle with radius 4 cm Use formula for area of sector. Substitute 4 for r and 135 for m. = 3 cm 9.42 cm Simplify. Upcoming • • • • • 6.7 Monday 6.7 Tuesday Chapter Review Wednesday Chapter Review Thursday Chapter 6 Test Friday