Title: Lesson 3 Rate Law and Reaction Order Learning Objectives: – Know that rate law can only be derived from experimental data – Understand the concept of reaction order – Identify reaction order from appropriate graphs – Complete an experiment to determine the order of a reaction with respect to the concentration of acid. Recap On the same axes, sketch the Maxwell-Boltzmann distribution for a lower and a higher temperature, and use this to explain why increasing the temperature increases the rate of reaction. Main Menu Recap Excess magnesium, was added to a beaker of aqueous hydrochloric acid. A graph of the mass of the beaker and contents was plotted against time (line 1). Mass 1 What change in the experiment could give line 2? A. B. C. D. The same mass of magnesium in smaller pieces The same volume of a more concentrated solution of hydrochloric acid A lower temperature A more accurate instrument to measure the time Main Menu 2 Time Recap Which quantities in the enthalpy level diagram are altered by the use of a catalyst? A. B. C. D. I and II only I and III only II and III only I, II and III II. III. II III Time Which statement is true about using sulfuric acid as a catalyst in the following reaction? CH3–CO–CH3(aq) + I2(aq) CH3–CO–CH2–I(aq) + HI(aq) I. I Enthalpy The catalyst increases the rate of reaction. The catalyst lowers the activation energy for the reaction. The catalyst has been consumed at the end of the chemical reaction. Main Menu A. B. C. D. I and II only I and III only II and III only I, II and III Ch 1.1 Finding the rate A2 In this reaction, the concentration of butyl chloride, C4H9Cl, was measured at various times, t. How do you find reaction rates? C4H9Cl(aq) + H2O(l) C4H9OH(aq) + HCl(aq) Finding the rate The average rate of the reaction over each interval is the change in concentration divided by the change in time: C4H9Cl(aq) + H2O(l) C4H9OH(aq) + HCl(aq) A2 How do you find reaction rates? Ch 1.1 Finding the rate How do you find reaction rates? Ch 1.1 A2 Finding the rate A2 What do you notice about the average rate? The average rate decreases as the reaction proceeds. Why? As the reaction goes forward, there are fewer collisions between reactant molecules. How do you find reaction rates? Ch 1.1 Given the following data, what is the average rate of the following reaction over the time interval from 54.0 min to 215.0 min? CH3OH (aq) + HCl (aq) → Time (min) 0.0 54.0 107.0 215.0 [HCl] (M) 1.85 1.58 1.36 1.02 CH3Cl (aq) + H2O (l) A2 How do you find reaction rates? Example Ch 1.1 Finding the rate Given: [HCl]54 min = 1.58 M [HCl]215 min = 1.02 M Find: avg. rate of disappearance of HCl Avg. rate = - D [HCl] Dt = - (1.02 M - 1.58 M) 215 min - 54 min = 0.0035M / min A2 How do you find reaction rates? Ch 1.1 Ch 1.1 Finding the rate A2 • A plot of concentration vs. time for this reaction yields a curve like this. • The slope of a line tangent to the curve at any point is the instantaneous rate at that time. How do you find reaction rates? C4H9Cl(aq) + H2O(l) C4H9OH(aq) + HCl(aq) Finding the rate Rate laws for the reaction must be determined experimentally. Measure the instantaneous reaction rate at the start of the reaction (i.e. at t = 0) for various concentrations of reactants. You CANNOT determine the rate law for the reaction by looking at the coefficients in the balanced chemical equation! A2 How do you find reaction rates? Ch 1.1 Now look at this example... An oxidised buckminsterfullerene, C60O3 decomposes into C60O, releasing O2: The reaction can be measured by change of absorbance of light of a certain wavelength. Absorption ∝ [C60O3] Remember: Rate is expressed as a positive value! Main Menu Rate calculated as a function of time: Rate decreases over time, slowing as the concentration of C60O3 decreases. This mirrors the absorbance graph on the previous slide! Rate must be related to concentration at each time Rate of reaction plotted against the absorbance of C60O3: The straight line graph of rate against absorbance confirms: Reaction rate ∝ [C60O3] Main Menu Rate expression or Rate law Reaction rate ∝ [C60O3] This proportional relationship is converted into an equation by introducing a constant. Reaction rate = k[C60O3] This expression is a first order expression because the concentration is raised to the power one. In general, the rate is proportional to the product of the concentrations of the reactants, each raised to a power. m and n, are known as the k = rate constant orders of the reaction with respect to reactants A and B. Main Menu Overall order is the SUM of the individual orders. The table below gives some examples of some reaction equations. There is no predictable relationship between the co-efficients in the equation and the values for the order of reaction with respect to the reactants. ORDERS OF REACTION CAN ONLY BE OBTAINED BY EXPERIMENTAL DATA! Main Menu Main Menu Solutions Main Menu What is reaction order? Reaction order describes how changes to the concentration of reactants affect the rate of a reaction Assuming temperature and pressure are fixed 0th Order (0o) 1st Order (1o) 2nd Order (2o) [R] doubled rate doubled [R] halved rate halved [R] trebled rate trebled [R] doubled rate quadrupled [R] halved rate quartered [R] trebled rate x 9 Changing the concentration does not affect the rate [R] doubled rate same [R] halved rate same [R] trebled rate same Main Menu For example: Initial [B] ([B]0) Initial Rate (v0) 1 1.00 M 1.00 M 1.25 x 10-2 M/s 2 1.00 M 2.00 M 2.5 x 10-2 M/s 3 2.00 M 2.00 M 2.5 x 10-2 M/s Comparing Runs 2 and 3: [A] doubles but [B] remains fixed Rate unchanged The reaction is 1st order w.r.t reactant B Comparing Runs 1 and 2: Initial [A] ([A]0) The reaction is 0th order w.r.t reactant A Run # [B] doubles but [A] remains fixed Rate doubles Overall the reaction is 1st order Main Menu Another example: Experiment Initial rate / mol (N2) dm–3 s–1 1 0.100 0.100 2.53×10–6 2 0.100 0.200 5.05×10–6 3 0.200 0.100 1.01×10–5 4 0.300 0.100 2.28×10–5 Comparing Runs 1 and 2: [H2] doubles but [NO] remains fixed Rate doubles The reaction is 2nd order w.r.t reactant NO Comparing Runs 1 and 3: Initial [H2] / mol dm–3 The reaction is 1st order w.r.t reactant H2 Initial [NO] / mol dm–3 [NO] doubles but [H2] remains fixed Rate quadruples Overall the reaction is 3rd order (1st order + 2nd order = 3rd order) Main Menu First Order Reactions Expt [A] (M) 1 0.50 Rate (M/s) 1.00 x2 2 1.00 x2 2.00 x2 3 2.00 x2 4.00 • First Order Reaction – Overall reaction order = 1 – Rate = k[A] As [A] doubles, the rate doubles [A] rate A2 How do you find reaction rates? Ch 1.1 Expt Second Order Reactions Initial [A] (M) 1 3 x2 1.6 x 10-2 0.2 x1 2 Rate (mol dm-3 s-1) Initial [B] (M ) 0.1 0.1 0.2 [A] stays the same [B] doubles [A] doubles [B] stays the same x2 x1 A2 x2 0.4 -2 3.2 x 10 x4 0.2 6.4 x 10-2 the rate doubles [B] rate the rate is x4 [A]2 rate How do you find reaction rates? Ch 1.1 Second Order Reactions [A] stays the same [B] doubles [A] doubles [B] stays the same the rate doubles [B] rate the rate is x4 [A]2 rate What is the rate equation for this reaction? Rate = k[A]2 [B] The reaction is second order in respect of A and first order in respect of B. The overall reaction order is 3. A2 How do you find reaction rates? Ch 1.1 Second Order Reactions Initial [X]/M 0.10 x1 X0.50.10 0.05 0.10 x1 x1 Initial [Y]/M 0.10 x1 0.10 0.10 0.40 x4 A2 Initial [Z] / M Initial rate/ mol dm-3 s-1 0.10 x3 x1 0.30 0.10 0.10 x1 2.40 x 10-3 x3 -3 NE 7.20 x 10 2.40 x 10-3x1 3.84 x 10-2 [Z] triples [X] &[Y] stay the same the rate trebles [Z] rate [X] halves [Y] & [Z] stay the same the rate is the same [X]0 rate [Y] quadruples [X] & [Z] stay the same the rate goes 2 rate [Y] 2 up by 16 (ie 4 ) How do you find reaction rates? Ch 1.1 Second Order Reactions [Z] triples [X] &[Y] stay the same the rate trebles [Z] rate [X] halves [Y] & [Z] stay the same the rate is the same [X]0 rate [Y] quadruples [X] & [Z] stay the same the rate goes 2 rate [Y] 2 up by 16 (ie 4 ) What is the rate equation for this reaction? Rate = k[Y]2 [Z] The reaction is second order in respect of Y and first order in respect of Z. The overall reaction order is 3. A2 How do you find reaction rates? Ch 1.1 Determination of the order of reaction Initial rates method This involves carrying out separate experiments with different starting concentrations of A, with other reactants held constant effect on [A] can be observed. This can then be repeated for reactant B. Main Menu Main Menu Main Menu Solutions Main Menu Main Menu Graphical representation of reaction kinetics Zero order reaction Concentration of reactant A does not affect the reaction Main Menu Graphical representation of reaction kinetics First-order reaction Rate is directly proportional to the concentration A Main Menu Graphical representation of reaction kinetics Second-order reaction Rate is directly proportional to the square of concentration A Note: The concentration – time graph is steeper at the start and levels off more (when compared to first-order graph) Main Menu Parabola shape – characteristic of the square function Summary Main Menu Rate-Concentration Graphs 1st Order 0th Order No effect Gradient 0 Direct proportion Gradient positive and constant Main Menu 2nd Order Squared relationship Gradient positive and increasing Concentration-Time Graphs 0th Order t1/2 t1/2 Half-life decreases 1st Order t1/2 t1/2 Half-life constant Main Menu 2nd Order t1/2 t1/2 Half-life increases Constant half life is a feature of only first order reactions Constant half life can be used to establish that a reaction is first order w.r.t that reactant. The shorter the half life, the faster the reaction. Main Menu Rate Graphs in Practice In the experiment you will follow the progress of a reaction using a data logger with pH probe Follow the instructions here. This will collect so much data that the only realistic way to analyse it will be by spreadsheet. There is an example here. Information about R2 values can be found here: https://www.youtube.com/watch?v=kiCeJHwpYDQ How to do line equations here: https://www.youtube.com/watch?v=Ogx7CJ1JD9k Main Menu Review The order of a reaction tells us the effect on the rate of changing the concentration of the reactants. Order can be determined by: Directly comparing experimental data The gradient of a rate-concentration graph The shape of a concentration-time graph Main Menu