STOICHIOMETRY LETS REVIEW- MOLES AND PARTICLES 1 mole = 6.022 x 1023 particles (formula units/ molecules/atoms) Moles Multiply by 6.022 x 1023 Particles Divide by 6.022 x 1023 Moles Particles ANOTHER WAY TO LOOK AT IT: N = n x NA N = Number of particles (molecules, formula units, atoms) n = amount (in mol) NA = Avagadro constant (mol-1) FOR EXAMPLE N = n x NA A sample contains 1.25 mol of nitrogen dioxide. How many molecules are in the sample? Molecules of NO2 = 1.25 mol x (6.022 x 1023 molecules/mol) = 7.52 x 1023 molecules How many atoms are in the sample? There is 1 atom of nitrogen and 2 atoms of oxygen in every molecule of NO2 7.52 x 1023 molecules x (3 atoms/ molecule) = 2.26 x 1024 atoms in 1.25 mol of NO2 LETS REVIEW- MOLAR MASS A mole of an element has a mass in grams that is numerically equivalent to the elements average atomic mass. Molar Mass (M)= mass of one mole of a substance (g/mol) Molar mass of an element can be found by looking at the periodic table Molar mass of a compound can be found by totalling the mass of all elements in the compound What is the molar mass of beryllium oxide? MBeO = MBe + MO = 9.01 g/mol + 16.00 g/mol =25.01 g/mol PARTICLES TO MASS What is the mass of 0.750 mol of CO2 gas? Divide by 6.022 x 1023 Multiply by M Mass Moles Particles Multiply by 6.022 x 1023 Divide by M 1. MCO2 = 2 x (16.00g/mol) + 12.01 g/mol = 44.01 g/mol 2. m = (0.750 mol)(44.01 g/mol) = 33.0g PARTICLES TO MASS How many molecules of iodine chloride, ICl, are in a 2.74 x 10-1 g sample? Multiply by M Divide by 6.022 x 1023 Mass Moles Particles Multiply by 6.022 x 1023 Divide by M 1. MICl =126.90 g/mol + 35.45 g/mol = 162.36 g/mol 2. n = (2.74 x 10-1 g)/(162.36 g/mol) = 1.69 x 10-3 mol 3. (1.69 x 10-3 mol)(6.022 x 1023 molecules/mol) = 1.01 x 1021 molecules MOLAR VOLUME PRESSURE What is pressure? Collisions Depend on: Temperature Volume PV=nRT STANDARD TEMPERATURE AND PRESSURE Since V depends on P and T, you must state both when describing a gases V. STP: Average atmospheric pressure at sea level (101.3 kPa) Freezing point of water (OoC, 273K) MOLAR VOLUME Joseph Louis Gay-Lussac (1778-1853) Law of combining volumes: when gases react the volume of reactants and products (measured at equal T and P) are always whole number ratios + 2L H2 1L O2 2L H2O MOLAR VOLUME Amedeo Avogadro (1776-1856) Realized he could relate the volume of a gas to the amount that was present (from mass) Avogadro’s Hypothesis: equal volumes of all ideal gases at the same temperature and pressure contain the same number of molecules In other words: 1 mole of any gas has the same volume as 1 mole of any other gas at STP. MOLAR VOLUME THOUGHT LAB- MOLAR VOLUME OF GASES Two students in a lab decided to calulate the molar volume of carbon dioxide, oxygen and methane gas. They measured the mass of an empty,150 mL syringe and then the mass of the syringe + gas. They repeated this procedure for each gas. The experiment was carried out in a room maintained at STP (273 K and 101.3 kPa). Their results are in the table on the next slide: THOUGHT LAB- MOLAR VOLUME OF GASES Gas: Carbon Dioxide Oxygen Methane Volume of gas (V) 150 mL 150 mL 150 mL Mass empty syringe 25.081 g 25.085 g 25.082 g Mass gas + syringe 25.383 g 25.304 g 25.197 g Mass of gas (m) Molar mass of gas (M) Number of moles of gas (n = m/M) Molar Volume of gas at STP (V/n) MOLAR VOLUME It turns out that the molar volume of any gas at STP is 22.4 L/mol! Well, actually, that’s not entirely true…. The molar volume of 22.4 L/mol is assumed for ideal gases- which are hypothetical gases that don’t take up space and do not attract one another Real gases do take up space and attract each other somewhat- so the molar volume would vary slightly from 22.4 L/mol….but it’s close We will always assume the molar volume of a gas is 22.4L/mol at STP! EXAMPLE: What is the volume of 3.0 mol of nitrogen dioxide gas at STP? TRY THIS: Suppose you have 44.8 L of methane gas at STP. 1. How many moles are present? 2. What is the mass of the gas? 3. How many molecules of the gas is present?