Predicting Products of Reactions

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Drill #4B 2/10/15

Predict the products and balance the equation for the following double-replacement reaction:

Na

2

CrO

4

(aq) + Ba(OH)

2

(aq) →

Drill #3 2/10/15

• Translate and predict products for the following reactants:

• calcium hydroxide + phosphoric acid

• FeCl

3

+ NH

4

OH

Answer

 1 Na

2

CrO

4

(aq) + 1 Ba(OH)

2

2 NaOH (aq) + 1 BaCrO

4

(s)

(aq) →

 BaCrO

4 is the precipitate (solid) we know this? Solubility Rules

– how do

Agenda

• Pass fwd 9-2 Practice Problems.

Drill # 4A 2/9/15

Write the balanced chemical equations for the following:

 aluminum bromide + chlorine yield aluminum chloride + bromine

 Potassium chlorate when heated yields potassium chloride + oxygen gas

 Hydrogen + nitrogen monoxide yield water

+ nitrogen

Agenda

• Predicting Products

• Precipitation Reactions and Solubility

Rules

Lab on Wed

Predicting

Products of

Reactions

Synthesis Reactions:

A + B  AB

• Element + Element  Compound

– There are other forms, but for your test, it will always be an ionic compound

• To predict the products of a synthesis reaction, just cross the charges of the elements

• Example:

– Li + Br

2

– Li + Br

2

2Li + Br

2

 ?

 LiBr

2LiBr (balanced)

Synthesis Practice

• Mg + N

2

 ?

• Mg + N

2

3Mg + N

2

 Mg

3

N

2

 Mg

3

N

2

• Mn + Cl

2

• Mn + Cl

2

 ? (Use Mn 2+ )

 MnCl

2

(already balanced)

• K + O

2

K + O

2

4K + O

2

 ?

 K

2

O

2K

2

O

Decomposition Reactions

AB  A + B

• Compound  Element + Element

– There are other forms, but for your test, we will always end with two elements.

• To predict the product, just separate the compound into elements.

DON’T FORGET THE

• Example:

DIATOMIC ELEMENTS!

– CaO  ?

H

2

, N

2

, O

2

, F

2

, Cl

2

, Br

2

, I

2

– CaO  Ca + O

2

2 CaO  2 Ca + O

2

Decomposition Practice

• PbI

2

 ?

• PbI

2

 Pb + I

2

(already balanced)

• NH

3

 ?

• NH

3

 N

2

2 NH

3

 N

+ H

2

2

+ 3 H

2

• Li

2

S  ?

• Li

2

S  Li + S

• Li

2

S  2 Li + S

• AlF

3

 ?

• AlF

3

2AlF

3

 Al + F

2

2Al + 3F

2

Single Replacement Reactions

• Element + Compound 

New Element + New Compound

• 2 forms:

– A + BC  AC + B (A is a metal)

• OR

– X + YZ  YX + Z (X is a nonmetal)

Single Replacement Rxns.

Cont.

• You must use an Activity Series to determine if there is a reaction.

– If the free metal is above the bonded metal on the Metal Activity Series (on the back of your

Periodic Table), the free metal will take the place of the bonded metal. (If it is below, then

NR – no reaction)

– If the free nonmetal is above the bonded nonmetal on the Periodic Table, the free nonmetal will take the place of the bonded nonmetal. (If it is below, then NR.)

Single Replacement Practice

• Fe + CuSO

4

 ? (use Fe 2+ )

• Fe + CuSO

4

 FeSO

4

+ Cu

(already balanced)

– Why? Fe is above Cu on the Activity Series

• Ca + HgO  ?

• Ca + HgO  CaO + Hg (already balanced)

– Why? Ca is above Hg on the Activity Series

Single Replacement Practice

• Ni + Mn

2

O

3

 ? (Use Ni 2+ )

• Ni + Mn

2

O

3

 NR (no need to balance!)

– Why? Ni is below Mn on the Activity Series

• Al + FeCl

2

 ?

• Al + FeCl

2

 Fe + AlCl

3

– Why? Al is above Fe on the Activity Series

2 Al + 3 FeCl

2

3 Fe + 2 AlCl

3

Single Replacement Practice

• MnCl

3

+ F

2

 ?

• MnCl

3

+ F

2

 MnF

3

+ Cl

2

– Why? F is above Cl on the Periodic Table

2 MnCl

3

+ 3 F

2

2 MnF

3

+ 3 Cl

2

• S + Na

2

O  ?

• S + Na

2

O  NR (no need to balance!)

– Why? S is below O on the Periodic Table

Double Replacement Reactions

AB + CD  AD + CB

• Compound + Compound 

New Compound + New Compound

• To predict, swap ion pairs and re-cross charges.

• Example:

– Fe(OH)

2

– Fe(OH)

2

– Fe(OH)

2

+ H

2

SO

4

 ?

+ H

+ H

2

SO

2

SO

4

4

 FeSO

4

 FeSO

4

+ HOH (H

2

O)

+ 2 H

2

O

Double Replacement Practice

• KI + PbCl

2

 ?

• KI + PbCl

2

2 KI + PbCl

 KCl + PbI

2

2

2 KCl + PbI

2

Combustion Reactions

C x

H x

+ O

2

 CO

2

+ H

2

O

• Any reaction between a compound of carbon and hydrogen (C x

H x

) and oxygen will produce the same two products – carbon dioxide and water!

• Example:

– CH

4

– CH

4

– CH

4

+ O

2

 ?

+ O

2

+ 2 O

 CO

2

2

+ H

 CO

2

2

O

+ 2 H

2

O

Combustion Practice

• C

6

H

6

+ O

2

 ?

• C

6

H

• 2 C

6

6

H

+ O

6

2

 CO

2

+ 15 O

2

+ H

2

O

 12 CO

2

+ 6 H

2

O

• C

2

H

5

OH + O

2

 ?

• C

2

H

5

OH + O

2

 CO

2

• C

2

H

5

OH + 3 O

2

+ H

2 CO

2

2

O

+ 3 H

2

O

Precipitation Reactions

• No ionic compound is entirely insoluble in water, however compounds of low solubility can be considered insoluble for most practical purposes.

• There are some general guidelines to help predict whether a compound made of a certain combination of ions is soluble.

Solubility Rules Table

 Use this table to determine if precipitation will occur.

 Precipitation occurs when the attraction between the ions is greater than the attraction between the ions and surrounding water molecules.

 Precipitate = solid

Assignment

 Complete the “Double Replacement

Reactions and the Solubility Rules” worksheet

 Directions: use the solubility rules handout to determine the correct phase for each product

• Review WS

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