Section 2.4 Enzymatic reactions Formative assessment 1. An enzyme is what type of molecule? Carbohydrate Lipid Nucleic acid Protein Sugar r 0% Su ga n id ac 0% Pr ot ei 0% ic L ip id 0% Nu c le bo hy dr at e 0% Ca r A. B. C. D. E. C B d nd an gy .. . B, a A, A io n en er t. . . lr ea c (o rg 0% ct iva t ica ca l lo gi 0% er a ch em io 0% Lo w up Ac ta sb Sp ee d 0% an ic . .. 0% 2. Cells need enzymes because they: A. Speed up chemical reactions for their particular substrate B. Act as biological (organic) catalysts C. Lower activation energy, making the reaction more likely to start D. A and B E. A, B, and C 3. Activation energy is : tt .. w lo al to to de d de d ne e gy En er 0% t.. 0% st ar rt af te as ed En er gy le re gy 0% he .. . g. .. 0% ne r le nt ia ot e lp En er ica m m Ch e Ch e ica lp ot e nt ia le ne r g. .. 0% ne e A. Chemical potential energy stored in the substrate B. Chemical potential energy stored in the product C. Energy released after the chemical reaction D. Energy needed to start the chemical reaction E. Energy needed to allow the substrate to bind to the active site. 5. Which part of the graph shows the activation energy for the enzyme catalyzed reaction? C B D 0% 0% 0% D 0% C A B A B C D A A. B. C. D. 6. The part of an enzyme where substrate binds is? A. Product B. Active site C. Enzyme substrate complex D. Protein E. Sugar pl e m co te 0% r n 0% Su ga x t sit En zy m e su b str a Ac t iv e Pr od uc 0% Pr ot ei 0% e 0% 7. All enzymes require an optimal pH, salt concentration, and temperature because under other conditions the protein may _____? 0% 0% ys t. ca t a sa to ea tiv ac to o 0% al lip id ... n Be co n ve r w do ke n br o te d a to am in rb o. .. at ur ca de n to Be te d co n ve r Be Be 0% . ed . 0% Be A. Be denatured. B. Be converted to a carbohydrate. C. Be broken down to amino acids. D. Be converted to a lipid. E. Be too active as a catalyst. A. B. C. D. E. C12H22O11 C12H22O11 & H2O C6H12O6 H2O and C6H12O6 C12H22O11 & H2O & C6H12O6 & H2 O 0% 2O 11 6 C6 H1 2O 0% C6 H1 2O 6 0% C1 2H 2 0% an d 0% H2 O Which is(are) the reactants of the chemical reaction described in this chemical equation ? C12H22O11 + H2O 2C6H12O6 C1 2H C1 22 2H O1 22 1 O1 1 & H2 O 8. A. Products B. Active sites C. Substrates te s sit Ac t iv e 0% Su bs tra 0% es 0% ts When they are bound to an enzyme, the reactants of a chemical equation are called: Pr od uc 9. 10 Enzymes are specific types of which biological macromolecule? Carbohydrates Proteins Lipids Nucleic acids 0% Nu c le ic ac id s s 0% L ip id 0% Pr ot ei ns bo hy dr at e s 0% Ca r A. B. C. D. 11 The molecule on which an enzyme acts: Catalyst Substrate Metabolism Homeostasis eo st as Ho m M et a bo l te 0% is 0% ism 0% Su bs tra al ys t 0% Ca t A. B. C. D. 12 Enzymes stop functioning if: .. ro w th e ith w to Th ey bi n d yz e al ca t ey Th 0% .. an y. o en ed om be c ey Th 0% m at u re d su bs tra a ac to n ey 0% ... te 0% Th A. They act on a substrate B. They become denatured due to improper pH or temperature C. They catalyze too many reactions D. They bind with the wrong substrate Passive Endothermic Exothermic Denatured at ur ed 0% De n Ex ot he ic rm th e En do 0% rm ic 0% e 0% Pa ss iv A. B. C. D. 13 When proteins, such as enzymes, lose their specific shape they have become __________. 14 What is the optimum pH for the enzyme pepsin, the stomach enzyme that digests protein? A. B. C. D. 1 2.5 5 6.5 100% pepsin trypsin 90% 80% 70% 60% 50% 40% 30% 20% 10% 0% 0% 0% 0% 0% 15 What is the optimum pH for the enzyme trypsin, the small intestinal enzyme that digests protein? A. B. C. D. 1 2.5 5 6.5 100% pepsin trypsin 90% 80% 70% 60% 50% 40% 30% 20% 10% 0% 0% 0% 0% 0% 16 Examine the graph of enzyme activity versus temperature, then choose the most probable explanation of the data. .. . n ho w hi ee nz ym es w Th ism rg an eo Th in us e ch in n ho w es 0% re .. . re ei ra t se ho ee nz ym 0% s.. . 0% . .. 0% Th D. nz ym ew C. ee B. The enzyme whose rate is shown in blue has optimal activity at 37°C but is denatured at 4°C The enzyme shown in red has a optimal temperature of 37°C, but is denatured at 4°C The organism which uses the enzyme shown in blue is likely to be a mammal, but the enzyme shown in green is likely an extremophile bacterium that lives in a geyser The enzyme shown in red has an optimal temperature of 37°C, but is denatured at 95°C and has too little activation energy at 4 °C Th A. 17 Why won’t the enzyme that breaks down sucrose also break down maltose? A. Organisms who eat sucrose don’t eat maltose B. Maltose is rare C. The enzyme that breaks down sucrose is denatured at the pH where maltose is active D. The substrate maltose has the wrong shape so can’t fit the active site of the sucrose digesting enzyme h. . al m te ha tb re et ub st ra es Th nz ym ee to se s.. . ak is to se al M Th Or ga n ism sw ho ea t su cr .. ra . re 25% 25% 25% 25% 18 Lactase is likely: A. An enzyme that digests lactose B. A carbohydrate found in milk C. A protein found in milk D. An enzyme that digests sucrose ... ilk ts s m en An A pr ge s di zy m e ot e in te th at fo un d nd fo u ge s di rb oh yd ra th at A ca zy m e en An in in ts l ... . .. 25% 25% 25% 25% 19 Which is NOT true of all enzymes? A. All enzymes have an optimal pH of 7 & optimal temperature of 37°C B. All enzymes are specific for a particular substrate because of the shape of the active site C. All enzymes are re-useable unless they become denatured D. All enzymes can be denatured when physical conditions are extremely different from their normal conditions de n -u se Al le nz ym es ca n ar e be re sp e Al le nz ym es ar e a. .. f.. c if ic op t. . . an e nz ym es es ha v le Al nz ym le Al ab .. 25% 25% 25% 25% Building Macromolecules • Polymer – large biomolecules made by linking together a large number of the same type of subunit • Monomer- small molecule that is a subunit of a polymer (building blocks) • Chemical reactions link monomers together to build polymers or break down polymers into monomers – Enzymes help speed up these reactions!! Organic Macromolecules (Polymers) MONOMER POLYMER Amino Acid Protein Sugar (monosaccharide) Carbohydrate (polysaccharide) Nucleotide Nucleic Acid https://www.youtube.com/watch?v=hzFn3jH1tK0 potato catalase enzyme activity lab video—pH https://www.youtube.com/watch?v=0nwI0xnG8W4 Enter Answer Text En te rA ns w er Te xt 100% Polymers are large biomolecules made of repeated subunits called Enzymes Sugars Monomers Proteins on om M Su ga 0% Pr ot ei ns 0% er s 0% rs 0% En zy m es A. B. C. D.