Engineering 45 Solid Crystallography Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Engineering-45: Materials of Engineering 1 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Crystal Navigation As Discussed Earlier A Unit Cell is completely Described by Six Parameters • Lattice Dimensions: a, b ,c • Lattice (InterAxial) Angles: , , Engineering-45: Materials of Engineering 2 Navigation within a Crystal is Performed in Fractional Units of the Lattice Dimensions a, b, c Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Point COORDINATES Cartesian CoOrds (x,y,z) within a Xtal are written in Standard Paren & Comma notation, but in terms of Lattice Fractions. Example • Given TriClinic unit Cell at Right Engineering-45: Materials of Engineering 3 Sketch the Location of the Point with Xtal CoOrds of: (1/2, 2/5, 3/4) Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Point CoOrdinate Example From The CoOrd Spec, Convert measurement to Lattice Constant Fractions • x → 0.5a • y → 0.4b • z → 0.75c To Locate Point Mark-Off Dists on the Axes Engineering-45: Materials of Engineering 4 Located Point (1/2, 2/5, 3/4) Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Crystallographic DIRECTIONS Convention to specify crystallographic directions: 3 indices, [uvw] - reduced projections along x,y,z axes Procedure to Determine Directions 1. vector through origin, or translated if parallelism is maintained 2. length of vectorPROJECTION on each axes is determined in terms of unit cell dimensions (a, b, c); negative index in x opposite direction Engineering-45: Materials of Engineering 5 3. reduce indices to smallest INTEGER values 4. enclose indices in brackets w/o commas z z [122] [111] y y [010] [110] _ [001] x Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Example Xtal Directions Write the Xtal Direction, [uvw] for the vector Shown Below Engineering-45: Materials of Engineering 6 Step-1: Translate Vector to The Origin in Two SubSteps Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Example Xtal Directions After −x Translation, Step-2: Project Make −z Translation Correctly Positioned Vector onto Axes Engineering-45: Materials of Engineering 7 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Example Xtal Directions Step-3: Convert Fractional Values to Integers using LCD for 1/2 & 1/3 → 1/6 • x: (−a/2)•(6/a) = −3 • y: a•(6/a) = 6 • z: (−2a/3)•(6/a) = −4 Step-4: Reduce to Standard Notation: 3 6 4 364 Engineering-45: Materials of Engineering 8 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Crystallographic PLANES Planes within Crystals Are Designated by the MILLER Indices The indices are simply the RECIPROCALS of the Axes Intersection Points of the Plane, with All numbers INTEGERS • e.g.: A Plane Intersects the Axes at (x,y,z) of (−4/5,3,1/2) Then The Miller indices: 1 1 1 5 1 2 5 3 1 4 2 12 15 4 24 4 5 3 1 2 4 3 1 4 3 3 4 1 12 Engineering-45: Materials of Engineering 9 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Miller Indices Step by Step MILLER INDICES specify crystallographic planes: (hkl) Procedure to Determine Indices 1. If plane passes through origin, move the origin (use parallel plane) 2. Write the INTERCEPT for each axis in terms of lattice parameters (relative to origin) 3. RECIPROCALS are taken: plane parallel to axis is zero (no intercept → 1/ = 0) Engineering-45: Materials of Engineering 10 4. Reduce indices by common factor for smallest integers 5. Enclose indices in Parens w/o commas Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Example Miller Indices Find The Miller Indices for the Cubic-Xtal Plane Shown Below Engineering-45: Materials of Engineering 11 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt The Miller Indices Example In Tabular Form Step Operation x y 1 2 3 4 5 Intercepts 3a/4 3/4 4/3 4 3a 3 1/3 1 (4 1 0) Intercepts in Lattice Dim Multiples Reciprocals Reduction to Integers Enclosure Engineering-45: Materials of Engineering 12 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt z a 0 0 More Miller Indices Examples Consider the (001) Plane z y x y z 1 0 1 (none needed) (001) Some Others Engineering-45: Materials of Engineering 13 Intercepts Reciprocals Reductions Enclosure x 0 2 3 6 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt FAMILIES of DIRECTIONS Crystallographically EQUIVALENT DIRECTIONS → < V-brackets > notation • e.g., in a cubic system, 100 100 010 010 001 001 Also : 123 312 123 Family of <111> directions: SAME Atomic ARRANGEMENTS along those directions Engineering-45: Materials of Engineering 14 100 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt FAMILIES of PLANES Crystallographically EQUIVALENT PLANES → {Curly Braces} notation • e.g., in a cubic system, 110 110 101 101 011 010 {110} Engineering-45: Materials of Engineering 15 Family of {110} planes: SAME ATOMIC ARRANGEMENTS within all those planes Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Hexagonal Structures Consider the Hex Structure at Right with 3-Axis CoOrds Plane-C The Miller Indices Plane-B • Plane-A → (100) • Plane-B → (010) • Plane-C → (110) BUT Plane-A • Planes A, B, & C are Crystallographically IDENTICAL – The Hex Structure has 6-Fold Symmetry • Direction [100] is NOT normal to (100) Plane Engineering-45: Materials of Engineering 16 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt 4-Axis, 4-Index System To Clear Up this Confusion add an Axis in the BASAL, or base, Plane Plane-C The Miller Indices now take the form of (hkil) • Plane-A → 1010 • Plane-B → 0110 • Plane-C → 1100 Engineering-45: Materials of Engineering 17 Plane-B Plane-A Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt 4-Axis Directions Find Direction Notation for the a1 axis-directed unit vector Noting the RightAngle Projections find Operation a1 a2 a3 Projections 1•a1 1 2 -a2/2 -1/2 -1 -a3/2 -1/2 -1 Projections in Lattice Multiples Mult by LCF to Clear Fracs Enclosure Engineering-45: Materials of Engineering 18 2110 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt z 0 More 4-Axis Directions 1120 1100 Engineering-45: Materials of Engineering 19 1210 2110 1120 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt 4-Axis Miller-Bravais Indices Construct Miller-Bravais (Plane) Index-Sets by the Intercept Method Plane Intercepts : , , ,1 Intercepts : 1,1,1 2 , Reciprocal s : 0,0,0,1 Reciprocals :1,1,2,0 Enclosure : 0001 Enclosure : 1120 Plane Engineering-45: Materials of Engineering 20 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt 4-Axis Miller-Bravais Indices Construct More Miller-Bravais Indices by the Intercept Method Plane Intercepts : 1, ,1, Intercepts : 1, ,1,1 Recipricals :1,0,1,0 Reciprical s :1,0, 1,1 Enclosure : 1010 Enclosure : 1011 Plane Engineering-45: Materials of Engineering 21 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt 3axis↔4axis Translation The 3axis Indices u' v' w' The 4axis Version uvtw Conversion Eqns u n 32u 'v ' v n 32v 'u ' t u v w nw' Engineering-45: Materials of Engineering 22 • Where n LCD/GCF needed to produce integers-only Example [100] u 3 32 1 0 2 v 3 32 0 1 1 t 1 0 1 w 1 0 0 Thus with n = 1 100 2110 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt 4axis Indices CheckSum 1011 Given 4axis indices • Directions → [uvtw] • Planes → (hkil) Engineering-45: Materials of Engineering 23 2111 1121 1010 Then due to Reln between a1, a2, a3 t u v or u v t 0 i h k or h k i 0 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Linear & Areal Atom Densities Linear Density, LD Number of Atoms per Unit Length On a Straight LINE Planar Density, PD Number of Atoms per Unit Area on a Flat PLANE • PD is also called The Areal Density In General, LD and PD are different for Different • Crystallographic Directions • Crystallographic Planes Engineering-45: Materials of Engineering 24 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Silicon Crystallography Structure = DIAMOND; not ClosePacked Lattice Constants InterAxial 's a (pm) b (pm) c (pm) 543.1 543.1 Engineering-45: Materials of Engineering 25 543.1 90 90 90 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt LD & PD for Silicon Si 1 1 A bh a 2 a 2 cos 30 2 2 Engineering-45: Materials of Engineering 26 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt LD and PD For Silicon PD(100) 6.781 1018 atom / m 2 For 100 Silicon • LD on Unit Cell EDGE LD PD111 is 15.5% HIGHER 2 0.5atom 1atom 1.841109 a 543.1 pm at / m For {111} Silicon • PD on (111) Plane – Use the (111) Unit Cell Plane 3 0.1667atom 3 0.5atom 2atom PD 1 2 base height 0.5 2 543.1 pm 2 543.1 pm cos 30 PD 2at 543.1 pm cos 30 7.830 1018 atom / m 2 2 Engineering-45: Materials of Engineering 27 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt X-Ray Diffraction → Xtal Struct. As Noted Earlier X-Ray Diffraction (XRD) is used to determine Lattice Constants Concept of XRD → Constructive Wave Scattering Consider a Scattering event on 2-Waves Amplitude 100% Added Constructive Scattering Engineering-45: Materials of Engineering 28 Amplitude 100% Subtracted Destructive Scattering Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt XRD Quantified X-Rays Have WaveLengths, , That are Comparable to Atomic Dimensions • Thus an Atom’s Electrons or Ion-Core Can Scatter these X-rays per The Diagram Below Path-Length Difference Engineering-45: Materials of Engineering 29 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt XRD Constructive Interference The Path Length Difference is Line Segment SQT Waves 1 & 2 will be IN-Phase if the Distance SQT is an INTEGRAL Number of X-ray WaveLengths • Quantitatively SQ ST d hkl sin Engineering-45: Materials of Engineering 30 1 1’ 2’ 2 Now by Constructive Criteria Requirement SQ ST dhkl sin dhkl sin n Thus the Bragg Law n 2d hkl sin Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt XRD Charateristics The InterPlanar Spacing, d, as a Function of Lattice Parameters (abc) & Miller Indices (hkl) d By Geometry for OrthoRhombic Xtals 1 h2 k 2 l 2 2 2 2 2 d hkl a b c For Cubic Xtals a = b = c, so 1 h2 k 2 l 2 h2 k 2 l 2 2 2 2 2 d hkl a a a a2 d hkl Engineering-45: Materials of Engineering 31 a h2 k 2 l 2 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt XRD Implementation X-Ray Diffractometer Schematic • T X-ray Transmitter • S Sample/Specimen • C Collector/Detector Typical SPECTRUM • Spectrum Intensity/Amplitude vs. Indep-Index Pb Engineering-45: Materials of Engineering 32 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt X-Ray Diffraction Pattern z z c Intensity (relative) c a z y (110) a b x c b y x a x b y (211) (200) Diffraction angle 2θ Diffraction pattern for polycrystalline α-iron (BCC) Engineering-45: Materials of Engineering 33 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt 33 XRD Example Nb Given Niobium, Nb with • Structure = BCC • X-ray = 1.659 Å • (211) Plane Diffraction Angle, 2∙θ = 75.99° • n = 1 (primary diff) FIND • ratom • d211 Engineering-45: Materials of Engineering 34 BCC Niobium Find InterPlanar Spacing by Bragg’s Law n 2d hkl sin or in this case n 11.659Å d 211 2 sin 2 sin 75.99 2 d 211 1.348Å Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Nb XRD cont To Determine ratom need The Cubic Lattice Parameter, a R • Use the PlaneSpacing Equation d hkl a h k l 2 2 2 a Nb d 211 2 2 12 12 So a For the BCC Geometry by Pythagorus 4ratom 2 a 2 a 2 a 2 3a so 4 a Nb 1.348 Å 6 3.302 Å 3 3.302Å rNb 1.4298Å 4 Bruce Mayer, PE Engineering-45: Materials of Engineering 35 ratom BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt PolyCrystals → Grains Most engineering materials are POLYcrystals Nb-Hf-W plate with an electron beam weld 1 mm Each "grain" is a single crystal. • If crystals are randomly oriented, then overall component properties are not directional. Crystal sizes typically range from 1 nm to 20 mm • (i.e., from a few to millions of atomic layers). Engineering-45: Materials of Engineering 36 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Single vs PolyCrystals • Single Crystals -Properties vary with direction: anisotropic. -Example: the modulus of elasticity (E) in BCC iron: • Polycrystals -Properties may/mayNot vary with direction. -If grains are randomly oriented: isotropic. 200 mm (Epoly iron = 210 GPa) -If grains are textured, anisotropic. Engineering-45: Materials of Engineering 37 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt 19 WhiteBoard Work Planar-Projection (Similar to P3.48) • Given Three Plane-Views, Determine Xtal Structure Also: macro 18.91 g / cc Engineering-45: Materials of Engineering 38 Find Aw Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Engineering-45: Materials of Engineering 39 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Engineering-45: Materials of Engineering 40 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt All Done for Today xTal Planes in Simple Cubic Unit Cell Engineering-45: Materials of Engineering 41 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Planar Projection 101 101 Engineering-45: Materials of Engineering 42 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Planar Projection Engineering-45: Materials of Engineering 43 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Engineering-45: Materials of Engineering 44 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt Engineering-45: Materials of Engineering 45 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-04_Crystallography.ppt