Structure of Matter (25%) Atomic Structure Important scientists Dalton's atomic theory o unique, indestructible atoms for each element o chemical reactions rearrange atoms o element mass proportion is constant in compound subatomic structure o J. J. Thomson: measured electron charge-to-mass o Millikan: measured electron charge o Rutherford: characterized dense, positive nucleus Components of the atom Particle Location Charge Mass Symbol 1 p or 1 H Proton nucleus +1 1.0 1 1 1 n Neutron nucleus 0 1.0 0 o e Electron outside -1 .00055 -1 Nuclear symbol AZX A = #p + #n Z = #p isotopes have same Z, but different A Average atomic mass (100mav = %1m1 + %2m2 + ...). Forms of matter pure substance has unique formula and properties o elements—one type of atom (diatomic: H2, N2, O2, F2, Cl2, Br2, I2) o compounds—two or more types of atoms molecular—formula defines size crystalline—formula shows ratio of atoms mixture of pure substances variable composition o uniform: homogenous mixture = solution o non-uniform: heterogeneous Three types of natural radioactivity Name Symbol Mass Charge Penetration 4He alpha low 4 +2 0e beta middle -1 0 gamma high 0 0 Nuclear reactions balance A (mass) and Z (charge) values determine symbol by Z number transmutations: induced nuclear reactions by impact Radioactive decay (first order reactions) rate = kNt ln(N0/Nt) = kt k = ln2/t½ Photon energy c = f Ephoton = hc/= 2.00 x 10-25/m (J) Hydrogen electron energy Eelectron = -2.18 x 10-18/n2 (J) E = Ehigh – Elow = Ephoton Quantum mechanical model unpredictable orbitals (Heisenberg uncertainty principle) orbital "address" o principle energy levels (n) o sublevels (l) = 0(s), 1(p), 2(d), 3(f), … (n -1) o orbital (ml) = - l, …, -1, 0, +1, …, l (degenerate) o spin (ms) = +½, -½ (Pauli exclusion principle) Electron configurations, orbital diagrams and quantum numbers the first three energy levels n 1 2 3 l 0 0 1 0 1 2 ml 0 0 -1 0 1 0 -1 0 1 -2 -1 0 1 2 ms electron configuration (1s22s22p6) orbital diagrams ()—maximize half filled (Hund’s rule) Quantum numbers (n,l,ml,ms) Periodic Table Electron arrangements in monatomic ions ions within 3 of a noble gas are isoelectric with noble gas transition metal: lose s, then d except columns 6, 11 Periodic table organization 1s 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p main group (1-8) families—similar properties o same valence-electron configuration o same ionic charge o alkali metals (1), alkaline earth metals (2), halogens (7 or 17), noble gases (8 or 18) Periodic nature of some properties. atomic size (volume/radius) o increase down a group—larger n o decrease to the right—increase core charge (nucleus – core electrons) on valence electron increases attraction (shielding effect = Zeff) ionization energy: X(g) X+(g) + 1eo +H: increases as radius decreases (harder to remove closer electron—more attraction to core) o successive ionization energies gradual increase until all valence electrons are removed electron affinity: X(g) + 1e- X-(g) o ±H: more negative as radius decreases (lower energy state as electron approaches core) o –H = stable anion electronegativity: attraction for covalent bond electrons o smaller atoms have greater electronegativity (closer to nucleus = stronger attraction) o electronegativity difference between bonding atoms is proportional to bond polarity anomalies (period 2) Group 1 2 3 4 5 6 7 element Li Be B C N O F valence electrons s1 s2 s 2 p 1 s 2p 2 s 2p 3 s 2p 4 s 2p 5 radius 1.34 0.90 0.82 0.77 0.75 0.73 0.71 electronegativity 1.0 1.5 2.0 2.5 3.0 3.5 4.0 ionization 520 899 801 1086 1402 1314 1681 affinity -60 >0 -27 -122 >0 -141 -328 sp: group 3 loses p electron lower ionization group 2 adds p electron + electron affinity : group 6 loses electron lower ionization group 5 adds electron + electron affinity metals, nonmetals—separated by stair step ion formed ion radius most reactive metal cation smaller than atom alkali metals nonmetal anion larger than atom halogens paramagnetism (unpaired electrons) and diamagetism (all paired electrons—when sublevel is full) Hybrid orbitals system atomic orbitals bonding hybrids 2 s+1p sp 3 s+2p sp2 4 s+3p sp3 5 s+3p+d sp3d 6 s+3p+2d sp3d2 single bond electrons (sigma bond—) and lone pairs are hybridized second and third bonding electron pairs (pi bonds—) remain in p orbitals Polar and/or multiple bonds are shorter and stronger Molecular Structure Octet rule lone + bonding pairs equals 8—octet rule exceptions: o H (2), Be (4), B (6)—2 x valence # o odd number of available valence electrons Lewis structures for molecules and ions count the total number of valence electrons draw a skeleton structure place electrons around each atom count Lewis structure electrons o if Lewis electrons > valence electrons: add multiple bonds o if Lewis electrons < valence electrons: add 2 or 4 electrons to central atom (expanded octet) resonance forms when placement of double bond is arbitrary bond order = # bonds to outer atoms # outer atoms best Lewis structure has minimum formal charge o assigned electrons (unshared + ½ bonding electrons) – valence electrons = formal charge o any negative charge goes to most electronegative atom Hybridization, bond angle and geometry from its Lewis structure # atoms + lone electron pairs around central atom # 2-sp 3-sp2 4-sp3 5-sp3d 6-sp3d2 o o o o o 120 109.5 90 + 120 90o 180 2 linear bent bent linear 3 T-shaped planar pyramid 4 tetrahedron Seesaw planar 5 pyramid bipyramid 6 octahedron Polarity of a simple molecule two possibilities o asymmetrical shape (lone pair of electrons around the central atom, except sp3d-linear and sp3d2square planar o symmetrical, but different outside atoms properties of polar molecules o soluble in water (polar solvent) o strong intermolecular attraction high melting and boiling temp., low evaporation rate—low volatility) Naming simple hydrocarbons prefix based on number of main chain carbons 1 2 3 4 5 6 meth… eth… prop… but… pent… hex… suffix based on bonding between carbons single 1-double 2-double 3-double triple …ane …ene …diene …triene …yne carbon branches number based on lowest number of main branch carbon and end in "yl" Effect of functional groups on a hydrocarbon halogen replaces H increases polarity oxygen containing groups o increases polarity (C–OH > C=O > C–O–C) o alcohols—OH (ending: …ane …anol) o acids—COOH (ending: …ane …anoic acid) amines o replace H in ammonia with hydrocarbon groups (CH3NH2 = methylamine, (CH3)2NH = dimethylamine) o weak bases Structural and geometric isomers structural isomer—same formula but different structure and name geometric isomer—same formula, structure and name, but different orientation around double bond: (cis X>C=C<X, trans X>C=C<X) States of Matter (25%) Gas and Liquid State Kinetic theory for gases (ideal gas) Kinetic energy: K = 3/2RTK (R = 8.31) velocity, u = (3RT/MM)½ [u1/u2 = (MM2/MM1)½] energy/temperature/velocity distribution curve energy/temperature/velocity molecular volume zero collisions produce pressure molecules don't interact Gas laws gas pressure is affected by: o n P: more gas molecules exert pressure o T P: more and harder collisions o V 1/P: spread out = less collisions/area ideal gas law: PV = nRT o R = 0.0821 (P in atm) or 8.31 (P in kPa) o TK = ToC + 273 o Patm = Ptorr/760 = PkPa/101 rate of effusion or diffusion: RateA/RateB = (MMB/MMA)½ partial pressure: Ptot = PA + PB, where PA = XAPtot Real gas deviation for ideal gas law low temperature: clumping = fewer molecules collide less pressure than ideal high pressure: crowding = gas molecules take up measureable space greater volume than ideal Phase diagram critical temperature and pressure (C) triple point (A) Vapor melting/freezing (A-B) o higher pressure favors more dense phase o Q = nHfus sublimation/deposition (A-D): skip the liquid state (dry ice—CO2) when below triple point pressure boiling/liquefaction (A-C) o temperature depends on atmospheric pressure (boiling point decreases as altitude increases) o Q = nHvap vapor: gaseous phase below boiling point evaporation (+Hvap)—opposite is condensation equilibrium vapor pressure o condensation = evaporation o independent of container size o vapor pressure increases with temperature Solid and Solution State Crystalline solid structure structural unit in geometric pattern + bond structural unit: molecule, atom or ion bond holding units together o covalent—strong bond C (diamond) and SiO2 (quartz) have strong 3-d crystal structure C (graphite) has 2-d structure, with dispersion forces holding sheets together o ionic—strong bond (strength depends on ionic charge, Q, and ion radius, d: E = kQ1Q2/(d1 + d2) o metallic—variable bond strength o molecular—weak bond (from strongest to weakest) H-bond: N, O, F bond to H dipole force: polar molecules dispersion force: temporary polarization o all molecules o more electrons = stronger o stronger than dipole force for large mass ranking from weakest bond/lowest melting point to strongest/highest: molecular < metallic < ionic < covalent conductors: metals and liquid/aqueous ionic water solubility: ionic and polar molecular malleable: metal and molecular Concentration units mass percent: % = g solute/total g x 100 mole fraction: X = mole solute/total moles molality: m = mole solute/kg solvent molarity: M = mole solute/ L solution Convert from one concentration unit to another Unit Solute Solvent % gsolute = % gsolvent = 100 – % X nsolute = X nsolvent = 1 – X M nsolute = M gsolvent = 1000d – (nsolute)MM m nsolute = m msolvent = 1000 g convert numerator and/or denominator o mass volume: m = (d)(V) o mass moles: m = (n)(MM) Principles of solubility solute-solvent interactions o breaking solute-solute bonds and solvent-solvent interactions absorbs energy (endothermic) o forming solute-solvent bonds releases energy (exothermic) effect of temperature upon solubility o dissolving most solids is endothermic higher temperature increases solubility o dissolving most gases is exothermic lower temperature increases solubility gas solubility proportional to pressure: Mg = kPg Colligative properties of solutions colligative properties o effect depends on concentration only o nonelectrolyte vs. electrolyte electrolyte forms ions in solution: conducts electricity number of ions i (van't Hoff factor) vapor pressure lowering o solute particles lower vapor pressure (VP) o VP = X1P1o (X1 and P1 are solvent values) osmotic pressure o solute increase osmotic pressure () o = MRTi (R = 0.0821) boiling point elevation and freezing point depression o solute extends the liquid phase of solvent o Tb = kbmi, Tf = kfmi Reactions (50%) Chemical Formulas and Equations Molar mass MM from a formula: add atomic masses Convert mass or volume of solution into moles, n _m x n/MM = n _V x n/V = n Preparing a solution moles needed: nstandard = MstandardVstandard o mass of stock powder, m = (nstandard)MM o volume of stock solution, V = (nstandard)/(Mstock) (Mstock)(Vstock) = (Mstandard)(Vstandard) % mass from a chemical formula mass % = mpart/mwhole x 100 Empirical (simplest ratio) formula convert m (or %) n divide each mole value by smallest multiple by factor to make whole numbers = subscripts Molecular formula determine molar mass o MM = mRT/PV = dRT/P (gas) o MM = kf • msolute/Tf • msolvent (kg) (solute) procedure o MM/empirical formula mass = N o empirical formula subscripts x N = molecular formula Formulas of ionic compounds memorize ions o columns ± 3 from noble gas (anions: ...ide) o transition: 2+ except Ag+, Cr3+ or Roman numeral o NH4+ (ammonium), OH- (hydroxide), CN- (cyanide) o …ate: Cr2O72- (dichromate), C2H3O2- (acetate) and 123NO3-, ClO3CO32O3 PO43O4 per… ClO4-, MnO4- SO42-, CrO42o …ite: 1 fewer O than …ate crisscross charges to become subscripts in formula Balance a chemical equation know formula, charge and state balance numbers and kinds of atoms reduce (coefficients don't have to be balanced) Write net ionic equations write aqueous species in ionic form show reacting species only (remove spectator ions— usually derived from strong acids and bases) Determine mass/volume values from balanced equations Given: A Find: B Grams of Grams of Substance A Substance B MM Moles of Substance A MM Coefficients from balanced equation Moles of Substance B M M Volume of Volume of Solution A Solution B Limiting reactant, theoretical yield determine limiting reactant and theoretical yield % yield = actual/theoretical x 100 Volumetric analysis (titration) end point (color change) equivalence (all reacted) calculations o balance equation to determine nX/nT ratio o moles of titrant: nT = (MT)(VT) o moles of unknown: nX = (nT)(nX/nT) o molar mass of unknown: MMX = mX/nX o molarity of unknown: MX = nX/VX Thermodynamics and Kinetics Enthalpy (H) H = – Qcalorimeter = –mcT (c = 4.18 J/goC for H2O) calculate H from bond energies o for gaseous reactions only o H =B.E broken – B.E formed calculate from standard heat of formation (Hfo) o H (25oC, 1 M [ions] and 1 atm gases) for the synthesis of compound from pure elements o Ho = Hfo products –Hfo reactants exothermic (-H), endothermic (+H) Laws of Thermochemistry o H is proportional to moles reacted o H of reverse reaction has opposite sign o Hess's Law: H = H1 + H2 + … Entropy (S) So = So products – So reactants +S: more disorder: solids liquids gases, diffusion, increase T, and production of additional gas molecules Free energy (G) spontaneous reactions (G < 0) o decrease in energy (stronger bonds) (–H) o increase in disorder (+S) Go= Ho – TSo (T in Kelvin) Temperatures for spontaneous reactions H and S have opposite signs, T has no effect +H and +S: spontaneous when T > Ho/So –H and –S: spontaneous when T < Ho/So Rate law rate = k[Reactant A]m[Reactant B]n o m, n = order (first, second, etc.), o overall order = m+n determine rate law from [ ]o and rate o write rate law for each experiment o divide rate laws to cancel out all but one reaction order o solve for unknown reaction order o repeat for all orders o solve for k (units are Mxt-1 (x = 1 – overall order)) Reactant concentration vs. time first-order reactions (see radioactivity). o ln(Xo/X) = kt o t1/2 = ln2/k linear plots (straight line graph for each order) o zero order: [A] vs. t o first order: ln[A] vs. t o second order: 1/[A] vs. t Collision theory and activation energy collisions must be forceful and with correct orientation activation energy (potential energy) diagrams o Ea = Hactivated complex - Hreactants o Ea' = Hactivated complex - Hproducts o H = Hproducts – Hreactants = Ea – Ea' reaction are faster (greater k) at higher T because more reactants have Ea (see kinetic energy graph) Catalyzed reactions have lower Ea Reaction rate vs. temperature ln(k1/k2) = (Ea/R)(1/T2 – 1/T1) R = 8.31, Ea in J, T in K reaction rate k Reaction mechanisms reaction occurs in steps (lower Ea and fewer molecules colliding), which add up to the overall reaction slow step (rate determining step) determines rate law intermediate formed early and consumed later enzyme consumed in slow step and reform later Electrochemistry Redox reactions assign oxidation numbers o standards always: group 1+1, group 2+2, F-1, Al+3 usually: O-2, H+1 o elements, compounds = 0, ions = charge balancing redox equations o assign oxidation numbers o split into half reactions o balance each half reaction balance atoms except O,H balance O, by adding H2O balance H, by adding H+ balance charge, by adding eo equalize electrons o add half reactions o if basic, add OH- for each H+ Electrochemical terms redox chemical reactions o cathode: site of reduction o anode: site of oxidation electric energy o 1 mole e– = 96,500 C (1 faraday-F) o I, current in amps (A) I = Q/t (C/s) Standard potentials Eoox = -Eored (1 M ions and 1 atm gases) oxidizing agent (attracts e–, more +Eored) reducing agent (loses e–, more –Eored) Eotot = Eored + Eoox Eotot > 0: spontaneous (Eotot < 0: nonspontaneous) Nonstandard potentials: E = Eo – (RT/nF)lnQ R = 8.31, T = 298, F = 96,500 C/mol e n = electrons transferred from redox Q = equilibrium expression including (g) and (aq) Voltaic Cells (+Etot) anode (attracts anions from salt bridge): electrons pulled from reducing agent (lower on Standard Potential Chart) cathode (attracts cations from salt bridge): electrons attracted to oxidizing agent (higher on Potential Chart) Electrolytic cells (–Etot) nonspontaneous redox reaction storage battery provides energy anode (+ pole) induces oxidation cathode (– pole) induces reduction Electrolysis in water cathode (reduction) o columns 1, 2, and Al3+: 2 H2O + 2 e- H2 + 2 OHo acid: 2 H+ + 2 e- H2 o others: Mx+ + X e- M anode (oxidation) o halide except F-: 2 X- X2 + 2 eo base: 4 OH- O2 + 2 H2O + 4 eo others: 2 H2O O2 + 4 H+ + 4 e- Equilibrium Equilibrium expression example: N2(g) + 3 H2(g) 2 NH3(g) Kc = 50 expression: Kc = [NH3]2/[N2][H2]3 equilibrium constant K o Kp = Kc x (RT)ng Kp = 50 x (0.0821 x 373)-2 = 0.053 o for 2 NH3(g) N2(g) + 3 H2(g): Kc' = 1/Kc = 1/50 = 0.020 o for NH3(g) 1/2 N2(g) + 3/2 H2(g): Kc'' = (kc')1/2 = (0.020)1/2 = 0.14 o adding chemical equations: K3 = K1 x K2 o large K = mostly product reaction favored K, Go and Eo (Go = -RTlnK = -nFEo ). (R = 8.31, T = 298, F = 96,500, n = # e-) Le Chatelier's principle system reduces stress by shifting or increase decrease Factor Response Reactant Product Temperature (exothermic) (K ) (K ) Temperature (endothermic) (K ) (K ) Volume (ng-reactant > ng-product) Volume (ng-reactant < ng-product) ng-reactant = ng-product: system doesn’t respond to V adding inert gas or catalyst has no effect Ionization of water H2O(l) H+(aq) + OH-(aq) H+ (proton) is hydrated (H3O+) = hydronium ion Kw = [H+][OH-] = 1 x 10-14 pure, "neutral" water: [H+] = [OH-] = 1 x 10-7 M acidic: [H+] > [OH-], basic: [H+] < [OH-] pH scale—pH = -log [H+], (pOH = -log[OH-]) o acidic < 7, neutral = 7, basic > 7 o pH + pOH = pKW = 14 Acids and bases Acids: proton donor o strong acids: HA H+ + A(HCl, HBr, HI, HNO3, HClO3, HClO4, H2SO4) o weak acids: HA H+ + A % ionization = [H+]/[HA]o x 100 HA (HF, H2S, organic acids—COOH) HXOy (HClO, HBrO2, H2SO3, H3PO4) o HClO > HBrO (Cl higher electronegativity) o HClO2 > HClO (more oxygens) nonmetal oxides: CO2(g) + H2O H+ + HCO3 bases: proton acceptor o strong bases (column 1, Sr2+, Ba2+) soluble hydroxides: MOH M+ + OH metal oxides: MO + H2O M2+ + 2 OHo weak bases ammonia (amines): NH3 + H2O NH4+ + OH anions: A- + H2O HA + OH acid and base properties of salts strong bases others M+ (spectator ions) M+ + H2O H+ + MOH X 7 strong (spectator) neutral acidic HX- H+ + X2acidic acidic X- + H2O HX + OHbasic ? weak acid–weak base: HF + NH3 F- + NH4+ o KaHF x KbF- = KbNH3 x KaNH4+ = Kw = 1 x 10-14 o from standard conditions equilibrium shifts from stronger acid and base to weaker acid and base Lewis concept–acid = electron pair acceptor and base = electron pair donor: Fe2+ + :SCN- Fe:SCN+ Aqueous systems ionization of a weak acid (HA) o HA(aq) H+(aq) + A-(aq), Ka = [H+][A-]/[HA] o polyprotic acids (H2A): [H+]E from first ionization Ka1: [H+][HA-]/[H2A] Ka2: [H+][A2-]/[HA-] hydrolysis of a weak bases (A- or B) o basic anion (A-—except from strong acids) A-(aq) + H2O(l) HA(aq) + OH-(aq), Kb = [HA][OH-]/[A-] o basic molecules (B—derived from NH3) B(aq) + H2O(l) HB+(aq) + OH-(aq), Kb = [HB+][OH-]/[B] ionization of water H2O(l) H+(aq) + OH-(aq), Kw = [H+][OH-] = 1 x 10-14 dissociation of a salt (MX) o MX(s) M+(aq) + X-(aq), Ksp = [M+][X-] o spectator ions: Na+, K+, NO3o common ppt.: AgCl, PbCl2, Hg2Cl2, BaSO4, SrSO4 formation of complex ions M+(aq) + :X(aq) M:X+(aq), Kf = [M:X+]/[M+][:X] Equilibrium problems determine direction ( or from [ ]o o substitute [ ]o into equilibrium expression = Q o if Q > K, then , if Q < K, then determine K, given [ ]E o write expression from equation o substitute [ ]E, solve for K determine K, given [ ]o and one [ ]E o set up an "ICE Box" (shaded boxes are given) [] A + 2B C + 3D [A]o [B]o [C]o [D]o I C - -2 [C]E – [C]o = 3 [C]E E [A]o - [B]o – 2 [D]o + 3 o write expression, substitute [ ]E , solve for K determine one [ ]E, given other [ ]E and K o write expression, substitute given [ ]E and K, solve for missing [ ]E determine [ ]E, given [ ]o and K o set up an "ICE Box" (shaded boxes are given) [] A + 2B C + 3D [A]o [B]o [C]o [D]o I -x -2x +x +3x C [A]o – x [B]o – 2x [C]o + x [D]o + 3x E o write expression, substitute [ ]E and K, solve for x o substitute x back into formulas solve for [ ]E Titration curve and calculations 0.1 M HCl added to 0.1 M NaOH (upper) or 0.1 M NH3 (lower) pH pure NaOH 14 [OH-] = [NaOH] = 0.10 M 13 [OH-] = (nOH- – nH+)/Vtotal 12 pure NH3 11 Kb = [OH-]2/[NH3] 10 Buffer 9 Kb = [OH-](nH+)/(nNH3 – nH+) 8 ½ way pure water 7 pKb = pOH [OH-] = [H+] = 10-7 M 6 equivalence 5 pure conjugate acid 4 Ka = [H+]2/(nNH3/Vtotal) 3 2 excess HCl 1 [H+] = (nH+ – NOH-)/Vtotal 0 mL HCl