Third Year Chemistry •2nd semester: Physical (2007-2008) •May exams •Physical: 4 lecturers 8 topics •Dónal Leech: one topic •Thermodynamics •Mixtures and phase diagrams 1 Phase Equilibria Phase transitions Changes in phase without a change in chemical composition Gibbs Energy is at the centre of the discussion of transitions Molar Gibbs energy Gm = G/n Depends on the phase of the substance A substance has a spontaneous tendency to change into a phase with the lowest molar Gibbs energy 2 Variation of G with pressure We can derive (see derivation 5.1 in textbook) that DGm = VmDp Therefore DGm>0 when Dp>0 Can usually ignore pressure dependence of G for condensed states Can derive that, for a gas: DGm = RT ln(pf/pi) 3 To be presented in Lecture 4 Variation of G with temperature DGm = -SmDT Can help us to understand why transitions occur The transition temperature is the temperature when the molar Gibbs energy of the two phases are equal. The two phases are in EQUILIBIRIUM at this temperature 5 Phase diagrams 6 Map showing conditions of T and p at which various phases are thermodynamically stable At any point on the phase boundaries, the phases are in dynamic equilibrium Location of phase boundaries Clapeyron equation (see derivation 5.4) D trsH Dp DT TD trsV Clausius-Clapeyron equation (derivation 5.5) D ln p D vap H RT 2 DT D vap H 1 1 constant ln p2 ln p1 R T2 T1 7 Constant is DvapS/R Derivations dGm = Vmdp – SmdT dGm(1) = dGm(2) Vm(1)dp – Sm(1)dT = Vm(2)dp – Sm(2)dT {Vm(2) – Vm(1)}dp = {Sm(2) – Sm(1)}dT DtrsV dp = DtrsS dT T DtrsV dp = DtrsH dT dp/dT = DtrsH/(T DtrsV) 8 Derivations: liquid-vapour transitions l 9 To be presented in lecture Characteristic points When vapour pressure is equal to external pressure bubbles form: boiling point Normal bp: 1 atm, Standard bp: 1 bar When a liquid is heated in a closed vessel the liquid density eventually becomes equal to the vapour density: a supercritical fluid is formed. 10 Using the C-C equation The vapour pressure of mercury is 160 mPa at 20°C. What is its vapour pressure at 50°C given that its enthalpy of vapourisation is 59.3 kJ/mol? The vapour pressure of pyridine is 50.0 kPa at 365.7 K and the normal boiling point is 388.4 K. What is the enthalpy of vapourisation of pyridine? Estimate the normal and standard boiling point of benzene given that its vapour pressure is 20.0kPa at 35°C and 50.0kPa at 58.8°C. Remember: BP: temperature at which the vapour pressure of the liquid is equal to the prevailing atmospheric pressure. At 1atm pressure: Normal Boiling Point (100°C for water) At 1bar pressure: Standard Boiling Point (99.6°C for water; 1bar=0.987atm, 1atm = 1.01325bar) 11 Phase Rule Can more than 3 phases co-exist (for a single substance)? Gibbs energies are equal: Gm(1)=Gm (2) Gm(2)=Gm(3) Gm(3)=Gm(4) All a function of p and T. Need to solve 3 equations for 2 unknowns: impossible! Phase rule F = C-P+2 12 CO2 Dry ice fog-special effects Supercritical fluids Caffeine extraction from coffee beans Dry-cleaning Polymerisations Chromatography 13 Water Ice I structure Solid-liquid boundary slopes to the left with increasing pressure volume decreases when ice melts, liquid is denser that solid at 273 K 14 Introduction to mixtures Homogeneous mixtures of a solvent (major component) and solute (minor component). Introduce partial molar property: contribution that a substance makes to overall property. V = nAVA + nBVB Note: can be negative, if adding solute to solvent results in decrease in total volume (eg MgSO4 in water) 15 The chemical potential, m We can extend the concept of partial molar properties to state functions, such as Gibbs energy, G. G = nAGA + nBGB This is so important that it is given a special name and symbol, the chemical potential, m. G = nAmA + nBmB 16 The chemical potential of perfect gases in a mixture Recall that Gm(pf) = Gm(pi) + RT ln (pf/pi) At standard pressure Gm(p) = Gm° + RT ln (p/p°) Therefore, for a mixture of gases mJ = mJ° + RT ln (pJ/p°) More simply (at p° = 1 bar) System is at equilibrium when m for each substance has the same value mJ = mJ° + RT ln pJ in every phase 17 Spontaneous mixing to be presented in lecture 18 Gas mixtures Perfect gases mix spontaneously in all proportions Compare DGmix = nRT {xAln xA+ xB ln xB} DG = DH – TDS Therefore DH = 0 DSmix = − nR {xAln xA+ xB ln xB} 19 Ideal Liquid Solutions Raoult’s Law pJ = xJpJ* Due to effect of solute on entropy of solution 20 Real Solutions 21 Chemical potential of a solvent At equilibrium mA(g) = mA(l) mA(l)= mA°(g) + RT ln pA mA(l)= mA°(g) + RT ln xApA* mA(l)= mA°(g) + RT ln pA* + RT ln xA └────────────────┘ mA* mA(l)= mA*+ RT ln xA 22 Is solution formation spontaneous? G = nAmA + nBmB Can show that DGmix = nRT {xAln xA+ xB ln xB} and DH = 0 DSmix = −nR {xAln xA+ xB ln xB} 23 Ideal-dilute solutions Raoult’s law generally describes well solvent vapour pressure when solution is dilute, but not the solute vapour pressure Experimentally found (by Henry) that vp of solute is proportional to its mole fraction, but proportionality constant is not the vp of pure solute. Henry’s Law pB = xBKB 24 Gas solubility Henry’s law constants for gases dissolved in water at 25°C KH/(kPa m mol ) 3 Ammonia, NH3 5.69 Carbon dioxide, CO2 2.937 Helium, He 282.7 Hydrogen, H2 121.2 Methane, CH4 67.4 Nitrogen, N2 Oxygen, O2 1 155 74.68 Concentration of 4 mg/L of oxygen is required to support aquatic life, what partial pressure of oxygen can achieve this? 25 Application-diving Gas narcosis caused by nitrogen in normal air dissolving into nervous tissue during dives of more than 120 feet [35 m] Pain due to expanding or contracting trapped gases, potentially leading to Barotrauma. Can occur either during ascent or descent, but are potentially most severe when gases are expanding. Decompression sickness due to evolution of inert gas bubbles. Table 1 Increasing severity of nitrogen narcosis symptoms with depth in feet and pressures in atmospheres. 26 Depth P Total P N2 Symptoms 100 4.0 3.0 Reasoning measurably slowed. 150 5.5 4.3 Joviality; reflexes slowed; idea fixation. 200 7.1 5.5 Euphoria; impaired concentration; drowsiness. 250 8.3 6.4 Mental confusion; inaccurate observations. 300 10. 7.9 Stupefaction; loss of perceptual faculties. Real Solutions-Activities mJ = mJ° + RT ln aJ Substance Standard state Activity, a Solid Pure solid, 1 bar 1 Liquid Pure liquid, 1 bar 1 Gas Pure gas, 1 bar p/po Solute Molar concentration of 1 mol dm 3 [J]/co po 1 bar ( 105 Pa), co 1 mol dm3. * Activities are for perfect gases and ideal-dilute solutions; all activities are dimensionless. 27 Colligative properties Properties of solutions that are a result of changes in the disorder of the solvent, and rely only on the number of solute particles present Lowering of vp of pure liquid is one colligative property Freezing point depression Boiling point elevation Osmotic pressure 28 Colligative properties Chemical potential of a solution (but not vapour or solid) decreases by a factor (RTlnxA) in the presence of solute Molecular interpretation is based on an enhanced molecular randomness of the solution Get empirical relationship for FP and BP (related to enthalpies of transition) DT f K f m DTb K b m 29 Cryoscopic and ebullioscopic constants Solvent 1 Kb/(K kg mol ) 1 Acetic acid 3.90 3.07 Benzene 5.12 2.53 Camphor 40 Carbon disulfide 3.8 2.37 Naphthalene 6.94 5.8 Phenol 7.27 3.04 Tetrachloromethane Water 30 Kf/(K kg mol ) 30 1.86 4.95 0.51 Osmotic pressure Van’t Hoff equation MRT 31 Phase diagrams of mixtures We will focus on twocomponent systems (F = 4 ─ P), at constant pressure of 1 atm (F’ = 3 ─ P), depicted as temperaturecomposition diagrams. 32 Fractional Distillation-volatile liquids Important in oil refining 33 Exceptions-azeotropes Azeotrope: boiling without changing High-boiling and Low-boiling Favourable interactions between components reduce vp of mixture Trichloromethane/propanone HCl/water (max at 80% water, 108.6°C) 34 Unfavourable interactions between components increase vp of mixture Ethanol/water (min at 4% water, 78°C) Liquid-Liquid (partially miscible) Hexane/nitrobenzene as example Relative abundances in 2 phases given by Lever Rule n’l’ = n’’l’’ Upper critical Temperature is limit at which phase separation occurs. In thermodynamic terms the Gibbs energy of mixing becomes negative above this temperature 35 Other examples Water/triethylamine Weak complex at low temperature disrupted at higher T. 36 Nicotine/water Weak complex at low temperature disrupted at higher T. Thermal motion homogenizes mixture again at higher T. Liquid-solid phase diagrams 37