Analytic Geometry Chapter 5 Analytic Geometry • Unites geometry and algebra • Coordinate system enables Use of algebra to answer geometry questions Proof using algebraic formulas • Requires understanding of points on the plane Points • Consider Activity 5.1 • Number line Positive to right, negative left (by convention) 1:1 correspondence between reals and points on line Some numbers constructible, some not (what?) Points • Distance between points on number line d ( x1 , x2 ) x1 x2 x1 x2 2 • Now consider two number lines intersecting Usually but not entirely necessary Denoted by 2 Cartesian product Points • Note coordinate axis from Activity 5.2 1, 2 • Note non- axes Units on each axis need not be equal Distance • How to determine distance? • Use Law of Cosines • Then generalize for any two ordered pairs • What happens when = 90 ? Midpoints • Theorem 5.1 The midpoint of the segment between two points P(xP, yP) and Q(xQ, yQ) is the point x p xq y p yq , 2 2 • Prove For non axes For axes Lines • A one dimensional object which has both Location Direction • Algebraic description must give both x y • Matching A) 1 B) a b Ax By C Intercept form C) y x h k Point-slope D) y y0 m x x0 E) y m x b Slope-intercept General form 2 Slope • Theorem 5.2 For a non vertical line the slope is well defined. No matter which two points are used for the calculation, the value is the same Slope • What about a vertical line? The x value is zero The slope is undefined • Should not say slope is infinite Positive? Negative? Actually infinity is not a number Linear Equation • Theorem 5.3 A line can be described by a linear equation, and a linear equation describes a line. • Author suggests general form is most versatile Consider the vertical line x y 1 a b Ax By C y y0 m x x0 y m x b Alternative Direction Description • Consider Activity 5.4 • Specify direction with angle of inclination Note relationship between slope and tan Consider what happens with vertical line Parallel Lines • Theorem 5.4 Two lines are parallel iff the two lines have equal slopes • Proof: Use x-axis as a transversal … corresponding angles Perpendicular Lines • Theorem 5.5 Two lines (neither vertical) with slopes m1 and m2 are perpendicular iff m1 m2 = -1 Equivalent to saying 1 m1 (the slopes are m2 negative reciprocals) Perpendicular Lines Proof • Use coordinates and results of Pythagorean Theorem for ABC • Also represent slopes of AC and CB using coordinates Distance • Circle: Locus of points, same distance from fixed center Can be described by center and radius r x a y b 2 2 Distance • For given circle with Center at (2, 3) Radius = 5 • Determine equation y=? Distance • Consider the distance between a point and a line What problems exist? • Consider the circle centered at C, tangent to the line Distance • Constructing the circle Centered at C Tangent to the line Using Analysis to Find Distance • Given algebraic descriptions of line and point Determine equation of line PQ Then determine intersection of two lines Now use distance formula Using Coordinates in Proofs • Consider Activity 5.7 The lengths of the three segments are equal • Use equations, coordinates to prove Using Coordinates in Proofs • Set one corner at (0,0) • Establish arbitrary distances, c and d • Determine midpoint coordinates Using Coordinates in Proofs • Determine equations of the lines AC, DE, FB • Solve for intersections at G and H • Use distance formula to find AH, HG, and GC Using Coordinates in Proofs • Note figure for algebraic proof that perpendiculars from vertices to opposite sides are concurrent (orthocenter) • Arrange one of perpendiculars to be the y-axis • Locate concurrency point for the lines at x = 0 Using Coordinates in Proofs • Recall the radical axis of two circles is a line • We seek points where Power P, C1 Power P, C2 • We calculate C1 ( x a)2 ( y b)2 r12 C2 ( x c) ( y d ) r 2 2 2 2 • Set these equal to each other, solve for y Polar Coordinates • Uses Origin point Single axis (a ray) • Describe a point P by giving Distance to the origin (length of segment OP) Angle OP makes with polar axis • Point P is r , 5.5, 3 Polar Coordinates • Try it out Locate these points (3, /2), (2, 2/3), (-5, /4), (5, -/3) • Note (x, y) (r, ) is not 1:1 (r, ) gives exactly one (x, y) (x, y) can be many (r, ) values Polar Coordinates • Conversion formulas From Cartesian to polar Try (3, -2) From polar to Cartesian Try (2, /3) x2 y 2 r 2 y tan x x r cos y r sin Polar Coordinates • Now Use these to convert Ax + By = C to r = f() • Try 3x + 5y = 2 Convert to polar equation • Also r sec = 3 Convert to Cartesian equation Polar Coordinates • Recall Activity 5.11 Shown on the calculator Graphing y = sin (6) Polar Coordinates • Recall Activity 5.11 Change coefficient of Graphing y = sin (3) Polar In Geogebra • Consider graphing r = 1 + cos (3) • Define f(x) = 1 + cos(3x) Hide the curve that appears. • Define Curve[f(t) *cos(t), f(t) *sin(t), t, 0, 2 * pi] Polar In Geogebra • Consider these lines • They will display polar axes Could be made into a custom tool Nine Point Circle, Reprise • Recall special circle which intersects special points • Identify the points Nine Point Circle • Circle contains … The foot of each altitude Nine Point Circle • Circle contains … The midpoint of each side Nine Point Circle • Circle contains … The midpoints of segments from orthocenter to vertex Nine Point Circle • Recall we proved it without coordinates • Also possible to prove by Represent lines as linear equations Involve coordinates and algebra • This is an analytic proof Nine Point Circle Steps required 1.Place triangle on coordinate system 2.Find equations for altitudes 3.Find coordinates of feet of altitudes, orthocenter 4.Find center, radius of circum circle of pedal triangle Nine Point Circle Steps required 5.Write equation for circumcircle of pedal triangle 6.Verify the feet lie on this circle 7.Verify midpoints of sides on circle 8.Verify midpoints of segments orthocenter to vertex lie on circle Analytic Geometry Chapter 5