Econometrics I Professor William Greene Stern School of Business Department of Economics 4-1/24 Part 4: Partial Regression and Correlation Econometrics I Part 4 – Partial Regression and Correlation 4-2/24 Part 4: Partial Regression and Correlation I have a simple question for you. Yesterday, I was estimating a regional production function with yearly dummies. The coefficients of the dummies are usually interpreted as a measure of technical change with respect to the base year (excluded dummy variable). However, I felt that it could be more interesting to redefine the dummy variables in such a way that the coefficient could measure technical change from one year to the next. You could get the same result by subtracting two coefficients in the original regression but you would have to compute the standard error of the difference if you want to do inference. This is the code I used in LIMDEP. My question: Is this a well known procedure? 4-3/24 Part 4: Partial Regression and Correlation Frisch-Waugh (1933) Theorem Context: Model contains two sets of variables: X = [ (1,time) : (other variables)] = [X1 X2] Regression model: y = X11 + X22 + (population) = X1b1 + X2b2 + e (sample) Problem: Algebraic expression for the second set of least squares coefficients, b2 4-4/24 Part 4: Partial Regression and Correlation Partitioned Solution Method of solution (Why did F&W care? In 1933, matrix computation was not trivial!) Direct manipulation of normal equations produces ( XX )b = X y X1 X1 X1 X 2 X1 y X = [X 1 , X 2 ] so X X = and X y = X X X X X y 2 2 2 1 2 X1 X1 X1 X 2 b1 X 1 y (X X)b = = X X X X b X y 2 2 2 2 1 2 X1 X1b1 X1 X 2b2 X1 y X 2 X1b1 X 2 X 2b2 X 2 y ==> X 2 X 2b2 X 2 y - X 2 X 1b1 = X 2 (y - X 1b1 ) 4-5/24 Part 4: Partial Regression and Correlation Probit = -1(%) + 5 4-6/24 Part 4: Partial Regression and Correlation Partitioned Solution Direct manipulation of normal equations produces b2 = (X2X2)-1X2(y - X1b1) What is this? Regression of (y - X1b1) on X2 If we knew b1, this is the solution for b2. Important result (perhaps not fundamental). Note the result if X2X1 = 0. Useful in theory: Probably Likely in practice? Not at all. 4-7/24 Part 4: Partial Regression and Correlation Partitioned Inverse Use of the partitioned inverse result produces a fundamental result: What is the southeast element in the inverse of the moment matrix? -1 X1'X1 X 'X 2 1 4-8/24 X1'X2 X2'X2 Part 4: Partial Regression and Correlation Partitioned Inverse The algebraic result is: [ ]-1(2,2) = {[X2’X2] - X2’X1(X1’X1)-1X1’X2}-1 = [X2’(I - X1(X1’X1)-1X1’)X2]-1 = [X2’M1X2]-1 Note the appearance of an “M” matrix. How do we interpret this result? Note the implication for the case in which X1 is a single variable. (Theorem, p. 34) Note the implication for the case in which X1 is the constant term. (p. 35) 4-9/24 Part 4: Partial Regression and Correlation Frisch-Waugh Result Continuing the algebraic manipulation: b2 = [X2’M1X2]-1[X2’M1y]. This is Frisch and Waugh’s famous result - the “double residual regression.” How do we interpret this? A regression of residuals on residuals. “We get the same result whether we (1) detrend the other variables by using the residuals from a regression of them on a constant and a time trend and use the detrended data in the regression or (2) just include a constant and a time trend in the regression and not detrend the data” “Detrend the data” means compute the residuals from the regressions of the variables on a constant and a time trend. 4-10/24 Part 4: Partial Regression and Correlation Important Implications Isolating a single coefficient in a regression. (Corollary 3.2.1, p. 34). The double residual regression. Regression of residuals on residuals – ‘partialling’ out the effect of the other variables. It is not necessary to ‘partial’ the other Xs out of y because M1 is idempotent. (This is a very useful result.) (i.e., X2M1’M1y = X2M1y) (Orthogonal regression) Suppose X1 and X2 are orthogonal; X1X2 = 0. What is M1X2? 4-11/24 Part 4: Partial Regression and Correlation Applying Frisch-Waugh Using gasoline data from Notes 3. X = [1, year, PG, Y], y = G as before. Full least squares regression of y on X. 4-12/24 Part 4: Partial Regression and Correlation Detrending the Variables - Pg 4-13/24 Part 4: Partial Regression and Correlation Regression of Detrended G on Detrended Pg and Detrended Y 4-14/24 Part 4: Partial Regression and Correlation Partial Regression Important terms in this context: Partialing out the effect of X1. Netting out the effect … “Partial regression coefficients.” To continue belaboring the point: Note the interpretation of partial regression as “net of the effect of …” Now, follow this through for the case in which X1 is just a constant term, column of ones. What are the residuals in a regression on a constant. What is M1? Note that this produces the result that we can do linear regression on data in mean deviation form. 'Partial regression coefficients' are the same as 'multiple regression coefficients.' It follows from the Frisch-Waugh theorem. 4-15/24 Part 4: Partial Regression and Correlation Partial Correlation Working definition. Correlation between sets of residuals. Some results on computation: Based on the M matrices. Some important considerations: Partial correlations and coefficients can have signs and magnitudes that differ greatly from gross correlations and simple regression coefficients. Compare the simple (gross) correlation of G and PG with the partial correlation, net of the time effect. (Could you have predicted the negative partial correlation?) 4 .5 0 CALC;list;Cor(g,pg)$ Result = .7696572 4 .0 0 3 .5 0 PG 3 .0 0 CALC;list;cor(gstar,pgstar)$ Result = -.6589938 2 .5 0 2 .0 0 1 .5 0 1 .0 0 .5 0 70 80 90 100 110 120 G 4-16/24 Part 4: Partial Regression and Correlation Partial Correlation 4-17/24 Part 4: Partial Regression and Correlation THE Application of Frisch-Waugh The Fixed Effects Model A regression model with a dummy variable for each individual in the sample, each observed Ti times. yi = Xi + diαi + εi, for each individual N columns y1 y2 yN X1 X 2 X N d1 0 0 d2 0 0 0 0 0 0 0 β ε α dN N may be thousands. I.e., the regression has thousands of variables (coefficients). β = [X, D] ε α = Zδ ε 4-18/24 Part 4: Partial Regression and Correlation Estimating the Fixed Effects Model The FEM is a linear regression model but with many independent variables b a Using b 4-19/24 1 X X X D X y DX DD Dy the Frisch-Waugh theorem 1 =[X MD X ] X MD y Part 4: Partial Regression and Correlation Application – Health and Income German Health Care Usage Data, 7,293 Individuals, Varying Numbers of Periods Variables in the file are Data downloaded from Journal of Applied Econometrics Archive. This is an unbalanced panel with 7,293 individuals. There are altogether 27,326 observations. The number of observations ranges from 1 to 7 per family. (Frequencies are: 1=1525, 2=2158, 3=825, 4=926, 5=1051, 6=1000, 7=987). The dependent variable of interest is DOCVIS = number of visits to the doctor in the observation period HHNINC = household nominal monthly net income in German marks / 10000. (4 observations with income=0 were dropped) HHKIDS = children under age 16 in the household = 1; otherwise = 0 EDUC = years of schooling AGE = age in years We desire also to include a separate family effect (7293 of them) for each family. This requires 7293 dummy variables in addition to the four regressors. 4-20/24 Part 4: Partial Regression and Correlation Fixed Effects Estimator (cont.) M1D 0 2 0 M D MD 0 0 0 0 (The dummy variables are orthogonal) N MD MDi I Ti di (didi ) 1 d = I Ti (1/Ti )did 1 - T1i - T1i 1 1 - Ti 1 - Ti = ... ... 1 - T1 Ti i 4-21/24 ... - T1i 1 ... - Ti ... ... ... 1 - T1i Part 4: Partial Regression and Correlation ‘Within’ Transformations XMD X = Ni=1 XiMDi X i , XMD y = XiM y i , N i=1 4-22/24 i D XM y X iMDi X i i i D i k k,l T i t=1 (x it,k -x i.,k )(x it,l -x i.,l ) T i t=1 (x it,k -x i.,k )(y it -y i. ) Part 4: Partial Regression and Correlation Least Squares Dummy Variable Estimator b is obtained by ‘within’ groups least squares (group mean deviations) Normal equations for a are D’Xb+D’Da=D’y a = (D’D)-1D’(y – Xb) ai=(1/Ti )Σ 4-23/24 Ti t=1 (yit -xitb)=ei Part 4: Partial Regression and Correlation Fixed Effects Regression 4-24/24 Part 4: Partial Regression and Correlation Time Invariant Variable f = a variable that is the same in every period (FEMALE) N i=1 i i D i N i=1 T i fMD f = fM f t=1 (fit -fi. )2 but fit = fi , so fit fi. and (fit -fi. ) 0 This is a simple case of multicollinearity. f = diag(fi )*D 4-25/24 Part 4: Partial Regression and Correlation 4-26/24 Part 4: Partial Regression and Correlation In the millennial edition of its World Health Report, in 2000, the World Health Organization published a study that compared the successes of the health care systems of 191 countries. The results notoriously ranked the United States a dismal 37th, between Costa Rica and Slovenia. The study was widely misrepresented , universally misunderstood and was, in fact, unhelpful in understanding the different outcomes across countries. Nonetheless, the result remains controversial a decade later, as policy makers argue about why the world’s most expensive health care system isn’t the world’s best. 4-27/24 Part 4: Partial Regression and Correlation The COMPOSITE Index Equation logCOMPi = Maximum Attainablei - Inefficiency i = α +β1logHealthExpi +β2logEduci +β3 (logEduci ) - ui 2 i = 1,...,191 countries 4-28/24 Part 4: Partial Regression and Correlation Estimated Model β1 β2 β3 α 4-29/24 Part 4: Partial Regression and Correlation Implications of results: Increases in Health Expenditure and increases in Education are both associated with increases in health outcomes. These are the policy levers in the analysis! 4-30/24 Part 4: Partial Regression and Correlation WHO Data 4-31/24 Part 4: Partial Regression and Correlation