Calculations of Thermochemistry May 21st 2015 Prior Knowledge • Two main forms of energy • Kinetic energy (energy of motion) • Ex. Thermal energy (Heat) • Potential Energy (energy of position) • Ex. Chemical Potential Energy • Law of conservation of energy • System vs Surrounding • Endothermic and exothermic Reactions • Temperature vs Heat • Units of measuring energy (cal, Cal, J) Anura Hewagama 2 Objectives • Conversions between different units of energy • Define specific heat of a substance • Relate chemical potential energy to the heat lost or gained in chemical reactions • Calculate the amount of heat absorbed or released by a substance as its temperature changes Anura Hewagama 3 Units defined Metric System of energy • 1 calorie (cal) is the amount of energy required to increase the temperature of 1g of pure water by 1 degree Celcius (oC). • Nutritional calorie (Cal) = 1000 calories = 1kcal SI Unit of Energy • Joule (J) ο 1 cal = 4.184 J Anura Hewagama 4 1. 2. 3. 4. 1. 2. 3. Convert 100 cal to Cal Convert 100 cal to J Convert 100 J to cal Convert 300 Cal to J 100 cal x 1 πΆππ 1000 πππ 100 cal x 100 J x 4. 300 Cal x 4.184 π½ 1 πππ = 0.100 πππ = 418.4 π½ 0.2390 πππ 1π½ = 23.90 πππ 1000 πππ 1 πΆππ 4.184 π½ 1 πππ x = 1255200 = 1.26 x 106 Practice problems 1,2 and 3 Anura Hewagama 5 Specific Heat © Definition: Amount of heat (J) required to raise the temperature of one gram (1g) of pure substance by one degree Celsius (1 .oC). The specific heat of water is 1 calorie/gram °C = 4.186 joule/gram °C which is higher than any other common substance. Anura Hewagama 6 Anura Hewagama 7 Calculating Heat Absorbed p.520 : 5.00 x 103 g (5kg) block of concrete sidewalk increased by 6.0 oC. How much heat is absorbed? qconcrete = 0.84 c = 0.84 J/g.oC g.oC x 5.00 x 103 g x 6.0 oC = 25000 J = 25 kJ m = 5.00 x 103 g qconcrete = ??? π½ qH2O = 4.184 π½ g.oC x 5.00 x 103 g x 6.0 oC = 130000 J = 130 kJ Anura Hewagama 8 Calculating heat… • We can use the same equation to calculate heat released in cooling down • Use example problem 15.2 as a guide and solve practice problems 4,5 and 6. • Try P.522 Section 15.1 assessment Anura Hewagama 9 15.2 Heat – Determining Specific Heat Objectives • Describe how a calorimeter is used to measure energy that is absorbed or released • Explain the meaning of enthalpy change in chemical reactions and processes Anura Hewagama 10 Calorimeter An insulated device used for measuring the amount of heat absorbed or released during a chemical or physical process. p.523 Anura Hewagama 11 Determining Specific Heat • p.524 Example • P.525 Example problem use this as a guide • Practice problems 12-15 Anura Hewagama 12