LECTURE № 7 Aromatic compounds as drugs (p-Aminophenol derivatives, quinones, phenols). Acids of aromatic series, their salts, esters and amides as drug substances associate prof. Mosula L. M. The Plan 1. Derivatives of p-aminophenol as drug. 2. Quinones, which are used in medicine. 3. Phenols as drugs. 4. Aromatic acids and their salts, which are used in medicine. 5. Esters of aromatic acids as drugs. 6. Amides of aromatic acids and their derivatives , which are used in medicine. p-Aminophenol derivatives The hydroxilated (o, m, p), better known as the aminophenols, are quite interesting from the standpoint of being considerably less toxic than aniline. The para-compounds (C-3) is of particular interast from two standpoint: namely it is the metabolic product of aniline, and it is the least toxic of the three possible aminophenols. It also possesses a strong antipyretic and analgesic action. However, it is too toxic to serve as a drug, and for this reason, there were numerous modifications attempted. One of the first was acetylation of the amine group to provide N-acetyl-paminophenol (acetaminophenol), a producr that retained a good measure of the desired activities. Another approach to the detoxication of paminophenol was the atherification of the phenolic group. The best known of these are anisidine(C-9) and phenetidine (C-10), which are the methyl and ethyl ethers, respectively. However, it becomes apparent that a free amino group in these compounds, although promoting a strong antipyretic action, was also conducive to methemoglobin formation. The only exception to the preceding was for compounds in which a carboxyl group or sulfonic acid group had been substituted on the benzene nucleus. In these compounds, however, the antipyretic activity also had disappeared. The foregoing consideration led to the preparation of the alkyl ethers of N-acetyl-p-aminophenol of which the ethyl ether was the best and is known as phenacetin (C-11). The methyl and propyl homologues were undesirable from the standpoint of causing emesis, salivation, diuresis and other reactions. Alkylation of the nitrogen with a methyl group has a potentiating effect on the analgesic action, but, unfortunately, has a highly irritant action on mucous membranes. Paracetamol O General Notices OH СН3СОNHC6H4OH C8H9NO2 М m. = 151,2 g/mol The chemical name: N - (4hydroxiphenyl) p-acetaminophenol. Content C Paracetamolum NH 99.0 per cent to 101.0 per cent (dried substance). CH3 Obtaining 1. Nitrosation of phenol with the next reduction and aceetylation: O N H Na-O-N=O OH - CH3COOH NH3 OH OH C CH3 (CH3CO)2O H2S H2SO4 HN NH2 O OH CHARACTERS Appearance White, crystalline powder. Solubility Sparingly soluble in water, freely soluble in alcohol, very slightly soluble in methylene chloride. IDENTIFICATION First identification A, C. Second identification A, B, D, E. A. Melting point (2.2.14): 168 °C to 172 °C. B. UV-spectroscopy. Dissolve 0.1 g in methanol R and dilute to 100.0 ml with the same solvent. To 1.0 ml of the solution add 0.5 ml of a 10.3 g/l solution of hydrochloric acid R and dilute to 100.0 ml with methanol R. Protect the solution from bright light and immediately measure the absorbance (2.2.25) at the absorption maximum at 249 nm. The specific absorbance at the maximum is 860 to 980. C. Infrared absorption spectrophotometry (2.2.24). Preparation Discs. Comparison paracetamol CRS. D. Indophenol test after acid hydrolysis (for a primary aromatic amino group).To 0.1 g add 1 ml of hydrochloric acid R, heat to boiling for 3 min, add 1 ml of water R and cool in an ice bath. No precipitate is formed. Add 0.05 ml of a 4.9 g/l solution of potassium dichromate R. A violet colour develops which does not change to red (difference from Phenacetinum). E. It gives the reaction of acetyl (2.3.1). Heat over a naked flame. About 15 mg test substances place in a test tube in length about 180 mm and external diameter 18 mm and add 0,15 ml of phosphoric acid R. Close test tube by means of stopper, through which 10 mm which contains water R are passed a small test tube the in length about 100 mm and in external diameter and carries out a refrigerator role. On an external surface of a smaller test tube place 1 drop of lanthanum nitrate solution R. If substance rather easily hydrolyzes, the device place on 5 mines at a water heater, then take out a smaller test tube. For substances, which it is difficult hydrolyzes, a mix slowly heat up on an open flame to boiling. A drop remove, mix on a porcelain plate about 0,05 ml of 0,01 M. iodine solution. On drop edge put 0,05 ml of ammonia diluted solution R2; through 1–2 mines in a junction of two drops there is a dark blue colouring which amplifies and remains during a short time interval. La (NO3) 3 + 2CH3COOK + NH4OH = LaOH (CH3COO) 2 + NH4NO3 + 2 KNO3 LaOH (CH3COO) 2 + I2 = LaOH (CH3COO) 2 I2 Dark blue colouring Other reactions of identification 1. SPU. Formation azo dye (identification of a primary aromatic amino group after acid hydrolysis). The examinee a solution acidify HCl diluted R, add 0,2 ml of solution sodium nitrite R NaNO2 a and through 1–2 mines add 1 ml of a solution naphthol; there is an intensive orange or red colouring and, as a rule, the precipitate of the same colour is formed. NaO + NHCOCH3 N NH2 N N HO N H +H2O H-O-N=O HCl (NaNO2 + HCl) Cl NaOH - CH3COOH OH OH OH ONa orange or red 2. Formation azo dye from diazonium salts (identification phenolic hydroxyl). At interaction with diazonium salts occurs azocoupling in o-position from OH-group to formation azo dye of red colour: N OH N ONa H Cl + NHCOCH3 2NaOH N N - HCl R R + NaCl + 2H2O NHCOCH3 azo dye of red colour 3. Interaction with solution of iron (III) chloride (presence phenolic hydroxyl). 0,1 g a drug shake up about 10 ml of water and add some drops of a solution FeCl3; there is a blue-violet colouring: СН3СОNHC6H4OH + FeCl3 = СН3СОNHC6H4OFeCl2 + HCl blue-violet 4. Acid hydrolysis with the next identification of acetic acid. 0,1 g drug cautiously boil about 2 ml of sulphatic acid diluted H2SO4 during 2 mines; there is a smell acetic acid CН3CООН: СН3СОNHC6H4OH + НОН = H2NC6H4OН + СН3СООH TESTS Related substances Liquid chromatography (2.2.29). Prepare the solutions immediately before use. Heavy metals (2.4.8) Maximum 20 ppm. Loss on drying (2.2.32) Maximum 0.5 per cent, determined on 1.000 g by drying in an oven at 100-105 °C. Sulphated ash (2.4.14) Maximum 0.1 per cent, determined on 1.0 g. ASSAY Ceriumetry, direct titration Dissolve 0.300 g in a mixture of 10 ml of water R and 30 ml of dilute sulphuric acid R. Boil under a reflux condenser for 1 h, cool and dilute to 100.0 ml with water R. To 20.0 ml of the solution add 40 ml of water R, 40 g of ice, 15 ml of dilute hydrochloric acid R and 0.1 ml of ferroin R. Titrate with 0.1 M cerium sulphate until a greenish-yellow colour is obtained. Carry out a blank titration. OH O +3 +4 + Ce2(SO4)2 + 2 Ce(SO4)2 O O HN N C C CH3 CH3 Еm (C8H9NO2) = M. m./2 1 ml of 0.1 M cerium sulphate is equivalent to 7.56 mg of C8H9NO2. + H2SO4 STORAGE Protected from light. Action and use Analgesic and antipyretic. Preparations Co-codamol Tablets Effervescent Co-codamol Tablets Co-dydramol Tablets Co-proxamol Tablets Paediatric Paracetamol Oral Solution Paracetamol Oral Suspension Paracetamol Suppositories Paracetamol Tablets Dispersible Paracetamol Tablets Soluble Paracetamol Tablets Vitamin K Quinone derivatives The term vitamin K was applied to the vitamin isolated from alfalfa, and a similar principle from fishmeal was named vitamin K2. Vitamin K2 refers to a series of compounds called the menaquinones. These have a longer side chain with more unsaturation. Many other closely related compounds possess vitamin K activity. The synthetic compounds menadione and menadiol are referred to as vitamin K3 and K4. Vitamin K is a naphthoquinone derivative containing diterpenoid units biosynthesized by the intermediate, geraylpyrophosphate. Numerous compounds have been tested for their antihemorrhagic activity, and significant biologic activity is manifested in compounds with the following structure when: R R' A B R" R"' 1. ring A is aromatic or hydroaromatic 2. ring A is not substituted 3. ring B is aromatic or hydroaromatic 4. R equals OH, CO, OR, OAc (the R in OR equals methyl or ethyl) 5. R’ equals methyl 6. R” equals H, sulfonic acid or an alkyl group containing ten or more carbon atoms. A double bond in the β, γ-position of this alkyl group enhances potency, whereas, if the double bound is further removed, it exerts no effect. Isoprenoid groups are more effective than straight chains. 7. R”’ equals H, OH, NH2, CO, OR, Ac (the R in OR equals methyl or ethyl). It is interesting that, if ring A is benzenoid, the introduction of sulfur in place of – CH=CH- in this ring in 2-methylnaphthoquinone permits the retention of some antihemorrhagic activity. Products: Menadione (2-methyl-1,4-naphthoquinone; menaphthone; thyloquinone). On a mole-for-mole basis, menadione is equal to vitamin K1 in activity and can be used as a complete substitute for this vitamin. It is effective orally, intravenously and intramuscularly. Menadione Sodium Bisulfite (2-methyl-1,4-naphthoquinone sodium bisulfite; Hykinone, Vikasol) is prepared by adding a solution of sodium bisulfite to menadione. O O CH3 CH3 NaHSO3 SO3Na O O Menadione sodium bisulfite occurs as a white, crystalline, odorless powder. One gram of it dissolves in about 2 ml of water, and it is slightly soluble in alcohol. It decomposes in the presence of alkali to liberate the free quinone. Menadione Sodium Diphosphate (tetrasodium 2- methyl-1,4-naphthalenediol bis(dihydrogen phosphate); Synkayvite; Kappadione) is a white hygroscopic powder, very soluble in water, giving solutions that have a pH of 7 to 9. OPO3Na2 CH3 OPO3Na2 It is available in ampules for use subcutaneusly, intramuscularly, intravenously and in tablets for oral administration. Identification A. Menadione Sodium Bisulfite and Menadione Sodium Diphosphate yield the reaction characteristic of sodium salts and burn with yellow flame. B. Menadione Sodium Bisulfite reacts with concentrated sulphuric acid to form sulphur(IV) oxide. O O CH3 2 CH3 SO3Na + + 2 H2SO4 O Na2SO4 + 2 SO2 + H2O O C. Destruction of Menadione Sodium Bisulfite in base medium to sodium sulphite and 2methyl-1,4- naphthoquinone. 2-Methyl-1,4- naphthoquinone may be identified by its melting point (104-107*C). O O CH3 CH3 SO3Na O + NaOH + Na2SO3 + H2O O This reaction may be used for assay of vitamin K. For this reason reduce obtained 2-methyl-1,4- naphthoquinone to 1,4-dioxi-2-methylnaphtaline and titrate with 0.2N Ce(SO4)3 using a o-phenantroline as an indicator. Derivatives of phenols Phenols are the derivatives of aromatic hydrocarbons containing in a molecule one or several hydroxygroups, which are directly connected with an aromatic ring. Phenolphthalein (Ph Eur monograph 1584) C20H14O4 318.3 77-09-8 Action and use Laxative. DEFINITION Phenolphthalein contains not less than 98.0 per cent and not more than the equivalent of 101.0 per cent of 3,3-bis(4hydroxyphenyl)isobenzofuran-1(3H)-one, calculated with reference to the dried substance. Phenol (Ph Eur monograph 0631) C6H6O M.m. 4.1 108-95-2 Obtaining From coal pitch At processing of coal pitch receive various products (oils), including phenol. With that end in view process alkali; phenolate С6Н5ОNa which we will well dissolve in water is formed and easily separates from insoluble impurity in water and other components of coal pitch: С6Н5ОН + NaОН = С6Н5ОNa + Н2О The received solution of phenolate process carbonic gas СО2 or the diluted mineral acid, for example, HCl. Thus receive phenol which is partially dissolved in water: С6Н5ОNa + Н2О + СО2 = С6Н5ОН + NaНСО3 С6Н5ОNa + HCl = С6Н5ОН + NaCl The received product overtake and collect fraction which boils at 180–200 C. 2. A synthetic method from benzol. a) Sulphonatoin of benzol by means of sulphatic acid Н2SO4 with formation benzolsulphoacid: H SO3H + HOSO3H + H2O b) eutralization of a product by means of Са (OH) 2 with formation calcium salts of benzolsulphoacid: SO3 SO3H 2 + Ca Ca(OH)2 +2H2O 2 Surplus Ca(OH)2 eliminate by means of sulphatic acid: Са (OH) 2 + Н2SO4 = СаSO4 + 2Н2О c) After filtering a filtrate process of solution sodium carbonate Na2CO3; it is formed sodium salt of benzolsulphoacid: SO3Na SO3 Ca2CO3 + Ca + Na2CO3 2 2 d) The received solution evaporate and alloy with alkali NaOH; sodium phenolate is formed: ONa SO3Na + 2NaOH t + Na2SO3 + H2O e) At processing of phenolate by sulphatic acid Н2SO4 obtain phenol: OH ONa 2 + H2SO4 Na2SO4 + The obtained product overtake and collect fraction which boils at 178–182 C. 2. Synthesis from benzene chloride: С6Н5Сl + НOH С6Н5ОH + HCl 3.Synthesis from benzolsulphoacid: С6Н5SO3H + 2NaOH С6Н5ОNa + NaHSO3 + H2O С6Н5ОNa + HCl С6Н5ОH + NaCl DEFINITION Phenol contains not less than 99.0 per cent and not more than the equivalent of 100.5 per cent of C6H6O. CHARACTERS Colourless or faintly pink or faintly yellowish crystals or crystalline masses, deliquescent, soluble in water, very soluble in alcohol, in glycerol and in methylene chloride. IDENTIFICATION A. Oxidation of phenol by means of sodium hypochlorite (NAClO) solution in the presence of concentrated ammonia (indophenol test). Dissolve 0.5 g in 2 ml of concentrated ammonia R. The substance dissolves completely. Dilute to about 100 ml with water R. To 2 ml of the dilute solution add 0.05 ml of strong sodium hypochlorite solution R. A blue colour develops and becomes progressively more intense. O OH O O H OH O H NaClO O H N -H2O -H2 NH OH N blue colour B. Reaction with a neutral iron (III) chloride solution (reaction for phenolic hydroxyl). To 1 ml of solution S (see Tests) add 10 ml of water R and 0.1 ml of iron (III) chloride (ferric chloride) solution R1. A violet colour is produced which disappears on addition of 5 ml of 2-propanol R. H .. H5C6-O 6C6H5OH + FeCl3 O-C6H5 .. O C6H5 Fe H + 3HCl O-C6H5 O-C6H5 .. O-C6H5 H This reaction it is possible to distinguish a solution of phenol from a solution of salicylic acid (phenolic acid); in this case colouring remains at presence of acetic acid. C. Reaction with bromine water (Br2) (reaction for benzene ring). To 1 ml of solution S add 10 ml of water R and 1 ml of bromine water R. A pale-yellow precipitate is formed. OH OH Br Br + + 3Br2 3H2O Br 2,4,6-tribromphenol pale-yellow precipitate D. SPU. IR-spectroscopy. The IR-spectrum of absorption of substance solution in ССl4 for should correspond to reference spectrum SPU of phenol. Not pharmacopoeial reactions Formation azo dye with diazonium salts. The alkaline solution of phenol with diazonium salts forms azo dyes durk red or orange-red colour. Azocoupling proceeds, basically, in para-position to OH-group (substitute of І sorts) and if this position is occupied replacement occurs in ortho-position: ONa OH NaOH +N + -H2O H ONa N Cl -HCl SO3H N N SO3H dark red or orange-red colour Reaction with nitric acid At interaction with HNO3 (depending on its concentration and quantity) can be formed mononitro-derivatives (orto - or para-) or 2,4,6-trinitrophenol (yellow dye – picric acid): a) with 20 % solution HNO3: OH OH OH NO2 H + 2H2O + + 2HONO2 NO2 H o-nitrophenol b) with HNO3 concentrated: OH p-nitrophenol OH O2N + NO2 3HONO2 + NO2 3H2O 2,4,6-trinitrophenol (yellow dye – picric acid) 3. Reaction with the Marki reagent (solution of formaldehyde НСНО in conc. sulphatic acid H2SO4); it is formed aurin dye of red colour. OH H C H H + O + H OH H2SO4 -H2O H HO O C OH -H2O H HO CH aurin dye of red colour O ASSAY Bromatometry, back titration, with iodometric finishing Dissolve 2.000 g in water R and dilute to 1000.0 ml with the same solvent. Transfer 25.0 ml of the solution to a ground-glass-stoppered flask and add 50.0 ml of 0.0167 M bromide-bromate and 5 ml of hydrochloric acid R, close the flask, allow to stand with occasional swirling for 30 min and then allow to stand for a further 15 min. Add 5 ml of a 200 g/l solution of potassium iodide R, shake and titrate with 0.1 M sodium thiosulphate until a faint yellow colour remains. Add 0.5 ml of starch solution R and 10 ml of chloroform R and continue the titration with vigorous shaking. Carry out a blank titration. Chemism it is possible to present by means of such equations: KBrO3 + 5KBr + 6HCl = 3Br2 + 6KCl + 3H2O Allocated bromine Br2 reacts with phenol С6Н5ОН with formation of a white precipitate 2,4,6-tribromphenol: OH OH Br Br + + 3Br2 Br 3H2O Not reacted bromine Br2 reacts with KI with formation of iodine I2: Br2 + 2KI = I2 + 2KBr The allocated iodine titrate by standard solution Na2S2O3 in the presence of the indicator of starch and solvent of chloroform before disappearance of dark blue colouring (add starch towards the end of titration): I2 + 2Na2S2O3 = 2NaI + Na2S4O6 I2 + 2е 2I– 2S2O32– – 2е S4O62– Еm (C6Н6О) = М m./6; k (KBrO3) = 6 1 ml of 0.0167 M bromide-bromate is equivalent to 1.569 mg of C6H6O. STORAGE Store in an airtight container , protected from light. Action and use Antiseptic; antimicrobial preservative; antipruritic. Preparations Aqueous Phenol Injection Oily Phenol Injection Phenol Ph Eur and Glycerol Injection Aromatic acids and their derivatives Aromatic acids and their salts Aromatic acids – derivatives of aromatic hydrocarbons in which molecules in an aromatic ring one or several atoms of the Hydrogene are substituted on carboxyl group – СООН. Properties. Aromatic acids – crystal substances, usually a little soluble in water and well soluble in organic solvents (spirit, benzene, chloroform). Constants of their acidity a little more than at fat acids. In particular, benzoic acid С6Н5СООН is a little stronger acid in comparison with СН3СООН, that speaks effect of linking of group –СООН with С6Н5-ring. Possess the general chemical properties, characteristic for carbopxylic acids: form salts, anhydrides, halogenanhydride, esters, amides, etc. Pharmacological action and medical application. Introduction carboxyl group – СООН in a molecule of aromatic hydrocarbon lowers toxicity of conpound and simultaneously causes occurrence of cauterising, irritating action on tisue. Apply aromatic acids as antiseptic, and their salts – as carriers specific anions. The best solubility of salts in water reduces irritating action. Benzioc acid in an organism easily react with amino acid glycol with formation hyppuric acid, which quantity testifies to a functional condition of a liver. In medical practice apply benzoic and salicylic acids, and also their salts: sodium benzoate and sodium salicylate. General Notices Benzoic Acid (Ph Eur monograph 0066) C7H6O2 M.m.=122.1 65-95-0 DEFINITION Benzoic acid contains not less than 99.0 per cent and not more than the equivalent of 100.5 per cent of benzenecarboxylic acid. Benzoic acid and its esters occur naturally in gum benzoin and in Peru and tolu balsams. It is found as a white crystalline solid that slowly sublimes at room temperature and is steam distillable. It is slightly soluble in water, but more soluble in alcohol and other polar organic solvents. Obtaining Now benzoic acid obtain several synthetic methods. 1. Toluene oxidation in the sulphatic-acid medium by means of MnO2 or K2Cr2O7: С6Н5СН3 + 3MnO2 + 3H2SO4 = С6Н5СООН + 3MnSO4 + 4Н2О С7Н8 + 2Н2О – 6е С7Н6О2 + 6Н+ MnO2 + 4Н+ + 2е Mn2+ + 2Н2О С6Н5СН3 + 3MnO2 + 6H+ С6Н5СООН + 3Mn2+ + 4Н2О2. 2. Chlorination of toluene with the further hydrolysis benzenetrichloride: O OH CH3 +3Cl2 -3HCl CCl3 +3HOH -3HCl C OH OH -H2O C OH CHARACTERS A white, crystalline powder or colourless crystals, odourless or with a very slight characteristic odour, slightly soluble in water, soluble in boiling water, freely soluble in alcohol and in fatty oils. IDENTIFICATION A. Melting point (2.2.14): 121 °C to 124 °C. B. Solution S (see Tests) gives reaction (a) of benzoates (2.3.1). a) Reaction with iron (ІІІ) chloride To 1 ml of the solution specified in separate article, add 0,5 ml solution of iron (ІІІ) chloride R1; the light-yellow precipitate, soluble in ether R is formed. C6H5COOH + NaOH = C6H5COONa + H2O 6C6H5COONa + 2FeCl3 + 10H2O = (C6H5COO)3FeFe(OH)37H2O + 3C6H5COOH + 6NaCl light-yellow SPU. Preparation sublimation Some crystals of the crushed drug moisten with sulphatic acid R, cautiously heat up a test tube bottom; on test tube walls white touch C6H5COOH is formed. Not pharmacopoeial reaction. Reaction with solution AgNO3 C6H5COOH + AgNO3 = C6H5COOAg + HNO3 white TESTS Solution S Dissolve 5.0 g in alcohol R and dilute to 100 ml with the same solvent. Appearance of solution Solution S is clear (2.2.1) and colourless (2.2.2, Method II). Carbonisable substances Oxidisable substances Dissolve 0.2 g in 10 ml of boiling water R. Cool, shake and filter. To the filtrate add 1 ml of dilute sulphuric acid R and 0.2 ml of 0.02 M potassium permanganate. After 5 min, the solution is still coloured pink. Halogenated compounds and halides. Heavy metals (2.4.8) 12 ml of solution S complies with limit test B for heavy metals (10 ppm). Prepare the standard using a mixture of 5 ml of lead standard solution (1 ppm Pb) R and 5 ml of alcohol R. Sulphated ash (2.4.14) Not more than 0.1 per cent, determined on 1.0 g. ASSAY Alkalimetry in alcohol solution, direct titration Dissolve 0.200 g in 20 ml of alcohol R and titrate with 0.1 M sodium hydroxide, using 0.1 ml of phenol red solution R as indicator, until the colour changes from yellow to violet-red. C6H5COOH + NaOH = C6H5COONa + H2O Еm (C6H5COOH) = М m. 1 ml of 0.1 M sodium hydroxide is equivalent to 12.21 mg of C7H6O2. Storage In dense corked container, protecting from action of a moisture and light. Action and use Antimicrobial preservative. Benzoic acid is employed externally as an antiseptic in lotions, ointment and mouthwashes. It is more effective as a preservative in foods and pharmaceutic products at low pH. When used as a preservative in emulsions, its effectiveness depends upon both pH and distribution into the two phases. Preparations Compound Benzoic Acid Ointment Benzoic Acid Solution Ph Eur General Notice Sodium benzoate COONa (Ph Eur monograph 0123) C7H5NaO2 M.m.=144.1 532-32-1 DEFINITION Sodium benzoate contains not less than 99.0 per cent and not more than the equivalent of 100.5 per cent of sodium benzenecarboxylate, calculated with reference to the dried substance. Obtaining Dissolution of benzoic acid in a hot solution of sodium carbonate Na2CO3. 2С6H5COOH + Na2CO3 = 2С6H5COONa + H2O + CO2 The received solution condenses before the crystallisation, the allocated crystals filter and dry up. CHARACTERS A white, crystalline or granular powder or flakes, slightly hygroscopic, freely soluble in water, sparingly soluble in alcohol (90 per cent V/V). IDENTIFICATION A. It gives reactions (b) and (c) of benzoates (2.3.1). b) Sublimation of benzoic acid. Some crystals of the crushed drug moisten with sulphatic acid R, cautiously heat up a test tube bottom; on test tube walls white touch C6H5COOH is formed. 2C6H5COONa + H2SO4 = 2C6H5COOH + Na2SO4 c) Definition of melting point (must be 121 °C to 124 °C) of benzoic acid, after interaction drug with chloride acid. To drug solution add HCl R; the precipitate which after recrystallization from warm water R and drying in vacuum has melting point (121 °C to 124 °C) is formed. C6H5COONa + HCl = C6H5COOH + NaCl Acidimetry,non-agueous titration Dissolve 0.250 g in 20 ml of anhydrous acetic acid R, heating to 50 °C if necessary. Cool. Using 0.05 ml of naphtholbenzein solution R as indicator, titrate with 0.1 M perchloric acid until a green colour is obtained. C6H5COONa + HClO4 = NaClO4 + C6H5COOH Еm(C6H5COONa) = М. m. Storage In the dense corked container, protecting from action of a moisture and light. ASSAY Action and use Expectorant. It is used as a preservative in acidic liquid preparations in which benzoic acid is released. Preparations Powder, mixture. Esters of aromatic carboxylic acids Methyl Salicylate General Notices (Ph Eur monograph 0230) C8H8O3 M.m. = 152.1 Chemical name: methyl salicylate, methyl 2-hydroxybenzoate, methyl ester of 2-oxybenzoic acid, methyl ester of salicylic acid. DEFINITION Methyl salicylate contains not less than 99.0 per cent m/m and not more than the equivalent of 100.5 per cent m/m of methyl 2hydroxybenzoate. CHARACTERS A colourless or slightly yellow liquid, very slightly soluble in water, miscible with alcohol and with fatty and essential oils. IDENTIFICATION A. Heat 0.25 ml with 2 ml of dilute sodium hydroxide solution R on a water-bath for 5 min. Add 3 ml of dilute sulphuric acid R. A crystalline precipitate is formed. Filter. The precipitate, washed with water R and dried at 100 °C to 105 °C, melts (2.2.14) at 156 °C to 161 °C. HOC6H4COOCH3 + 2NaOH = NaOC6H4COONa + CH3OH + H2O NaOC6H4COONa + 2HCl = HOC6H4COOH + 2NaCl It is possible to confirm formation of salicylic acid with reaction with the Marki reagent; it is formed aurin dye of red colour . HO H + H C H + H OH O HOOC H2SO4 COOH H HO C [O] OH H HOOC HO HOOC COOH C H O . COOH B. To 10 ml of a saturated solution add 0.05 ml of iron (III) chloride (ferric chloride) solution R1. A violet colour develops. СН3ОСОС6Н4ОН + FeCl3 = СН3ОСОС6Н4ОFeCl2 + HCl violet colour ASSAY Acidimetry after alkaline hydrolysis, back titration HOC6H4COOCH3 + 2NaOH = NaOC6H4COONa + CH3OH + H2O excess NaOC6H4COONa + HCl = HOC6H4COONa + 2NaCl T 2NaOH + 2HCl = 2NaCl + 2H2O rest Еm(C8H8O3) = М. м./2 Store protected from light. STORAGE Counter-irritant. Action and use Preparations Methyl Salicylate Liniment Methyl Salicylate Ointment Amides of aromatic acids and their derivatives as drugs Salicylamide O Salicylamidum C Algamon NH2 Salamide Salіamide НОС6Н4СОNH2 М m. = 137,14 OH g/mol Not less than 99,0 % The chemical name: salicylamide, o-hydroxybenzamide, amide of salicylic acid. A white crystaline powder without a smell. At heating it is sublimated. Melting point 140–142 C. Very slightly soluble in water, soluble in 95 % ethanol, ether, slightly soluble in chloroform. Identification 1. Interaction with iron (III) chloride FeCl3 solution (presence phenolic hydroxyl); red-violet colour is formed: O C 2. Reaction with bromic water (for benzene ring). A substance 3. Alkaline hydrolysis with ammonia allocation (for amide group). At boiling of substance with 30 % NaOH is felt a specific smell of ammonia NH3 which can be identified by means of blue discoloration wet litmus paper: NH2 C + FeCl3 OH dissolve in alcohol, dilute with water and add 1 ml of bromic water Br2; the white precipitate dibromderivatives is formed: O + HCl OFeCl2 O C NH2 O Br NH2 C + 2Br2 OH NH2 OH Br O O C NH2 OH H O Na + t 0 C ONa OH + NH3 Assay Modified Keldal method, establishing the maintenance of ammonia, which is formed at alkaline hydrolysis. a) Hydrolysis of substance by alkali NaOH: НОС6Н4СОNH2 + NaOH = НОС6Н4СООNa + NH3 b) The allocated ammonia distil off in the container (receiver) with hydrochloric acid: NH3 + HCl = NH4Cl c) Ammonium chloride titrate with standard solution of sodium hydroxide: NH4Cl + NaOH = NH4OH + NaCl In parallel spend control experience. Еm (НОС6Н4СОNH2) = M.m. Storage. In good corked container, in the place protected from light. Action and use. Anaesthetic, antipyretic and antirheumatic. Preparations: powder and tablets (0,25 g and 0,5 g). Thanks for attention!