Feyza Selçuk 9-C Δ°HSAN DOΔRAMACI FOUNDATION BΔ°LKENT ERZURUM LABORATORY SCHOOL 2nd Semester 2011-2012 Academic Year 9th Grade Physics LAB REPORT Name: Feyza Selçuk Topic: Specific Heat Capacity of Normal Tap Water 1 Feyza Selçuk 9-C Research Question: Specific heat capacity of pure water is known as 4200 J/(kgoC). But what is the specific heat capacity of normal tap water? Hypothesis: In my opinion, normal tap water will have a different specific heat capacity than water because it is not pure. Introduction: The specific heat capacity of a solid or liquid is defined as the heat required raising unit mass of substance by one degree of temperature. It is Formula is: ππππππ¦ π‘ππππ ππππππ = ππβπ Where m is mass of substance, c is specific heat capacity, and βπ is change in temperature. The aim of this experiment is to find the specific heat capacity of normal tap water. To find the energy transferred, this formula can be used: πππ€ππ: ππππππ¦ π‘πππ where power is known as 1000 W. (the kettle which is used to heat the water in experiment has 1000 W rating) 2 Feyza Selçuk 9-C Experimental Setup: Before start to the experiment, area of experiment, equipments and safety should be controlled. List of Equipment: οΌ Kettle (1⁄2 liter capacity, 1000 W rating) οΌ Thermometer οΌ Stopwatch οΌ Tap water (1⁄2 kg) To get more reliable results, the experiment should be repeated at least 4 times (or more.) For each experiment, make sure that all items are ready. Procedure to Follow: ο· Firstly, prepare the apparatus needed during the experiment. ο· Fill the kettle with water. Make sure that it is ½ kg. ο· Then, measure the temperature of water before heating it, and record. ο· Monitor time by using stopwatch. Make sure that the water does not boil to prevent evaporating. ο· After some time, measure the temperature of hot water and record it again. ο· Repeat these procedures for 4 times and for the each repetition, determine a different time. ο· Decide a temperature and heat water until it reaches this target. Measure the times passed. (to get more reliable result.) ο· Last, use your recorded data to calculate the specific heat capacity. 3 Feyza Selçuk 9-C Data: First Experiment: Time: 0 second 45th second Temp.: 26oC 44 oC βπ‘πππ 45s 18oC βπ The specific heat capacity of tap water found in this experiment is: ππππππ¦ π‘ππππ ππππππ = ππβπ πππ€ππ = ππππππ¦ π‘πππ 1000 W= energy/45s Energy = 45 000 J 45 000 J = ½ kg x c x 18oC c = 5000 J/kg oC Second Experiment: Time: Temp.: 0 second 60th second 17 oC 41 oC βπ‘πππ 60s 24oC βπ 4 Feyza Selçuk 9-C The specific heat capacity of tap water found in this experiment is: ππππππ¦ π‘ππππ ππππππ = ππβπ πππ€ππ = ππππππ¦ π‘πππ 1000 W= energy/60s Energy = 60 000 J 60 000 J = ½ kg x c x 24oC c = 5000 J/kg oC Third Experiment: Time: Temp: 0 second 75th second 13 oC 47 oC βπ‘πππ 75s 34oC βπ The specific heat capacity of tap water found in this experiment is: ππππππ¦ π‘ππππ ππππππ = ππβπ πππ€ππ = 1000 W= energy/75s 5 ππππππ¦ π‘πππ Feyza Selçuk 9-C Energy = 75 000 J 75 000 J = ½ kg x c x 34oC C = 4411 J/kg oC (approximately) Fourth Experiment: Time: Temp: 0 second 90th second 19 oC 56oC βπ‘πππ 90s 37oC βπ The specific heat capacity of tap water found in this experiment is: ππππππ¦ π‘ππππ ππππππ = ππβπ πππ€ππ = 1000 W= energy/90s Energy = 90 000 J 90 000 J = ½ kg x c x 37oC c = 4864 J/kg oC (approximately) 6 ππππππ¦ π‘πππ Feyza Selçuk 9-C Fifth Experiment: Time: Temp: 0 second 166th second 12oC 80 oC βπ‘πππ 166s βπ 68oC The specific heat capacity of tap water found in this experiment is: ππππππ¦ π‘ππππ ππππππ = ππβπ πππ€ππ = ππππππ¦ π‘πππ 1000 W= energy/166s Energy = 166 000 J 166 000 J = ½ kg x c x 68oC c = 4882 J/kg oC Data Result: Experiment: Specific Heat Capacity Found: (J/kg oC) 1st (for βT of 18oC) 5000 J/kg oC 2nd (for βT of 24oC) 5000 J/kg oC 3rd (for βT of 34oC) 4411 J/kg oC 4th (for βT of 37oC) 4864 J/kg oC 5th (for βT of 68oC) 4882 J/kg oC 7 Feyza Selçuk 9-C According to these experiments, average specific heat capacity of tap water found is: 4831 J/kg oC. Conclusion and Evaluation: As a conclusion, we see the result is different from the specific heat capacity of pure water. Because tap water is not pure and it contains some other additives, its specific heat capacity is different. During the experiment, volume of water should be kept constant to get more reliable result because in this experiment time is our changeable factor. So change in volume of water would cause unreliable results. The other important thing is using kettle instead of Bunsen burner. If we used Bunsen burner, then the experiment would not be done fairly because we cannot provide the same conditionals for each repetition. Also, we make sure that thermometer just touches to water molecules because to get just water temperature, thermometer should be used very carefully. In other ways, thermometer will give us different results. To get more reliable result, this experiment can be re-done but by changing constant and independent values such as volume of water and time. In this experiment, average specific heat capacity of tap water is 4831 J/kg oC but by eliminating human errors and using more precise measuring techniques, we will be able to get more accurate and more consistent readings. 8