Division 6 Dividing using decimal points Objectives Use efficient ‘chunking’ to divide numbers greater than 100 by single-digit numbers including those which leave a remainder Divide numbers with one decimal place by multiplying by 10 before division, then dividing by 10 afterwards, e.g. work out 78.6 ÷ 3 by finding 786 ÷ 3, then dividing by 10 Divide numbers with two decimal places by multiplying by 100 before division, then dividing by 100 afterwards, e.g. work out 7.86 ÷ 3 by finding 786 ÷ 3, then dividing by 100 For this unit you will need: calculators Watch out for pupils who: do not know their multiplication facts and so can’t make use of them to solve divisions; repeatedly subtract 10 jumps of the divisor rather than first working out whether there are more than 10, 20, 30... or 100 lots of the divisor; try to partition numbers into 100s, 10s and 1s to divide (as they would for multiplication), rather than into a multiple of 10/100 of the divisor and the rest, e.g. partition 375 into 300, 70 and 5 to divide by 5 rather than into 350 and 25; do not know the common equivalents between fractions and decimals. HSNP © Hamilton 2014 Keeping up Term 3 Division 6 Session 1 Objective: Use efficient ‘chunking’ to divide numbers greater than 100 by single-digit numbers including those which leave a remainder Teacher input with whole class Write 637 ÷ 5 on the board. Approximately how many 5s do you think might be in 637? More than 10? More than 50? More than 100? More than 200? Agree that there are between 100 and 200 5s in 637, and that this is a useful estimate as it helps us to subtract our first number when using ‘chunking’. Work through the steps together: 100 + 20 +7, r2 127 r 2 or 127.4 5 ) 637 ─ 500 137 ─ 100 37 ─ 35 2 Remind pupils of the stages in using this written method: 1. Look for a multiple of 100 of 5 in the 637, i.e. 500. Subtract 500 (leaving 137). Write 100 at the top to record how many 5s are in 500. 2. Look for how many lots of ten 5s there are in 137, e.g. 20 x 5 = 100. Subtract 100 and write 20 at the top to record how many 5s are in 100. 3. Work out how many 5s are in 37 (7). Write 7 at the top. 4. Subtract 35 to find the remainder, 2. Find this as a fraction of the divisor (2/5), and record as decimal if known (0.4). Repeat the process with 813 ÷ 7, agreeing the answer as 1161/7. Individual practice Pupils work out 668 ÷ 6, 436 ÷ 3, 672 ÷ 5, 626 ÷ 3, 759 ÷ 7, expressing the remainder as fractions to decimals where they can. Encourage pupils to list multiples of 10 of the divisor, e.g. 30, 60, 90, 120… lots of the divisor, so that they subtract large numbers, rather than repeatedly subtracting 10 lots of the divisor. They check one using multiplication, remembering to add on the remainder at the end. HSNP © Hamilton 2014 Keeping up Term 3 Division 6 Session 2 Objective: Divide numbers with one decimal place by multiplying by 10 before division, then dividing by 10 afterwards, e.g. work out 78.6 ÷ 3 by finding 786 ÷ 3, then dividing by 10 Teacher input with whole class Ask half the class to work out 37.2 ÷ 3 and the other half to work out 372 ÷ 3, both using calculators. Discuss the two answers. Draw out that the answer to the first division is a tenth of the answer to the second. Ask all pupils to use efficient chunking to work out 524 ÷ 4. (100x4=400, 30x40, 1x4=4 so answer = 131) What might be the answer to 52.4 ÷ 4? Use a calculator to check pupil’s suggestions. If we round 52.4 to the nearest whole and then divide by 4 what would the answer be? So our answer of 13.1 makes sense. Write 36.8 ÷ 4 on the board. Ask pupils to round 36.8 to the nearest whole and discuss in pairs how many 4s would be in that number. Take feedback and agree that there would be between nine and ten 4s in 37. Ask pupils to use efficient chunking to work out 368 ÷ 4, and then divide the answer by 10, checking that the answer makes sense given their estimate. Paired pupil work Write the following divisions on the board: 142 ÷ 3, 14.2 ÷ 3 486 ÷ 6, 48.6 ÷ 6 375 ÷ 5, 37.5 ÷ 5 176 ÷ 8, 17.6 ÷ 8 423 ÷ 3, 42.3 ÷ 3 576 ÷ 4, 57.6 ÷ 4 Pupils work out the answers to the first divisions in each pair and use these to answer the second divisions in each pair. They each choose one of the second divisions to check using grid multiplication. HSNP © Hamilton 2014 Keeping up Term 3 Division 6 Session 3 Objective: Divide numbers with two decimal places by multiplying by 100 before division, then dividing by 100 afterwards, e.g. work out 7.86 ÷ 3 by finding 786 ÷ 3, then dividing by 100 Teacher input with whole class Say that a piece of wood measuring 4.86m is to be divided into 3 equal lengths. Discuss how we might find the length of each piece. Draw out converting the length to centimetres, dividing 486 by 3, then converting back to metres. Ask pupils to do this. Discuss how the answer to 4.86 ÷ 3 is a hundredth of the answer to 486 ÷ 3. Repeat the process with 5.24m ÷ 4, agreeing the answer as 1.31m. Ask pupils to work in pairs to find 117 ÷ 3, 11.7 ÷ 3 and 1.17 ÷ 3. Take feedback on how they did this. Round 11.7 to 12 to see that the answer to 11.7 should be just under 4, and discuss how 1 point something divided by 3 must be less than 1. Paired pupil work Pupils use efficient chunking to work out the first division in each group of three, then agree what the answers to the next two in each group should be. 348 ÷ 4, 34.8 ÷ 4, 3.48 ÷ 4 632 ÷ 4, 63.2 ÷ 4, 6.43 ÷ 4 237 ÷ 3, 23.7 ÷ 3, 2.37 ÷ 3 645 ÷ 3, 64.5 ÷ 3, 6.45 ÷ 3 435 ÷ 5, 43.5 ÷ 5, 4.35 ÷ 5 372 ÷ 6, 37.2 ÷ 6, 3.72 ÷ 6 732 ÷ 6, 73.2 ÷ 6, 7.32 ÷ 6 Teacher input with whole class Ask pupils to work out 870 ÷ 10 and compare the answer with 435 ÷ 5. Agree that they are the same and so another way to divide 435 by 5, would be to double both numbers, then work out 870 ÷ 10 which is easy! HSNP © Hamilton 2014 Keeping Up Term 3