A Level Maths Summer Work 2015

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MV16 Mathematics Department

Induction Booklet

We want you to start AS Maths with the skills that you need in order to be successful. These are higher level GCSE skills, which this booklet provides examples for you to practice. In order for us to assess your suitability for the

AS course, we will look carefully at the work you have done throughout, but we will assess your ability by marking the yellow practice booklet test.

Please use separate file paper to answer the questions

Chapter 1

Chapter 2

Chapter 3

Chapter 4

Chapter 5

Chapter 6

Chapter 7

Practice booklet test

CONTENTS

Removing brackets

Linear equations

Simultaneous equations

Factorising

Change the subject of the formula

Solving quadratic equations

Indices

Page 2

2

3

3

4

5

6

7

To help you with these exercises you could consider using the following book.

AS-Level Maths Head Start

Published by CGP Workbooks

ISBN: 978 1 84146 993 5

Cost: £3.99 (Amazon)

MV16 1

Chapter 1: REMOVING BRACKETS

EXERCISE A

1.

Multiply out the following brackets and simplify.

7(4 x + 5) 7. ( x + 2)( x + 3)

2.

3.

4.

5.

6.

EXERCISE B

1. ( x - 1) 2

2. (3 x + 5) 2

3. (7 x - 2) 2

-3(5 x - 7)

5 a – 4(3 a - 1)

4 y + y (2 + 3 y )

-3 x – ( x + 4)

5(2 x - 1) – (3 x - 4)

Multiply out

8.

9.

10.

11.

12.

( t - 5)( t - 2)

(2 x + 3 y )(3 x – 4 y )

4( x - 2)( x + 3)

(2 y - 1)(2 y + 1)

(3 + 5 x )(4 – x )

4. ( x + 2)( x - 2)

5. (3 x + 1)(3 x - 1)

6. (5 y - 3)(5 y + 3)

Chapter 2: LINEAR EQUATIONS

Exercise A : Solve the following equations, showing each step in your working:

2) 5 x

– 2 = 13

3) 11

– 4 x = 5 1) 2 x + 5 = 19

4) 5 – 7 x = -9 5) 11 + 3 x = 8 – 2 x 6) 7 x + 2 = 4 x – 5

Exercise B: Solve the following equations.

1) 5(2 x

– 4) = 4

3) 8 – ( x + 3) = 4

2) 4(2

4)

– x ) = 3(

14 x

– 9)

– 3(2 x + 3) = 2

MV16 2

EQUATIONS CONTAINING FRACTIONS

Exercise C : Solve these equations

1)

3)

1

2

( x

3)

5 y

4

   y

3

5)

7)

7 x

1

13

 x

2

2 x

 x

2

1

5 x

3

3

2)

4)

6)

8)

2 x x

3

  

3

4

2 3

 x

7 14 y

1

2 y

3

1

2 y

5

6

2

 

10

1 x x

Chapter 3: SIMULTANEOUS EQUATIONS

Exercise E :

Solve the pairs of simultaneous equations in the following questions:

1) x + 2 y = 7

3 x + 2 y = 9

3) 3 x – 2 y = 4

2 x + 3 y = -6

5) 4 a + 3 b = 22

5 a – 4 b = 43

2)

4)

6) x

3

9

4

3

2

+ 3 x x x p p y

+ 2

– 2

– 5

+ 3

+ 5

= 0 y y y q q

= -7

= 25

= 7

= 15

= 14

Chapter 4: FACTORISING

Common factors

We can factorise some expressions by taking out a common factor.

Exercise A

Factorise each of the following

1) 3 x + xy

2) 4 x 2 – 2 xy

3) pq 2 – p 2 q

4) 3 pq - 9 q 2

5) 2 x

6) 8 a

7) 5 y (

3

5 b

– 6 y

2 x 2

– 12 a 3 b

– 1) + 3( y

4

– 1)

MV16 3

Factorising quadratics

Exercise B

Factorise

1) x

2  

6

2) x 2 

6 x

16

3) 2 x

2 

5 x

2

4) 2 x

2 

3 x

5) 3 x 2 

5 x

2

6) 2 y

2 

17 y

21

7) 7 y

2 

10 y

3

11)

12)

13)

14)

8)

9)

10)

10 x

2 

5 x

30

4 x 2 

25 x

2 

3 x

 xy

3 y

2

4 x

2 

12 x

8

16 m

2 

81 n

2

4

3 

9

2 y a y

8( x

1)

2 

2( x

 

Chapter 5: CHANGING THE SUBJECT OF A FORMULA

Exercise A

Make x the subject of each of these formulae:

1) y = 7 x – 1 2) y

 x

5

4

3) 4 y

 

3

2 4) y

4(3 x

5)

9

Rearranging equations involving squares and square roots

Exercise B:

Make t the subject of each of the following

1) P

 wt

32 r

2) P

 wt

2

32 r

3) V

1

3

2 t h 4) P

2 t g

5) Pa

(

 t ) g

6) r

  bt

2

MV16 4

More difficult examples

Sometimes the variable that we wish to make the subject occurs in more than one place in the formula. In these questions, we collect the terms involving this variable on one side of the equation, and we put the other terms on the opposite side.

Exercise C

Make x the subject of these formulae:

1)

3) ax y

3 bx

2 x

3

5 x

2

 c 2)

4)

3( x a x

 a

 

) x b

(

2)

Chapter 6: SOLVING QUADRATIC EQUATIONS

Method 1: Factorising

Method 2: Using the formula

Recall that the roots of the quadratic equation ax 2  bx

 

0 are given by the formula:

EXERCISE A x

 b

2 b a

2 

4 ac

1) Use factorisation to solve the following equations: a) x 2 + 3 x + 2 = 0 b) x 2 – 3 x – 4 = 0

2) Find the roots of the following equations: a) x 2 + 3 x = 0 b) x 2 – 4 x = 0 c) x 2 = 15 c) 4 – x 2 = 0

3) Solve the following equations either by factorising or by using the formula: a) 6 x 2 - 5 x – 4 = 0 b) 8 x 2 – 24 x + 10 = 0

– 2 x

4) Use the formula to solve the following equations to 3 significant figures. Some of the equations can’t be solved. a) x 2 +7 x +9 = 0 b) 6 + 3 x = 8 x 2 c) 4 x 2 – x

– 7 = 0 e) 3 x 2 + 4 x + 4 = 0 d) f) x

3

2 x 2

– 3 x + 18 = 0

= 13 x – 16

MV16 5

Exercise A

Simplify the following:

1) b

5 b

5

2) 3 c 2 

2 c 5

3)

2  3

4) 2 n

6   n

2

)

More complex powers

Exercise B:

Find the value of:

1) 4

1 / 2

2)

1 / 3

27

3)

 

1 / 2

4) 5

2

18

0

5)

6) 7

1

7) 27

2 / 3

Simplify each of the following:

13) 2 a 1 / 2 

3 a 5 / 2

14) x

3  x

2

Chapter 7: INDICES

5)

6)

7)

8)

8)

9)

10)

11)

12)

15)

8 n

8 

2 n

3 d

11  d

9

 

2 a

 

3

2

 

2

8

2 / 3

 

1 / 2

0.04

8

 2 / 3

27

1

3 / 2

16

2 4 x y

1 / 2

MV16 6

Practice Booklet Test

You may NOT use a calculator

If ax 2 + bx + c = 0 then x =

 b

 b

2 

4 ac

2 a

1. Expand and simplify

(a) (2 x + 3)(2 x – 1) (b) ( a + 3) 2 (c) 4 x (3 x – 2) –

2. Factorise

(a) x 2 – 7 x (b) y 2 – 64 (c) 2 x 2 + 5 x

– 3

(d) 6 t 2 – 13 t + 5 x (2 x + 5)

3. Simplify

4 x

3

(a)

8 x

2 y y

3

(b)

3 x

2

3

+

4 x

1

6

4. Solve the following equations

(a) h

4

1

+

3 h

5

= 4 (b) x 2 – 8 x = 0 (c) p 2 + 4 p = 12

5. Write each of the following as single powers of x and / y

(a)

1 x

4

(b) ( x 2 y ) 3 (c) x

5 x

2

6. Work out the values of the following, giving your answers as fractions

1

3

(a) 4 -2 (b) 10 0 (c)

8

27

7. Solve the simultaneous equations 3 x – 5y = -11

5 x

– 2y = 7

8. Rearrange the following equations to make x the subject

(a) v 2 = u 2 + 2a x (b) V =

1

3

π x 2 h (c) y = x x

2

1

9. Solve 5 x 2 – x – 1 = 0 giving your solutions in surd form

With grateful thanks to Dr A Duncombe, MGSC for much of the content of this booklet

MV16 7

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