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Understanding Leamer
How The Distance Forrnula Applies to Real Life
d=m
(TheDistance
Formula)
1) Thedistanceformulacanbe usedto find distancebetweentwo point on a globe. For
example,the coordinates
of onecity is (30,l7). A secondcity is locatedat point (21,l0).
+ (17-10)'. D : sqwreroot 8l+ 49. D:squareroot of 130.
d:squareroot (30-21)'z
Usingthe distanceformula,we were ableto prove that the distancebetweenthe two cities
is equalto the squareroot of 130.
2) The distanceformulacanalsobe usedin football. Supposethe quarterbackis at point
(8, 40) andthe defensive
endis at points(3,25). Usingthe distanceformula,you can
determinethe distancebetweenthe two players.Squareroot (8-3)'z+ (40-25)2:D. Square
root (25+225):p. Onceagainusingthe distanceformula,we haveconfirmedthat the
distancebetweenthe two playersis 5 squareroot 10.
(16,90)
3) Supposea soldieris searching
for a mine.Themineis placedat coordinates
+ (90andthe soldieris location(13,72). With the distanceformula,squa.re
root (16-13)'?
7212:D. 32+182:D2.324+9:D2. The distanceformulashowedthat the soldier'sdistance
from the minewasequalto the squareroot of 333.
4) SusieandJakewereplayinghopscotch.Suziewasat coordinates
(6,3). Jakewasat
(4, 0).
coordinates
StepBy Step
D: squareroot of (6-4) 'z+ (3-0) 'z.
D: squareroot (4+9)
D: squareroot of 13
The distancebetweenSusieandJakeduringhopscotchwasequalto the squareroot of
13.
(400,2200).It's destinationis at (630,200).
5) A planeis flyingat coordinates
StepBy Step
+ (2200-200)2
D: squareroot of (400-630)'z
D: squareroot of 52,900+4,000,000
D= squareroot of 4,052,900
Usingthe formula,we havedeterminedthat the planeis 4,052,900units awayfrom the
destination.