Name: ___________________________________ Get Ready Classify Polynomials 1. Classify each polynomial by the number of terms. a) −2y b) x2 + 3x + 2 c) 6x2y + 2xy + 4 d) x2 + y2 e) 3x2 + 2x + y − 4 Date: _______________________________ …BLM 5–1... 6. Expand using the distributive property. a) 6m(2m − 4) b) −8xy(2x − y) c) 6a2(−3a + 4ab) d) −2a(b2 − 6ab + 7) 7. A rectangular prism has the dimensions shown. 2. State the degree of each polynomial. a) x2 + 3x − 1 b) x + 2y + 4z c) 6 + 2y3 + xy d) 7a3b2 + 6a2b2 − 7ab Add and Subtract Polynomials 3. Simplify. a) (3x + 7) + (3x − 6) b) (2a − b) + (6a − 4b) c) (3x2 + 2x − 4) − (2x2 − 5x + 1) d) (9y3 − 7y2 + 4) − (3y3 + 2y2 − 1) 4. Simplify. a) (6x2 + 2xy − 3y2) + (8x2 − 4xy − 2y2) b) (8ab2 + 8a − b2) − (9ab2 − 7a + b2) c) (6x − 8) − (4x + 7) + (6x − 2) d) (6a2 + b) − (2b − 3a2) − (11b2 + 9a2 + 2) The Product of a Monomial and a Polynomial 5. Expand using the distributive property. a) 2x(x + y) b) −8(6a2 − 4a) c) −6(a + 7) d) 2(3x2 + 2x + 4) Principles of Mathematics 10: Teacher’s Resource BLM 5–1 Get Ready a) Find a simplified expression for the volume. b) Find a simplified expression for the surface area. Factors 8. Write all of the factors of each number. a) 6 b) 34 c) 17 d) 44 9. Write each number as the product of prime factors. a) 12 b) 9 c) 40 d) 55 Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ Section 5.1 Practice Master 1. What binomial product does each model represent? a) b) …BLM 5–3... 5. Expand and simplify. a) 2(x − 7)(2x + 1) b) (x + 3)(x + 6) − 2(x + 1) c) −(x − 4)(x − 1) + 5(3x − 1)(2x + 1) d) (m − 2)2 − (3m + 2)2 e) −(m + 7)(m − 1) + 4(2m + 1)(3m − 4) f) −6(2x + 1)(6x + 1) + 3(4x − 3)2 6. Write and simplify an expression to represent the area of each shaded region. a) b) 2. Model each product using algebra tiles, virtual tiles, or a diagram. a) 3x(x + 3) b) (x + 3)(x + 2) c) (x + 1)(2x + 1) 3. Use the distributive property to find each binomial product. a) (x − 2)(x + 3) b) (y + 6)(y + 2) c) (n + 4)(n − 5) d) (d + 6)(d + 7) e) (x − 8)(x − 6) f) (a − 6)(a − 3) 4. Use the distributive property to find each binomial product. a) (x − 2y)(x + 2y) b) (2x + 1)(x − 3) c) (k − 6)(k + 7) d) (2p − 7q)(2p − 5q) e) (3 − 2s)(2 − 3s) f) (−2t − r)(−3t + r) Principles of Mathematics 10: Teacher’s Resource BLM 5–3 Section 5.1 Practice Master 7. A rectangular prism has a width of x centimetres. Its length is 4 cm more than its width and its height is 5 cm more than its width. a) Draw a diagram of the prism. b) Write a simplified expression for the volume of the prism. c) Write a simplified expression for the surface area of the prism. Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–4... Section 5.2 Practice Master 1. Draw a diagram to represent each product. a) (x + 3)2 b) (x + 2)2 2. Expand and simplify. a) (x + 4)2 b) (y + 7)2 c) (a + 8)2 d) (q + 5)2 3. Expand and simplify. a) (3y + 6)2 b) (3x + 2y)2 c) (2x + y)2 d) (6c + 7d)2 4. Expand and simplify. a) (x − 6)2 b) (b − 25)2 c) (r − 11)2 d) (e − 7)2 5. Expand and simplify. a) (8a − 1)2 b) (2u − 3v)2 c) (6p − 7)2 d) (5q − 8r)2 6. Expand and simplify. a) (v − 2)(v + 2) b) (x + 6)(x − 6) c) (x + y)(x − y) d) (r − s)(r + s) Principles of Mathematics 10: Teacher’s Resource BLM 5–4 Section 5.2 Practice Master 7. Expand and simplify. a) (6g − 7h)(6g + 7h) b) (3x + y)(3x − y) c) (g − 9x)(g + 9x) d) (4x − 5y)(4x + 5y) 8. A cube has length, width, and height of x metres. Each dimension is increased by y metres. a) Write a simplified formula for the volume of the new cube. b) Write a simplified formula for the surface area of the new cube. 9. A parabola has equation y = (x − 3)2. a) Identify the coordinates of the vertex. b) Expand and simplify the equation. c) Verify that the coordinates of the vertex satisfy your equation from part b). 10. The side length of a square is represented by x centimetres. The length of a rectangle is 3 cm greater than the side length of the square. The width of the rectangle is 3 cm less than the side length of the square. Which figure has the greater area and by how much? 11. Expand and simplify. a) (4x2 + 3y2)2 b) (3x2 + 2y2)(3x2 − 2y2) c) (x − 3)2 − (x + 3)(x − 3) d) 3(2b + 1)(2b − 1) + (b − 3)2 e) (3x2 + 5x − 1)2 f) (2x − 3)3 Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–6... Section 5.3 Practice Master 1. Use algebra tiles or a diagram to illustrate the factoring of each polynomial. a) x2 + 3x b) 2x2 + 10x c) 3x2 + 6x 2. Factor fully. a) 3x + 6y b) 17ac − 34ad c) 16x2y2 − 24xy d) 27x3y3 + 18x2y2 + 9xy e) 6n2p2 + 12np2 + 36n3p3 f) 33c4d3e2 − 11c2de g) 3g2 + 6g + 9 3. Factor fully. a) 2x(x + 7) + 3(x + 7) b) a(b − 7) + 2(b − 7) c) 4s(r + u) − 3(r + u) d) y(x + s) + z(x + s) 6. Factor. a) 3x(6 − y) + 2(y − 6) b) 2y(x − 3) + 4z(3 − x) 7. Write an expression in factored form for the area of each shaded region. a) b) 4. Factor by grouping. a) ax + ay + 3x + 3y b) 4x2 + 6xy + 12y + 8x c) y2 + 3y + ay + 3a d) 25x2 + 5x + 15xy + 3y 5. The formula for the surface area of a rectangular prism is SA = 2lw + 2lh + 2wh. a) Write this formula in factored form. b) If l is 10 cm, w is 5 cm, and h is 8 cm, find the surface area using both the original formula and the factored form. What do you notice? Explain why this is so. Principles of Mathematics 10: Teacher’s Resource BLM 5–6 Section 5.3 Practice Master Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ Section 5.4 Practice Master …BLM 5–7... 1. Illustrate the factoring of each trinomial using algebra tiles or a diagram. a) x2 + 5x + 6 b) x2 + 6x + 9 c) x2 + 8x + 15 d) x2 + 12x + 27 5. Determine two values of b so that each expression can be factored. a) x2 + bx + 12 b) x2 − bx + 18 c) x2 + bx − 15 d) x2 − bx − 18 2. Find two integers with the given product and sum. a) product = 48 and sum = 14 b) product = −15 and sum = 2 c) product = −30 and sum = −1 d) product = 2 and sum = −3 6. Determine two values of c so that each expression can be factored. a) x2 + 4x + c b) x2 − 9x + c 3. Factor, if possible. a) x2 + 8x + 12 b) c2 − 3c − 18 c) d2 + 10d + 21 d) d2 − 12d + 35 e) x2 + x + 1 f) c2 − 11c + 30 g) y2 + 15y + 56 h) x2 − x − 72 7. A parabola has equation y = 3x2 − 30x + 48. a) Factor the right side of the equation fully. b) Identify the x-intercepts of the parabola. c) Find the equation of the axis of symmetry, find the vertex, and draw a graph of the parabola. 8. Determine expressions to represent the dimensions of this rectangular prism. 4. Factor fully by first removing the greatest common factor (GCF). a) 3x2 − 12x − 36 b) −2x2 + 2x + 4 c) 6x2 − 42x + 72 d) −3x2 − 18x − 24 e) 4x2 − 40x + 84 f) x3 + 7x2 + 12x Principles of Mathematics 10: Teacher’s Resource BLM 5–7 Section 5.4 Practice Master Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–8... Section 5.5 Practice Master 1. Use algebra tiles or a diagram to factor each trinomial. a) 2x2 + 7x + 3 b) 6x2 + 11x + 4 c) 3x2 + 7x + 2 d) 4x2 + 18x + 20 5. The area of a rectangular parking lot is represented by A = 6x2 − 19x − 7. a) Factor the expression to find expressions for the length and width. b) If x represents 15 m, what are the length and width of the parking lot? 2. Factor. a) 6x2 + 10x − 4 b) 56x2 − 9x − 2 c) 9x2 + 6x + 1 d) 12c2 − 26c − 16 e) 2d2 − 11d − 6 f) 2r2 + 13r + 20 g) 6s2 − 29s + 35 h) 15r2 − 7r − 2 i) 4r2 − 20r + 25 j) 13x2 − 57x + 20 6. The height, h, in metres, of a baseball above the ground relative to the horizontal distance, d, in metres, from the batter is given by h = −0.005d2 + 0.49d + 1. a) Write the right side of the equation in factored form. Hint: First divide each term by the common factor, −0.005. b) At what horizontal distance from the batter will the baseball hit the ground if it is not caught by an outfielder? 3. Factor. a) 6x2 − 5xy − 4y2 b) 9x2 + 12xy + 4y2 c) 12r2 + 7rs − 10s2 d) 15r2 − 23rs + 4s2 e) 2x2 − 19xy + 42y2 f) 18y2 + 21yx − 4x2 4. Find two values of k so that each trinomial can be factored over the integers. a) 12x2 + kx + 14 b) 6x2 + kx + 10 c) 4x2 − 12x + k d) kx2 − 40xy + 16y2 Principles of Mathematics 10: Teacher’s Resource BLM 5–8 Section 5.5 Practice Master 7. Sydney Harbour Bridge in Australia is unusually wide for a long-span bridge. It carries two rail lines, eight road lanes, a cycle lane, and a walkway. a) Factor the expression 10x2 − 7x − 3 to find binomials that represent the length and the width of the bridge. b) If x represents 50 m, what are the length and the width of the bridge, in metres? 8. Factor. a) 10x4 − 3x2 − 18 b) 20x6 − 59x3y2 + 42y4 Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–10... Section 5.6 Practice Master 1. Factor. a) x2 − 25 b) y2 − 49 c) 9k2 − 1 d) 16k2 − 49 e) 25w2 − 36 f) 4 − 9w2 2. Factor. a) x2 − y2 b) 36x2 − y2 c) 25r2 − 36s2 d) 144r2 − 49s2 e) 121x2 − 9y2 f) 100r2 − 81s2 3. Factor. a) x2 + 14x + 49 b) x2 − 6x + 9 c) x2 − 8x + 16 d) 100 − 20x + x2 e) 4x2 − 12xy + 9y2 f) 49x2 + 56xy + 16y2 5. Determine the value(s) of b so that each trinomial is a perfect square. a) bx2 + 10xy + y2 b) 36x2 − bxy + 49y2 6. Determine two values of k so that each trinomial can be factored as a difference of squares. a) 25x2 − ky2 b) kx2 − 16 7. Factor, if possible. a) (5c + 3)2 − (2c + 1)2 b) 100 + (x − 3)2 c) 9x2 + 8x + 25 d) 25x2y2 − 150xyab + 225a2b2 8. A parabola has equation y = 4x2 + 32x + 64. Rewrite the equation in factored form to find the coordinates of the vertex. 9. Find an algebraic expression for the area of the shaded region in factored form. 4. Factor fully, if possible. a) 2a2 + 12a + 18 b) 25x2 − 16y c) 75x2 + 210xy + 147y2 d) 9x3y − 16xy3 e) 36m2 − 96mn + 64n2 f) 20x2 + 20xy + 5y2 Principles of Mathematics 10: Teacher’s Resource BLM 5–10 Section 5.6 Practice Master Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–11... (page 1) Chapter 5 Review 5.1 Multiply Polynomials 1. Use the distributive property to find each binomial product. a) (x + 7)(x + 3) b) (y − 3)(y + 5) c) (x − 3y)(x + 2y) d) (3a + 8b)(5a + 6b) 2. Expand and simplify. a) −4(a + 6)(a − 3) b) −3x(x + 2y)(x + 6y) c) (10y + 6)(3y + 7) − (y + 2)(y − 4) d) 2b(4b − 7)(3b + 2) − b(5b + 2)(b − 6) e) −x(x + y)(2x + y) − y(3x + y)(x − y) 3. A parabola has equation y = 2(x − 3)(x − 6). a) Expand and simplify the right side of the equation. b) State the x-intercepts of the parabola. c) Verify in the expanded form that these are the x-intercepts. 4. a) Write a simplified algebraic expression to represent the area of the figure. 8. Expand and simplify. a) (x − 3y)2 b) −5(2x + 5b)2 c) (11x − 13y)(11x + 13y) d) −(a − 6b)(a + 6b) 9. A square has side length 4a. One dimension is increased by 6 and the other is decreased by 6. a) Write an algebraic expression to represent the area of the resulting rectangle. b) Expand this expression and simplify. c) Write and simplify an algebraic expression for the change in area from the square to the rectangle. d) Calculate the new area of the rectangle if a represents 5 cm. 5.3 Common Factors 10. Use algebra tiles or a diagram to illustrate the factoring of each polynomial. a) x2 + 5x b) 8x2 + x 11. Factor. a) 2x2 + 4x c) 10x2 + 20y2 b) Expand and simplify your expression from part a). 5.2 Special Products 5. Draw a diagram to illustrate each product. a) (x + 5)2 b) (y + 3)2 6. Expand and simplify. b) (r − 3)2 a) (x + 6)2 c) (y + 10)2 d) (e − 5)2 b) 5x2 + 3x d) 3xy − 7xz 12. Factor by grouping. a) 2x2 + 2x + 3xy + 3y b) x3 + x2y + yx + y2 c) 5ab − 5a + 3b − 3 d) 3a2x + 3a2y + b2x + b2y 13. Factor, if possible. a) 2z(x + y) + 3xy(x + y) b) x2 + y2 + z2 c) 6a3 + 3a2 + 12a + 6 d) x2yz2 − x2z2 + xyz 7. Expand and simplify. a) (b + 9)(b − 9) b) (y − 11)(y + 11) c) (m + 13)(m − 13) d) (14 − x)(14 + x) Principles of Mathematics 10: Teacher’s Resource BLM 5–11 Chapter 5 Review Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–11... (page 2) 14. Write an expression in fully factored form for the shaded area. 5.4 Factor Quadratic Expressions of the Form x2 + bx + c 15. Illustrate the factoring of each trinomial using algebra tiles or a diagram. a) x2 + 6x + 9 b) x2 + 12x + 35 16. Factor. a) x2 − 4x − 12 b) x2 − 7x + 12 c) x2 − 4x − 45 d) x2 + 9x + 14 17. Factor completely by first removing the greatest common factor (GCF). a) −2x2 + 16x − 30 b) x3 + 3x2 − 28x 18. Determine binomials to represent the length and width of the rectangle, and then determine the dimensions of the rectangle if x = 11 cm. 5.5 Factor Quadratic Expressions of the Form ax2 + bx + c 19. Factor, using algebra tiles or a diagram if necessary. a) 12x2 − 5x − 3 b) 3x2 − 13x − 10 c) 10x2 + 9x − 7 d) 21x2 + 4x − 1 20. Factor, if possible. a) 3x2 + 15y + 33 b) 2x2 + 7x + 9 c) 30x2 + 9x − 12 d) −6x2 − 34x + 12 21. Find a value of k so that each trinomial can be factored over the integers. a) 3x2 + kx − 10 b) 24x2 + 47x + k 5.6 Factor a Perfect Square Trinomial and a Difference of Squares 22. Factor fully. a) x2 − 100 b) c2 − 25 c) 9x2 − 16 d) 128 − 18x2 e) 1 − 225y2 f) −3x2 + 27y2 23. Verify that each trinomial is a perfect square, and then factor. a) y2 + 16y + 64 b) x2 − 20x + 100 c) 225 − 90y + 9y2 d) 121c2 + 308cd + 196d2 24. Factor, if possible. b) 50x2 − 60xy + 18y2 a) 9y2 + 24y − 16 c) (x − 3)2 − (y − 4)2 d) x2 + 9y2 25. A rectangular prism has a volume of 4x3 + 12x2 + 9x. a) Determine algebraic expressions for the dimensions of the prism. b) Describe the faces of the prism. c) Determine the volume if x = 3 cm. d) Determine the surface area if x = 3 cm. Principles of Mathematics 10: Teacher’s Resource BLM 5–11 Chapter 5 Review Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–13... (page 1) Chapter 5 Practice Test 1. What binomial product does each diagram represent? a) 4. If it is possible to remove a common factor from the expression 2x2 + ky + 4, where k is an integer, what can you state about the possible values of k? Explain. 5. a) Write an algebraic expression for the volume of this rectangular prism. b) b) Expand and simplify the expression. c) Find the volume if x = 2. 6. Factor fully. a) x2 + 10x + 25 b) 25r2 − 20rs + 4s2 c) 5x2 − 5 d) 1 − 49m2 e) 5m2 + 17m + 6 f) m2 − 9mn + 14n2 2. Expand and simplify. a) −2x3(4x2 + 2x + 4) b) −xy(6x2 + xy + 1) − 2(x3y + 4xy) 3. Expand and simplify. a) (x − 3)(x − 9) b) (2x + 3)(2x − 1) c) −3(x − 4)2 + 2(x − 3)(x + 3) d) (3c + d)2 + 2c(c − d) e) 2(x − 1)(x − 6) − 3(2x − 1)2 f) (2c + 3d)2 − 3(c + 1)2 Principles of Mathematics 10: Teacher’s Resource BLM 5–13 Chapter 5 Practice Test 7. Factor, if possible. a) 3y3 − 7y2 + 2y b) 4m2 + 16 c) 6y2 + y − 1 d) x(m − 2) − 4(m − 2) e) y2 + 2x + 2y + xy f) 9t − 4t3 8. A ball is thrown into the air and its path is given by h = −5t2 + 20t + 25, where h is the height, in metres, above the ground and t is the time, in seconds. a) Factor the right side of the equation fully. b) When does the ball hit the ground? c) Find the height of the ball 2 s after it is thrown. Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–13... (page 2) 9. Determine two values of k so that each expression can be factored over the integers. a) x2 + kx + 36 b) 3x2 − 8x + k c) 36x2 − kxy + 49y2 d) 49x2 − ky2 10. Write and simplify an algebraic expression for the area of the shaded region. 11. The volume of a rectangular prism is represented by the equation V = 12x3 − 3x. a) Factor the right side of the equation fully. b) Draw a diagram of the prism. c) If x represents 6 cm, what are the dimensions of the prism? 13. Describe the steps needed to determine whether the expression ax3 + bx2 + cx can be factored over the integers. 14. Factor to evaluate each difference. a) 232 − 222 b) 252 − 232 c) 812 − 772 d) 1542 − 1502 15. a) Two numbers that differ by 2 can be multiplied by squaring their average and then subtracting 1. For example, 14 × 16 = 152 − 1, which is 225 − 1, or 224. How does the product of the sum and difference (x − 1)(x + 1) explain the method? b) Develop a similar method for multiplying two numbers that differ by 4. c) Show how the product of a sum and a difference explains your method from part b). 12. The face of a Canadian $20 bill has an area that can be represented by the expression 10x2 + 9x − 40. a) Factor 10x2 + 9x − 40 to find expressions to represent the dimensions of the bill. b) If x represents 32 mm, what are the dimensions of the bill, in millimetres? Principles of Mathematics 10: Teacher’s Resource BLM 5–13 Chapter 5 Practice Test Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–14... (page 1) Chapter 5 Test 1. Represent each binomial product using a diagram. a) (x + 3)(2x + 1) b) (2x + 3)(3x + 2) 2. Expand and simplify. a) 3x2y(y2x + 4xy − 2y2) b) −4(x2 + 3x − 11) + 5x(x − 4) 6. Factor. a) x2 − 10x + 25 b) 4x2 − 12x + 9 c) 2y2 + 5y + 2 d) 3k2 − 11k − 4 e) 10r2 + r − 3 f) 6s2 − 11st − 10t2 3. Expand and simplify. a) (k + 4)(k − 1) b) (6x − 1)(x − 5) c) 2(3x − 2)2 − 3(x − 1)(x + 5) d) (2x − 3y)2 + 2y(y − x) e) 6(1 − x)(x + 4) − 2(5 − 2x)2 7. Factor fully, if possible. a) 21x2 + 21x − 42 b) 7g2 + 28g − 147 c) 3x2 + 11x − 13 d) c3 − 9c e) 6d2 − 13d + 6 f) 50x2 − 72 4. In baseball, the first base bag is a square. Its side length can be represented by the expression 5x + 3. a) Write and expand an expression to represent the area of the top of the bag. b) If x represents 7 cm, what is the area of the top of the bag, in square centimetres? 8. A stone is thrown straight down from a tall building. The relation h = 150 − 5t − 5t2 approximates its path, with h in metres and t in seconds. a) How tall is the building? b) Factor the right side of the equation fully. c) When does the stone hit the ground? 5. a) Write an algebraic expression for the volume of the rectangular prism. 9. The North Stone Pyramid at Dahshur in Egypt has a square base with an area that can be represented by the trinomial 9x2 − 12x + 4. a) Factor the trinomial to find a binomial to represent the side length of the base of the pyramid. b) If x represents 74 m, what is the side length of the base, in metres? b) Expand and simplify the expression. c) Find the volume if x = 1 cm. Principles of Mathematics 10: Teacher’s Resource BLM 5–14 Chapter 5 Test Copyright © 2007 McGraw-Hill Ryerson Limited Name: ___________________________________ Date: _______________________________ …BLM 5–14... (page 2) 10. Determine the value(s) of k so that each trinomial can be factored as a perfect square. a) x2 − 12x + k b) 9x2 + kx + 25 c) kx2 − 4x + 1 d) 16y2 + ky + 9 e) x2 + kx + 36 f) 4x2 − 24x + k g) 36x2 − kxy + 49y2 h) 49x2 − 42xy + ky2 13. Explain how to determine the value(s) of k that would make x2 + kx + 100 a perfect square trinomial. 14. If a and b are integers, find values of a and b so that a2 – b2 is 21. 15. a) Write an expression for the shaded area in the diagram. 11. Write and simplify an algebraic expression for the area of the shaded region. 12. The area of a rectangle is represented by the equation A = 6x2 + 5x − 4. a) Factor the right side of the equation fully to find expressions for the length and width of the rectangle. b) Find an expression for the perimeter of the rectangle. c) If x represents 7 cm, find the area and the perimeter of the rectangle. Principles of Mathematics 10: Teacher’s Resource BLM 5–14 Chapter 5 Test b) Factor this expression. c) Find the area of the shaded region if x = 3 cm. Copyright © 2007 McGraw-Hill Ryerson Limited …BLM 5–16... (page 1) BLM Answers Get Ready 1. a) c) e) 2. a) 3. a) c) 4. a) c) 5. a) c) 6. a) c) 7. a) 8. a) c) 9. a) c) monomial b) trinomial trinomial d) binomial four-term polynomial 2 b) 1 c) 3 d) 5 6x + 1 b) 8a − 5b x2 + 7x − 5 d) 6y3 − 9y2 + 5 b) −ab2 + 15a − 2b2 14x2 − 2xy − 5y2 8x − 17 d) −11b2 − b − 2 2 2x + 2xy b) −48a2 + 32a −6a − 42 d) 6x2 + 4x + 8 2 b) −16x2y + 8xy2 12m − 24m 3 3 −18a − 24a b d) −2ab2 + 12a2b − 14a 3 2 30x + 20x b) 62x2 + 28x 1, 2, 3, 6 b) 1, 2, 17, 34 1, 17 d) 1, 2, 4, 11, 22, 44 2×2×3 b) 3 × 3 2×2×2×5 d) 5 × 11 b) c) Section 5.1 Practice Master 1. a) (x + 1)(x + 3) b) (x + 2)(x + 2) 2. Diagrams may vary. For example: a) 3. a) c) e) 4. a) c) e) 5. a) c) e) 6. a) b) 7. a) x2 + x − 6 b) y2 + 8y + 12 2 d) d2 + 13d + 42 n − n − 20 2 f) a2 − 9a + 18 x − 14x + 48 2 2 b) 2x2 − 5x − 3 x − 4y 2 d) 4p2 − 24pq + 35q2 k + k − 42 2 6 − 13s + 6s f) 6t2 + rt − r2 2 b) x2 + 7x + 16 4x − 26x − 14 2 d) −8m2 − 16m 29x + 10x − 9 2 f) −24x2 − 120x + 21 23m − 26m − 9 2x(3x + 1) + 2x(2x + 2 − 2x) = 6x2 + 6x (x + 6)(x − 3) − 2x(x + 1) = −x2 + x − 18 b) x3 + 9x2 + 20x Principles of Mathematics 10: Teacher’s Resource Chapter 5 Practice Masters Answers c) 6x2 + 36x + 40 Copyright © 2007 McGraw-Hill Ryerson Limited …BLM 5–16... Section 5.2 Practice Master 1. Diagrams may vary. For example: a) 11. a) c) e) f) 16x4 + 24x2y2 + 9y4 b) 9x4 − 4y4 −6x + 18 d) 13b2 − 6b + 6 9x4 + 30x3 − 19x2 − 10x + 1 8x3 − 36x2 + 54x − 27 (page 2) Section 5.3 Practice Master 1. Diagrams may vary. For example: a) b) b) 2. a) x2 + 8x + 16 b) y2 + 14y + 49 2 c) a + 16a + 64 d) q2 + 10q + 25 2 3. a) 6y + 36y + 36 b) 6x2 + 12xy + 4y2 c) 4x2 + 4xy + y2 d) 36c2 + 84cd + 49d2 2 b) b2 − 50b + 625 4. a) x − 12x + 36 c) r2 − 22r + 121 d) e2 − 14e + 49 5. a) 64a2 − 16a + 1 b) 4u2 − 12uv + 9v2 c) 36p2 − 84p + 49 d) 25q2 − 80qr + 64r2 6. a) v2 − 4 b) x2 − 36 2 2 d) r2 − s2 c) x − y 2 2 b) 9x2 − y2 7. a) 36g − 49h 2 2 c) g − 81x d) 16x2 − 25y2 3 2 8. a) V = x + 3x y + 3xy2 + y3 b) SA = 6x2 + 12xy + 6y2 9. a) (3, 0) b) y = x2 − 6x + 9 c) Substitute the coordinates into the left and right sides of the equation. L.S. = x 2 − 6 x + 9 R.S. = y =0 = 32 − 6(3) + 9 c) = 9 − 18 + 9 =0 L.S. = R.S. 10. the square, by 9 cm2 Principles of Mathematics 10: Teacher’s Resource Chapter 5 Practice Masters Answers Copyright © 2007 McGraw-Hill Ryerson Limited …BLM 5–16... (page 3) 3(x + 2y) b) 17a(c − 2d) 8xy(2xy − 3) d) 9xy(3x2y2 + 2xy + 1) 6np2(n + 2 + 6n2p) f) 11c2de(3c2d2e − 1) 3(g2 + 2g + 3) (x + 7)(2x + 3) b) (b − 7)(a + 2) (r + u)(4s − 3) d) (x + s)(y + z) (a + 3)(x + y) b) 2(x + 2)(2x + 3y) (y + 3)(y + a) d) (5x + 1)(5x + 3y) SA = 2(lw + lh + wh) Both formulas give 340 cm2 because the formulas are equivalent. 6. a) −(y − 6)(3x − 2) b) 2(x − 3)(y − 2z) 5 b) r2(π − 2) 7. a) xy (9 x − 2) 2 2. a) c) e) g) 3. a) c) 4. a) c) 5. a) b) Section 5.4 Practice Master c) d) 1. Diagrams may vary. For example: a) b) 2. a) 6, 8 b) −3, 5 c) −6, 5 d) −2, −1 3. a) (x + 6)(x + 2) b) (c − 6)(c + 3) c) (d + 3)(d + 7) d) (d − 5)(d − 7) e) not possible f) (c − 5)(c − 6) g) (y + 7)(y + 8) h) (x − 9)(x + 8) 4. a) 3(x − 6)(x + 2) b) −2(x − 2)(x + 1) c) 6(x − 4)(x − 3) d) −3(x + 2)(x + 4) e) 4(x − 7)(x − 3) f) x(x + 3)(x + 4) 5. Answers may vary. For example: a) b = 8, b = −8 b) b = 9, b = −9 c) b = 2, b = −2 d) b = 3, b = 7 6. Answers may vary. For example: a) c = 3, c = −5 b) c = −10, c = 8 7. a) 3(x − 8)(x − 2) b) 2, 8 c) x = 5, (5, −27) 8. x by x + 2 by x + 3 Principles of Mathematics 10: Teacher’s Resource Chapter 5 Practice Masters Answers Copyright © 2007 McGraw-Hill Ryerson Limited …BLM 5–16... (page 4) Section 5.5 Practice Master 1. a) (x + 3)(2x + 1) b) (2x + 1)(3x + 4) c) (x + 2)(3x + 1) d) 2(x + 2)(2x + 5) 2. a) 2(x + 2)(3x − 1) b) (7x − 2)(8x + 1) c) (3x + 1)(3x + 1) d) 2(2c + 1)(3c − 8) e) (d − 6)(2d + 1) f) (r + 4)(2r + 5) g) (2s − 5)(3s − 7) h) (3r − 2)(5r + 1) i) (2r − 5)(2r − 5) j) (x − 4)(13x − 5) 3. a) (2x + y)(3x − 4y) b) (3x + 2y)(3x + 2y) c) (3r − 2s)(4r + 5s) d) (3r − 4s)(5r − s) e) (x − 6y)(2x − 7y) f) (3y + 4x)(6y − x) 4. Answers may vary. For example: a) k = 26, k = −29 b) k = 16, k = −17 c) k = 5, k = −7 d) k = 9, k = −11 5. a) length 3x + 1, width 2x − 7 b) length 46 m, width 23 m 6. a) −0.005(x − 100)(x + 2) b) 100 m 7. a) 10x + 3, x – 1 b) 53 m; 49 m 8. a) (2x2 − 3)(5x2 + 6) b) (5x3 − 6y2)(4x3 − 7y2) 3. a) y = 2x2 − 18x + 36 b) 3, 6 c) Substitute the coordinates of the points at the x-intercepts into both sides of the equation. L.S. = y R.S. = 2 x 2 − 18 x + 36 =0 = 2(6) 2 − 18(6) + 36 = 72 − 108 + 36 =0 L.S. = R.S. 4. a) (x − 3)(x + 9) − 9(x − 5) b) x2 − 3x + 18 5. Diagrams may vary. For example: a) Section 5.6 Practice Master 1. a) (x − 5)(x + 5) b) (y − 7)(y + 7) c) (3k − 1)(3k + 1) d) (4k − 7)(4k + 7) e) (5w − 6)(5w + 6) f) (2 − 3w)(2 + 3w) 2. a) (x − y)(x + y) b) (6x − y)(6x + y) c) (5r − 6s)(5r + 6s) d) (12r − 7s)(12r + 7s) e) (11x − 3y)(11x + 3y) f) (10r − 9s)(10r + 9s) b) (x − 3)2 3. a) (x + 7)2 d) (10 − x)2 c) (x − 4)2 2 f) (7x + 4y)2 e) (2x − 3y) 2 4. a) 2(a + 3) b) not possible c) 3(5x + 7y)2 d) xy(3x − 4y)(3x + 4y) f) 5(2x + y)2 e) 4(3m − 4n)2 5. a) b = 25 b) b = 84 or b = −84 6. Answers may vary, but k must be a perfect square. For example: a) k = 25, k = 4 b) k = 9, k = 81 7. a) (3c + 2)(7c + 4)2 b) not possible c) not possible d) 25(xy − 3ab)2 8. y = 4(x + 4)2; (−4, 0) 9. A = 4(x + 3)(2x + 1) Chapter 5 Review 1. a) c) 2. a) c) e) x2 + 10x + 21 b) y2 + 2y − 15 2 2 d) 15a2 + 58ab + 48b2 x − xy − 6y 2 −4a − 12a + 72 b) −3x3 − 24x2y − 36xy2 29y2 + 90y + 50 d) 19b3 + 2b2 − 16b −2x3 − 6x2y + xy2 + y3 Principles of Mathematics 10: Teacher’s Resource Chapter 5 Practice Masters Answers b) 6. a) c) 7. a) c) 8. a) c) 9. a) c) x2 + 12x + 36 b) r2 − 6r + 9 2 y + 20y + 100 d) e2 − 10e + 25 b2 − 81 b) y2 − 121 2 d) 196 − x2 m − 169 2 2 b) −20x2 − 100xb − 125b2 x − 6xy + 9y 2 2 121x − 169y d) 36b2 − a2 (4a + 6)(4a − 6) b) 16a2 − 36 2 (4a)(4a) − (16a − 36) = 36 d) 364 cm2 Copyright © 2007 McGraw-Hill Ryerson Limited …BLM 5–16... (page 5) 10. Diagrams may vary. For example: a) b) 11. a) 2x(x + 2) b) x(5x + 3) d) x(3y − 7z) c) 10(x2 + 2y2) 12. a) (x + 1)(2x + 3y) b) (x + y)(x2 + y) c) (5a + 3)(b − 1) d) (3a2 + b2)(x + y) 13. a) (x + y)(2z + 3xy) b) not possible c) 3(2a + 1)(a2 + 2) d) xz(xyz − xz + y) 14. xy(2x + 5) 15. Diagrams may vary. For example: a) b) 16. a) (x − 6)(x + 2) b) (x − 3)(x − 4) c) (x − 9)(x + 5) d) (x + 2)(x + 7) 17. a) −2(x − 5)(x − 3) b) x(x + 7)(x − 4) 18. length x − 9, width x − 10; length 2 cm, width 1 cm 19. a) (3x + 1)(4x − 3) b) (x − 5)(3x + 2) c) (2x − 1)(5x + 7) d) (3x + 1)(7x − 1) 20. a) 3(x2 + 5y + 11) b) not possible c) 3(2x − 1)(5x + 4) d) −2(x + 6)(3x − 1) 21. Answers may vary. For example: a) k = −7 b) k = 13 22. a) (x − 10)(x + 10) b) (c − 5)(c + 5) c) (3x − 4)(3x + 4) d) 2(8 − 3x)(8 + 3x) e) (1 − 15y)(1 + 15y) f) −3(x − 3y)(x + 3y) 23. a) Since y2 = (y)2 and 64 = 82, the first and last terms are perfect squares. Since 16y = 2(y)(8), the middle term is twice the product of the square roots of the first and last terms. Therefore, y2 + 16y + 64 is a perfect square trinomial. (y + 8)2 b) Since x2 = (x)2 and 100 = (−10)2, the first and last terms are perfect squares. Since −20x = 2(x)(−10), the middle term is twice the product of the square roots of the first and last terms. Therefore, x2 − 20x + 100 is a perfect square trinomial. (x − 10)2 c) Since 225 = (15)2 and 9y2 = (−3y)2, the first and last terms are perfect squares. Since −90y = 2(15)(−3y), the middle term is twice the product of the square roots of the first and last terms. Therefore, 225 − 90y + 9y2 is a perfect square trinomial. (15 − 3y)2 This is not fully factored: (15 − 3y)2 = [3(5 − y)]2 = 9(5 − y)2 d ) Since 121c2 = (11c)2 and 196d2 = (14d)2, the first and last terms are perfect squares. Since 308cd = 2(11c)(14d), the middle term is twice the product of the square roots of the first and last terms. Therefore, 121c2 + 308cd + 196d2 is a perfect square trinomial. (11c + 14d)2 24. a) not possible b) 2(5x − 3y)2 c) (x + y − 7)(x − y + 1) d) not possible 25. a) x by 2x + 3 by 2x + 3 b) two congruent squares and four congruent rectangles c) 243 cm3 d) 270 cm2 Chapter 5 Practice Test 1. a) (x + 3)(x + 2) b) (2x + 1)(x + 4) 2. a) −8x5 − 4x4 − 8x3 b) −8x3y − x2y2 − 9xy 2 b) 4x2 + 4x − 3 3. a) x − 12x + 27 2 c) −x + 24x − 66 d) 11c2 + 4cd + d2 2 f) c2 + 12cd − 6c + 9d2 − 3 e) −10x − 2x + 9 4. k must be divisible by 2, because the only common factor of the other two coefficients is 2. Principles of Mathematics 10: Teacher’s Resource Chapter 5 Practice Masters Answers Copyright © 2007 McGraw-Hill Ryerson Limited …BLM 5–16... 5. a) x2(3x + 1)(2x + 5) b) 6x4 + 17x3 + 5x2 c) 252 cubic units b) (5r − 2s)2 6. a) (x + 5)2 c) 5(x − 1)(x + 1) d) (1 − 7m)(1 + 7m) e) (m + 3)(5m + 2) f) (m − 2n)(m − 7n) 7. a) y(y − 2)(3y − 1) b) 4(m2 + 4) c) (2y + 1)(3y − 1) d) (m − 2)(x − 4) e) (x + y)(y + 2) f) t(3 − 2t)(3 + 2t) 8. a) −5(t − 5)(t + 1) b) after 5 s c) 45 m 9. Answers may vary. For example: a) k = −12, k = 13 b) k = 5, k = 4 c) k = 84, k = 85 d) k = 1, k = 169 (k must be a perfect square) 10. π(r + 3)2 − πr2 = 3π(2r + 3) 11. a) 3x(2x − 1)(2x + 1) b) (page 6) Chapter 5 Test 1. Diagrams may vary. For example: a) b) c) 18 cm by 11 cm by 13 cm 12. a) (2x + 5)(5x – 8) b) 69 mm by 152 mm 13. First, remove the greatest common factor, x, to get x(ax2 + bx + c). Then, find two integers, m and n, whose product is ac and whose sum is b. Break up the middle term, bx, into mx + nx and then factor by grouping. 14. a) 232 − 222 = (23 − 22)(23 + 22) = 1(55) = 55 b) 252 − 232 = (25 − 23)(25 + 23) = 2(48) = 96 c) 812 − 772 = (81 − 77)(81 + 77) = 4(158) = 632 d) 1542 − 1502 = (154 − 150)(154 + 150) = 4(204) = 816 15. a) You can write any two numbers that differ by 2 as x – 1 and x + 1. Their average is x −1+ x + 1 2x = or x. Their product is 2 2 2 (x – 1)(x + 1), or x – 1. b) Find the square of their average and subtract 4. c) Write the two numbers as x – 2 and x + 2. Their average is x. Their product is (x – 2)(x + 2), or x2 – 4. Principles of Mathematics 10: Teacher’s Resource Chapter 5 Practice Masters Answers 2. a) 3x3y3 + 12x3y2 − 6x2y3 b) x2 − 32x + 44 b) 6x2 − 31x + 5 3. a) k2 + 3k − 4 d) 4x2 − 14xy + 11y2 c) 15x2 − 36x + 23 2 e) −14x + 22x − 26 4. a) (5x + 3)2 = 25x2 + 30x + 9 b) 1444 cm2 5. a) 2x(5x − 2)(3x + 4) b) 30x2 + 28x2 − 16x c) 42 cm3 6. a) (x − 5)2 b) (2x − 3)2 c) (y + 2)(2y + 1) d) (k − 4)(3k + 1) e) (2r − 1)(5r + 3) f) (2s − 5t)(3s + 2t) 7. a) 21(x − 1)(x + 2) b) 7(g − 3)(g + 7) c) not possible d) c(c − 3)(c + 3) e) (2d −3)(3d − 2) f) 2(5x − 6)(5x + 6) 8. a) 150 m b) −5(t − 5)(t + 6) c) after 5 s 9. a) 3x – 2 b) 220 m Copyright © 2007 McGraw-Hill Ryerson Limited …BLM 5–16... (page 7) 10. a) k = 36 b) k = −30, k = 30 c) k = 4 d) k = −24, k = 24 e) k = −12, k = 12 f) k = 36 g) k = −84, k = 84 h) k = 9 11. (2x + 3)(x + 4) − x2 = x2 + 11x + 12 12. a) (2x − 1)(3x + 4) b) 10x + 6 c) 325 cm2, 76 cm Principles of Mathematics 10: Teacher’s Resource Chapter 5 Practice Masters Answers 13. Multiply the square root of 100, −10 or 10, by 2, to get −20 or 20. 14. There are eight possible answers for the ordered pair (a, b): (5, 2), (–5, 2), (5, –2), (–5, –2), (11, 10), (–11, 10), (11, –10), and (–11, –10). 15. a) (2x + 3)(2x + 3) − (2)(2) b) (2x + 1)(2x + 5) c) 77 cm2 Copyright © 2007 McGraw-Hill Ryerson Limited