HORIZON EDUCATION SINGAPORE Additional Mathematics Practice Questions: Coordinate Geometry 1 Set 1 1 In the figure, π΄π΅πΆπ· is a rhombus with coordinates π΄(2, 9) and πΆ(8, 1). The diagonals π΄πΆ and π΅π· cut at πΈ. (i) Calculate the co-ordinates of πΈ. [1] (ii) Find the equation of π΅π·. [2] It is given that the equation of π΄π· is π₯ + 7π¦ − 65 = 0. (iii) Find the equation of π΅πΆ. (iv) 2 3 4 Calculate the length of π΄π΅. [2] [3] The line 3π₯ − π¦ = 7 intersects the curve π₯ 2 − π₯π¦ + π¦ 2 = 7 at π΄ and π΅. Find (a) the coordinates of the points π΄ and π΅, [3] (b) the equation of the perpendicular bisector of π΄π΅. [3] 1 The line π¦ = 2π₯ intersects the curve π¦ = π₯ + π₯ at points π΄ and π΅. Find the equation of the perpendicular bisector of the line π΄π΅. [6] Two points π΄ and π΅ have coordinates (3√2, 2√5) and (−2√5, √2) respectively. Without the use of a calculator, calculate the gradient of the line π΄π΅, leaving your answer in the form π + π√10, where π and π are integers. [4] Page 1 of 12 Division of Mathematics, Horizon Education Singapore 5 Solution to this question by accurate drawing will not be accepted. y B (6, 13) C A 3 y ο½ 4 x ο 10 x D (1, ) The diagram shows a trapezium π΄π΅πΆπ· in which π΄π΅ is parallel to π·πΆ. The point π΄ lies on the π¦-axis. Points π΅ and π· are (6, 13) and (1, −2) respectively. π΄π΅Μ πΆ = π΅πΆΜ π· = 90°. Given that the equation of π·πΆ is 3π¦ = 4π₯ − 10, find (a) the coordinates of π΄, [3] 6 (b) the coordinates of πΆ, [4] (c) the area of the trapezium π΄π΅πΆπ·. [3] Solutions to this question by accurate drawing will not be accepted. The coordinates of π and π are (−1, 10) and (11, 6) respectively. (i) Find the equation of the perpendicular bisector of ππ. [3] (ii) (iii) Given that there is a pair of coordinates of point π΄ which meets the perpendicular bisector of ππ at the π¦-axis, find coordinates of π΄. [3] If ππ΄ππ΅ is a parallelogram, find the coordinates of point π΅. [3] Page 2 of 12 Division of Mathematics, Horizon Education Singapore 7 Solutions to this question by accurate drawing will not be accepted. y A(7, 10) B . M(8, 6) D C x The diagram shows a rhombus π΄π΅πΆπ· in which π΄ is (7, 10) and π· is on the π¦-axis. The point π(8, 6) is the midpoint of π΄πΆ. Find (a) the coordinates of πΆ, [2] (b) the coordinates of π·, [3] (c) the coordinates of π given that π is on ππ· such that area of triangle π΄ππΆ = 1 area of triangle π΄π·πΆ. [3] 4 8 Solutions to this question by accurate drawing will not be accepted. y C (2, 1) B x 0 D A (−1, −4) In the quadrilateral π΄π΅πΆπ·, the points π΄ and πΆ are (−1, −4) and (2, 1) respectively. The line π΅πΆ is parallel to π₯ − 4π¦ − 1 = 0 and perpendicular to π΄π΅. The foot of the perpendicular from π΄ to πΆπ· bisects πΆπ· and the rest on the π₯-axis with the π₯-coordinate 3. Find (i) the coordinates of π΅ and of π·, (ii) the radius of the circle which passes through π΄, π΅ and πΆ. Page 3 of 12 Division of Mathematics, Horizon Education Singapore [8] 9 Solution to this question by accurate drawing will not be accepted. πππ π is a trapezium in which ππ is parallel to ππ and ππ is perpendicular to both ππ and ππ . The coordinate of π, π and π are (0, 11), (3, 2) and (13, 12) respectively. y S R (13, 12) P(0, 11) Q(3, 2) 10 x Find (a) the equation of ππ , [2] (b) the coordinates of the point π, [2] π is a point on π π produced such that πππ π is a parallelogram. Find (c) the coordinates of π, [2] (d) the ratio π π: ππ, [2] (e) the shortest distance of π from ππ. [2] π΄π΅πΆπ· is a rectangle, where π΄ is (−3, 0) and πΆ is (1, 7). Given that the equation of π΄π΅ is 3π¦ = 2π₯ + 6, find (i) the equation of π΅πΆ, [2] (ii) the coordinates of π΅, [2] (iii) the coordinates of π·, [2] (iv) the area of π΄π΅πΆπ·. [2] Page 4 of 12 Division of Mathematics, Horizon Education Singapore 11 The diagram, which is not drawn to scale, shows a right-angled triangle πππ in which ∠πππ = 90° and the coordinates of π and π are (3, 5) and (−1, −3) 1 respectively. Given that the gradient of ππ is 2 and the the perpendicular from π to ππ to meets ππ at π, find P (3, 5) y R S x O Q(ο1, ο3) (a) the equation of ππ and of ππ , [3] (b) the coordinates of π and of π, [5] (c) the ratio, ππ: ππ , [1] area of Δπππ (d) the numerical value of area of Δπππ . Page 5 of 12 Division of Mathematics, Horizon Education Singapore [1] 12 In the quadrilateral π΄π΅πΆπ·, the points π΄, π΅ and π· are (3, 3), (0, −1) and (6, 2) respectively. The line π΅π· bisects the line π΄πΆ at right angles at the point π. Find the coordinates of π and of πΆ. [8] π¦ π΄ (3, 3) π· (6, 2) π π₯ π΅ (0, −1) 13 πΆ The straight line π¦ + 2π₯ = 5 intersects the curve π₯ 2 + π¦ 2 + π₯ + 12π¦ = 29 at the points π΄ and π΅. Given that π΄ lies below the π₯-axis, and that π lies on π΄π΅ such that 1 the area of Δπ΄ππ is 4 of the area of Δπ΄ππ΅, where π is the origin, find the coordinates of π. [6] Page 6 of 12 Division of Mathematics, Horizon Education Singapore 14 Solutions to this question by accurate drawing will not be accepted. The diagram shows a kite ππ΄π΅πΆ whose diagonals meet at π. The coordinates of π΄, π΅ and πΆ are (11, π), (5, 3) and (π, π + 3) respectively, where π and π are y constants. C(c, c + 3) B(5, 3) M x O A(11, a) 15 16 Find (a) the coordinates of π, [1] (b) the equation of π΄πΆ, [3] (c) the value of π, [1] (d) the coordinates of πΆ, [2] (e) the area of the kite ππ΄π΅πΆ. [3] π, π, π and π are the points (0, 9), (−3, −3), (1, −2) and (3, 7) respectively. (i) Find the area of the quadrilateral πππ π. [2] (ii) Find the equation of the line, π1, that is perpendicular to ππ and passes through the point π . [3] (iii) If ππ is extended to meet the line π1 at π, find the ratio of ππ: ππ. [4] A point π lies on the line 2π¦ + π₯ = 10 and is at a distance of 5 units from the origin (0, 0). Find the possible π₯-coordinates of π. [3] Page 7 of 12 Division of Mathematics, Horizon Education Singapore 17 18 π΄π΅πΆπ· is a rectangle such that π΄, π΅ and πΆ are the points (0, 1), (π‘, 2π‘ + 1) and (4, 4) respectively. (i) Show that the value of π‘ is 2. [2] (ii) Find the equation of πΆπ·. [2] (iii) Find the coordinates of the point of intersection of the 2 diagonals. [2] (iv) Find the equation of the perpendicular bisector of π΄π΅. [3] Solutions to this question by accurate drawing will not be accepted. The line 4π₯ − 3π¦ = 1 intersects the curve π₯π¦ = 28π¦ − 27π₯ at the points π and π. (a) Find the coordinates of π and of π. [4] (b) Find the equation of the perpendicular bisector of ππ. [3] It is given that the perpendicular bisector of ππ intersects the π¦-axis at the point π . (c) Find the distance of π from ππ. [3] 19 In the given diagram, point π΄ is located on the π¦-axis and the equation of the straight line π΄π΅ is 2π¦ = π₯ + 8. y B (p, q) A O x (a) Write the coordinates of the midpoint of π΄π΅ in terms of π and π. [2] (b) Show that the equation of the perpendicular bisector of π΄π΅ is 2π¦ + 4π₯ = 2π + π + 4. [2] (c) If the perpendicular bisector of π΄π΅ intersects the π¦-axis at π¦ = 14, find the value of π and of π. [3] 20 The line 5π₯ + π¦ = 9 intersects the curve π¦ 2 + 3π₯π¦ = −5 at the points π and π. Find the midpoint of ππ. [6] Page 8 of 12 Division of Mathematics, Horizon Education Singapore 21 Solution to the question by accurate drawing will not be accepted. y A (2, 9) B y = 2x x O The diagram shows a right-angled triangle π΄π΅π in which π is the origin, π΄ is the point (2, 9) and π΄π΅Μ π = 90°. The equation of the line ππ΅ is π¦ = 2π₯. Find (i) the equation of the line π΄π΅, [2] (ii) the coordinates of π΅. [2] πΆ is a point on the perpendicular bisector of ππ΄ and is such that π΅πΆ is parallel to the π¦-axis. (iii) Find the coordinates of πΆ. [3] area of Δππ΄π΅ 1 π· lies on π΄π΅ produced such that area of Δππ΄π· = 3. (iv) Find the coordinates of π·. Page 9 of 12 Division of Mathematics, Horizon Education Singapore [3] 22 Solutions to this question by accurate drawing will not be accepted. The diagram shows a trapezium π΄π΅πΆπ· in which the coordinates of π΄ and πΆ are (2, −1) and (3, 4) respectively Given that πΈ is a point on the π¦-axis, such that π΄π΅πΆπΈ is a square. y C (3, 4) D E B x O A(2, ο1) (i) Find the coordinates of πΈ and π΅. [4] (ii) Find the equation of π΄π΅. [2] (iii) Given that the area of square π΄π΅πΆπΈ is 4 times the area of triangle πΆπ·πΈ, find the coordinates of π·. [3] Page 10 of 12 Division of Mathematics, Horizon Education Singapore 23 Solutions to this question by accurate drawing will not be accepted. y A (6, 9) C (8,4) B (6, 1) 0 7 E (p, -2 x ) 13 D The diagram shows an isosceles triangle π΄π΅πΆ in which π΄ is the point (6, 9). π΅ is the point (6, 1). It is given that the area of the triangle π΄π΅πΆ is 8 units2. (i) Find the coordinates of πΆ. [2] The line πΆπ΅ is extended to the point π· such that the area of triangle π΄π·πΆ is thrice the area of triangle π΄π΅πΆ. (ii) Find the coordinates of π·. [3] 7 A line is drawn from π΄, parallel to πΆπ·, to the point πΈ (π, −2 13). (iii) Find the value of π. [2] (iv) Determine whether ∠π΄πΈπ· = 90°. [3] Page 11 of 12 Division of Mathematics, Horizon Education Singapore 24 Solutions to this question by accurate drawing will not be accepted. The diagram shows a quadrilateral π΄π΅πΆπ· in which π΄ is (3, 0), πΆ is (3π, 5π + 3) and π· is (−2, 5). The equation of π΄π΅ is 5π¦ = 3π₯ − 9 and angle π΄π·πΆ = 90°. y C (3a, 5a + 3) D (– 2, 5) B x A (3, 0) (i) Find the value of π. If πΉ is the foot of the perpendicular bisector of πΆπ· from π΅, find (ii) the coordinates of πΉ, (iii) the coordinates of π΅, and (iv) the area of the quadrilateral π΄π΅πΆπ·. [11] 25 The line 2π¦ + π₯ = 5 intersects the cruve π¦ 2 + π₯π¦ = 6 at the points π΄ and π΅. Find the equation of the perpendicular bisector of π΄π΅. [6] 26 The points π΄ and π΅ have coordinates (−8, −10) and (−2, −2). Find the equation of the perpendicular bisector of π΄π΅. [4] END Page 12 of 12 Division of Mathematics, Horizon Education Singapore