L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 FUNDAMENTALS OF ORGANIC Chpt. 24: p.1 CHEMISTRY 有機化學 Organic Chemistry is the chemistry of compounds containing carbon. Most of these compounds also contain hydrogen, oxygen or other elements. Note: Carbon containing compounds such as carbon monoxide and dioxide, carbonic acid, metal carbides, carbonates and hydrogencarbonates are not classified as organic compounds. (I) NATURAL SOURCES OF ORGANIC COMPOUNDS Organic compounds are extremely important as they are found in living things. Many products and materials are also organic products. Naturally occurring Synthetic Fuels (e.g. coal crude oil) in living orgainisms Carbohydrates plastics gasoline proteins cosmetics, perfumes kerosene fats and oils anaesthetics many petroleum products vitamins dyes, explosives (II) THE UNIQUE NATURE OF CARBON 碳的獨特性 1. Introduction The carbon atoms has a unique property of forming many naturally occurring and synthetic compounds with a narrow range of elements than all other elements. Reasons : Carbon is able <1> to extend its maximum covalency to four 均有形成四個共價鍵的趨勢 <2> to form stable bonds with itself. e.g. Chain structures straight chain : butane polythene <3> (A) branched chain : 2-methylbutane Ring structures : cyclohexane form double and triple bonds amongst themselves or with other elements . 可與碳或其他元素形成雙鍵,及三鍵 e.g ethene propyne butanone Physical properties Organic compounds are usually <1> covalent gases, volatile liquids or low melting solids <2> insoluble in water (polar solvent) unless with the presence of some polar groups such as -OH, -COOH, and –SO3H in the compounds <3> more soluble in organic, non-polar solvents such as ethoxyethane/ether, trichloromethane. L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 (B) (III) 1. Chpt. 24: p.2 Chemical properties <1> The products yielded when burnt in excess oxygen are usually ,carbon dioxide and water. <2> They usually react more slowly than inorganic compounds. Energy in the form of heat is usually required. <3> The reactions are seldom complete reacted. Purification is usually required to obtain the desired product. <4> Organic compounds are often exist in groups or families (Homologous series) having similar chemical properties and graduation of physical properties. <5> They can exist in large amounts is due to the possibility of catenation and isomerism in their compounds. FUNCTIONAL GROUP AND HOMOLOGOUS SERIES 官能基及同系列 Functional Groups of Organic Compounds The diversity of organic molecules are very often classified by the presence of functional, groups in the molecules. The functional group represents the part of molecule which gives a characteristic type of reactivity upon the compound and effectively determines the compound’s chemical properties and many of its physical properties as well. L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 2. Chpt. 24: p.3 Homologous Series A homologous series is a series of compounds with adjacent members differing in their formula by a —CH2— unit. Examples Alkanes series 烷烴 CH4 Alkanols series 烷醇 CH3OH Alkenes series 烯烴 C2H4 Note : <1> e.g. Members of a homologous series exhibit similar chemical properties but have a gradation physical properties (melting points, viscosity, density etc.) Alkanes C1-C4 : gases C5-C16 : liquids C17 above : solids <2> Members in the same series have a general formula e.g. Alkanes Alkenes IV. Alkanols General Introduction to the major families of Organic Compounds (A) Hydrocarbons 碳氫化合物: The families of organic compounds whose molecules contain carbon and hydrogen only. Alkanes — contain only C—C single bond between carbon atoms Alkenes — contain a C=C double bond Alkynes — contain a CC triple bond Aromatic Hydrocarbons — contain an aromatic ring Alkanes 烷烴 These molecules are saturated hydrocarbons with only C—C bond and C—H single bond inside. The carbon atoms form four single bonds with other atoms and have unshared electrons in their valence orbitals. Examples : (a) Chain structures 鍊狀結構: 1. no Methane Propane 2—methylbutane (b) Ring structures 環狀結構: Cyclopentane Cyclohexane L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 2. Chpt. 24: p.4 Alkenes 烯烴 The two carbon atoms in such hydrocarbons share two pairs of electrons to form a C=C double bond. This C=C double bond is therefore a centre of unsaturation in the molecule and can undergo addition reaction to utilize its covalency to the full (four). H H C C H H + Br Br C C Br Br The C=C double bond can be regarded as the functional group of alkene since most of the chemical reactions take place here. Examples Propene cis—But—2—ene cis—1, 2—dibromoethene Cyclohexene trans—But—2—ene trans—1 , 2—dibromoethene Alkynes 炔烴 These are hydrocarbons in which two of the carbon atoms share 3 pairs of electrons between them and are thus bonded by a CC triple bond. The reactive site is the CC triple bond at which the addition reactions take place. Examples : H-CC-H Ethyne Propyne 3—Methylbutyne 3. 4. Aromatic Hydrocarbons 芳香烴 This is a class of cyclic hydrocarbons in which benzene is typical example . Benzene derivatives : (substitution of the —H group) Methylbenzene 1. 2—dibromobenzene 1, 3—dibromobenzene Chlorobenzene 1,4—dibromobenzene When benzene ring is attached to some other groups of atoms in a molecule, it is called a phenyl group. L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 (B) 1. Chpt. 24: p.5 Hydroxyl Compounds 羥基化合物: Such family of compounds have the functional group —OH. There are two large groups of hydroxyl compounds : alcohols and phenols Alcohols 酒精 This group of compounds can either be regarded as hydroxyl derivatives of alkanes or as alkyl derivatives of water. RH Example CH3CH2-H ROH CH3CH2—OH ethanol (ethyl alcohol) HOH H2O Based on the condition of the carbon atom to which he —OH group is directly attached, alcohols are generally classified into three groups : primary (1°) , secondary (2°) and tertiary (30) alcohols. a primary alcohol e.g. ethanol 乙醇 a second alcohol propan-2-ol 丙-2-醇 a tertiary alcohol 2-methylpropan-2-ol 2-甲基丙-2-醇 2. Phenols 酚 This is a hydroxyl derivatives of benzene and is almost always called phenol. OH (C) Ethers 醚: Such family of compounds can be thought as derivatives of water in which both hydrogen have been replaced by alkyl groups. They have the general formula R—O—R, and the bond angle of R—O—R is slightly larger than H—O—H. H R O O H R water ether (D) Carbonyl Compounds 羰基化合物: Such family of compounds contain the carbonyl group C O in their 1. structures. Aldehydes 醛 The carbonyl group bonded to at least one hydrogen atom. The general formula is O C R H where R may also be H Examples Methanal 甲醛 (formaldehyde) Ethanal 乙醛 (Acetaldehyde) propanal 丙醛 L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 Chpt. 24: p.6 Ketones 酮 The carbonyl group is attached to alkyl groups. The general formula is 2. O C R' R Examples Propanone 丙酮 (Acetone) Butanone 丁酮 3-methylbutanone 3-甲基丁酮 (E) Carboxylic Acids : The family of compounds have the carboxyl group. O C OH as the functional group. The general formula is O C OH R or RCOOH or RCO2 H Examples Methanoic acid 甲酸 Ethanoic acid 乙酸 Benzoic acid Ethandioic acid 乙二酸 (F) Acid Derivatives 酸的衍生物 :These refers to the acid halides 酉先鹵, amides 酉先胺, esters 酯 and acid anhydrides 酉先酐. They are derived from the substitution of the hydroxyl group of -COOH by -X, - NH2 , - OR and -COOR Carboxylic Acid Derivatives Structure Name Structure O R R C Cl Acyl(acid)chloride O O C O C R C C NH2 O R' Acid anhydride R C NHR Amides O O R Name O OR Ester R C NR2 Halogen Hydrocarbons : Any —H group(s) in a hydrocarbon skeleton is substituted by one or more halogen atoms (i.e. Cl, Br, I etc.) Examples (G) 2, 2-Dibrombutane 3-chlorobut-1-ene Bromobenzene L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 (H) Amines 烷基胺 Chpt. 24: p.7 : These are organic derivatives of ammonia 為氨的有基衍生物. H N H R N H R N H R N R'' H H R' R' primary(1°) amine (2H) secondary(2°) amine (1H) tertiary(3°) amine (no H) Examples Ethyl amine (I) V. Propylamine Polyfunctional Compounds : Compounds contain more than one typical functional groups. Examples 2—Hydroxylpropanoic acid (Lactic acid) Ethane—1.2—diol 2—Aminoethanoic acid (Glycine) Phenyl ethyne Representation of structural formula <1> Dot formula — to show the number of valence electrons and the way they are shared. <2> Dash formula — to show the way atoms are attached to one another. <3> Condensed formula — to impart all the information implied in the dot and dash formula. <4> bond—line formula — to show only the carbon skeleton. Hydrogen atoms are omitted. N, O ,Cl are written in. Examples : Dot formula Dash formula Condensed formula CH3CH2CH2CH2CH2OH Bond—line formula (CH3)2CHCH2OH <5> Three-dimensional formula — to show the arrangement of atoms in space and give the 3dimensional structure of a molecule. (i) (ii) . (iii) Dash—line—wedge formula : bond lines notation bonds directed behind the plane of the page bonds projected out of the plane of the page bonds on the plane of the page Sawhorse projection : to show the carbon skeleton by solid lines with indications of the terminal group attached to it Newman projection : to show the structure by looking down one particular carbon—carbon bond axis. Bonds of the front carbon are depicted as Bonds of the back carbon are depicted as L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 Chpt. 24: p.8 Exercises : CH3 CH CH2 CH CH CH3 CH3 H CH3 C and CH3 CH3 CH CH3 CH3 CH3 CH2 CH3 1. Identify, groups in each of the following compounds. as far as possible, all the functional OH H COOH O a) O OH C OH N c) O b) C Cl O CH3 C Cl C O d) 2. e) Which of the following pairs of structure represent the same compound and which are different compounds? CH3 CH CH2 CH CH CH3 CH3 CH3 CH3 and H CH3 C CH3 CH3 CH CH2 a) CH3 CH3 C2H5 OCH3 and b) CH3 c) Cl H3C O C2H5 Cl and CH3 L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 Chpt. 24: p.9 VI. STRUCTURE AND SHAPE OF HYDROCARBONS (A). Tetravalent Carbon in Saturated Compounds The electronic configuration of Carbon is 1s2 2s2 2p2 It is not divalent (the 2 unpaired 2p electrons forming covalent bonds by overlapping with the orbitals of two unpaired electrons from other atoms) but tetravalent because hybridization of the atomic orbitals takes place at the carbon atom. The hybrid orbitals are in tetravalent arrangement in order to minimize the repulsion among them. For such sp3 orbitals overlapping with is orbitals from four hydrogen atoms, methane is formed. Note <1> The carbon atom prefers the tetravalent state because large amount of bond energy is released by form two extra ‘bonds. Such energy can outweigh the energy required for excitation and hybridization. <2> The strong covalent bonds formed is called a bond. The bonding electrons are localized symmetrically along the internuclear axis of boding atoms. <3> The tetrahedral configuration around an sp3 carbon is retained in any compound where carbon forms four single covalent bonds with other atoms. L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 Chpt. 24: p.10 <4>The atoms joined by a a bond can rotate with respect to one another. Example : For ethane molecule, C—H and C—C bonds can be rotated. Conformations (conformers) of the molecules can be obtained by rotation about the C—C bond. The two extreme cases are staggered and eclipsed forms. <i> staggered form : The molecule is lower in Reason : energy and more stable. <ii> eclipsed form : The molecule is higher in energy and less stable. Reason : <5> In the case of cyclic compounds, the tetrahedral configuration around sp3 carbon also tend to preserve other additional interactions have to be taken into account. (i) Cyclohexane: The ring is slightly puckered from a planar form (regular hexagon with interior angle 1200 ) to a puckered form in order to relieve the 12 C—H bonds interaction. It has two conformations : <a> Chair form — — — <b> Boat form — — the The ring is puckered that all sp carbons have tetrahedral configuration. It is free of ring strain. All the C—H bonds are perfectly staggered so that there will be no H—H interaction. Hydrogens of the side carbons are eclipsed Two of the hydogens on C1 and C4 exert repulsion on each other. Such repulsion cause the form to have higher energy than chair form. chair form boat form L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 (B). Chpt. 24: p.11 Unsaturated Hydrocarbons — Double and Triple Bonds (1) Formation of C=C Double Bond In forming the C=C bond, carbon atoms undergo sp2 hybridization. The three sp2 hybridized orbitals are in a trigonal planar arrangement with 120° between any two orbitals. The unhybridized 2p orbital is in a plane at right angle to them. In forming the ethane (C2H4) molecule, <a> A strong sp2—sp2 __________ is formed between the carbon atoms <b> Four sp2—s __________ are formed between the sp2 carbons and hydrogens by overlapping with their is orbitals. <c> The two unhybridized 2p orbitals of carbon overlap laterally to form a _______ bond above and below the plane. Note <i> <ii> The Lateral overlap in bond is ______ effective than the linear overlap in a bond. The electrons in the bond are delocalized over both carbon atoms, moving freely throughout an orbital above and below the plane of the carbon framework. Such carbon framework is the nodal plane of the it bond. L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 <iii> Chpt. 24: p.12 The rotation of the bond through 90° would result in the breakage of the bond. The breakage if usually involves a large amount of energy (220 kJmol-1) and the temperature required should be above 300°C. The bond is rigid that prevents double bond rotation and keep the structure of the ethene molecular planar, with all the hydrogen atoms lying in the same plane. <iv> The rigidity of mm bond is till maintained in the structure of cyclohexene, C=C bond in which carbons are sp2 hybridized : planar 3 C—C bond in which carbons are sp hybridized : tetrahedral (2) Formation of —CC— Triple Bond In forming —CC— bond, carbon atoms undergo sp hybridization by utilizing their 2s and 2p orbitals. The sp hybrid orbitals are co-linear and are at 180° to one another. The other two unhybridized orbitals of each carbon atom remain in planes at right angles to one another. L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 Chpt. 24: p.13 In forming the ethyne (C2H2) molecule, <1> One sp—sp ________ is formed between two carbon atoms. <2> Two pairs of unhybridized. 2p orbitals overlap each other laterally to form two it bonds which are mutually at right angles to each other. <3> The difference in bonding and electronic structure of the C— C, C=C and CC bonds is reflected in their bond energy and bond lengths. Table - Values of bond length and bond energy in ethane, ethene and ethyne Carbon-carbon bond Carbon-carbon bond Compound ‘ length/nm energy/kJ mol-1 in ethane 0.154 350 in ethene 0.134 600 in ethyne 0.120 815 Interpretation (i) The carbon—carbon bond length decreases from C—C to CC Reason: The formation of double and triple bonds is accompanied by an increase in overlap of the electron clouds of the combining atoms. The increases electron density enhances the electrostatic binding between the two nuclei. As a result, the bonds are shorter. (ii) The carbon—carbon bond energy increases from C—C to CC Reason : More energy is required to rupture the bond from C—C bond to CC bond. VII. Aromatic Hydrocarbons — Special case of Benzene (A) Electronic Structure and Special Distribution of Bonds The structure of benzene can be considered as a further extension of delocalisation from the conjugated dienes. <1> <2> Each carbon atom undergoes sp2 hybridization and form 2 bonds with another two carbon atoms as well as 1 bond with hydrogen atom. All the 6 carbon atoms and 6 hydrogen atoms form a planar hexagon. The 6 unhybridized 2p orbitals overlap each other on both side to give an annular electron cloud above and below the plane of the ring. This extended delocalisation of the p orbitals accounts for the planar nature of the ring. Note: <1> Benzene can be regarded as the resonance hybrid of two Kelule structures. The true structure is the intermediate between them. L.S.T. Leung Chik Wai Memorial School F.6 Chemistry Chapter 24-25 Chpt. 24: p.14 <2> The electrons are delocalized around the whole system and the structure of benzene is better represented as follow : <3> Due to the delocalization of the electron cloud, the C—C bond lengths in benzene are exactly the same (0.140 nm). Such value lies between the value for a CC triple bond (0.154 nm) and a C=C double bond (0.134 nm). Exercise Explain why the benzene molecule is planar, whereas the cyclohexane molecule is puckered. Exercise Certain bond angles have been marked in the compound shown below. The 2—dimensional diagram does not indicate the true angles. (a) (b) Suggest approximate values for the bond angles marked 1, and 4 in the three dimensional structure, and explain any difference between these values. Arrange the bonds C—Cl, C=O, C—O, CC, CN and C—H (in H—CC—H) in order of increasing length. Give explanation when necessary. SOLUTION ,