Geom graphing parallel perpendicular midpoint distance

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Pre-AP Geometry
Graphing, Parallel, Perpendicular, Midpoint, Distance
Name _______________
Hey there. Class, over the next hour, your mission is to undertake the awesome responsibility of expressing to
the yourself how much you have learned about graphing, slopes, y-intercepts, equations, parallel, perpendicular,
midpoint, distance, and story problems. These topics may be the most important foundation skills necessary
for success in high school math. “We can only see a short distance ahead, but we can see plenty there that needs to be done.” Alan Turing
Solve for y and graph using the y-intercept and the slope.
1. 4 x  3 y  15
2. 6 x  3 y  12
3.  2 x  y  3
4. Is the point (-6, 13) on the line from question #1. Use substitution. Show your work for credit.
Find an equation from the given information.
Steps 1. Identify x1 , y1 and m
2. Write the definition
y  y1  m( x  x1)
(Hey, that’s the point-slope form)
3. Plug in values and solve for y
5. Write the equation of the line with the point (3, -5) and slope 6.
6. Write the equation of the line with the point (-4, 7) and parallel to y 
3
x  5.
2
y2  y1
x x y y 
, find midpoint  xm , ym    1 2 , 1 2  and distance d 
2 
x2  x1
 2
for the following sets of ordered pairs.
 x2  x1    y2  y1 
Find slope, m 
y2  y1
x2  x1
m
x1  x2 y1  y2 
,

2 
 2
 x2  x1    y2  y1 
2
y2  y1
x2  x1
x1  x2 y1  y2 
,

2 
 2
 xm , ym   
d
2
8. (5,  3) (4,  6)
7. (4, 5) ( 8, 11)
m
2
 xm , ym   
2
d
 x2  x1    y2  y1 
2
2
Class, we have also learned to find the equation from two points. Use the steps provided to successfully
complete your math mission.
Steps 1. Identify ( x1 , y1 ) ( x2 , y2 )
2. Find the slope using m 
3. Write the definition
y 2  y1
x 2  x1
y  y1  m( x  x1)
(Hey, that’s the point-slope form)
4. Plug in values and solve for y
9. Write the equation of the line through the points (6, 4) (8,14) .
10. Write the equation of the line containing the midpoint of (8,  3) (4,5) and perpendicular to y 
3
x5
2
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