Test-1/12th/JEEMAIN(1)/Set-1
Mittal Sir
III-A/172 , Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091.
email : bmcchemistry@gmail.com, website : www.bmcchemistry.com
CODE
TEST-1/12th/JEE-MAIN(1)
1
Topic : Solid State (75%),
Nomenclature of Hydrocarbons (XI), Metallurgy of Al & Ag (25%)
Date : 6 April 2014
Max Marks : 120
Time : 50 minutes
INSTRUCTIONS
General Instructions
1.
Ensure matching of OMR sheet code with the Question paper
Code before you start marking your answers on OMR sheet
2.
On the answer sheet, darken the appropriate bubble with
Blue/Black Pen only. Use of pencil and any other ink pink
strictly prohibited.
3.
Any kind of cutting, rubbing or use of whitener not allowed on
answer sheet.
Marking Scheme
(Ques 1 - 30) contains 30 multiple choice question which have
one correct answer. Each question carries +4 marks for correct
response and -1 mark for wrong answer. [120 Marks]
Roll No.
Name of the student
“All the best”
BMC CLASSES
III-A/172, Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091
Page No - 1
Test-1/12th/JEEMAIN(1)/Set-1
Mittal Sir
(Total Marks : 120)
Single Correct Answer Type(+4/-1)
This section contains 30 multiple choice questions. Each question has 4 choices (a), (b), (c) and (d) for its
answer, out of which ONLY ONE is correct.
1. Radius of tetrahedral void in a c.c.p lattice is 100 Pm. Radius of octahedral void is –
(a) 184 Pm
(b) 100 Pm
(c) 54.3 Pm
(d) 414 Pm
2. Which of the following is not correct about graphite and diamond
(a) graphite  sp2, diamond  sp3
(b) graphite  good conductor of heat, diamond  Insulator of heat
(c) graphite  crystalline, diamond  crystalline
(d) graphite  good conductor of electricity, diamond  Insulator of electricity
3. A crystal has formula P3Q2. If ‘P’ atoms form c.c.p lattice than
(a) ‘Q’ atom occupy all tetrahedral void
(c) ‘Q’ atoms occupy all octahedral voids
(b) ‘Q’ atoms occupy 2 rd of tetrahedral voids
3
2
(d) ‘Q’ atoms occupy rd of octahedral voids.
3
4. An element ‘A’ (atomic mass = 54 gm/mol) crystallises in F.C.C lattice with edge length 300
Pm. The pyknometric density of crystal was found to be 10 gm/cm3. This data show that
crystal has –
(a) No defect
(b) vacancy defect (c) impurity defect (d) Interstitial defect
5. An element has b.c.c structure with cell edge 288 Pm. The density of element is 7.2 gm/cm3.
Number of atoms present in 208 gm of element are
(a) 2.4  1022 atoms
(b) 2.4  1023 atoms (c) 2.4  1024 atoms
(d) 2.4  1025 atoms
6. Coordination number of a molecule in a square close packed layer is –
(a) 4
(b) 6
(c) 8
(d) 12
7. If NaCl is doped with 2  10–4 mol% TlCl3, number of cation vaccancies formed are –
(a) 4  10+19
(b) 2.4  10+18
(c) 2.4  10+19
(d) 1.2  10+18
8. Which of the following set contain all network solid (covalent solid)
(a) graphite, diamond, SiO2
(b) graphite, SiO2, I2
(c) Diamond, ice & Ar
(d) HCl, SO2 & ice
9. Packing fraction of the face shown in figure is
(a) 74 %
(b) 68%
(c) 57 %
(d) None of these
10. Gallium (atomic mass = 70) has comparatively very low melting point for this one of the
reason that it exist as Ga2 molecular solid. Gallium crystallises in ABCABC type packing in
which each lattice point is occupied by Ga2 molecule. If volume of unit cell is 1.25  10–22 cm3
than density of crystal is –
(a) 7.47 gm/cm3
(b) 3.73 gm/cm3
(c) 5.6 gm/cm3
(d) 11.2 gm/cm3
Space for rough work
BMC CLASSES
III-A/172, Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091
Page No - 2
Test-1/12th/JEEMAIN(1)/Set-1
Mittal Sir
11. When silicon is doped with arsenic the semiconductor formed is of type
(a) ‘n’ type
(b) ‘p’ type
(c) n-p type
(d) p-n type
12. Total number of tetrahedral voids in 11.2 gm of crystal of iron which has H.C.P structure
(Fe = 56 gm/mol)
(a) 1.2  1023
(b) 2.4  1023
(c) 3.6  1023
(d) 4.8  1023
13. The length of body diagonal of a F.C.C lattice is 300 3 Pm. Distance between the centre of
two adjoining faces is –
(a) 300
2
(b)
300
3
(c)
300
2
(d)
300 2
3
14. A compound AB has rock salt structure in which ‘A’ ion occupy octahedral void of the F.C.C
unit cell of ‘B’ ion. If all the ions present from an axis passing through two opposite faces are
removed than formula of resulting crystal is
(a) A4B3
(b) A3B4
(c) A2B3
(d) AB
15. A sample of non stoichiometric cuprous oxide contain 90% Cu+ and remaining Cu++. The
formula of oxide would be
(a) Cu2O
(b) Cu2.1O
(c) Cu1.8O
(d) Cu1.9O
16. In which case(s) the coordination number of cation is ‘8’
(i) ‘CsCl’ structure
(ii) Fluorite structure
(iii) Anti fluorite structure
(iv) Rock salt structure
(a) (i) & (ii)
(b) (i) & (iii)
(c) (i), (ii) & (iv)
(d) All of these structures
17. Total number of hexagonal faces in a truncated octahedron are
(a) 4
(b) 6
(c) 8
(d) 12
18. An element ‘A’ crystallises in ABABAB close packed structure. If radius of ‘A’ atom is
120 cm. Volume of unit cell is –
(a) 3.85  10–24 cm3
(b) 5.864  10–24 cm3 (c) 3.85  10–23 cm3 (d) 5.864  10–23 cm3
19. The correct I.U.P.A.C name of compound
CH3 – CH – CH2 – CH – CH2 – CH3
CH3
CH2CH3
(a) 3-Ethyl-5-methyl hexane
(b) 4-Ethyl-2-methyl hexane
(c) 3-(-2-methyl propyl) pentane
(d) all of these
20. In compound 5-(2-Ethyl butyl)-3, 3-dimethyl decane, total number of ‘CH3’ present are –
(a) 6
(b) 5
(c) 7
(d) 8
21. In cyanide process of metallurgy of silver, the ore is leached with a dilute solution of NaCN in
presence of gas –
(a) O2
(b) Ar
(c) CO2
(d) H2
Space for rough work
BMC CLASSES
III-A/172, Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091
Page No - 3
Test-1/12th/JEEMAIN(1)/Set-1
Mittal Sir
22. In metallurgy of aluminium, bauxite ore is leached with concentrated solution of NaOH
because –
(a) Impurity Fe2O3 & TiO2 are soluble in NaOH
(b) Impurity SiO2 and Fe2O3 are soluble in NaOH
(c) Impurities Fe2O3 & TiO2 are insoluble in NaOH
(d) All impurities & Al2O3 are soluble in NaOH
23. Percentage of Fe+++ ion is Fe0.95O is –
(a) 10.52%
(b) 89.5%
(c) 8.4%
(d) 95%
24. Cryolite is added in alumina to –
(a) decrease electrical consumption during electrolysis
(b) make more malleable aluminium
(c) decrease melting point of alumina
(d) decrease conductivity of alumina
25. In cyanide process of metallurgy of silver, role of zinc is –
(a) Reducing agent
(b) oxidation agent
(c) to decrease M. point of [Ag(CN)2]–
(d) to increase M. point of [Ag(CN)2]–
26. If ‘a’ stands for the edge length of the cubic systems :
simple cubic, body centred cubic and face centred cubic, then the ratio of radii of the
spheres in these systems will be respectively.
1
(a) 1 a : 3 a: 1 a
(b) a : 3 a: 1 a
2
2
4
2
2 2
(c)
1
2
3
a:
a:
a
2
2
2
(d) 1a :
3 a:
2a
27. Structure of a mixed oxide is cubic close packed (c.c.p). The cubic unit cell of mixed oxide is
composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A
and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is
(a) ABO2
(b) A2BO2
(c) A2B3O4
(d) AB2O2
28. What will be the percentage of free space in bcc lattice?
(a) 32
(b) 68
(c) 75
(d) no free space
29. The arrangement of X– ions around A+ ion in solid AX is given in the figured (not drawn to
scale). If the radius of X– is 250 pm, the radius of A+ is.
X–
A+
(a) 104 pm
(b) 125 pm
(c) 183 pm
(d) 57 pm
30. If ionic radius of Cs+ and Cl– are 1.69Å and 1.81 Å respectively, the edge length of unit cell is
(a) 4.04 Å
(b) 3.50 Å
(c) 7.00 Å
(d) None of these
Space for rough work
BMC CLASSES
III-A/172, Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091
Page No - 4
Test-1/12th/JEEMAIN(1)/Set-1
Mittal Sir
III-A/172 , Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091.
email : bmcchemistry@gmail.com , website : www.bmcchemistry.com
TEST-1/12th/JEE-MAIN(1)
CODE
1
Topic : Solid State (75%),
Nomenclature of Hydrocarbons (XI), Metallurgy of Al & Ag (25%)
Date : 6 April 2014
Max Marks : 120
Time : 50 minutes
Roll No.
Name of the student
Note : Write your name and roll no. above in box before filling the answers.
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BMC CLASSES
III-A/172, Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091
Page No - 5
Test-1/12th/JEEMAIN(1)/Set-1
BMC CLASSES
III-A/172, Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091
Mittal Sir
Page No - 6