MAT-115 Week 5 CheckPoint Assignment -- Due Day 5 (Friday)
NAME:
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B99
Instructions: In order to complete your assignment in an organized and efficient manner, please use this template to type
your work and answers. Save this template to your computer, complete the problems (showing all work as if you did not
have a calculator, unless otherwise stated), and post as an attachment to your <Individual> forum. If you cannot read the
problems on this template, refer to the eTextbook on the course aXcess page. Note: DO NOT CHANGE RATIOS TO
MIXED NUMBERS because they are not fractions. Mixed numbers is a format applied only to fractions.
REMEMBER: NO WORK = NO CREDIT
Problems (2 points each)
Section 5.1 #8 (pg. 381)
Write the following ratio in simplest form.
3
1
8. The ratio of 5 to 2
10
5
Section 5.1 #24 (pg. 381)
Write the following ratio in simplest form.
24. The ratio of 7 dimes to 3 quarters
Section 5.1 #34 (pg. 383)
34. Marc took 3 hours to mow a lawn while Angelina
took 150 minutes to mow the same lawn a week earlier.
Write the ratio of Marc’s time to Angelina’s time as a
ratio of whole numbers.
Section 5.2 #14 (pg. 390)
Find the rate.
240 _ pounds _ of _ fertilizer
14.
6 _ lawns
Section 5.2 #30 (pg. 392)
30. Which is the better buy: 5 pounds of sugar for $4.75
or 20 pounds of sugar for $19.92?
Section 5.3 #10 (pg. 400)
Write the proportion that is equivalent to the given
statement.
10. If Maria hit 8 home runs in 15 softball games, then
she should hit 24 home runs in 45 games.
TYPE YOUR SOLUTION(S) HERE
Convert to improper fractions:
28/5 to 21/10
Multiply by 10:
56 to 21
Divide by 7:
8 to 3
7 dimes = 0.7
3 quarters = 0.75
0.7 to 0.75
Multiply by 100:
70 to 75
Divide by 5:
14 to 15
3 hours = 180 minutes
180 to 150
Divide by 10:
18 to 15
Divide by 3:
6 to 5
240 divided by 6
= 40 pounds per lawn
4.75/5 = 0.95
19.92/20 = 0.996
The 5 pounds is a better buy.
8/15 = 24/45
MAT-115 Week 5 CheckPoint Assignment -- Due Day 5 (Friday)
Problems (2 point each)
Section 5.3 #28 (pg. 401)
Determine whether each pair of fractions is proportional.
5 75
28. 
8 120
Section 5.3 #48 (pg. 402)
Determine if the given rates are equivalent.
12 _ gallons _ of _ pa int 9 _ gallons _ of _ pa int
48.

8,329ft 2
1,240ft 2
Section 5.5 #16 (pg. 415)
TYPE YOUR SOLUTION(S) HERE
Cross multiply:
5*120 = 600
8*75 = 600
They are the same, so YES.
Cross multiply:
12*1240 = 14880
9*8329 = 74961
No, they are different.
16. A store has T-shirts on sale at 2 for $5.50. At this
rate, what do five T-shirts cost?
Price of 1:
5.5/2 = 2.75
Multiply by 5:
5*2.75 = $13.75
Activity 15: Question 1 (pg. 420)
Calorie information:
1. If a person jogs at a rate of 5½ miles per hour for 3½
hours in a week, how many calories do they burn?
Important fact is that a person needs to burn off 3,500 calories more than he or she takes
in to lose 1 pound. The following table is shows the number of calories burned per hour
based on a 150 pound person.
Bicycleing 6 mi/h 240 running 10 mi/h 1,280 Bicycle 12mi/h 410
Cross-ctry skiing 700 Jogging 5 1/2 mi/h 740 jogging 7 mi/h 920
Jump Rope 750 Running in place 650 Swimming 10mi/h 275
Swimming 50yd/min 500 Tennis (single) 400 walking 2 mi/h 240
walking 3mi/h 320 walking 4 1/2 mi/h 440
Jogging at that rate burns 740 calories per hour.
Multiply that by 3 ½ hours:
= 2590 calories
Activity 15: Question 2 (pg. 420)
2. If a person runs in place for 15 minutes, how many
calories will be burned?
Activity 15: Question 3 (pg. 420)
3. If a person cross-country skis for 35 minutes, how
many calories will be burned?
Activity 15: Question 4 (pg. 420)
4. How many hours would a person have to jump rope
in order to lose 1 pound? (Assume calorie consumption
is just enough to maintain weight, with no activity.)
Activity 15: Question 5 (pg. 420)
5. At what rate would a120-pound person burn calories
while bicycling at 12 miles per hour?
Activity 15: Question 6 (pg. 420)
6. At what rate would a180-pound person burn calories
while bicycling at 12 miles per hour?
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15 minutes is ¼ of an hour
Multiply that by 650 calories
¼ * 650
= 162.5 calories (162 ½)
Skiing is 700 calories per hour
35 minutes / 60 minutes per hour
35/60 * 700
= 408 1/3 calories
It takes 3500 cal to lose a pound.
Jumping roper is 750 per hour
Divide:
3500 / 750
= 4 2/3 hours
Set up a proportion:
120/150 = x/410
Multiply by 410 on each side:
X = 120*410/150
X = 328 cal per hour
Set up a proportion:
180/150 = x/410
Multiply by 410 on each side:
X = 180*410/150
X = 492 cal per hour
MAT-115 Week 5 CheckPoint Assignment -- Due Day 5 (Friday)
Problems (2 point each)
Activity 15: Question 7 (pg. 420)
7. How many hours of jogging at 5½ miles per hour
would be needed for a 200-pound person to lose 5
pounds? (Again, assume calorie consumption is just
enough to maintain weight, with no activity.)
TYPE YOUR SOLUTION(S) HERE
5 pounds * 3500 calories = 17500 calories
Get the rate:
200/150 = x/740
X = 200*740/150
X = 986.66666 cal per hour
Divide:
17500/986.66666
= 17.736 hours (2625/148 hours)
Finished? I encourage you to go back and check each answer. Did you show all your work? Did you label every answer?
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