Chapter 3 The Lone-Chooser Method 1. By random draw, a decision

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Chapter 3 The Lone-Chooser Method
For 3 Players:
1. By random draw, a decision is made as to who is
the lone chooser and who are the dividers.
2. The dividers divide the booty between themselves
using the divider-chooser method.
D1
D2
3. Each divider divides his share into 3 sub-shares
D2
D1
4. The lone-chooser now selects one piece from
each of the divider's 3 sub-shares. Each divider then
gets his remaining 2 sub-shares.
D1
Chooser picks these two pieces
D2
Chapter 3 The Lone-Chooser Method
For 3 Players:
1. By random draw, a decision is made as to who is
the lone chooser and who are the dividers.
2. The dividers divide the booty between themselves
using the divider-chooser method.
D1
D2
3. Each divider divides his share into 3 sub-shares
D2
D1
4. The lone-chooser now selects one piece from
each of the divider's 3 sub-shares. Each divider then
gets his remaining 2 sub-shares.
D1
Chooser picks these two pieces
D2
31.
$9
$12
$27
$18
Angela
$24
$12
Boris
Carlos
Angela & Boris are the dividers and cake is cut as shown
(using divider-chooser method)
Angela's
{
{
Boris'
a. Angela's second division:
Vanilla portion is worth
Strawberry portion is worth
So total value of Angela's half is
She will make 3 pieces worth
To figure this:
o
x
90
13.50
= 6.00
each.
b. Boris' second division:
$12
Vanilla portion is worth
$18
Strawberry portion is worth
So total value of Boris' half is
He will make 3 pieces worth
each.
To figure this:
)
erry
awb
r
t
s
(
o
x
90
9.00
= 5.00
nilla
(va
)
o
x
90
6.00
= 5.00
c. Carlos' turn to choose:
(Carlos likes vanilla twice as much as strawberry, so we
assume he chooses pieces with the most vanilla.)
From Boris' cake:
From Angela's cake:
o
d. Angela gets two 40 pieces of strawberry:
o
o
Boris gets one 90 piece of strawberry and one 15 piece of vanilla
o
o
(from Angela) Carlos gets a 90 piece of van. and a 10 piece of str.
o
(from Boris) Carlos gets a 75 piece of van.
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