1. Do WebAssign 7.7 #8 - #11. Z 1 √ 2. 0 Z 3. 0 π 10 dφ θ3 + θ 5. Decide if the integral converges or diverges. If it converges, find it’s value, or give a bound on its value. Z 1 −3/2 dx sin(x) 0 2 − sin(φ) dφ φ2 4. (a) Circle one: f (t) = ln(t) is increasing, decreasing on (0, 1]. √ (b) Insert ≥ or ≤: x x on (0, 1]. (c) Explain how (a) and (b) together show that √ ln( x) ≥ ln(x) on (0, 1]. (d) Use (c) and the result from the quiz to show that Z 1 ln 0 √ x dx converges. 6. For what values of p does the integral converge/diverge. Z 1 2 dx dx x [ln(x)]p Areas and Volumes Understand Understand Apply Apply Apply Apply Section 8.1 February 16, 2016 Name: Math 129 - 20 Given a stack of slices, correctly identify the variable that will be used for integration. Given a stack of slices, correctly identify the area or volume of the approximating shapes. Express the approximate area or volume of the slices in terms of the variable of integration. Express the approximate area (or volume) or a stack of slices in the form of a Riemann Sum. Express the exact area (or volume) as a definite integral by taking a limit. Idenify the correct bounds of the definite integral In this problem, we will demonstrate how to calculate the exact area of a circle by slicing it horizontally. l ∆h h (b) The slices will be stacked in the same direction of h, use the fact that a h2 + ( 2l )2 = 32 to express the area of the rectangle in terms of h and ∆h. 3 The horizontal edges of each slice are straight, but the vertical edges are curved. Explain why the curved walls can be approximated by straight lines. (a) Express the approximate area of the shaded slice in terms of l and ∆h. (c) Write a Riemann sum to approximate the total area or the circle by stacking rectangles. (d) Write your Riemann sum as a definite integral by taking the limit as the number of height of each slice goes to zero (or simultaneously, as the number of slices goes to infinity). (Make sure the bounds on the definite integral are correct, they should be −3 and +3.) Quiz (Leave this space blank)