(C) Prep 101 and Pavel Sedach
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Chem 203 – Term Test 1 – 2013 Fall
*These are the summarized solutions. There are worked solutions for each question in the
later pages.
Multiple Choice
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
C
E
D
B
A
C
A
A
D
E
11.
12.
Written
13.a. 2.5 × 102 mL
14.i. Container 3
ii. Container 1
iii. Container 3
15.1. favor forward
2. at equilibrium
3. favor reverse
16.a. 1,6,6,6
b. 3.94 L
c. 9.33 × 1022 molecules
17.a. 3.19 atm
b. [CH2 Cl2 ] = 0.0364 M, [CH4 ] = [CCl4 ] = 0.0373 M
c. See written answers
© Pavel Sedach 2014
B
B
(C) Prep 101 and Pavel Sedach
Chem 203 – Term Test 1 – 2013 Spring
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
B
A
B
D
D
A
B
C
D
C
11.
12.
13.
14.
15.
Written: See worked solutions in the later part of this document.
© Pavel Sedach 2014
E
B
B
E
E
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(C) Prep 101 and Pavel Sedach
Chem 203 – Term Test 1 – 2013 Winter
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
E
A
E
D
B
D
E
C
B
C
11.
12.
13.
14.
15.
16.
Written: See worked solutions in the later part of this document.
© Pavel Sedach 2014
D
D
C
B
C
B
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Chem 203 – Term Test 1 – 2012 Fall
*These are the summarized solutions. There are worked solutions for each question in the
later pages.
Multiple Choice
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
B
A
E
B
C
C
D
C
E
A
11.
12.
13.
14.
D
B
D
E
Written
15.a. Kc = 8.18
b. 299 atm
c. response is to shift right
i. Because K = products/reactants, K increases
ii. The amount of CCl4 relative to CrCl decreases, therefore its partial pressure
decreases.
iii. If 1.0g of C(s) is added to a system at equilibrium, [CrCl3] remains constant because
graphite is a solid.
16.a. ΔH = -583 kJ/mol
b. -334.5 kJ
c. It is exothermic because ΔH is negative
17.a. n = 0.0757 moles PCl5
b. At equilibrium PCl2=1.40 atm
18.a. Q = 10.7 kJ
b. -0.792 kJ
c. By creating a gas the system does work on the surrounding (negative energy for the
system) through the new volume of gas created
d. 9.9 kJ
19.a. Rate = 2.8 × 10−7 s −1 [CS2 ]
b. Average rate = −8.0 × 10−4
mol
L×s
© Pavel Sedach 2014
(C) Prep 101 and Pavel Sedach
5
c. The rate depends on the concentration of CS2 (first order). Because the concentration
of CS2 is so much lower at 2000h, so is the rate. Also you can just look at/compare the
slopes to find the difference in rate (see image)
© Pavel Sedach 2014
(C) Prep 101 and Pavel Sedach
6
Chem 203 – Term Test 1 – Winter 2012
*These are the summarized solutions. There are worked solutions for each question in the
later pages.
Multiple Choice
17.
18.
19.
20.
21.
22.
23.
24.
25.
26.
A
C
B
B
D
B
D
D
C
D
27.
28.
29.
30.
31.
32.
E
A
B
C
B
D
Written
33.a. 5.2 × 104 K
b. Mol fraction is 0.43. Partial Pressure is 3.0 × 102 mmHg
c. response is to shift right
34.a. shift right
b. K increases and the system shifts right
c. Shifts right and increase
d. does not affect.
e. does not affect.
f. does not affect.
35.a. false
b. false
c. true
d. true
36.a. 1.2 g
b. 8.6 g
37.a. −541.8 kJ
b. −847.6 kJ
c. -10.04 kJ/g Al in chromium reaction, -15.71 kJ/g Al in Fe reaction and therefore more
exothermic/efficient.
© Pavel Sedach 2014
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