Copyright, Arizona State University The Basics Bonding and Structure I 1 Energies of Electrons in Atoms and Molecules • Bonding, structure, shape and reactions of organic molecules are determined PRIMARILY by the Energies of the electrons in ATOMIC and MOLECULAR ORBITALS • In organic chemistry we use MODELS, generally the most useful model is the simplest one that explains what we are trying to understand, in this case the relative energies of elecrons • Here we introduce a simple model that summarizes the basic factors that determine electron energies in atoms. Later we will develop more sophisticated models for orbitals and bonding to understand electron energies 1.1 Energies of Electrons in Atomic Orbitals • Simple picture of factors controlling electron energies (a better description is coming later…..) electron stabilized by nucleus, held "tightly" close to nucleus, relatively low energy electron 6+ electron in larger 2s A.O., further from nucleus and shielded by two 1s electrons, not held tightly, relatively high energy electron 3+ electron in even larger 2p A.O., but, higher positive charge on the nucleus (6+), thus outer electrons held reasonably tightly by nucleus, moderate energy even higher positive charge on the nucleus (8+), but now atomic orbital has another negatively charged electron, outer electrons held reasonably tightly by nucleus, moderate energy 8+ 1.2 Quantitative Energies of Electrons in Atoms • Quantitative information about the relative energies of electrons is obtained from measurements of Ionization Energies, or Ionization Potentials (IPs) • The "first" IP is the energy required to completely remove the highest energy electron from an atom or molecule, we are interested mainly in the energies of these highest energy electrons since these are the ones that are involved in chemical reactions, when we talk about I.P. we are always talking about the FIRST I.P. Example from General Chemistry (energies in eV, i.e. electron Volts) (do NOT memorize these!) Energy energy of an electron that is infinitely far from any nucleus 2s 1s 2p 1s 2p 2p 2p 2s 1s 2p 2p 2p 2p 2s 2s 1s 1s 2p – "valence" electrons, are involved in reactions/bonding – "core" electrons, not involved in reactions/bonding • VALENCE ELECTRONS are in the outer shell, they are highest in energy and get involved in bonding • CORE ELECTRONS are in the inner shells, are not involved in bonding Bonding and Structure 1 Copyright, Arizona State University • Electrons in atoms are low in energy because they are negatively charged and are stabilized by the positively charged nucleus • Electrons that are held "less tightly" by the nucleus are HIGH in energy, and thus require less energy to remove from an atom, and thus have a low IP • Many factors influence atomic I.P.s, (orbital size, nuclear charge, orbital occupancy, etc.), which looks intimidating at first, however, a detailed understanding is not necessary at this point, • What you SHOULD KNOW at this point is that I.P. increases (electron energy decreases) roughly with increasing electronegativity (i.e., left to right across the periodic table and from bottom to top, going up the periodic table) hydrogen helium 1 2 H He 1.0079 4.0026 lithium beryllium boron carbon nitrogen oxygen fluorine 3 4 5 6 7 8 9 6.941 9.012 10.811 sodium magnesium aluminium 11 12 Li Be B C 13 Na Mg 14.007 silicon phosphorus 14 Al N 12.0107 Si 15 P O 15.999 sulfur 16 S neon 10 F Ne 18.998 20.180 chlorine argon 17 18 Ar Cl 22.990 24.306 26.912 28.086 30.974 32.067 35.453 39.948 potassium calcium scandium titanium vanadium chromium manganese iron cobalt nickel copper zinc gallium germanium arsenic selenium bromine krypton 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 39.098 40.078 44.956 47.867 50.942 51.996 54.938 55.845 39.098 58.693 63.546 65.39 69.723 72.61 74.922 78.96 79.904 rubidium strontium yttrium zirconium niobium molybdenum technetium ruthenium rhodium palladium silver cadmium indium tin antimony tellurium iodine 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 85.468 87.62 91.224 92.906 95.94 [98.91] 101.07 85.468 106.42 107.87 112.41 114.818 118.71 121.760 127.60 126.904 cesium barium lutetium hafnium tantalum tungsten rhenium osmium iridium platinum gold mercury thallium lead bismuth polonium astatine 55 56 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 132.905 137.32 174.97 178.49 186.21 190.23 132.905 195.08 196.97 200.59 204.383 207.2 208.980 [208.98] [209.99] K Ca Sc Ti Rb Sr Y 88.906 Cs Ba V 36 Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Zr Nb Mo Tc Ru Rh Pd Ag Cd Lu Hf Ta W Re Os Ir 180.95183.84 Pt Au Hg In Sn Sb Te Kr 83.80 xenon 54 I Tl Pb Bi Po At Xe 131.29 radon 86 Rn [222.08] 1.3 Energies of Electrons in Molecules, e.g. Hydrogen (more) • We can also measure energies of electrons in molecules as Ionization Potentials Energy energy of an electron that is infinitely far from any nucleus IP ~ 13.6 IP ~ 15.4 lower energy IN A BOND H atom 1s atomic orbital H2 molecule σ molecular orbital • IP in MOLECULAR hydrogen is LARGER than in atomic hydrogen • the electrons in MOLECULAR hydrogen are thus LOWER in energy Question. Why are the electrons lower in energy in molecular hydrogen compared to H atom? Answer Because they are IN A BOND - this is really important each electron stabilized by two nuclei electron stabilized by one nucleus H atom 1s atomic orbital H2 molecule, covalent bond σ molecular orbital • In the molecule, the nuclei are shielded from each other by the two electrons • In the molecule there is an electrostatically stable configuration for the two negatively and two positively charged particles (the electrons and the protons) • this is the STANDARD explanation for why the energies of electrons are lowered when in a bond, later we will learn a better explanation We have already learned the TWO MOST CRITICAL CONCEPTS for UNDERSTANDING organic chemistry: 1. Forming bonds stabilizes (lowers the energies of) electrons 2. Higher energy electrons are MORE CHEMICALLY REACTIVE Bonding and Structure 2 Copyright, Arizona State University 2 Introduction to Bonding in Molecules: The Lewis Structure Model 2.1 Atomic Valence and Lewis Structures Making a Molecule of H2 as a Simple Example 1 valence electron H 1s H electron configuration H• shared electrons: covalent bond H H •H Lewis "dot" structure H H Lewis or Kekule structure • each hydrogen atom makes one bond, because in doing so it lowers the energy of its one electron • hydrogen can only make one bond because it only has one VALENCE electron Making a Molecule of CH4 as a Simple Example 2 core electrons H 4 valence electrons 1s2 2s22p2 C H C electron configuration H C H shares 8 C H shares 2 H H Lewis "dot" structure H H H C H H Lewis or Kekule structure • carbon has four valence electrons, therefore it lowers the energy of four electrons by making four bonds • after making four bonds, according to the Lewis dot model its outer shell is now "full" with 8 electrons, it obeys the "filled shell", sometimes call "octet rule" for second row elements, but really what it did was lower the energies of as many electrons as it could, the 4 valence electrons in this case • the hydrogens also have a "full" first shell with 2 electrons • The filled shell rule and the pictures of the Lewis dot structures are MODELS (remember, we use the simplest model that is useful) Making a Molecule of NH3 as a Simple Example H X 2 core electrons 5 valence electrons 1s2 2s22p3 N N electron configuration H H N shares 2 H N H no more bonds H shares 8 Lewis "dot" structure H non-bonding electrons H N H H Lewis or Kekule structure • nitrogen has five valence electrons, but can only lower the energy of three electrons to make bonds before "filling" the outer electron shell, attempting to make another bond "overfills" the shell and violates the "filled shell rule" (later we will show that attempting to make another bond, violating the filled shell rule, increases instead of decreasing electron energy) • Nitrogen in this case has two NON-BONDING electrons in the outer shell • The octet rule and the pictures of the atoms and molecules as Lewis dot and Lewis structues are MODELS (we use the simplest useful model) UNFORTUNATELY, there is MORE THAN ONE USE of the word VALENCE 1) The outer shell is the VALENCE SHELL, the electrons in the outer shell are the VALENCE ELECTRONS 2) the number of bonds that an atom normally makes without violating the "filled shell rule" is the NORMAL VALENCE Bonding and Structure 3 Copyright, Arizona State University • "Normal" Bonding Patterns (normal VALENCE) for various atoms obtained from the atomic configuration and by using the filled shell rule (again, a better model is coming soon!) • do NOT memorize this table, learn the Normal Valences by working with them by building organic structures atom 1st shell 2nd shell 3rd shell electron configuration # valence electrons maximum possible number of electrons in outer shell normal valence (normal # of covalent bonds) H 1s 1 2 1 B 1s2 2s22p1 3 8 3 C 1s2 2s22p2 4 8 4 N 1s2 2s22p3 5 8 3 O 1s2 2s22p4 6 8 2 F 1s2 2s22p5 7 8 1 P 1s2 2s22p63s23p3 5 8 3 or 5! S 1s2 2s22p63s23p4 6 8 2,4 or 6! • # of valence electrons = # of electrons in highest energy shell • normal valence = # of electrons required to fill shell rule = # of bonds atoms "normally" makes • Boron does not have enough electrons to fill the shell, even if all are involved in bonding • Filled shell or Octet rule doesn't really work for 3rd row elements, e.g. phosphorus and sulfur, see why later • Obeying the filled shell "rule" is the same as obeying the normal RULES OF VALENCE (normal number of bands), i.e. 4 bonds to each C, 3 bonds to each N, 2 bonds to each O etc. Example Problem 1 Draw a Lewis "dot" and a Lewis (Kekule) structure for N2H4 The filled shell "rule"/Normal Valence requires…. • 3 bonds to each nitrogen, N is TRIvalent (each nitrogen wants to make THREE bonds) • 1 bond to each hydrogen, H is MONOvalent (each hydrogen wants to make ONE bond) non-bonding electrons (lone pairs) octet rule satisfied for N H H H H N N N N H H H H Lewis "dot" structure Lewis structure • Each N has 8 electrons associated with the formal outer (valence) shell • Each N "shares" 6 electrons in the three bonds, each N is considered to "own" 1 of each shared pair in each bond, thus each N "owns" 3 of the bonding electrons • Each N "has" 2 (or one pair of) nonbonding electrons • Thus each N shares 8 electrons and "owns" 5 (3 bonding + 2 non-bonding = 5) • note that the NON-BONDING electrons are shown in the Lewis structure • LEWIS DOT STRUCTURES ARE TEDIOUS TO DRAW, THIS IS THE LAST TIME WE WILL USE THEM! Example Problem 2 Draw two different Lewis structures for C2H6O The filled shell "rule" /Normal Valence Requires….. • 4 bonds to each TETRAvalent carbon (each carbon wants to make FOUR bonds) • 2 bonds to each DIvalent oxygen (each oxygen wants to make TWO bonds) • 1 bond to each MONOvalent hydrogen (each hydrogen wants to make ONE bond) Bonding and Structure 4 Copyright, Arizona State University • The oxygen "shares" 4 electrons in the 2 bonds, "has" 4 non-bonding electrons, thus "owns" 6 electrons • Lewis/Kekule structures indicate connectivity of atoms, orientation doesn't matter (for now!) • Different Lewis (Kekule) structures are ISOMERS, more on isomers later….. Example Problem 3 Draw a Lewis structure for HNO2, satisfying the normal rules of valence • 3 bonds to each TRIvalent nitrogen • 2 bonds to each DIvalent oxygen • 1 bond to each MONOvalent hydrogen 7 electrons around each O O H 6 electrons on N 7 on one O N O H N H O O O O N 8 electrons on both O and N • N "shares" 6 electrons and "has" 2 electrons (obeys octet rule) • H "shares" 2 electrons" • EACH O "shares" 4 electrons in the 2 bonds, "has" 4 non-bonding electrons (obeys octet rule) • NOTE, the nitrogen-oxygen DOUBLE bond is required to satisfy normal rules of valence for N and O 2.2 Condensed Structures • Equivalent to abbreviated Lewis structures, the order of atom connectivity/bonding implied by the "written" order but the bonds are not explicitely included Example 1: Convert the provided condensed formula into a Lewis/Kekule structure • Obeying the normal rules of valence for C (4 bonds), H (1 bond) and O (2 bonds) can generate only one possible Lewis structure carbon with 3 H's connected to carbon with 2 H's connected to carbon with 2 H's connected to oxygen with 1 H CH3CH2CH2OH condensed H H H H C C C H H H O Lewis H • note that the non-bonding electrons ARE shown in Lewis structures • H3C- is a common structural motif in organic structures (end of a chain) Example 2: Convert the provided condensed formula into a Lewis/Kekule structure • Obeying the normal rules of valence for C (4 bonds), H (1 bond) and O (2 bonds) can generate only one possible Lewis structure parenthesis means repeated unit parenthesis means "off" the main chain CH3C(CH3)2CH(OH)CO2CH3 functional group H H C H H H C C only possible H H C H connectivity order H O C H H "double bond" O C 2 bonds to C H O C H H -CO2CH3 = C H O O C H H • note carbon to oxygen double bond, required to satisfy the normal rules of valence for all atoms • note TWO DIFFERENT USES OF PARENTHESES 1) Indicates a part of the structure that comes "off" the main chain 2) Indicates repeating units along the main chain Bonding and Structure 5 Copyright, Arizona State University Example 3. Convert the provided condensed formula into a Lewis/Kekule structure • Obeying the normal rules of valence for C (4 bonds), H (1 bond) and O (2 bonds) can generate only one possible Lewis structure parenthesis means 2 -CH2- groups in a row CH3(CH2)2CCCOCH2CO2H acid functional group H H H H C H C C H H C C O H C C H O C must be a triple bond here O H • Note the use of parentheses to indicate repeating units (the other use is to represent a group "off" the main chain). These two uses are easily distinguishable using the normal rules of valence, only one will "work" in a particular context 2.3 Line-angle Structures • Sometimes also called SKELETAL structures • The lines show bonds between carbon atons, no H's shown unless part of a functional group (see later for definition) Example 1 H H O C H C (CH3)3CCOCH2OCH3 H C C H C H H condensed O C H H C H Lewis structure H H H H O O Line angle (skeletal) • there is an atom (carbon unless otherwise specified) at each "end" of each line, each line is a covalent bond • Full Lewis structures sometimes just take too long to draw, and we will usually use line-angle (skeletal) structures instead (especially for rings) Example 2 Draw TWO DIFFERENT Lewis (Kekule), condensed and line angle structures for C4H6O (i.e. draw two ISOMERS, defined in detail below) Lewis structure H C H O C C H H H C C H H C H C H Condensed structure Line Angle structure O H H C O CH2CHCH2CHO this H is part of the aldehyde functional group H2C H2C CH CHO O H H Bonding and Structure H line angle good for rings 6 Copyright, Arizona State University • condensed formulas are not very good for drawing rings • line-angle structures are very good for rings • where reasonable, draw the angles roughly correct for the molecular shape, see later Q. Which Kind of Structure to Draw (condensed, Lewis, line-angle etc)? A. Depends upon the context, we will use mainly line angle or a line angle/Lewis mix 3 Isomers • Isomers are different compounds with same molecular formula (we have already seen some of these) • We meet two kinds of isomers in this course, structural isomers and stereoisomers 3.1 Structural (Constitutional) Isomers • These are isomers that differ in the order in which the atoms are connected (connectivity of the atoms), they differ in the order in which the atoms are bonded together • Their physical and chemical properties are DIFFERENT, they are different structures, different molecules, different chemicals Example 1: Structural isomers for C4H10 C4H10 TWO isomers are possible H3C CH2 CH2 CH3 H3C CH CH3 CH3 isobutane b.p. = -11.7° butane b.p. = -0.5° Example 2: Structural isomers for C5H12 4 3 CH2 CH3 C5H12 THREE isomers H3C CH2 CH2 CH2 CH3 (5) 2 H3C CH 4 CH3 3 CH2 CH3 1 2 CH 1 CH3 are possible (5) CH3 CH3 H3C C CH3 CH3 same structure NOT isomers • Note that the direction in which the bonds "point" is irrelevant, structural isomers are generated by connecting atoms together in a different order only • There are thus THREE different structural isomers that have the molecular formula C5H12 Example 3: Generate ALL Structural isomers for C6H14 • useful strategy is often to start with the longest possible chain, and progressively "branch" CH3 CH2 CH2 CH2 CH2 CH3 • We find that there are FIVE possible structural isomers • the direction in which the bonds "point" is irrelevant, structural isomers are generated by connecting atoms together in a different order only Bonding and Structure 7 Copyright, Arizona State University Example 4: How many DIFFERENT isomers are there shown below? CH3 CH3 CH2 CH 1 2 3 1 2 3 CH3 CH2 CH CH2 CH3 4 5 4 5 CH2 CH3 1 2 H3C CH2 CH3 5 CH3 H3C 1 2 3 4 CH2 CH CH2 1 CH3 5 CH 3 2 3 4 CH2 CH CH2 CH3 3 HC CH3 5 4 H3C CH2 CH3 there are no structural isomers here, this is the SAME structure, the order of connectivity of he atoms is the same in each, the structure is simply drawn differently on paper Visualize Isomers, or Lack Of! 3.2 Stereoisomers, Specifically cis/trans or Geometrical Isomers • These are isomers of structures that contain C=C double bonds, that have the same atom connectivity (the atoms are connected together in the same order), but that differ in the orientation of at least some of the atoms in space (the direction in which they point) • Their physical and chemical properties are DIFFERENT, they are different structures, different molecules, different chemicals • There are different NAMES for stereoisomers! This can be confusing but we will try to use the simplest terminology • The isomers that we are talking about in this section of the notes are called geometrical isomers, but that is an older term that is seldom used now, they are also called configurational isomers, this is sometimes still used, but the term cis/trans isomers is very commonly used and is very explicit (it is easy to understand) this is the term that we will mainly use • Cis/trans geometrical isomers that can occur when a structure contains a C=C double bond • The term diastereomers also applies to this kind of stereoisomers, and we will use it to distinguish this from another kind of stereoisomer that we will meet later in the course. It is better to introduce the term diastereomer now (it will be less confusing later), although we will probably mainly use the term cis/trans isomers. H3C (opposite sides) H C H C stereoisomers (diastereomers) b.p. 0.8° H C H Bonding and Structure H C H3C CH3 trans-butene Br H b.p. 3.7° C (same side) CH3 cis-butene Br C Br C Br stereoisomers (diastereomers) H 8 H Br C C H H structural isomers C Br Copyright, Arizona State University BOND ROTATION (OR LACK OF) IS RESPONSIBLE FOR CIS/TRANS ISOMERS, AND IS THE REASON THAT THERE ARE NO EQUIVALENT STEREOISOMERS FOR STRUCTURES THAT DO NOT HAVE A C=C DOUBLE BOND Compare rotation around SINGLE and DOUBLE bonds Br CH3 H C C H single bond H rotation H3C same structure • rotation around a single bond occurs READILY and does NOT generate isomers • rotation around single bonds generates conformers of the same structure, to be discussed in more detail later Visualize Isomerization and Single Bonds Br CH3 Br = C H3C C trans- H NO! double bond rotation H Br C H3C DIFFERENT structures stereoisomers = C cis- Br CH3 • rotation around a double bond is RESTRICTED (essentially we can assume that it does not occur under normal conditions), STEREOISOMERS CAN thus form in suitable structures that have C=C double bonds (although not all structures with C=C double bonds will have isomers) • Here we have one TRANS-stereoisomer where the two -CH3 groups are on OPPOSITE SIDES of the double bond, and one CIS-stereoisomer where the two -CH3 groups are on the SAME SIDE of the double bond Visualize Isomerization and Double Bonds Bonding and Structure 9 Copyright, Arizona State University • Note that here we have not really explained WHY bond rotation occurs (rapidly) for C-C single bonds and not for C=C double bonds, for now we will just accept it as a fact, and we will revisit the question of exactly why later in the course 3.3 Superimposibility • identical structures are SUPERIMPOSABLE Example: Are the following two structures the same or are they isomers? 30° rotate around rotate entire indicated bond structure 30° same shape superimposable • remember, rotation around a single bond occurs readily and does not generate a new structure • bond rotation followed by complete molecule rotation (by 30°) generates a new version of the original that is SUPERIMPOSABLE on the second structure • the structures are superimposable, therefore they are the same structure (just drawn two different ways) Visualize Bond Rotation with a Model Example: Are the following two structures the same or are they isomers? C H H Cl C C H cis-diastereomer H C Cl trans-diastereomer Cl Cl C HC H H NON-Superimposable!! X Cl X Cl NON-Superimposable!! C Cl C Cl H • trying to superimpose the cis- structure on top of the trans- fails, the structures are non-superimposable, they are this isomers, in this case they are stereoisomers • Note: It is NOT NECESSARY to confirm lack of superimposability when identifying isomers, often this is not necessary (overkill!), but superimposibility is the most critical test for isomers that we will resort to in difficult cases, and especially when we encounter more subtle forms of stereoisomers later 3.4 Generating Structural Isomers Using Degrees of Unsaturation • The degrees (ALSO KNOWN AS ELEMENTS) of unsaturation is an important piece of information about a molecule/structure that is obtained from the molecular formula Consider structures consisting of linear chains of carbon atoms joined by single bonds. How many hydrogen atoms can be attached to these chains of carbon atoms? Bonding and Structure 10 Copyright, Arizona State University 3 carbons - 8 hydrogens H H H H C C C H H H 4 carbons - 10 hydrogens add 1 carbon to the chain H H H H H H C C C C H H H H H 2 "end" hydrogens each added carbon also adds 2 hydrogens • every time ONE CARBON is added to a chain, TWO HYDROGEN ATOMS are also added • that maximum # of H's any organic molecule can have is (2 x # of carbons) + 2 (the "end" H atoms) • a molecule that has the maximum number of hydrogen atoms is referred to as SATURATED • a molecule that does not have the maximum number of hydrogen atoms is UNSATURATED • a molecule can be unsaturated by having double or triple bonds and rings, each "cost" hydrogen atoms H H H H H H C H H H H H C C C H C H H H C H H C C C C C C C C C H H H H H H H H H H H H H H H C5H12 (5 x 2) + 2 = 12 0 degrees of unsaturation C5H10 double bond "costs" 2xH 1 degree of unsaturation C5H12 ring "costs" 2xH 1 degree of unsaturation Calculating Degrees (Elements) of Unsaturation (Max # of H atoms) - (Actual # of H atoms) degrees (elements) of unsaturation = 2 (Max # of H atoms = (# carbons x 2) What if the molecule contains other elements? Halogens are monovalent, they take the place a hydrogen and are counted as a hydrogen H H X H C C C X = F, Cl, Br, I H H H H Oxygen is divalent, when an oxygen atom is added to a chain zero hydrogens are added, oxygen is IGNORED 2 carbons - 6 hydrogens H H add 1 oxygen to the chain H C C H H 2 carbons and 1 oxygen - STILL 6 hydrogens H H H H O C H C H zero H atoms added to the chain H Nitrogen is trivalent, when a nitrogen atom is added to a chain, one hydrogen atom is also added. Thus one nitrogen atom is equivalent to half a carbon atom as far as adding hydrogen atoms to the chain is concerned, N is counted as HALF a carbon atom 2 carbons and 1 nitrogen - 7 hydrogens 2 carbons - 6 hydrogens H H H C C H H Bonding and Structure add 1 nitrogen to the chain H H C H H 11 each N adds 1 H to the chain H H N C H H Copyright, Arizona State University Example 1 C5H9OCl Max # of H atoms = (5 x 2) + 2 = 12 Actual # of H atoms = 9 + 1 = 10 (Cl counted as H) degrees of unsaturation = (12 - 10) / 2 = 1 degree e.g. C5H9OCl MUST have O Cl HO etc Cl double bond one ring or one double bond but NOT both ring • Two POSSIBLE structures are shown, other isomers are also possible for this molecular formula Example 2 C4H7NO C4H7NO H Max # of H atoms = (4 x 2) + 1 + 2 = 11 Actual # of H atoms = 7 degrees of unsaturation = (11 - 7) / 2 = 2 degrees C4H7NO MUST have O e.g. 2 rings or 2 double bonds or 1 ring and 1 double bond N Cl etc N H • Two POSSIBLE structures are shown, other isomers are also possible for this molecular formula • knowing the degrees (elements) of unsaturation helps in drawing Lewis structures, from the molecular formula you can determine the number of double bonds, rings etc. Example 3 generate as many line-angle structures as you can that have the molecular formula C5H10 degrees (elements) of unsaturation = (5 x 2) + 2) - (10) = 1 degree 2 • all structures must have ONE double bond or a ring, but not both…. • approach the problem systematically, start with the longest chain and progressively branch • where rings are possible, start with the largest ring and progressively get smaller same = • A maximum of TEN possible STRUCTURAL ISOMERS can be drawn, AND one PAIR OF STEREOISOMERS trans-isomer (from above) cis-isomer 4 Formal Charges • The Lewis structure model attempts to obey the filled shell/octet rule for as many atoms as possible by getting as many electrons as possible into bonds (remember, forming bonds lowers electron energy) • Sometimes this can result in structures that disobey the normal rules of valence, resulting in an atom "owning" either more or less electrons than its valence electrons • This results in an atom having a FORMAL CHARGE • atoms SHARE electrons in bonds, atoms "own" half of the shared electrons and their non-bonding electrons Bonding and Structure 12 Copyright, Arizona State University Simple Example H # of valence electrons H=1 C=4 H H H C H H H C H "sees" 2 electrons "owns" 1 electron, is neutral C "sees" 8 valence electrons "owns" 4 valence electrons, is neutral H • the carbon "sees" the two shared electrons in each of the four bonds • the carbon "owns" half of each electron pair in each bond • the carbon owns 4 electrons, neutral carbon has four valence electrons, the carbon has NO FORMAL CHARGE Example # of valence electrons O=6 N=5 H CH3NO2 H C H O N O sees 8, owns 6 electrons, neutral N sees 8 electrons, owns 4, positive charge O O sees 8, owns 7 electrons, negative charge • this is the only reasonable way to draw a Lewis structure for CH3NO2 • the "filled shell/octet rule" is obeyed for all atoms, but the normal rules of valence are not (4 bonds to the nitrogen instead of 3, and 1 bond to the lower oxygen instead of two) • the central nitrogen "sees" 8 electrons, i.e. the ones that are shared in the 4 bonds, and "owns" 4 electrons (half of the shared electrons), but requires 5 valence electrons to be neutral, the charge is +1 • the LOWER oxygen "sees" 8 electrons (6 non-bonding and the shared pair in the bond), "owns" 7 electrons (the non-bonding ones and half the shared pair), but requires 6 valence electrons to be neutral, the charge is -1 The Calculation of formal charge using a formula: formal charge = (# valence e's- (# non-bonding e's) - 1/2 (# e's in bonds) (for TWO electrons per bond) for CH3NO2 (above) C = (4) - (0) - 1/2 (8) = 0 (zero formal charge) Each H = (1) - (0) - 1/2 (2) = 0 (zero formal charge) N = (5) - (0) - 1/2 (8) = +1 (one positive charge) O(upper) = (6) - (4) - 1/2 (4) = –0 (zero formal charge) O(lower) = (6) - (6) - 1/2 (2) = –1 (one negative charge) • Later we will see that it is easier to determine formal charges on organic structures by NOT using this formula, but it is useful at this point as a way of making progress in understanding structures, so it is OK to use it for now Example Na 5 valance electrons : 5 electrons to be NEUTRAL Na formally "owns" 1 electron for each bond = 4 Na has zero non-bonding electrons "owns" one eless lectron than needed for neutrality : POSITIVE CHARGE H CH2N2 C H Na Nb Nb = (5) - (4) - (4) = –1 (one negativecharge) valence in bonds non-bonding • the "filled shell/octet" rule is obeyed in all cases, but the normal rules of valence are not • formal charges are associated with structures in which the normal rules of valence are not obeyed Bonding and Structure 13 Copyright, Arizona State University But # non-bonding zero formal charge Charge = 4 - 2 - (4/2) = 0 C H H 1/2 # bonding # valence • this is methylene (you do not have to know this), it is very reactive (its lifetime is less than 0.0000000001 second in solution), but we can still draw a valid Lewis structure for it • not ALL atoms that disobey the normal valence rules have a formal charge! 5 Functional Groups • Organic molecules consist, in general, of a carbon/hydrogen (hydrocarbon) "skeleton", that mainly determines the size and shape of the molecule, and…… • the FUNCTIONAL GROUPS, generally involving atoms that are more electronegative than carbon (so that polar bonds result), such as O, N, S etc. • chemistry takes place at the FUNCTIONAL GROUPS. When we start to discuss reactions, we will divide them into those characteristic of the various functional groups Example of an organic molecule O HO functional groups functional groups OH O cortisone anti-inflammatory carbon/hydrogen "skeleton" O functional groups Alkane (hydrocarbon) Not really a functional group, but the important "backbone" or "skeleton" of many organic molecules C-C and C-H bonds tend to be strong and relatively unreactive H H H C H means "the rest of the molecule is attached here" C C H H R stands for any alkyl chain, e.g. R–OH could be: H3C–OH or or an alkyl chain CH3CH2OH NH OH etc. N bupivacaine, an epidural anesthetic O Some Notation • a group with ONE substituents is referred to as PRIMARY (1°), the substituent is often an alkyl chain (-R) or an aryl (aromatic) group (-Ar) • a group with TWO substituents is referred to as SECONDARY (2°), the substituents are often alkyl chains (-R) or aryl groups (Ar) • a group with THREE substituents is referred to as TERTIARY (3°), the substituents are often alkyl chains (-R) or aryl groups (-Ar) Bonding and Structure 14 Copyright, Arizona State University H Z H H Primary or 1° R R Z R R Secondary or 2° Z R R Tertiary or 3° Alkene Functional Group carbon-carbon double bond OH C alkene diene alkene C linalool, used in the perfume industry NOT aromatic (see next section) does not have alternating double/single bonds Aromatic Functional Group Alternating C-C and C=C bonds in a ring - be careful to distinguish from Alkene orange B, food coloring EtO aromatic O N N N N SO3H O aromatic HO3S Ar stands for any aromatic ring system, e.g. Ar–OH could be: OH OH Cl or N OH etc. or Alkyne Functional Group carbon-carbon triple bond HO C mestranol, the estrogen used in many oral contraceptives C O Bonding and Structure 15 Copyright, Arizona State University Amine Functional Group contain a nitrogen with at least one alkyl or aryl group, here R1, R2 etc stands for any alkyl chain that may or may not be the same R2 R1 R1 R1 N N N R3 R2 3° H H 2° secondary tertiary HO R or Ar H O 1° primary S O amine NH2 taurine, supposedly active ingredient in energy drinks e.g. Red Bull Ether Functional Group oxygen between 2 alkyl or aryl groups (R, Ar) O O ether (R, Ar) tetrahydrofuran, THF, common organic solvent Epoxide Functional Group 3-membered ring containing oxygen 4,5-benzo[a]pyrene oxide, highly carcinognic O epoxide O Alcohol oxygen with 1 R or Ar group and 1 hydrogen O (R, Ar) OH H bisabolol is used to aid in the transfer of drugs through the skin alcohol Halide Functional Group aryl or alkyl group with fluoride, chloride, bromide, iodide... chloride R or Ar R R F R Cl Cl Cl Cl chloride Br R Cl I chloride a polychlorinated biphenyl (PCB), many industrial uses but toxic, bioaccumulates in animals chloride Ketone Functional Group C=O double bond with 2 akyl or aryl groups (R, Ar) O C ketone acetone, the simplest ketone, common organic solvent, nail-polish remover O (R, Ar) Aldehyde Functional Group C=O double bond with 1 R or Ar group and 1 H O (R, Ar) O C aldehyde H H HO vanillin, main extract fron vanilla bean OMe Bonding and Structure 16 Copyright, Arizona State University Carboxylic Acid Functional Group C=O with 1 R or Ar group and 1 –OH O (R, Ar) C carboxylic acid O sorbic acid, food preservative OH OH Ester Functional Group C=O double bond with –OR or -OAr group ester O (R, Ar) C O methyl paraben, food preservative, cosmetics additive, anibacterial/fungal HO O (R, Ar) O Amide Functional Group C=O with -NR2 (R or Ar) amide O C 3° O N R R C N O N R H 2° C 1° N O OH H H Cl loperamide, anti-diarrhea drug Acid Halide Functional Group C=O double bond with a halide, X means any halide, Cl, Br etc. acid chloride O (R, Ar) C O acetyl chloride, many useful reactions Cl X Nitrile Functional Group Aryl or alkyl group with carbon nitrogen triple bond O N (Ar, R) C N nitrile C N citalopram, antidepressant drug (Ar,R) means aryl or alkyl Here are some functional groups incorporated into line-angle and condensed structures that you will see and need to understand Bonding and Structure 17 Copyright, Arizona State University aldehyde alcohol carboxylic acid O O H O O H or or CHO N N H OH or nitrile and amine amide H or CO2H or O OH N H C NC NH NH2 Example problems: Indicate all functional groups, do not include alkanes ester (not ketone or ether) O O N O ether H aromatic (not alkene) ether N OH aromatic (not alkene) O amine O O ester (not ketone or ether) alkene ketone aromatic fluoride CF3 Fluoxetine (Prozac) Heroin Bonding and Structure alcohol amine 18 O alkene testosterone Copyright, Arizona State University