Kuwait University Physics Department Physics 121 Final Exam Summer Semester 2011-2012 July 30, 2012 (11.00 am – 1.00 pm) Name:…………………………………… Student No. …………………….. Instructors: Drs. Yahya Kokaj, Fikry El-Akkad Atmospheric Pressure = 1.013 x105 Pa Density of water = 103 kg/m3 Density of mercury = 13.6 x 103 kg/m3 Instructions to the students: 1. 2. 3. 4. Solve all the problems. Points for each problem are indicated. The solution should be given explicitly for each problem. Take g = 10 m/s2 except otherwise mentioned. Check the name of your instructor. NOTE: IT IS STRICTLY FORBIDDEN TO BRING ANY MOBILE COMMUNICATION DEVICES (MOBILE PHONES, PAGERS, ETC.), INTO THE EXAMINATION HALL. For use by Instructors only Problem Marks 1 2 3 4 5 6 7 8 9 10 Total Answer the following questions 1- The figure shows a system of two rods of lengths l 1 and l 2 and masses m 1 = 10 kg and m 2 = 20 kg . Find the distance between the center of mass of this system and the origin O. [4 points] M xCM = m1 x1 + m2 x 2 xCM = 10(0 ) + 20 (4 ) = 2.67 m 10 + 20 l1= 6m M y CM = m1 y1 + m2 y 2 y CM = 10 (3) + 20 (0 ) =1 m 10 + 20 2 2 rcm = xcm + y cm = (2.67 )2 + 12 O l2= 8m = 2.8 m 2- A stone is thrown vertically upward from the top of a 24 m high building as shown in the figure. It strikes the ground with a speed of 26 m/s. Find the Initial speed of the stone. [3 points] vi v = v − 2 g∆y 2 2 0 (26)2 = v02 − 2 (10)(− 24) vo =14 m / s 24 m 3. A 2-kg mass moves with a speed of 4 m/s on a frictionless surface. It strikes a spring of force constant k= 2200 N/m. Find the maximum compression of the spring. [4 points] Ei = E f m 1 2 1 2 mv = k x 2 2 2(4 ) x= = 0.12 m 2200 2 4. A disk of radius 2.5 m rotates with constant angular acceleration of 1200 rev/min2. At the moment when its angular speed is 2.0 rad/s, Find a- The tangential acceleration of a point at the rim of the disk αT = αr = [2 points] 1200 (2π ) 2.5 = 5.2 m / s 2 2 (60) b- The radial acceleration of a point at the rim of the disk α R = ω 2 r = (2 )2 2.5 = 10 m / s 2 c- The total linear acceleration. α t = α T2 + α R2 = (5.23)2 + (10)2 [2points] [1points] =11.3 m / s 2 5. A 6-kg block moves on a rough surface (µ k =0.30) under the action of a force F =60 N as shown in the figure. a. Find the normal force on the block [3 points] F ΣFy = N + F sin θ − mg = 0 N = 6 (10) − 60 sin 30 = 30 N 30 ̊ b. Find the frictional force [2 points] f k = µk N f k = 0.3 (30) = 9 N 6. A uniform rod of mass m = 4 kg and length 42 m is pivoted at point “A” while two forces are acting on it as shown in the figure. A block of mass M is hanged on the rod at a distance x from point “A” so that the system becomes in a state of equilibrium. F1= 35 N a. Find the value of M F2= 60 N [2 points] ΣFy = F1 + F2 − mg − Mg = 0 M = 35 + 60 − 4(10 ) = 5.5 kg 10 b. Find the value of x A 12m 28m [3points] Σiˆ = F1 r1 + F2 r2 − mgr − Mg x = 0 x= 35 (12 ) + 60 (40) − 4(10)21 = 36 m 5.5 (10) 7. A point source emits a spherical wave. At a distance of 10 m from the source, the wave intensity is 84 W/m2. At what distance from the source will the intensity be 8.0 W/m2. I1 r2 = I 2 r1 r2 = r1 [3points] 2 I1 84 = 10 = 32m I2 8 8. A loud music passage produces a sound level of 70 dB. What is the ratio between the intensity of this sound and that of a person speaking normally whose sound level is 40 dB? β1 − β 2 =10 log I1 I2 70 − 40 = 10 log I1 =10 3 I2 I1 I2 [3points] 9. A garden hose of area A = 12 cm2 is used to fill a round swimming pool 8.0 m in diameter. How long (in hours) will it take to fill the pool to a depth of 3.8 m if water issues from the hose at a speed v = 4.0 m/s? [4 points] v ( ) πr h V = t t 2 3.14 (4 ) 3.8 −4 12 ×10 (4 ) = t 4 t = 3.98 ×10 s = 11 h Av = A 2 3.8 m 10- A U-Shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of the U-shaped tube until the vertical height of the water column is 27.2 cm. Calculate the vertical distance h (in cm) of the mercury ( see figure) [4 points] ρ ω ghω = ρ m gh h= 10 3 (272 ) = 2 cm 13.6 × 10 3 Water h 27.2 cm Mercury